{"id":1082,"date":"2015-11-12T18:35:32","date_gmt":"2015-11-12T18:35:32","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&p=1082"},"modified":"2015-11-12T18:35:32","modified_gmt":"2015-11-12T18:35:32","slug":"solutions-49","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/chapter\/solutions-49\/","title":{"raw":"Solutions","rendered":"Solutions"},"content":{"raw":"

Solutions to Try Its<\/h2>\n1.\u00a0[latex]m=\\frac{4 - 3}{0 - 2}=\\frac{1}{-2}=-\\frac{1}{2}\\\\[\/latex] ; decreasing because [latex]m<0\\\\[\/latex].\n\n2.\u00a0[latex]m=\\frac{1,868 - 1,442}{2,012 - 2,009}=\\frac{426}{3}=142\\text{ people per year}\\\\[\/latex]\n\n3.\u00a0[latex]y - 2=-2\\left(x+2\\right)\\\\[\/latex]; [latex]y=-2x - 2\\\\[\/latex]\n\n4.\u00a0[latex]y - 0=-3\\left(x - 0\\right)\\\\[\/latex] ; [latex]y=-3x\\\\[\/latex]\n\n5.\u00a0[latex]y=-7x+3\\\\[\/latex]\n\n6.\u00a0[latex]H\\left(x\\right)=0.5x+12.5\\\\[\/latex]\n

Solutions to Odd-Numbered Exercises<\/h2>\n1.\u00a0Terry starts at an elevation of 3000 feet and descends 70 feet per second.\n\n3.\u00a03 miles per hour\n\n5.\u00a0[latex]d\\left(t\\right)=100 - 10t\\\\[\/latex]\n\n7.\u00a0Yes.\n\n9.\u00a0No.\n\n11.\u00a0No.\n\n13.\u00a0No.\n\n15.\u00a0Increasing.\n\n17.\u00a0Decreasing.\n\n19.\u00a0Decreasing.\n\n21.\u00a0Increasing.\n\n23.\u00a0Decreasing.\n\n25. 3\n\n27.\u00a0[latex]-\\frac{1}{3}\\\\[\/latex]\n\n29.\u00a0[latex]\\frac{4}{5}\\\\[\/latex]\n\n31.\u00a0[latex]f\\left(x\\right)=-\\frac{1}{2}x+\\frac{7}{2}\\\\[\/latex]\n\n33.\u00a0[latex]y=2x+3\\\\[\/latex]\n\n35.\u00a0[latex]y=-\\frac{1}{3}x+\\frac{22}{3}\\\\[\/latex]\n\n37.\u00a0[latex]y=\\frac{4}{5}x+4\\\\[\/latex]\n\n39.\u00a0[latex]-\\frac{5}{4}\\\\[\/latex]\n\n41.\u00a0[latex]y=\\frac{2}{3}x+1\\\\[\/latex]\n\n43.\u00a0[latex]y=-2x+3\\\\[\/latex]\n\n45.\u00a0[latex]y=3\\\\[\/latex]\n\n47.\u00a0Linear, [latex]g\\left(x\\right)=-3x+5\\\\[\/latex]\n\n49.\u00a0Linear, [latex]f\\left(x\\right)=5x - 5\\\\[\/latex]\n\n51.\u00a0Linear, [latex]g\\left(x\\right)=-\\frac{25}{2}x+6\\\\[\/latex]\n\n53.\u00a0Linear, [latex]f\\left(x\\right)=10x - 24\\\\[\/latex]\n\n55.\u00a0[latex]f\\left(x\\right)=-58x+17.3\\\\[\/latex]\n\n57.\n\"\"\n\n59.\u00a0a. [latex]a=11,900\\\\[\/latex] ; [latex]b=1001.1\\\\[\/latex] b. [latex]q\\left(p\\right)=1000p - 100\\\\[\/latex]\n\n61.\n\"..\"\n\n63.\u00a0[latex]x=-\\frac{16}{3}\\\\[\/latex]\n\n65.\u00a0[latex]x=a\\\\[\/latex]\n\n67.\u00a0[latex]y=\\frac{d}{c-a}x-\\frac{ad}{c-a}\\\\[\/latex]\n\n69.\u00a0$45 per training session.\n\n71.\u00a0The rate of change is 0.1. For every additional minute talked, the monthly charge increases by $0.1 or 10 cents. The initial value is 24. When there are no minutes talked, initially the charge is $24.\n\n73.\u00a0The slope is \u2013400. This means for every year between 1960 and 1989, the population dropped by 400 per year in the city.\n\n75. c","rendered":"

Solutions to Try Its<\/h2>\n

1.\u00a0[latex]m=\\frac{4 - 3}{0 - 2}=\\frac{1}{-2}=-\\frac{1}{2}\\\\[\/latex] ; decreasing because [latex]m<0\\\\[\/latex].\n\n2.\u00a0[latex]m=\\frac{1,868 - 1,442}{2,012 - 2,009}=\\frac{426}{3}=142\\text{ people per year}\\\\[\/latex]\n\n3.\u00a0[latex]y - 2=-2\\left(x+2\\right)\\\\[\/latex]; [latex]y=-2x - 2\\\\[\/latex]\n\n4.\u00a0[latex]y - 0=-3\\left(x - 0\\right)\\\\[\/latex] ; [latex]y=-3x\\\\[\/latex]\n\n5.\u00a0[latex]y=-7x+3\\\\[\/latex]\n\n6.\u00a0[latex]H\\left(x\\right)=0.5x+12.5\\\\[\/latex]\n\n\n

Solutions to Odd-Numbered Exercises<\/h2>\n

1.\u00a0Terry starts at an elevation of 3000 feet and descends 70 feet per second.<\/p>\n

3.\u00a03 miles per hour<\/p>\n

5.\u00a0[latex]d\\left(t\\right)=100 - 10t\\\\[\/latex]<\/p>\n

7.\u00a0Yes.<\/p>\n

9.\u00a0No.<\/p>\n

11.\u00a0No.<\/p>\n

13.\u00a0No.<\/p>\n

15.\u00a0Increasing.<\/p>\n

17.\u00a0Decreasing.<\/p>\n

19.\u00a0Decreasing.<\/p>\n

21.\u00a0Increasing.<\/p>\n

23.\u00a0Decreasing.<\/p>\n

25. 3<\/p>\n

27.\u00a0[latex]-\\frac{1}{3}\\\\[\/latex]<\/p>\n

29.\u00a0[latex]\\frac{4}{5}\\\\[\/latex]<\/p>\n

31.\u00a0[latex]f\\left(x\\right)=-\\frac{1}{2}x+\\frac{7}{2}\\\\[\/latex]<\/p>\n

33.\u00a0[latex]y=2x+3\\\\[\/latex]<\/p>\n

35.\u00a0[latex]y=-\\frac{1}{3}x+\\frac{22}{3}\\\\[\/latex]<\/p>\n

37.\u00a0[latex]y=\\frac{4}{5}x+4\\\\[\/latex]<\/p>\n

39.\u00a0[latex]-\\frac{5}{4}\\\\[\/latex]<\/p>\n

41.\u00a0[latex]y=\\frac{2}{3}x+1\\\\[\/latex]<\/p>\n

43.\u00a0[latex]y=-2x+3\\\\[\/latex]<\/p>\n

45.\u00a0[latex]y=3\\\\[\/latex]<\/p>\n

47.\u00a0Linear, [latex]g\\left(x\\right)=-3x+5\\\\[\/latex]<\/p>\n

49.\u00a0Linear, [latex]f\\left(x\\right)=5x - 5\\\\[\/latex]<\/p>\n

51.\u00a0Linear, [latex]g\\left(x\\right)=-\\frac{25}{2}x+6\\\\[\/latex]<\/p>\n

53.\u00a0Linear, [latex]f\\left(x\\right)=10x - 24\\\\[\/latex]<\/p>\n

55.\u00a0[latex]f\\left(x\\right)=-58x+17.3\\\\[\/latex]<\/p>\n

57.
\n\"\"<\/p>\n

59.\u00a0a. [latex]a=11,900\\\\[\/latex] ; [latex]b=1001.1\\\\[\/latex] b. [latex]q\\left(p\\right)=1000p - 100\\\\[\/latex]<\/p>\n

61.
\n\"..\"<\/p>\n

63.\u00a0[latex]x=-\\frac{16}{3}\\\\[\/latex]<\/p>\n

65.\u00a0[latex]x=a\\\\[\/latex]<\/p>\n

67.\u00a0[latex]y=\\frac{d}{c-a}x-\\frac{ad}{c-a}\\\\[\/latex]<\/p>\n

69.\u00a0$45 per training session.<\/p>\n

71.\u00a0The rate of change is 0.1. For every additional minute talked, the monthly charge increases by $0.1 or 10 cents. The initial value is 24. When there are no minutes talked, initially the charge is $24.<\/p>\n

73.\u00a0The slope is \u2013400. This means for every year between 1960 and 1989, the population dropped by 400 per year in the city.<\/p>\n

75. c<\/p>\n\n\t\t\t

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