## Logic

Logic is a systematic way of thinking that allows us to deduce new information from old information and to parse the meanings of sentences. You use logic informally in everyday life and certainly also in doing mathematics. For example, suppose you are working with a certain circle, call it “Circle X,” and you have available the following two pieces of information.

1. Circle X has radius equal to 3.
2. If any circle has radius r, then its area is πr2 square units.

You have no trouble putting these two facts together to get:

1. Circle X has area 9π square units.

In doing this you are using logic to combine existing information to produce new information. Since a major objective in mathematics is to deduce new information, logic must play a fundamental role. This chapter is intended to give you a sufficient mastery of logic.

It is important to realize that logic is a process of deducing information correctly, not just deducing correct information. For example, suppose we were mistaken and Circle X actually had a radius of 4, not 3. Let’s look at our exact same argument again.

1. Circle X has radius equal to 3.
2. If any circle has radius r, then its area is πr2 square units.
3. Circle X has area 9π square units.

The sentence “Circle X has radius equal to 3.” is now untrue, and so is our conclusion “Circle X has area 9π square units.” But the logic is perfectly correct; the information was combined correctly, even if some of it was false. This distinction between correct logic and correct information is significant because it is often important to follow the consequences of an incorrect assumption. Ideally, we want both our logic and our information to be correct, but the point is that they are different things.

In proving theorems, we apply logic to information that is considered obviously true (such as “Any two points determine exactly one line.”) or is already known to be true (e.g., the Pythagorean theorem). If our logic is correct, then anything we deduce from such information will also be true (or at least as true as the “obviously true” information we began with).

## Statements

The study of logic begins with statements. A statement is a sentence or a mathematical expression that is either definitely true or definitely false. You can think of statements as pieces of information that are either correct or incorrect. Thus statements are pieces of information that we might apply logic to in order to produce other pieces of information (which are also statements).

### Example 1

Here are some examples of statements. They are all true.

If a circle has radius r, then its area is πr2 square units.

Every even number is divisible by 2.

$2\text{ }{\in}\text{ }\mathbb{Z}$ (2 is an element of the set of integers (or more simply, 2 is an integer).)

$\sqrt{2}\text{ }{\notin}\text{ }\mathbb{Z}$ (The square root of 2 is not an integer.)

$\mathbb{N}\text{ }{\subseteq}\text{ }\mathbb{Z}$ (The set of natural numbers is a subset of the set of integers.)

The set {0,1,2} has three elements.

Some right triangles are isosceles.

### Example 2

Here are some additional statements. They are all false.

All right triangles are isosceles.

5 = 2

$\sqrt{2}\text{ }{\notin}\text{ }\mathbb{R}$ (The square root of 2 is not a real number.)

$\mathbb{Z}\subseteq\mathbb{N}$ (The set of integers is a subset of the set of natural numbers.)

${0,1,2}\cap\mathbb{N}=\varnothing$ (The intersection of the set {0,1,2} and the natural numbers is the empty set.)

### Example 3

Here we pair sentences or expressions that are not statements with similar expressions that are statements.

NOT Statements Statements
Add 5 to both sides. Adding 5 to both sides of − 5 = 37 gives x = 42.
$\mathbb{Z}$ (The set of integers) $42\text{ }{\in}\text{ }\mathbb{Z}$ (42 is an element of the set of integers.)
42 42 is not a number.
What is the solution of 2x = 84? The solution of 2x = 84 is 42.

### Example 4

We will often use the letters P, Q, R, and S to stand for specific statements. When more letters are needed we can use subscripts. Here are more statements, designated with letters. You decide which of them are true and which are false.

P : For every integer n > 1, the number 2n − 1 is prime.
Q : Every polynomial of degree n has at most n roots.
R : The function f(x) = xis continuous.
S1 : $\mathbb{N}\subseteq\varnothing$
S2 : ${0,-1,-2}\cap\mathbb{N}=\varnothing$

Designating statements with letters (as was done above) is a very useful shorthand. In discussing a particular statement, such as “The function f(x) = x2 is continuous,” it is convenient to just refer to it as R to avoid having to write or say it many times.

Statements can contain variables. Here is an example.

P : If an integer x is a multiple of 6, then x is even.

This is a sentence that is true. (All multiples of 6 are even, so no matter which multiple of 6 the integer x happens to be, it is even.) Since the sentence P is definitely true, it is a statement. When a sentence or statement P contains a variable such as x, we sometimes denote it as P(x) to indicate that it is saying something about x. Thus the above statement can be denoted as

P(x) : If an integer x is a multiple of 6, then x is even.

A statement or sentence involving two variables might be denoted P(x, y), and so on.

It is quite possible for a sentence containing variables to not be a statement. Consider the following example.

Q(x) : The integer x is even.

Is this a statement? Whether it is true or false depends on just which integer x is. It is true if x = 4 and false if x = 7, etc. But without any stipulations on the value of x it is impossible to say whether Q(x) is true or false. Since it is neither definitely true nor definitely false, Q(x) cannot be a statement. A sentence such as this, whose truth depends on the value of one or more variables, is called an open sentence. The variables in an open sentence (or statement) can represent any type of entity, not just numbers. Here is an open sentence where the variables are functions:

R(f, g) : The function f is the derivative of the function g.

This open sentence is true if f(x) = 2x and g(x) = x2. It is false if f(x) = x3 and g(x) = x2, etc. We point out that a sentence such as R(f, g) (that involves variables) can be denoted either as R(f, g) or just R. We use the expression R(f, g) when we want to emphasize that the sentence involves variables.

We will have more to say about open sentences later, but for now let’s return to statements.

Statements are everywhere in mathematics. Any result or theorem that has been proved true is a statement. The quadratic formula and the Pythagorean theorem are both statements:

P : The solutions of the equation $\displaystyle{a}x^2+bx+c=0\text{ are }x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$.
Q : If a right triangle has legs of lengths a and b and hypotenuse of length $a^2+b^2={c}^2$..

Here is a very famous statement, so famous, in fact, that it has a name. It is called Fermat’s last theorem after Pierre Fermat, a seventeenth-century French mathematician who scribbled it in the margin of a notebook.

R : For all numbers a, b, c, n ∈ $\mathbb{N}$ with n > 2, it is the case that $a^n+b^n\neq{c}^n$.

Fermat believed this statement was true. He noted that he could prove it was true, except his notebook’s margin was too narrow to contain his proof. It is doubtful that he really had a correct proof in mind, for after his death generations of brilliant mathematicians tried unsuccessfully to prove that his statement was true (or false). Finally, in 1993, Andrew Wiles of Princeton University announced that he had devised a proof. Wiles had worked on the problem for over seven years, and his proof runs through hundreds of pages. The moral of this story is that some true statements are not obviously true.

Here is another statement famous enough to be named. It was first posed in the eighteenth century by the German mathematician Christian Goldbach, and thus is called the Goldbach conjecture:

S : Every even integer greater than 2 is a sum of two prime numbers.

You must agree that S is either true or false. It appears to be true, because when you examine even numbers that are bigger than 2, they seem to be sums of two primes: 4 = 2+2, 6 = 3+3, 8 = 3+5, 10 = 5+5, 12 = 5+7, 100 = 17+83 and so on. But that’s not to say there isn’t some large even number that’s not the sum of two primes. If such a number exists, then S is false. The thing is, in the over 260 years since Goldbach first posed this problem, no one has been able to determine whether it’s true or false. But since it is clearly either true or false, S is a statement.

This book is about the methods that can be used to prove that S (or any other statement) is true or false. To prove that a statement is true, we start with obvious statements (or other statements that have been proven true) and use logic to deduce more and more complex statements until finally we obtain a statement such as S. Of course some statements are more difficult to prove than others, and S appears to be notoriously difficult; we will concentrate on statements that are easier to prove.

But the point is this: In proving that statements are true, we use logic to help us understand statements and to combine pieces of information to produce new pieces of information. In the next several sections we explore some standard ways that statements can be combined to form new statements, or broken down into simpler statements.

## And, Or, Not

The word “and” can be used to combine two statements to form a new statement. Consider for example the following sentence.

R1 : The number 2 is even and the number 3 is odd.

We recognize this as a true statement, based on our common-sense understanding of the meaning of the word “and.” Notice that R1 is made up of two simpler statements:

P : The number 2 is even.
Q : The number 3 is odd.

These are joined together by the word “and” to form the more complex statement R1. The statement R1 asserts that P and Q are both true. Since both P and Q are in fact true, the statement R1 is also true.

Had one or both of P and Q been false, then R1 would be false. For instance, each of the following statements is false.

R2 : The number 1 is even and the number 3 is odd.
R3 : The number 2 is even and the number 4 is odd.
R4 : The number 3 is even and the number 2 is odd.

From these examples we see that any two statements P and Q can be combined to form a new statement “P and Q.” In the spirit of using letters to denote statements, we now introduce the special symbol ∧ to stand for the word “and.” Thus if P and Q are statements, PQ stands for the statement “P and Q.” The statement PQ is true if both P and Q are true; otherwise it is false. This is summarized in the following table, called a truth table.

P Q PQ
T T T
T F F
F T F
F F F

In this table, T stands for “True,” and F stands for “False.” (T and F are called truth values.) Each line lists one of the four possible combinations or truth values for P and Q, and the column headed by PQ tells whether the statement PQ is true or false in each case.

Statements can also be combined using the word “or.” Consider the following four statements.

S1 : The number 2 is even or the number 3 is odd.
S2 : The number 1 is even or the number 3 is odd.
S3 : The number 2 is even or the number 4 is odd.
S4 : The number 3 is even or the number 2 is odd.

In mathematics, the assertion “P or Q” is always understood to mean that one or both of P and Q is true. Thus statements S1, S2, S3 are all true, while S4 is false. The symbol ∨ is used to stand for the word “or.” So if P and Q are statements, P ∨ Q represents the statement “P or Q.” Here is the truth table.

P Q PQ
T T T
T F T
F T T
F F F

It is important to be aware that the meaning of “or” expressed in the above table differs from the way it is sometimes used in everyday conversation. For example, suppose a university official makes the following threat:

You pay your tuition or you will be withdrawn from school.

You understand that this means that either you pay your tuition or you will be withdrawn from school, but not both. In mathematics we never use the word “or” in such a sense. For us “or” means exactly what is stated in the table for ∨. Thus PQ being true means one or both of P and Q is true. If we ever need to express the fact that exactly one of P and Q is true, we use one of the following constructions:

P or Q, but not both.

Either P or Q.

If the university official were a mathematician, he might have qualified his statement in one of the following ways.

Pay your tuition or you will be withdrawn from school, but not both.
Either you pay your tuition or you will be withdrawn from school.

To conclude this section, we mention another way of obtaining new statements from old ones. Given any statement P, we can form the new statement “It is not true that P.” For example, consider the following statement.

The number 2 is even.

This statement is true. Now change it by inserting the words “It is not true that” at the beginning:

It is not true that the number 2 is even.

This new statement is false.

For another example, starting with the false statement “$2\in\varnothing$” we get the true statement “It is not true that $2\in\varnothing$.”

We use the symbol ∼ to stand for the words “It’s not true that,” so ∼ P means “It’s not true that P.” We often read ∼ P simply as “not P.” Unlike ∧ and ∨, which combine two statements, the symbol ∼ just alters a single statement. Thus its truth table has just two lines, one for each possible truth value of P.

P P
T F
F T

The statement ∼ P is called the negation of P. The negation of a specific statement can be expressed in numerous ways. Consider

P : The number 2 is even.

Here are several ways of expressing its negation.

P : It’s not true that the number 2 is even.
P : It is false that the number 2 is even.
P : The number 2 is not even.

In this section we’ve learned how to combine or modify statements with the operations ∧, ∨ and ∼. Of course we can also apply these operations to open sentences or a mixture of open sentences and statements. For example, (x is an even integer)∧(3 is an odd integer) is an open sentence that is a combination of an open sentence and a statement.

## Conditional Statements

There is yet another way to combine two statements. Suppose we have in mind a specific integer a. Consider the following statement about a.

R : If the integer a is a multiple of 6, then a is divisible by 2.

We immediately spot this as a true statement based on our knowledge of integers and the meanings of the words “if” and “then.” If integer a is a multiple of 6, then a is even, so therefore a is divisible by 2. Notice that R is built up from two simpler statements:

P : The integer a is a multiple of 6.
Q : The integer a is divisible by 2.
R : If P, then Q.

In general, given any two statements P and Q whatsoever, we can form the new statement “If P, then Q.” This is written symbolically as PQ which we read as “If P, then Q,” or “P implies Q.” Like ∧ and ∨, the symbol ⇒ has a very specific meaning. When we assert that the statement PQ is true, we mean that if P is true then Q must also be true. (In other words we mean that the condition P being true forces Q to be true.) A statement of form PQ is called a conditional statement because it means Q will be true under the condition that P is true.

You can think of PQ as being a promise that whenever P is true, Q will be true also. There is only one way this promise can be broken (i.e. be false) and that is if P is true but Q is false. Thus the truth table for the promise PQ is as follows:

P Q PQ
T T T
T F F
F T T
F F T

Perhaps you are bothered by the fact that PQ is true in the last two lines of this table. Here’s an example to convince you that the table is correct. Suppose your professor makes the following promise:

If you pass the final exam, then you will pass the course.

Your professor is making the promise

(You pass the exam) ⇒ (You pass the course).

Under what circumstances did she lie? There are four possible scenarios, depending on whether or not you passed the exam and whether or not you passed the course. These scenarios are tallied in the following table.

You pass exam You pass course (You pass exam) ⇒ (You pass course)
T T T
T F F
F T T
F F T

The first line describes the scenario where you pass the exam and you pass the course. Clearly the professor kept her promise, so we put a T in the third column to indicate that she told the truth. In the second line, you passed the exam, but your professor gave you a failing grade in the course. In this case she broke her promise, and the F in the third column indicates that what she said was untrue.

Now consider the third row. In this scenario you failed the exam but still passed the course. How could that happen? Maybe your professor felt sorry for you. But that doesn’t make her a liar. Her only promise was that if you passed the exam then you would pass the course. She did not say passing the exam was the only way to pass the course. Since she didn’t lie, then she told the truth, so there is a T in the third column.

Finally look at the fourth row. In that scenario you failed the exam and you failed the course. Your professor did not lie; she did exactly what she said she would do. Hence the T in the third column.

In mathematics, whenever we encounter the construction “If P, then Q” it means exactly what the truth table for ⇒ expresses. But of course there are other grammatical constructions that also mean PQ. Here is a summary of the main ones.

${P}\Rightarrow{Q}\begin{cases}{\text{If }P\text{, then }Q.}\\{Q\text{ if }P.}\\{Q\text{ whenever }P.}\\{Q\text{, provided that }P.}\\{\text{Whenever }P\text{, then also }Q.}\\{P\text{ is a sufficient condition for }Q.}\\{\text{For }Q\text{, it is sufficient that }P.}\\{Q\text{ is a necessary condition for }P.}\\{\text{For }P\text{, it is necessary that }Q.}\\{P\text{ only if }Q.}\end{cases}$

These can all be used in the place of (and mean exactly the same thing as) “If P, then Q.” You should analyze the meaning of each one and convince yourself that it captures the meaning of PQ. For example, PQ means the condition of P being true is enough (i.e., sufficient) to make Q true; hence “P is a sufficient condition for Q.”

The wording can be tricky. Often an everyday situation involving a conditional statement can help clarify it. For example, consider your professor’s promise:

(You pass the exam) ⇒ (You pass the course)

This means that your passing the exam is a sufficient (though perhaps not necessary) condition for your passing the course. Thus your professor might just as well have phrased her promise in one of the following ways.

Passing the exam is a sufficient condition for passing the course.
For you to pass the course, it is sufficient that you pass the exam.

However, when we want to say “If P, then Q” in everyday conversation, we do not normally express this as “Q is a necessary condition for P” or “P only if Q.” But such constructions are not uncommon in mathematics. To understand why they make sense, notice that PQ being true means that it’s impossible that P is true but Q is false, so in order for P to be true it is necessary that Q is true; hence “Q is a necessary condition for P.” And this means that P can only be true if Q is true, i.e., “P only if Q.”

## Biconditional Statements

It is important to understand that PQ is not the same as QP. To see why, suppose that a is some integer and consider the statements

(a is a multiple of 6) ⇒ (a is divisible by 2),
(a is divisible by 2) ⇒ (a is a multiple of 6).

The first statement asserts that if a is a multiple of 6 then a is divisible by 2. This is clearly true, for any multiple of 6 is even and therefore divisible by 2. The second statement asserts that if a is divisible by 2 then it is a multiple of 6. This is not necessarily true, for a = 4 (for instance) is divisible by 2, yet not a multiple of 6. Therefore the meanings of PQ and QP are in general quite different. The conditional statement QP is called the converse of PQ, so a conditional statement and its converse express entirely different things.

However, the contrapositive of P ⇒ Q, ~Q ⇒ ~P, is equivalent to P ⇒ Q. Similarly, the inverse of PQ, which is ~P ⇒ ~Q, is equivalent to the converse QP. In “Truth Tables for Statements,” we will learn how to show these equivalences using a truth table.

But sometimes, if P and Q are just the right statements, it can happen that PQ and QP are both necessarily true. For example, consider the statements

(a is even) ⇒ (a is divisible by 2),
(a is divisible by 2) ⇒ (a is even).

No matter what value a has, both of these statements are true. Since both PQ and QP are true, it follows that (PQ)∧(QP) is true.

We now introduce a new symbol ⇔ to express the meaning of the statement (PQ)∧(QP). The expression PQ is understood to have exactly the same meaning as (PQ)∧(QP). According to the previous section, QP is read as “P if Q,” and PQ can be read as “P only if Q.” Therefore we pronounce PQ as “P if and only if Q.” For example, given an integer a, we have the true statement

(a is even) ⇔ (a is divisible by 2),

which we can read as “Integer a is even if and only if a is divisible by 2.

The truth table for ⇔ is shown below. Notice that in the first and last rows, both P ⇒ Q and Q ⇒ P are true (according to the truth table for ⇒), so (P ⇒ Q) ∧ (Q ⇒ P) is true, and hence P ⇔ Q is true. However, in the middle two rows one of P ⇒ Q or Q ⇒ P is false, so (P ⇒ Q)∧(Q ⇒ P) is false, making P ⇔ Q false.

P Q P ⇔ Q
T T T
T F F
F T F
F F T

Compare the statement R : (a is even) ⇔ (a is divisible by 2) with this truth table. If a is even then the two statements on either side of ⇔ are true, so according to the table R is true. If a is odd then the two statements on either side of ⇔ are false, and again according to the table R is true. Thus R is true no matter what value a has. In general, PQ being true means P and Q are both true or both false.

Not surprisingly, there are many ways of saying PQ in English. The following constructions all mean PQ:

${P}\iff{Q}\begin{cases}{P\text{ if and only if }Q.}\\{P\text{ is a necessary and sufficient condition for }Q.}\\{\text{For }P\text{ it is necessary and sufficient that }Q.}\\{\text{If }P\text{, then }Q\text{, and conversely.}}\end{cases}$

The first three of these just combine constructions from the previous section to express that PQ and QP. In the last one, the words “and conversely” mean that in addition to “If P, then Q” being true, the converse statement “If Q, then P” is also true.

## Truth Tables for Statements

You should now know the truth tables for ∧, ∨, ∼, ⇒ and ⇔. They should be internalized as well as memorized. You must understand the symbols thoroughly, for we now combine them to form more complex statements.

For example, suppose we want to convey that one or the other of P and Q is true but they are not both true. No single symbol expresses this, but we could combine them as

(PQ)∧ ∼ (PQ),

which literally means:

P or Q is true, and it is not the case that both P and Q are true.

This statement will be true or false depending on the truth values of P and Q. In fact we can make a truth table for the entire statement. Begin as usual by listing the possible true/false combinations of P and Q on four lines. The statement (PQ)∧ ∼ (PQ) contains the individual statements (PQ) and (PQ), so we next tally their truth values in the third and fourth columns. The fifth column lists values for ∼ (PQ), and these are just the opposites of the corresponding entries in the fourth column. Finally, combining the third and fifth columns with ∧, we get the values for (PQ)∧ ∼(PQ) in the sixth column.

P Q (PQ) (PQ) ∼(PQ) (PQ)∧ ∼(PQ)
T T T T F F
T F T F T T
F T T F T T
F F F F T F

This truth table tells us that (PQ)∧ ∼(P ∧ Q) is true precisely when one but not both of P and Q are true, so it has the meaning we intended. (Notice that the middle three columns of our truth table are just “helper columns” and are not necessary parts of the table. In writing truth tables, you may choose to omit such columns if you are confident about your work.)

For another example, consider the following familiar statement concerning two real numbers x and y:

The product xy equals zero if and only if x = 0 or y = 0.

This can be modeled as (xy = 0) ⇔ (x = 0 ∨ y = 0). If we introduce letters P, Q, and R for the statements xy = 0, x = 0 and y = 0, it becomes P ⇔ (R). Notice that the parentheses are necessary here, for without them we wouldn’t know whether to read the statement as P ⇔ (R) or (PQ) ∨ R.

Making a truth table for P ⇔ (R) entails a line for each T/F combination for the three statements P, Q, and R. The eight possible combinations are tallied in the first three columns of the following table.

P Q R QR P ⇔ (QR)
T T T T T
T T F T T
T F T T T
T F F F F
F T T T F
F T F T F
F F T T F
F F F F T

We fill in the fourth column using our knowledge of the truth table for ∨. Finally the fifth column is filled in by combining the first and fourth columns with our understanding of the truth table for ⇔. The resulting table gives the true/false values of P ⇔ (QR) for all values of P, Q, and R.

Notice that when we plug in various values for x and y, the statements P : xy = 0, Q : x = 0 and R : y = 0 have various truth values, but the statement P ⇔ (QR) is always true. For example, if x = 2 and y = 3, then P, Q, and R are all false. This scenario is described in the last row of the table, and there we see that P ⇔ (QR) is true. Likewise if x = 0 and y = 7, then P and Q are true and R is false, a scenario described in the second line of the table, where again P ⇔ (QR) is true. There is a simple reason why P ⇔ (R) is true for any values of x and y: It is that P ⇔ (R) represents (xy = 0) ⇔ (x = 0 ∨ y = 0), which is a true mathematical statement. It is absolutely impossible for it to be false.

This may make you wonder about the lines in the table where P ⇔ (R) is false. Why are they there? The reason is that P ⇔ (QR) can also represent a false statement. To see how, imagine that at the end of the semester your professor makes the following promise.

You pass the class if and only if you get an “A” on the final or you get a “B” on the final.

This promise has the form P ⇔ (QR), so its truth values are tabulated in the above table. Imagine it turned out that you got an “A” on the exam but failed the course. Then surely your professor lied to you. In fact, P is false, Q is true and R is false. This scenario is reflected in the sixth line of the table, and indeed P ⇔ (QR) is false (i.e., it is a lie).

The moral of this example is that people can lie, but true mathematical statements never lie.

We close this section with a word about the use of parentheses. The symbol ∼ is analogous to the minus sign in algebra. It negates the expression it precedes. Thus ∼PQ means (∼P) ∨ Q, not ∼(PQ). In ∼(PQ), the value of the entire expression PQ is negated.

## Logical Equivalence

In contemplating the truth table for PQ, you probably noticed that PQ is true exactly when P and Q are both true or both false. In other words, PQ is true precisely when at least one of the statements PQ or ∼∧ ∼Q is true. This may tempt us to say that PQ means the same thing as (PQ)∨(∼∧ ∼Q).

To see if this is really so, we can write truth tables for PQ and (PQ) ∨ (∼∧ ∼Q). In doing this, it is more efficient to put these two statements into the same table, as follows. (This table has helper columns for the intermediate expressions ∼P, ∼Q, (PQ), and (~∧ ∼Q).)

P Q P Q (PQ) (∼∧ ∼Q) (PQ)∨(∼∧ ∼Q) PQ
T T F F T F T T
T F F T F F F F
F T T F F F F F
F F T T F T T T

The table shows that PQ and (PQ)∨(∼∧ ∼Q) have the same truth value, no matter the values P and Q. It is as if PQ and (PQ)∨(∼∧ ∼Q) are algebraic expressions that are equal no matter what is “plugged into” variables P and Q. We express this state of affairs by writing

PQ = (PQ)∨(∼∧ ∼Q)

and saying that PQ and (PQ)∨(∼∧ ∼Q) are logically equivalent.

In general, two statements are logically equivalent if their truth values match up line-for-line in a truth table.

Logical equivalence is important because it can give us different (and potentially useful) ways of looking at the same thing. As an example, the following table shows that PQ is logically equivalent to (∼Q) ⇒ (∼P).

P Q P Q (∼Q) ⇒ (∼P) PQ
T T F F T T
T F F T F F
F T T F T T
F F T T T T

The fact that PQ = (∼Q) ⇒ (∼P) is useful because so many theorems have the form PQ. As we will see in Chapter 5, proving such a theorem may be easier if we express it in the logically equivalent form (∼Q) ⇒ (∼P).

There are two pairs of logically equivalent statements that come up again and again throughout this book and beyond. They are prevalent enough to be dignified by a special name: DeMorgan’s laws.

### Fact: DeMorgan’s Laws

1. ∼(PQ) = (∼P)∨(∼Q)
2. ∼(PQ) = (∼P)∧(∼Q)

The first of DeMorgan’s laws is verified by the following table. You are asked to verify the second in one of the exercises.

P Q ~P ~Q PQ  ∼(PQ) (∼P)∨(∼Q)
T T F F T F F
T F F T F T T
F T T F F T T
F F T T F T T

DeMorgan’s laws are actually very natural and intuitive. Consider the statement ∼(PQ), which we can interpret as meaning that it is not the case that both P and Q are true. If it is not the case that both P and Q are true, then at least one of P or Q is false, in which case (∼P)∨(∼Q) is true. Thus ∼(PQ) means the same thing as (∼P)∨(∼Q).

DeMorgan’s laws can be very useful. Suppose we happen to know that some statement having form ∼(PQ) is true. The second of DeMorgan’s laws tells us that (∼Q)∧(∼P) is also true, hence ∼P and ∼Q are both true as well. Being able to quickly obtain such additional pieces of information can be extremely useful.

Here is a summary of some significant logical equivalences. Those that are not immediately obvious can be verified with a truth table.

$\text{Contrapositive law}\begin{cases}P\Rightarrow{Q}=(\sim{Q})\Rightarrow(\sim{P})\end{cases}$

$\text{DeMorgan's laws}\begin{cases}{\sim(P\land{Q})=\sim{P}\lor\sim{Q}}\\{\sim(P\lor{Q})=\sim{P}\land\sim{Q}}\end{cases}$

$\text{Commutative laws}\begin{cases}{(P\land{Q})={P}\land{Q}}\\{(P\lor{Q})={P}\lor{Q}}\end{cases}$

$\text{Distributive laws}\begin{cases}{{P}\land(Q\lor{R})=({P}\land{Q})\lor(P\land{R})}\\{P\lor(Q\land{R})=({P}\lor{Q})\land(P\lor{R})}\end{cases}$

$\text{Associative laws}\begin{cases}{P\land(Q\land{R})=(P\land{Q})\land{R}}\\{P\lor(Q\lor{R})=(P\lor{Q})\lor{R}}\end{cases}$

Notice how the distributive law P ∧ (QR) = (PQ) ∨ (PR) has the same structure as the distributive law p(q + r) = p · q + p · r from algebra. Concerning the associative laws, the fact that P ∧ (R) = (PQ) ∧ R means that the position of the parentheses is irrelevant, and we can write this as PQR without ambiguity. Similarly, we may drop the parentheses in an expression such as P ∨ (QR).

But parentheses are essential when there is a mix of ∧ and ∨, as in P ∨(QR). Indeed, P ∨(QR) and (PQ) ∧ R are not logically equivalent.

## Negating Statements

Given a statement R, the statement ∼R is called the negation of R. If R is a complex statement, then it is often the case that its negation ∼R can be written in a simpler or more useful form. The process of finding this form is called negating R. In proving theorems it is often necessary to negate certain statements. We now investigate how to do this.

We have already examined part of this topic. DeMorgan’s laws

∼ (P ∧Q) = (∼ P)∨(∼ Q)
∼ (P ∨Q) = (∼ P)∧(∼ Q)

(from “Logical Equivalence”) can be viewed as rules that tell us how to negate the statements P ∧Q and P ∨Q. Here are some examples that illustrate how DeMorgan’s laws are used to negate statements involving “and” or “or.”

### Example 5

Consider negating the following statement.

R : You can solve it by factoring or with the quadratic formula.

Now, R means (You can solve it by factoring) ∨ (You can solve it with Q.F.), which we will denote as PQ. The negation of this is

∼(PQ) = (∼P)∧(∼Q).

Therefore, in words, the negation of R is

R : You can’t solve it by factoring and you can’t solve it with the quadratic formula.

Maybe you can find ∼R without invoking DeMorgan’s laws. That is good; you have internalized DeMorgan’s laws and are using them unconsciously.

### Example 6

We will negate the following sentence.

R : The numbers x and y are both odd.

This statement means (x is odd) ∧ (y is odd), so its negation is

~[(x is odd) ∧ (y is odd)] = ∼(x is odd) ∨ ∼(y is odd)
(x is odd) ∧ (y is odd) = (x is even) ∨ (y is even).

Therefore the negation of R can be expressed in the following ways:

∼ R : The number x is even or the number y is even.
∼ R : At least one of x and y is even.

Now let’s move on to a slightly different kind of problem. It’s often necessary to find the negations of quantified statements. For example, consider ∼(∀x ∈ $\mathbb{N}$, P(x)). Reading this in words, we have the following:

It is not the case that P(x) is true for all natural numbers x.

This means P(x) is false for at least one x. In symbols, this is ∃ x ∈ $\mathbb{N}$, ∼P(x). Thus ∼ (∀x ∈ $\mathbb{N}$, P(x)) = ∃ x ∈ $\mathbb{N}$, ∼P(x). Similarly, you can reason out that ∼ (∃ x ∈ $\mathbb{N}$, P(x)) = ∀x ∈ $\mathbb{N}$, ∼P(x). In general:

∼ (∀xS, P(x)) = ∃ xS, ∼P(x)
∼ (∃ xS, P(x)) = ∀xS, ∼P(x)

## Logical Inference

Suppose we know that a statement of form PQ is true. This tells us that whenever P is true, Q will also be true. By itself, PQ being true does not tell us that either P or Q is true (they could both be false, or P could be false and Q true). However if in addition we happen to know that P is true then it must be that Q is true. This is called a logical inference: Given two true statements we can infer that a third statement is true. In this instance true statements PQ and P are “added together” to get Q. This is described below with PQ and P stacked one atop the other with a line separating them from Q. The intended meaning is that PQ combined with P produces Q. Two other logical inferences are listed above. In each case you should convince yourself (based on your knowledge of the relevant truth tables) that the truth of the statements above the line forces the statement below the line to be true.

Following are some additional useful logical inferences. The first expresses the obvious fact that if P and Q are both true then the statement PQ will be true. On the other hand, PQ being true forces P (also Q) to be true. Finally, if P is true, then PQ must be true, no matter what statement Q is. These inferences are so intuitively obvious that they scarcely need to be mentioned. However, they represent certain patterns of reasoning that we will frequently apply to sentences in proofs, so we should be cognizant of the fact that we are using them.

The first two statements in each case are called “premises” and the final statement is the “conclusion.” We combine premises with ∧ (“and”). The premises together imply the conclusion. Thus, the first argument would have (( PQ) ∧ P) ⇒ Q as its symbolic statement.

## An Important Note

It is important to be aware of the reasons that we study logic. There are three very significant reasons. First, the truth tables we studied tell us the exact meanings of the words such as “and,” “or,” “not,” and so on. For instance, whenever we use or read the “If…, then” construction in a mathematical context, logic tells us exactly what is meant. Second, the rules of inference provide a system in which we can produce new information (statements) from known information. Finally, logical rules such as DeMorgan’s laws help us correctly change certain statements into (potentially more useful) statements with the same meaning. Thus logic helps us understand the meanings of statements and it also produces new meaningful statements.

Logic is the glue that holds strings of statements together and pins down the exact meaning of certain key phrases such as the “If…, then” or “For all” constructions. Logic is the common language that all mathematicians use, so we must have a firm grip on it in order to write and understand mathematics.

But despite its fundamental role, logic’s place is in the background of what we do, not the forefront. From here on, the beautiful symbols ∧, ∨, ⇒, ⇔, ∼, ∀ and ∃ are rarely written. But we are aware of their meanings constantly. When reading or writing a sentence involving mathematics we parse it with these symbols, either mentally or on scratch paper, so as to understand the true and unambiguous meaning.