{"id":1374,"date":"2015-11-12T18:35:30","date_gmt":"2015-11-12T18:35:30","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=1374"},"modified":"2015-11-12T18:35:30","modified_gmt":"2015-11-12T18:35:30","slug":"section-exercises-46","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/chapter\/section-exercises-46\/","title":{"raw":"Section Exercises","rendered":"Section Exercises"},"content":{"raw":"<p>1. If division of a polynomial by a binomial results in a remainder of zero, what can be conclude?\n\n2.\u00a0If a polynomial of degree <em>n<\/em>\u00a0is divided by a binomial of degree 1, what is the degree of the quotient?\n\nFor the following exercises, use long division to divide. Specify the quotient and the remainder.\n\n3. [latex]\\left({x}^{2}+5x - 1\\right)\\div \\left(x - 1\\right)\\\\[\/latex]\n\n4.\u00a0[latex]\\left(2{x}^{2}-9x - 5\\right)\\div \\left(x - 5\\right)\\\\[\/latex]\n\n5. [latex]\\left(3{x}^{2}+23x+14\\right)\\div \\left(x+7\\right)\\\\[\/latex]\n\n6.\u00a0[latex]\\left(4{x}^{2}-10x+6\\right)\\div \\left(4x+2\\right)\\\\[\/latex]\n\n7. [latex]\\left(6{x}^{2}-25x - 25\\right)\\div \\left(6x+5\\right)\\\\[\/latex]\n\n8.\u00a0[latex]\\left(-{x}^{2}-1\\right)\\div \\left(x+1\\right)\\\\[\/latex]\n\n9. [latex]\\left(2{x}^{2}-3x+2\\right)\\div \\left(x+2\\right)\\\\[\/latex]\n\n10.\u00a0[latex]\\left({x}^{3}-126\\right)\\div \\left(x - 5\\right)\\\\[\/latex]\n\n11. [latex]\\left(3{x}^{2}-5x+4\\right)\\div \\left(3x+1\\right)\\\\[\/latex]\n\n12.\u00a0[latex]\\left({x}^{3}-3{x}^{2}+5x - 6\\right)\\div \\left(x - 2\\right)\\\\[\/latex]\n\n13. [latex]\\left(2{x}^{3}+3{x}^{2}-4x+15\\right)\\div \\left(x+3\\right)\\\\[\/latex]\n\nFor the following exercises, use synthetic division to find the quotient.\n\n14. [latex]\\left(3{x}^{3}-2{x}^{2}+x - 4\\right)\\div \\left(x+3\\right)\\\\[\/latex]\n\n15. [latex]\\left(2{x}^{3}-6{x}^{2}-7x+6\\right)\\div \\left(x - 4\\right)\\\\[\/latex]\n\n16.\u00a0[latex]\\left(6{x}^{3}-10{x}^{2}-7x - 15\\right)\\div \\left(x+1\\right)\\\\[\/latex]\n\n17. [latex]\\left(4{x}^{3}-12{x}^{2}-5x - 1\\right)\\div \\left(2x+1\\right)\\\\[\/latex]\n\n18.\u00a0[latex]\\left(9{x}^{3}-9{x}^{2}+18x+5\\right)\\div \\left(3x - 1\\right)\\\\[\/latex]\n\n19. [latex]\\left(3{x}^{3}-2{x}^{2}+x - 4\\right)\\div \\left(x+3\\right)\\\\[\/latex]\n\n20.\u00a0[latex]\\left(-6{x}^{3}+{x}^{2}-4\\right)\\div \\left(2x - 3\\right)\\\\[\/latex]\n\n21. [latex]\\left(2{x}^{3}+7{x}^{2}-13x - 3\\right)\\div \\left(2x - 3\\right)\\\\[\/latex]\n\n22.\u00a0[latex]\\left(3{x}^{3}-5{x}^{2}+2x+3\\right)\\div \\left(x+2\\right)\\\\[\/latex]\n\n23. [latex]\\left(4{x}^{3}-5{x}^{2}+13\\right)\\div \\left(x+4\\right)\\\\[\/latex]\n\n24.\u00a0[latex]\\left({x}^{3}-3x+2\\right)\\div \\left(x+2\\right)\\\\[\/latex]\n\n25. [latex]\\left({x}^{3}-21{x}^{2}+147x - 343\\right)\\div \\left(x - 7\\right)\\\\[\/latex]\n\n26.\u00a0[latex]\\left({x}^{3}-15{x}^{2}+75x - 125\\right)\\div \\left(x - 5\\right)\\\\[\/latex]\n\n27. [latex]\\left(9{x}^{3}-x+2\\right)\\div \\left(3x - 1\\right)\\\\[\/latex]\n\n28.\u00a0[latex]\\left(6{x}^{3}-{x}^{2}+5x+2\\right)\\div \\left(3x+1\\right)\\\\[\/latex]\n\n29. [latex]\\left({x}^{4}+{x}^{3}-3{x}^{2}-2x+1\\right)\\div \\left(x+1\\right)\\\\[\/latex]\n\n30.\u00a0[latex]\\left({x}^{4}-3{x}^{2}+1\\right)\\div \\left(x - 1\\right)\\\\[\/latex]\n\n31. [latex]\\left({x}^{4}+2{x}^{3}-3{x}^{2}+2x+6\\right)\\div \\left(x+3\\right)\\\\[\/latex]\n\n32.\u00a0[latex]\\left({x}^{4}-10{x}^{3}+37{x}^{2}-60x+36\\right)\\div \\left(x - 2\\right)\\\\[\/latex]\n\n33. [latex]\\left({x}^{4}-8{x}^{3}+24{x}^{2}-32x+16\\right)\\div \\left(x - 2\\right)\\\\[\/latex]\n\n34.\u00a0[latex]\\left({x}^{4}+5{x}^{3}-3{x}^{2}-13x+10\\right)\\div \\left(x+5\\right)\\\\[\/latex]\n\n35. [latex]\\left({x}^{4}-12{x}^{3}+54{x}^{2}-108x+81\\right)\\div \\left(x - 3\\right)\\\\[\/latex]\n\n36.\u00a0[latex]\\left(4{x}^{4}-2{x}^{3}-4x+2\\right)\\div \\left(2x - 1\\right)\\\\[\/latex]\n\n37. [latex]\\left(4{x}^{4}+2{x}^{3}-4{x}^{2}+2x+2\\right)\\div \\left(2x+1\\right)\\\\[\/latex]\n\nFor the following exercises, use the graph of the third-degree polynomial and one factor to write the factored form of the polynomial suggested by the graph. The leading coefficient is one.\n\n38. Factor is [latex]{x}^{2}-x+3\\\\[\/latex]\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201543\/CNX_PreCalc_Figure_03_05_2012.jpg\" alt=\"Graph of a polynomial that has a x-intercept at -1.\" data-media-type=\"image\/jpg\"\/>\n\n39. Factor is [latex]\\left({x}^{2}+2x+4\\right)\\\\[\/latex]\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201544\/CNX_PreCalc_Figure_03_05_2022.jpg\" alt=\"Graph of a polynomial that has a x-intercept at 1.\" data-media-type=\"image\/jpg\"\/>\n\n40. Factor is [latex]{x}^{2}+2x+5\\\\[\/latex]\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201545\/CNX_PreCalc_Figure_03_05_2032.jpg\" alt=\"Graph of a polynomial that has a x-intercept at 2.\" data-media-type=\"image\/jpg\"\/>\n\n41. Factor is [latex]{x}^{2}+x+1\\\\[\/latex]\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201546\/CNX_PreCalc_Figure_03_05_2042.jpg\" alt=\"Graph of a polynomial that has a x-intercept at 5.\" data-media-type=\"image\/jpg\"\/>\n\n42.\u00a0Factor is [latex]{x}^{2}+2x+2\\\\[\/latex]\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201548\/CNX_PreCalc_Figure_03_05_2052.jpg\" alt=\"Graph of a polynomial that has a x-intercept at -3.\" data-media-type=\"image\/jpg\"\/>\n\nFor the following exercises, use synthetic division to find the quotient and remainder.\n\n43. [latex]\\frac{4{x}^{3}-33}{x - 2}\\\\[\/latex]\n\n44.\u00a0[latex]\\frac{2{x}^{3}+25}{x+3}\\\\[\/latex]\n\n45. [latex]\\frac{3{x}^{3}+2x - 5}{x - 1}\\\\[\/latex]\n\n46.\u00a0[latex]\\frac{-4{x}^{3}-{x}^{2}-12}{x+4}\\\\[\/latex]\n\n47. [latex]\\frac{{x}^{4}-22}{x+2}\\\\[\/latex]\n\nFor the following exercises, use a calculator with CAS to answer the questions.\n\n48. Consider [latex]\\frac{{x}^{k}-1}{x - 1}\\\\[\/latex] with [latex]k=1, 2, 3\\\\[\/latex]. What do you expect the result to be if <em>k<\/em> = 4?\n\n49. Consider [latex]\\frac{{x}^{k}+1}{x+1}\\\\[\/latex] for [latex]k=1, 3, 5\\\\[\/latex]. What do you expect the result to be if\u00a0<em>k<\/em> = 7?\n\n50.\u00a0Consider [latex]\\frac{{x}^{4}-{k}^{4}}{x-k}\\\\[\/latex] for [latex]k=1, 2, 3\\\\[\/latex]. What do you expect the result to be if\u00a0<em>k<\/em> = 4?\n\n51. Consider [latex]\\frac{{x}^{k}}{x+1}\\\\[\/latex] with [latex]k=1, 2, 3\\\\[\/latex]. What do you expect the result to be if\u00a0<em>k<\/em> = 4?\n\n52.\u00a0Consider [latex]\\frac{{x}^{k}}{x - 1}\\\\[\/latex] with [latex]k=1, 2, 3\\\\[\/latex]. What do you expect the result to be if\u00a0<em>k<\/em> = 4?\n\nFor the following exercises, use synthetic division to determine the quotient involving a complex number.\n\n53. [latex]\\frac{x+1}{x-i}\\\\[\/latex]\n\n54.\u00a0[latex]\\frac{{x}^{2}+1}{x-i}\\\\[\/latex]\n\n55. [latex]\\frac{x+1}{x+i}\\\\[\/latex]\n\n56.\u00a0[latex]\\frac{{x}^{2}+1}{x+i}\\\\[\/latex]\n\n57. [latex]\\frac{{x}^{3}+1}{x-i}\\\\[\/latex]\n\nFor the following exercises, use the given length and area of a rectangle to express the width algebraically.\n\n58. Length is [latex]x+5\\\\[\/latex], area is [latex]2{x}^{2}+9x - 5\\\\[\/latex].\n\n59. Length is [latex]2x\\text{ }+\\text{ }5\\\\[\/latex], area is [latex]4{x}^{3}+10{x}^{2}+6x+15\\\\[\/latex]\n\n60.\u00a0Length is [latex]3x - 4\\\\[\/latex], area is [latex]6{x}^{4}-8{x}^{3}+9{x}^{2}-9x - 4\\\\[\/latex]\n\nFor the following exercises, use the given volume of a box and its length and width to express the height of the box algebraically.\n\n61. Volume is [latex]12{x}^{3}+20{x}^{2}-21x - 36\\\\[\/latex], length is [latex]2x+3\\\\[\/latex], width is [latex]3x - 4\\\\[\/latex].\n\n62.\u00a0Volume is [latex]18{x}^{3}-21{x}^{2}-40x+48\\\\[\/latex], length is [latex]3x - 4\\\\[\/latex],\u00a0width is [latex]3x - 4\\\\[\/latex].\n\n63. Volume is [latex]10{x}^{3}+27{x}^{2}+2x - 24\\\\[\/latex], length is [latex]5x - 4\\\\[\/latex],\u00a0width is [latex]2x+3\\\\[\/latex].\n\n64.\u00a0Volume is [latex]10{x}^{3}+30{x}^{2}-8x - 24\\\\[\/latex], length is 2, width is [latex]x+3\\\\[\/latex].\n\nFor the following exercises, use the given volume and radius of a cylinder to express the height of the cylinder algebraically.\n\n65. Volume is [latex]\\pi \\left(25{x}^{3}-65{x}^{2}-29x - 3\\right)\\\\[\/latex], radius is [latex]5x+1\\\\[\/latex].\n\n66.\u00a0Volume is [latex]\\pi \\left(4{x}^{3}+12{x}^{2}-15x - 50\\right)\\\\[\/latex], radius is [latex]2x+5\\\\[\/latex].\n\n67. Volume is [latex]\\pi \\left(3{x}^{4}+24{x}^{3}+46{x}^{2}-16x - 32\\right)\\\\[\/latex], radius is [latex]x+4\\\\[\/latex].<\/p>","rendered":"<p>1. If division of a polynomial by a binomial results in a remainder of zero, what can be conclude?<\/p>\n<p>2.\u00a0If a polynomial of degree <em>n<\/em>\u00a0is divided by a binomial of degree 1, what is the degree of the quotient?<\/p>\n<p>For the following exercises, use long division to divide. Specify the quotient and the remainder.<\/p>\n<p>3. [latex]\\left({x}^{2}+5x - 1\\right)\\div \\left(x - 1\\right)\\\\[\/latex]<\/p>\n<p>4.\u00a0[latex]\\left(2{x}^{2}-9x - 5\\right)\\div \\left(x - 5\\right)\\\\[\/latex]<\/p>\n<p>5. [latex]\\left(3{x}^{2}+23x+14\\right)\\div \\left(x+7\\right)\\\\[\/latex]<\/p>\n<p>6.\u00a0[latex]\\left(4{x}^{2}-10x+6\\right)\\div \\left(4x+2\\right)\\\\[\/latex]<\/p>\n<p>7. [latex]\\left(6{x}^{2}-25x - 25\\right)\\div \\left(6x+5\\right)\\\\[\/latex]<\/p>\n<p>8.\u00a0[latex]\\left(-{x}^{2}-1\\right)\\div \\left(x+1\\right)\\\\[\/latex]<\/p>\n<p>9. [latex]\\left(2{x}^{2}-3x+2\\right)\\div \\left(x+2\\right)\\\\[\/latex]<\/p>\n<p>10.\u00a0[latex]\\left({x}^{3}-126\\right)\\div \\left(x - 5\\right)\\\\[\/latex]<\/p>\n<p>11. [latex]\\left(3{x}^{2}-5x+4\\right)\\div \\left(3x+1\\right)\\\\[\/latex]<\/p>\n<p>12.\u00a0[latex]\\left({x}^{3}-3{x}^{2}+5x - 6\\right)\\div \\left(x - 2\\right)\\\\[\/latex]<\/p>\n<p>13. [latex]\\left(2{x}^{3}+3{x}^{2}-4x+15\\right)\\div \\left(x+3\\right)\\\\[\/latex]<\/p>\n<p>For the following exercises, use synthetic division to find the quotient.<\/p>\n<p>14. [latex]\\left(3{x}^{3}-2{x}^{2}+x - 4\\right)\\div \\left(x+3\\right)\\\\[\/latex]<\/p>\n<p>15. [latex]\\left(2{x}^{3}-6{x}^{2}-7x+6\\right)\\div \\left(x - 4\\right)\\\\[\/latex]<\/p>\n<p>16.\u00a0[latex]\\left(6{x}^{3}-10{x}^{2}-7x - 15\\right)\\div \\left(x+1\\right)\\\\[\/latex]<\/p>\n<p>17. [latex]\\left(4{x}^{3}-12{x}^{2}-5x - 1\\right)\\div \\left(2x+1\\right)\\\\[\/latex]<\/p>\n<p>18.\u00a0[latex]\\left(9{x}^{3}-9{x}^{2}+18x+5\\right)\\div \\left(3x - 1\\right)\\\\[\/latex]<\/p>\n<p>19. [latex]\\left(3{x}^{3}-2{x}^{2}+x - 4\\right)\\div \\left(x+3\\right)\\\\[\/latex]<\/p>\n<p>20.\u00a0[latex]\\left(-6{x}^{3}+{x}^{2}-4\\right)\\div \\left(2x - 3\\right)\\\\[\/latex]<\/p>\n<p>21. [latex]\\left(2{x}^{3}+7{x}^{2}-13x - 3\\right)\\div \\left(2x - 3\\right)\\\\[\/latex]<\/p>\n<p>22.\u00a0[latex]\\left(3{x}^{3}-5{x}^{2}+2x+3\\right)\\div \\left(x+2\\right)\\\\[\/latex]<\/p>\n<p>23. [latex]\\left(4{x}^{3}-5{x}^{2}+13\\right)\\div \\left(x+4\\right)\\\\[\/latex]<\/p>\n<p>24.\u00a0[latex]\\left({x}^{3}-3x+2\\right)\\div \\left(x+2\\right)\\\\[\/latex]<\/p>\n<p>25. [latex]\\left({x}^{3}-21{x}^{2}+147x - 343\\right)\\div \\left(x - 7\\right)\\\\[\/latex]<\/p>\n<p>26.\u00a0[latex]\\left({x}^{3}-15{x}^{2}+75x - 125\\right)\\div \\left(x - 5\\right)\\\\[\/latex]<\/p>\n<p>27. [latex]\\left(9{x}^{3}-x+2\\right)\\div \\left(3x - 1\\right)\\\\[\/latex]<\/p>\n<p>28.\u00a0[latex]\\left(6{x}^{3}-{x}^{2}+5x+2\\right)\\div \\left(3x+1\\right)\\\\[\/latex]<\/p>\n<p>29. [latex]\\left({x}^{4}+{x}^{3}-3{x}^{2}-2x+1\\right)\\div \\left(x+1\\right)\\\\[\/latex]<\/p>\n<p>30.\u00a0[latex]\\left({x}^{4}-3{x}^{2}+1\\right)\\div \\left(x - 1\\right)\\\\[\/latex]<\/p>\n<p>31. [latex]\\left({x}^{4}+2{x}^{3}-3{x}^{2}+2x+6\\right)\\div \\left(x+3\\right)\\\\[\/latex]<\/p>\n<p>32.\u00a0[latex]\\left({x}^{4}-10{x}^{3}+37{x}^{2}-60x+36\\right)\\div \\left(x - 2\\right)\\\\[\/latex]<\/p>\n<p>33. [latex]\\left({x}^{4}-8{x}^{3}+24{x}^{2}-32x+16\\right)\\div \\left(x - 2\\right)\\\\[\/latex]<\/p>\n<p>34.\u00a0[latex]\\left({x}^{4}+5{x}^{3}-3{x}^{2}-13x+10\\right)\\div \\left(x+5\\right)\\\\[\/latex]<\/p>\n<p>35. [latex]\\left({x}^{4}-12{x}^{3}+54{x}^{2}-108x+81\\right)\\div \\left(x - 3\\right)\\\\[\/latex]<\/p>\n<p>36.\u00a0[latex]\\left(4{x}^{4}-2{x}^{3}-4x+2\\right)\\div \\left(2x - 1\\right)\\\\[\/latex]<\/p>\n<p>37. [latex]\\left(4{x}^{4}+2{x}^{3}-4{x}^{2}+2x+2\\right)\\div \\left(2x+1\\right)\\\\[\/latex]<\/p>\n<p>For the following exercises, use the graph of the third-degree polynomial and one factor to write the factored form of the polynomial suggested by the graph. The leading coefficient is one.<\/p>\n<p>38. Factor is [latex]{x}^{2}-x+3\\\\[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201543\/CNX_PreCalc_Figure_03_05_2012.jpg\" alt=\"Graph of a polynomial that has a x-intercept at -1.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>39. Factor is [latex]\\left({x}^{2}+2x+4\\right)\\\\[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201544\/CNX_PreCalc_Figure_03_05_2022.jpg\" alt=\"Graph of a polynomial that has a x-intercept at 1.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>40. Factor is [latex]{x}^{2}+2x+5\\\\[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201545\/CNX_PreCalc_Figure_03_05_2032.jpg\" alt=\"Graph of a polynomial that has a x-intercept at 2.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>41. Factor is [latex]{x}^{2}+x+1\\\\[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201546\/CNX_PreCalc_Figure_03_05_2042.jpg\" alt=\"Graph of a polynomial that has a x-intercept at 5.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>42.\u00a0Factor is [latex]{x}^{2}+2x+2\\\\[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201548\/CNX_PreCalc_Figure_03_05_2052.jpg\" alt=\"Graph of a polynomial that has a x-intercept at -3.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>For the following exercises, use synthetic division to find the quotient and remainder.<\/p>\n<p>43. [latex]\\frac{4{x}^{3}-33}{x - 2}\\\\[\/latex]<\/p>\n<p>44.\u00a0[latex]\\frac{2{x}^{3}+25}{x+3}\\\\[\/latex]<\/p>\n<p>45. [latex]\\frac{3{x}^{3}+2x - 5}{x - 1}\\\\[\/latex]<\/p>\n<p>46.\u00a0[latex]\\frac{-4{x}^{3}-{x}^{2}-12}{x+4}\\\\[\/latex]<\/p>\n<p>47. [latex]\\frac{{x}^{4}-22}{x+2}\\\\[\/latex]<\/p>\n<p>For the following exercises, use a calculator with CAS to answer the questions.<\/p>\n<p>48. Consider [latex]\\frac{{x}^{k}-1}{x - 1}\\\\[\/latex] with [latex]k=1, 2, 3\\\\[\/latex]. What do you expect the result to be if <em>k<\/em> = 4?<\/p>\n<p>49. Consider [latex]\\frac{{x}^{k}+1}{x+1}\\\\[\/latex] for [latex]k=1, 3, 5\\\\[\/latex]. What do you expect the result to be if\u00a0<em>k<\/em> = 7?<\/p>\n<p>50.\u00a0Consider [latex]\\frac{{x}^{4}-{k}^{4}}{x-k}\\\\[\/latex] for [latex]k=1, 2, 3\\\\[\/latex]. What do you expect the result to be if\u00a0<em>k<\/em> = 4?<\/p>\n<p>51. Consider [latex]\\frac{{x}^{k}}{x+1}\\\\[\/latex] with [latex]k=1, 2, 3\\\\[\/latex]. What do you expect the result to be if\u00a0<em>k<\/em> = 4?<\/p>\n<p>52.\u00a0Consider [latex]\\frac{{x}^{k}}{x - 1}\\\\[\/latex] with [latex]k=1, 2, 3\\\\[\/latex]. What do you expect the result to be if\u00a0<em>k<\/em> = 4?<\/p>\n<p>For the following exercises, use synthetic division to determine the quotient involving a complex number.<\/p>\n<p>53. [latex]\\frac{x+1}{x-i}\\\\[\/latex]<\/p>\n<p>54.\u00a0[latex]\\frac{{x}^{2}+1}{x-i}\\\\[\/latex]<\/p>\n<p>55. [latex]\\frac{x+1}{x+i}\\\\[\/latex]<\/p>\n<p>56.\u00a0[latex]\\frac{{x}^{2}+1}{x+i}\\\\[\/latex]<\/p>\n<p>57. [latex]\\frac{{x}^{3}+1}{x-i}\\\\[\/latex]<\/p>\n<p>For the following exercises, use the given length and area of a rectangle to express the width algebraically.<\/p>\n<p>58. Length is [latex]x+5\\\\[\/latex], area is [latex]2{x}^{2}+9x - 5\\\\[\/latex].<\/p>\n<p>59. Length is [latex]2x\\text{ }+\\text{ }5\\\\[\/latex], area is [latex]4{x}^{3}+10{x}^{2}+6x+15\\\\[\/latex]<\/p>\n<p>60.\u00a0Length is [latex]3x - 4\\\\[\/latex], area is [latex]6{x}^{4}-8{x}^{3}+9{x}^{2}-9x - 4\\\\[\/latex]<\/p>\n<p>For the following exercises, use the given volume of a box and its length and width to express the height of the box algebraically.<\/p>\n<p>61. Volume is [latex]12{x}^{3}+20{x}^{2}-21x - 36\\\\[\/latex], length is [latex]2x+3\\\\[\/latex], width is [latex]3x - 4\\\\[\/latex].<\/p>\n<p>62.\u00a0Volume is [latex]18{x}^{3}-21{x}^{2}-40x+48\\\\[\/latex], length is [latex]3x - 4\\\\[\/latex],\u00a0width is [latex]3x - 4\\\\[\/latex].<\/p>\n<p>63. Volume is [latex]10{x}^{3}+27{x}^{2}+2x - 24\\\\[\/latex], length is [latex]5x - 4\\\\[\/latex],\u00a0width is [latex]2x+3\\\\[\/latex].<\/p>\n<p>64.\u00a0Volume is [latex]10{x}^{3}+30{x}^{2}-8x - 24\\\\[\/latex], length is 2, width is [latex]x+3\\\\[\/latex].<\/p>\n<p>For the following exercises, use the given volume and radius of a cylinder to express the height of the cylinder algebraically.<\/p>\n<p>65. Volume is [latex]\\pi \\left(25{x}^{3}-65{x}^{2}-29x - 3\\right)\\\\[\/latex], radius is [latex]5x+1\\\\[\/latex].<\/p>\n<p>66.\u00a0Volume is [latex]\\pi \\left(4{x}^{3}+12{x}^{2}-15x - 50\\right)\\\\[\/latex], radius is [latex]2x+5\\\\[\/latex].<\/p>\n<p>67. Volume is [latex]\\pi \\left(3{x}^{4}+24{x}^{3}+46{x}^{2}-16x - 32\\right)\\\\[\/latex], radius is [latex]x+4\\\\[\/latex].<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1374\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1374","chapter","type-chapter","status-publish","hentry"],"part":1346,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1374","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":1,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1374\/revisions"}],"predecessor-version":[{"id":2388,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1374\/revisions\/2388"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/1346"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1374\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/media?parent=1374"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=1374"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/contributor?post=1374"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/license?post=1374"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}