{"id":467,"date":"2022-07-11T18:48:10","date_gmt":"2022-07-11T18:48:10","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/alphamodule\/?post_type=chapter&#038;p=467"},"modified":"2022-08-09T15:58:26","modified_gmt":"2022-08-09T15:58:26","slug":"interpreting-the-mean-and-median-of-a-data-set-learn-it-4","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/alphamodule\/chapter\/interpreting-the-mean-and-median-of-a-data-set-learn-it-4\/","title":{"raw":"Interpreting the Mean and Median of a Data Set: Learn It 4","rendered":"Interpreting the Mean and Median of a Data Set: Learn It 4"},"content":{"raw":"<h3>Mean and Median Under Skew<\/h3>\r\n<div class=\"textbox tryit\">\r\n<h3>effects of skew on mean and median<\/h3>\r\n<span style=\"background-color: #99cc00;\">[Perspective video -- a 3-instructor video that shows how to think about the tail and the two outliers in the data above together with the fact that the mean is larger than the median to begin to understand that the mean tends to be pulled to the right of the median under a right skew.]\u00a0<\/span>\r\n\r\n<\/div>\r\nFor each of the plots of data below, choose the description that matches the shape of the data\u2019s distribution, and then select the choice that gives the relationship between the mean and median for those data. Base your answers on the understanding you established in Questions 1 - 9 about the direction the mean was pulled in under the skewness in the data set.\r\n<div class=\"textbox key-takeaways\">\r\n<h3>question 10<\/h3>\r\n[ohm_question hide_question_numbers=1]257533[\/ohm_question]\r\n\r\n[reveal-answer q=\"16821\"]Hint[\/reveal-answer]\r\n[hidden-answer a=\"16821\"]Refer to the definitions at the top of the page and your answer to Question 7 for guidance.[\/hidden-answer]\r\n\r\n<\/div>\r\n\r\n<h3>Resistance<\/h3>\r\n<div class=\"textbox tryit\">\r\n<h3>Resistant and Nonresistant Measures of Center<\/h3>\r\n<span style=\"background-color: #99cc00;\">[Worked example - a 3-instructor video showing a symmetric data set with the mean and median identical, then, skewing the distribution to show what happens to the mean while the median remains in place.]<\/span>\r\n\r\n<\/div>\r\n<div class=\"textbox key-takeaways\">\r\n<h3>question 11<\/h3>\r\n[ohm_question hide_question_numbers=1]241104[\/ohm_question]\r\n\r\n[reveal-answer q=\"56189\"]Hint[\/reveal-answer]\r\n[hidden-answer a=\"56189\"]\r\n\r\nConsider which measure (mean or median) seemed to be \"pulled\" in the direction of the tail in the skewed distributions and which did not.\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nWhen a distribution is symmetric, the mean and median occupy the same value. But under a skew, the mean is \"pulled\" in the direction of the outliers: greater than the median in the case of positive (right) skew, and less than the median in the case of negative (left) skew. The value of the mean is affected by the presence of outliers and skew while the median is not.","rendered":"<h3>Mean and Median Under Skew<\/h3>\n<div class=\"textbox tryit\">\n<h3>effects of skew on mean and median<\/h3>\n<p><span style=\"background-color: #99cc00;\">[Perspective video &#8212; a 3-instructor video that shows how to think about the tail and the two outliers in the data above together with the fact that the mean is larger than the median to begin to understand that the mean tends to be pulled to the right of the median under a right skew.]\u00a0<\/span><\/p>\n<\/div>\n<p>For each of the plots of data below, choose the description that matches the shape of the data\u2019s distribution, and then select the choice that gives the relationship between the mean and median for those data. Base your answers on the understanding you established in Questions 1 &#8211; 9 about the direction the mean was pulled in under the skewness in the data set.<\/p>\n<div class=\"textbox key-takeaways\">\n<h3>question 10<\/h3>\n<p><iframe loading=\"lazy\" id=\"ohm257533\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=257533&theme=oea&iframe_resize_id=ohm257533\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q16821\">Hint<\/span><\/p>\n<div id=\"q16821\" class=\"hidden-answer\" style=\"display: none\">Refer to the definitions at the top of the page and your answer to Question 7 for guidance.<\/div>\n<\/div>\n<\/div>\n<h3>Resistance<\/h3>\n<div class=\"textbox tryit\">\n<h3>Resistant and Nonresistant Measures of Center<\/h3>\n<p><span style=\"background-color: #99cc00;\">[Worked example &#8211; a 3-instructor video showing a symmetric data set with the mean and median identical, then, skewing the distribution to show what happens to the mean while the median remains in place.]<\/span><\/p>\n<\/div>\n<div class=\"textbox key-takeaways\">\n<h3>question 11<\/h3>\n<p><iframe loading=\"lazy\" id=\"ohm241104\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=241104&theme=oea&iframe_resize_id=ohm241104\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q56189\">Hint<\/span><\/p>\n<div id=\"q56189\" class=\"hidden-answer\" style=\"display: none\">\n<p>Consider which measure (mean or median) seemed to be &#8220;pulled&#8221; in the direction of the tail in the skewed distributions and which did not.\n<\/p><\/div>\n<\/div>\n<\/div>\n<p>When a distribution is symmetric, the mean and median occupy the same value. But under a skew, the mean is &#8220;pulled&#8221; in the direction of the outliers: greater than the median in the case of positive (right) skew, and less than the median in the case of negative (left) skew. The value of the mean is affected by the presence of outliers and skew while the median is not.<\/p>\n","protected":false},"author":17533,"menu_order":34,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-467","chapter","type-chapter","status-publish","hentry"],"part":20,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/pressbooks\/v2\/chapters\/467","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/wp\/v2\/users\/17533"}],"version-history":[{"count":4,"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/pressbooks\/v2\/chapters\/467\/revisions"}],"predecessor-version":[{"id":596,"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/pressbooks\/v2\/chapters\/467\/revisions\/596"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/pressbooks\/v2\/parts\/20"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/pressbooks\/v2\/chapters\/467\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/wp\/v2\/media?parent=467"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/pressbooks\/v2\/chapter-type?post=467"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/wp\/v2\/contributor?post=467"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/alphamodule\/wp-json\/wp\/v2\/license?post=467"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}