{"id":4511,"date":"2017-06-07T18:50:12","date_gmt":"2017-06-07T18:50:12","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/aacc-collegealgebrafoundations\/chapter\/read-simplify-compound-expressions-with-real-numbers\/"},"modified":"2017-08-15T12:13:34","modified_gmt":"2017-08-15T12:13:34","slug":"read-simplify-compound-expressions-with-real-numbers","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/aacc-collegealgebrafoundations\/chapter\/read-simplify-compound-expressions-with-real-numbers\/","title":{"raw":"Order of Operations With Compound Expressions and Distributive Property","rendered":"Order of Operations With Compound Expressions and Distributive Property"},"content":{"raw":"<div class=\"bcc-box bcc-highlight\">\r\n<h3>Learning Objectives<\/h3>\r\n<ul>\r\n \t<li>Simplify compound expressions with real numbers\r\n<ul>\r\n \t<li>Simplify expressions with fraction bars, brackets, and parentheses<\/li>\r\n \t<li>Use the distributive property to simplify expressions with grouping symbols<\/li>\r\n \t<li>Simplify expressions containing absolute values<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ul>\r\n<\/div>\r\nIn this section, we will use the skills from the last section to simplify mathematical expressions that contain many grouping symbols and many operations. We are using the term compound to describe expressions that have many operations and many grouping symbols. More care is needed with these expressions when you apply the order of operations. Additionally, you will see how to handle absolute value terms when you simplify expressions.\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example<\/h3>\r\nSimplify [latex] \\frac{5-[3+(2\\cdot (-6))]}{{{3}^{2}}+2}[\/latex]\r\n\r\n[reveal-answer q=\"906386\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"906386\"]This problem has brackets, parentheses, fractions, exponents, multiplication, subtraction, and addition in it.\r\n\r\nGrouping symbols are handled first. The parentheses around the [latex]-6[\/latex] aren\u2019t a grouping symbol; they are simply making it clear that the negative sign belongs to the 6. Start with the innermost set of parentheses that are a grouping symbol. In this example, the innermost set of parentheses\u00a0would be in\u00a0the numerator of the fraction, [latex](2\\cdot(\u22126))[\/latex]. Begin working out from there. (The fraction line acts as a type of grouping symbol, too; you simplify the numerator and denominator independently, and then divide the numerator by the denominator at the end.)\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{5-\\left[3+\\left(2\\cdot\\left(-6\\right)\\right)\\right]}{3^{2}+2}\\\\\\\\\\frac{5-\\left[3+\\left(-12\\right)\\right]}{3^{2}+2}\\end{array}[\/latex]<\/p>\r\nAdd [latex]3[\/latex] and [latex]-12[\/latex], which are in brackets, to get [latex]-9[\/latex].\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{5-\\left[3+\\left(-12\\right)\\right]}{3^{2}+2}\\\\\\\\\\frac{5-\\left[-9\\right]}{3^{2}+2}\\end{array}[\/latex]<\/p>\r\nSubtract [latex]5\u2013\\left[\u22129\\right]=5+9=14[\/latex].\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{5-\\left[-9\\right]}{3^{2}+2}\\\\\\\\\\frac{14}{3^{2}+2}\\end{array}[\/latex]<\/p>\r\nThe top of the fraction is all set, but the bottom (denominator) has remained untouched. Apply the order of operations to that as well. Begin by evaluating\u00a0[latex]3^{2}=9[\/latex].\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{14}{3^{2}+2}\\\\\\\\\\frac{14}{9+2}\\end{array}[\/latex]<\/p>\r\nNow add. [latex]9+2=11[\/latex].\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{14}{9+2}\\\\\\\\\\frac{14}{11}\\end{array}[\/latex]<\/p>\r\n\r\n<h4>Answer<\/h4>\r\n[latex]\\frac{5-\\left[3+\\left(2\\cdot\\left(-6\\right)\\right)\\right]}{3^{2}+2}=\\frac{14}{11}[\/latex]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nThe video that follows contains an example similar to the written one above. Note how the numerator and denominator of the fraction are simplified separately.\r\n\r\nhttps:\/\/youtu.be\/xIJLq54jM44\r\n<h2>The Distributive Property<\/h2>\r\nParentheses are used to group or combine expressions and terms in mathematics. \u00a0You may see them used when you are working with formulas, and when you are translating a real situation into a mathematical problem so you can find a quantitative solution.\r\n\r\n[caption id=\"attachment_4417\" align=\"alignleft\" width=\"366\"]<img class=\"wp-image-4417\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2011\/2017\/06\/07185011\/Screen-Shot-2016-05-27-at-1.17.49-PM-300x151.png\" alt=\"Combo Meal Distributive Property\" width=\"366\" height=\"184\" \/> Combo Meal Distributive Property[\/caption]\r\n\r\nFor example, you are on your way to hang out with your friends, and call them to ask if they want something from your favorite drive-through. \u00a0Three people want the same combo meal of 2 tacos and one drink. \u00a0You can use the distributive property to find out how many total tacos and how many total drinks you should take to them.\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\,\\,\\,3\\left(2\\text{ tacos }+ 1 \\text{ drink}\\right)\\\\=3\\cdot{2}\\text{ tacos }+3\\text{ drinks }\\\\\\,\\,=6\\text{ tacos }+3\\text{ drinks }\\end{array}[\/latex]<\/p>\r\n<p style=\"text-align: left\">The distributive property allows us to explicitly describe\u00a0a total that is a result of a group of groups. In the case of the combo meals, we have three groups of ( two tacos plus one drink).\u00a0The following definition describes how to use the distributive property in general terms.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3>The Distributive Property of Multiplication<\/h3>\r\nFor all real numbers <i>a, b,<\/i> and <i>c<\/i>,\u00a0[latex]a(b+c)=ab+ac[\/latex].\r\nWhat this means is that when a number multiplies an expression inside parentheses, you can distribute the multiplication to each term of the expression individually.\r\n\r\n<\/div>\r\nTo simplify \u00a0[latex]3\\left(3+y\\right)-y+9[\/latex], it may help to see\u00a0the expression translated into words:\r\n<p style=\"text-align: center\">multiply three by (the sum of three and y), then subtract y, then add 9<\/p>\r\n<p style=\"text-align: left\">To multiply three by the sum of three and y, you use the distributive property -<\/p>\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\,\\,\\,\\,\\,\\,\\,\\,\\,3\\left(3+y\\right)-y+9\\\\\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\underbrace{3\\cdot{3}}+\\underbrace{3\\cdot{y}}-y+9\\\\=9+3y-y+9\\end{array}[\/latex]<\/p>\r\n<p style=\"text-align: left\">Now you can subtract y from 3y and add 9 to 9.<\/p>\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}9+3y-y+9\\\\=18+2y\\end{array}[\/latex]<\/p>\r\n<p style=\"text-align: left\">The next example shows how to use the distributive property\u00a0when one of the terms involved is negative.<\/p>\r\n\r\n<div class=\"textbox exercises\">\r\n<h3>Example<\/h3>\r\nSimplify [latex]a+2\\left(5-a\\right)+3\\left(a+4\\right)[\/latex]\r\n[reveal-answer q=\"233674\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"233674\"]\r\n\r\nThis expression has two sets of parentheses with variables locked up in them. \u00a0We will use the distributive property to remove the parentheses.\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}a+2\\left(5-a\\right)+3\\left(a+4\\right)\\\\=a+2\\cdot{5}-2\\cdot{a}+3\\cdot{a}+3\\cdot{4}\\end{array}[\/latex]<\/p>\r\n<p style=\"text-align: left\">Note how we placed the negative sign that was on b in front of the 2 when we applied the distributive property. When you multiply a negative by a positive the result is negative, so [latex]2\\cdot{-a}=-2a[\/latex]. \u00a0It is important to be careful with negative signs when you are using the distributive property.<\/p>\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}a+2\\cdot{5}-2\\cdot{a}+3\\cdot{a}+3\\cdot{4}\\\\=a+10-2a+3a+12\\\\=2a+22\\end{array}[\/latex]<\/p>\r\n<p style=\"text-align: left\">We combined all the terms we could to get our final result.<\/p>\r\n\r\n<h4 style=\"text-align: left\">Answer<\/h4>\r\n[latex]a+2\\left(5-a\\right)+3\\left(a+4\\right)=2a+22[\/latex]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<h2>Absolute Value<\/h2>\r\nAbsolute value expressions are one final method of grouping that you may see. Recall that the absolute value of a quantity is always positive or 0.\r\n\r\nWhen you see an absolute value expression included within a larger expression, treat the absolute value like a grouping symbol and evaluate the expression within the absolute value sign first. Then take the absolute value of that expression. The example below shows how this is done.\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example<\/h3>\r\nSimplify [latex]\\frac{3+\\left|2-6\\right|}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}[\/latex].\r\n\r\n[reveal-answer q=\"572632\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"572632\"]This problem has absolute values, decimals, multiplication, subtraction, and addition in it.\r\n\r\nGrouping symbols, including absolute value, are handled first. Simplify the numerator, then the denominator.\r\n\r\nEvaluate [latex]\\left|2\u20136\\right|[\/latex].\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{3+\\left|2-6\\right|}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\\\\\\\\\frac{3+\\left|-4\\right|}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\end{array}[\/latex]<\/p>\r\nTake the absolute value of [latex]\\left|\u22124\\right|[\/latex].\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{3+\\left|-4\\right|}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\\\\\\\\\frac{3+4}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\end{array}[\/latex]<\/p>\r\nAdd the numbers in the numerator.\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{3+4}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\\\\\\\\\frac{7}{2\\left| 3\\cdot 1.5 \\right|-(-3)}\\end{array}[\/latex]<\/p>\r\nNow that the numerator is simplified, turn to the denominator.\r\n\r\nEvaluate the absolute value expression first. [latex]3 \\cdot 1.5 = 4.5[\/latex], giving\r\n<p style=\"text-align: center\">\u00a0[latex]\\begin{array}{c}\\frac{7}{2\\left|{3\\cdot{1.5}}\\right|-(-3)}\\\\\\\\\\frac{7}{2\\left|{ 4.5}\\right|-(-3)}\\end{array}[\/latex]<\/p>\r\nThe expression \u201c[latex]2\\left|4.5\\right|[\/latex]\u201d reads \u201c2 times the absolute value of 4.5.\u201d Multiply 2 times 4.5.\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{7}{2\\left|4.5\\right|-\\left(-3\\right)}\\\\\\\\\\frac{7}{9-\\left(-3\\right)}\\end{array}[\/latex]<\/p>\r\nSubtract.\r\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{7}{9-\\left(-3\\right)}\\\\\\\\\\frac{7}{12}\\end{array}[\/latex]<\/p>\r\n\r\n<h4>Answer<\/h4>\r\n[latex]\\frac{3+\\left|2-6\\right|}{2\\left|3\\cdot1.5\\right|-3\\left(-3\\right)}=\\frac{7}{12}[\/latex]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nThe following video uses the order of operations to simplify an expression in fraction form that contains absolute value terms. Note how the absolute values are treated like parentheses and brackets when using the order of operations.\r\n\r\nhttps:\/\/youtu.be\/6wmCQprxlnU\r\n<h2><\/h2>","rendered":"<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ul>\n<li>Simplify compound expressions with real numbers\n<ul>\n<li>Simplify expressions with fraction bars, brackets, and parentheses<\/li>\n<li>Use the distributive property to simplify expressions with grouping symbols<\/li>\n<li>Simplify expressions containing absolute values<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/div>\n<p>In this section, we will use the skills from the last section to simplify mathematical expressions that contain many grouping symbols and many operations. We are using the term compound to describe expressions that have many operations and many grouping symbols. More care is needed with these expressions when you apply the order of operations. Additionally, you will see how to handle absolute value terms when you simplify expressions.<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Example<\/h3>\n<p>Simplify [latex]\\frac{5-[3+(2\\cdot (-6))]}{{{3}^{2}}+2}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q906386\">Show Solution<\/span><\/p>\n<div id=\"q906386\" class=\"hidden-answer\" style=\"display: none\">This problem has brackets, parentheses, fractions, exponents, multiplication, subtraction, and addition in it.<\/p>\n<p>Grouping symbols are handled first. The parentheses around the [latex]-6[\/latex] aren\u2019t a grouping symbol; they are simply making it clear that the negative sign belongs to the 6. Start with the innermost set of parentheses that are a grouping symbol. In this example, the innermost set of parentheses\u00a0would be in\u00a0the numerator of the fraction, [latex](2\\cdot(\u22126))[\/latex]. Begin working out from there. (The fraction line acts as a type of grouping symbol, too; you simplify the numerator and denominator independently, and then divide the numerator by the denominator at the end.)<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{5-\\left[3+\\left(2\\cdot\\left(-6\\right)\\right)\\right]}{3^{2}+2}\\\\\\\\\\frac{5-\\left[3+\\left(-12\\right)\\right]}{3^{2}+2}\\end{array}[\/latex]<\/p>\n<p>Add [latex]3[\/latex] and [latex]-12[\/latex], which are in brackets, to get [latex]-9[\/latex].<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{5-\\left[3+\\left(-12\\right)\\right]}{3^{2}+2}\\\\\\\\\\frac{5-\\left[-9\\right]}{3^{2}+2}\\end{array}[\/latex]<\/p>\n<p>Subtract [latex]5\u2013\\left[\u22129\\right]=5+9=14[\/latex].<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{5-\\left[-9\\right]}{3^{2}+2}\\\\\\\\\\frac{14}{3^{2}+2}\\end{array}[\/latex]<\/p>\n<p>The top of the fraction is all set, but the bottom (denominator) has remained untouched. Apply the order of operations to that as well. Begin by evaluating\u00a0[latex]3^{2}=9[\/latex].<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{14}{3^{2}+2}\\\\\\\\\\frac{14}{9+2}\\end{array}[\/latex]<\/p>\n<p>Now add. [latex]9+2=11[\/latex].<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{14}{9+2}\\\\\\\\\\frac{14}{11}\\end{array}[\/latex]<\/p>\n<h4>Answer<\/h4>\n<p>[latex]\\frac{5-\\left[3+\\left(2\\cdot\\left(-6\\right)\\right)\\right]}{3^{2}+2}=\\frac{14}{11}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>The video that follows contains an example similar to the written one above. Note how the numerator and denominator of the fraction are simplified separately.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Simplify an Expression in Fraction Form\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/xIJLq54jM44?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<h2>The Distributive Property<\/h2>\n<p>Parentheses are used to group or combine expressions and terms in mathematics. \u00a0You may see them used when you are working with formulas, and when you are translating a real situation into a mathematical problem so you can find a quantitative solution.<\/p>\n<div id=\"attachment_4417\" style=\"width: 376px\" class=\"wp-caption alignleft\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-4417\" class=\"wp-image-4417\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2011\/2017\/06\/07185011\/Screen-Shot-2016-05-27-at-1.17.49-PM-300x151.png\" alt=\"Combo Meal Distributive Property\" width=\"366\" height=\"184\" \/><\/p>\n<p id=\"caption-attachment-4417\" class=\"wp-caption-text\">Combo Meal Distributive Property<\/p>\n<\/div>\n<p>For example, you are on your way to hang out with your friends, and call them to ask if they want something from your favorite drive-through. \u00a0Three people want the same combo meal of 2 tacos and one drink. \u00a0You can use the distributive property to find out how many total tacos and how many total drinks you should take to them.<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\,\\,\\,3\\left(2\\text{ tacos }+ 1 \\text{ drink}\\right)\\\\=3\\cdot{2}\\text{ tacos }+3\\text{ drinks }\\\\\\,\\,=6\\text{ tacos }+3\\text{ drinks }\\end{array}[\/latex]<\/p>\n<p style=\"text-align: left\">The distributive property allows us to explicitly describe\u00a0a total that is a result of a group of groups. In the case of the combo meals, we have three groups of ( two tacos plus one drink).\u00a0The following definition describes how to use the distributive property in general terms.<\/p>\n<div class=\"textbox shaded\">\n<h3>The Distributive Property of Multiplication<\/h3>\n<p>For all real numbers <i>a, b,<\/i> and <i>c<\/i>,\u00a0[latex]a(b+c)=ab+ac[\/latex].<br \/>\nWhat this means is that when a number multiplies an expression inside parentheses, you can distribute the multiplication to each term of the expression individually.<\/p>\n<\/div>\n<p>To simplify \u00a0[latex]3\\left(3+y\\right)-y+9[\/latex], it may help to see\u00a0the expression translated into words:<\/p>\n<p style=\"text-align: center\">multiply three by (the sum of three and y), then subtract y, then add 9<\/p>\n<p style=\"text-align: left\">To multiply three by the sum of three and y, you use the distributive property &#8211;<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\,\\,\\,\\,\\,\\,\\,\\,\\,3\\left(3+y\\right)-y+9\\\\\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\underbrace{3\\cdot{3}}+\\underbrace{3\\cdot{y}}-y+9\\\\=9+3y-y+9\\end{array}[\/latex]<\/p>\n<p style=\"text-align: left\">Now you can subtract y from 3y and add 9 to 9.<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}9+3y-y+9\\\\=18+2y\\end{array}[\/latex]<\/p>\n<p style=\"text-align: left\">The next example shows how to use the distributive property\u00a0when one of the terms involved is negative.<\/p>\n<div class=\"textbox exercises\">\n<h3>Example<\/h3>\n<p>Simplify [latex]a+2\\left(5-a\\right)+3\\left(a+4\\right)[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q233674\">Show Solution<\/span><\/p>\n<div id=\"q233674\" class=\"hidden-answer\" style=\"display: none\">\n<p>This expression has two sets of parentheses with variables locked up in them. \u00a0We will use the distributive property to remove the parentheses.<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}a+2\\left(5-a\\right)+3\\left(a+4\\right)\\\\=a+2\\cdot{5}-2\\cdot{a}+3\\cdot{a}+3\\cdot{4}\\end{array}[\/latex]<\/p>\n<p style=\"text-align: left\">Note how we placed the negative sign that was on b in front of the 2 when we applied the distributive property. When you multiply a negative by a positive the result is negative, so [latex]2\\cdot{-a}=-2a[\/latex]. \u00a0It is important to be careful with negative signs when you are using the distributive property.<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}a+2\\cdot{5}-2\\cdot{a}+3\\cdot{a}+3\\cdot{4}\\\\=a+10-2a+3a+12\\\\=2a+22\\end{array}[\/latex]<\/p>\n<p style=\"text-align: left\">We combined all the terms we could to get our final result.<\/p>\n<h4 style=\"text-align: left\">Answer<\/h4>\n<p>[latex]a+2\\left(5-a\\right)+3\\left(a+4\\right)=2a+22[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<h2>Absolute Value<\/h2>\n<p>Absolute value expressions are one final method of grouping that you may see. Recall that the absolute value of a quantity is always positive or 0.<\/p>\n<p>When you see an absolute value expression included within a larger expression, treat the absolute value like a grouping symbol and evaluate the expression within the absolute value sign first. Then take the absolute value of that expression. The example below shows how this is done.<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Example<\/h3>\n<p>Simplify [latex]\\frac{3+\\left|2-6\\right|}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q572632\">Show Solution<\/span><\/p>\n<div id=\"q572632\" class=\"hidden-answer\" style=\"display: none\">This problem has absolute values, decimals, multiplication, subtraction, and addition in it.<\/p>\n<p>Grouping symbols, including absolute value, are handled first. Simplify the numerator, then the denominator.<\/p>\n<p>Evaluate [latex]\\left|2\u20136\\right|[\/latex].<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{3+\\left|2-6\\right|}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\\\\\\\\\frac{3+\\left|-4\\right|}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\end{array}[\/latex]<\/p>\n<p>Take the absolute value of [latex]\\left|\u22124\\right|[\/latex].<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{3+\\left|-4\\right|}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\\\\\\\\\frac{3+4}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\end{array}[\/latex]<\/p>\n<p>Add the numbers in the numerator.<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{3+4}{2\\left|3\\cdot1.5\\right|-\\left(-3\\right)}\\\\\\\\\\frac{7}{2\\left| 3\\cdot 1.5 \\right|-(-3)}\\end{array}[\/latex]<\/p>\n<p>Now that the numerator is simplified, turn to the denominator.<\/p>\n<p>Evaluate the absolute value expression first. [latex]3 \\cdot 1.5 = 4.5[\/latex], giving<\/p>\n<p style=\"text-align: center\">\u00a0[latex]\\begin{array}{c}\\frac{7}{2\\left|{3\\cdot{1.5}}\\right|-(-3)}\\\\\\\\\\frac{7}{2\\left|{ 4.5}\\right|-(-3)}\\end{array}[\/latex]<\/p>\n<p>The expression \u201c[latex]2\\left|4.5\\right|[\/latex]\u201d reads \u201c2 times the absolute value of 4.5.\u201d Multiply 2 times 4.5.<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{7}{2\\left|4.5\\right|-\\left(-3\\right)}\\\\\\\\\\frac{7}{9-\\left(-3\\right)}\\end{array}[\/latex]<\/p>\n<p>Subtract.<\/p>\n<p style=\"text-align: center\">[latex]\\begin{array}{c}\\frac{7}{9-\\left(-3\\right)}\\\\\\\\\\frac{7}{12}\\end{array}[\/latex]<\/p>\n<h4>Answer<\/h4>\n<p>[latex]\\frac{3+\\left|2-6\\right|}{2\\left|3\\cdot1.5\\right|-3\\left(-3\\right)}=\\frac{7}{12}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>The following video uses the order of operations to simplify an expression in fraction form that contains absolute value terms. Note how the absolute values are treated like parentheses and brackets when using the order of operations.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Simplify an Expression in Fraction Form with Absolute Values\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/6wmCQprxlnU?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<h2><\/h2>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-4511\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li>Revision and Adaptation. <strong>Provided by<\/strong>: Lumen Learning. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Screenshot Combo Meal. <strong>Provided by<\/strong>: Lumen Learning. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Simplify an Expression in Fraction Form. <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com) for Lumen Learning. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/xIJLq54jM44\">https:\/\/youtu.be\/xIJLq54jM44<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Simplify an Expression in Fraction Form with Absolute Values. <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com) for Lumen Learning. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/6wmCQprxlnU\">https:\/\/youtu.be\/6wmCQprxlnU<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Unit 9: Real Numbers, from Developmental Math: An Open Program. <strong>Provided by<\/strong>: Monterey Institute of Technology and Education. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/nrocnetwork.org\/dm-opentext\">http:\/\/nrocnetwork.org\/dm-opentext<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":17533,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Simplify an Expression in Fraction Form\",\"author\":\"James Sousa (Mathispower4u.com) for Lumen 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