## Characteristics of exponential models

Doubling time and half-life: In an exponential model, equal steps in the input variable will always increase (or decrease) the value of the output variable by the same percentage. When the input variable is time, it is often useful to describe the process by how long it takes for the output to double (for growth) or decline to half (for decay) — these are called the “doubling time” or “half-life”. These values can be estimated from the graph of the model by taking the y value in the model that is furthest from zero, drawing a horizontal line at half that height, then noting the difference between the x values of the original point and the point where the half-height line crosses the graph of the model.

### Example 2: Estimate the doubling time of the model for the 1780-1870 U.S. census data.

Solution: The highest point on the graph of the model is (x=90, y=40.0), predicting a 1870 population (90 years after 1780) of 40.0 million people. Half that y value is 20.0, and we can see that the model graph crosses that value about x=65, halfway between the x=60 and x=70 data points. Subtracting 65 from 90 tells us that the y values in the model double in about 25 years.

Comments on this solution: Notice that the model predicts a population of 10 million at about x=40, then 20 million at about x=65, then 40 million at about x=90 — this shows that the doubling time of 25 years is the same for different parts of the graph (this is true only for exponential models). Using the highest point graphed on the model makes it easier to estimate the coordinates (estimating the x position for y=5 would be harder, for example). For a decaying-exponential model, we still use the highest point but it is the first point on the left, so the time to the half-height point is a half-life rather than a doubling time.

Convergence to zero: Exponential decay models have a negative “growth” rate, so that at each step the output becomes smaller by a fixed percentage. This leads to output values that come closer and closer to zero but never quite reach it. But the difference from zero can quickly become small enough to be negligible for practical purposes—a process whose output value decreases by half every hour will be less than a ten-millionth of its original size a day later. Notice that if the initial value is negative, this convergence to zero is from below the x-axis, with increasing values of y that come closer and closer.

Example 3: The intensity in Curies of a radioactive material that is used to make x-ray images of pipes is calibrated every 15 days, giving the dataset shown to the right. Fit an exponential model to the data to determine if this intensity exhibits exponential decay. If it does, find the decay rate of the material.

Solution process:

1. Copy the data into the ExponentialModel.xls spreadsheet on the course website.
2. Make a scatter plot of the data and model (columns A, B, and C).
3. Set the InitialAmount parameter (in G2) equal to the first data y value.
4. Set the GrowthRate parameter to a small negative number (start with –0.02, which is a decay rate of 2% per day), then adjust this parameter so that the model matches the data well. We find that a growth rate of –0.0094 gives the best fit.

Since the data fits the model well, the intensity exhibits exponential decay.

The growth rate of the model is –0.0094, a decay rate of 0.94% per day.

Example 4: Estimate the half-life of the exponential decay process above.

Solution process:

Examine the model graph (or the values in column C) to find when the output declines to half the initial amount of 160 Curies. This time is the half-life of the decay process.