{"id":390,"date":"2015-10-26T17:51:16","date_gmt":"2015-10-26T17:51:16","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=390"},"modified":"2015-11-12T18:38:00","modified_gmt":"2015-11-12T18:38:00","slug":"using-the-square-root-property","status":"web-only","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/chapter\/using-the-square-root-property\/","title":{"raw":"Using the Square Root Property","rendered":"Using the Square Root Property"},"content":{"raw":"When there is no linear term in the equation, another method of solving a quadratic equation is by using the <strong>square root property<\/strong>, in which we isolate the [latex]{x}^{2}[\/latex] term and take the square root of the number on the other side of the equals sign. Keep in mind that sometimes we may have to manipulate the equation to isolate the [latex]{x}^{2}[\/latex] term so that the square root property can be used.\r\n<div class=\"textbox\">\r\n<h3>A General Note: The Square Root Property<\/h3>\r\nWith the [latex]{x}^{2}[\/latex] term isolated, the square root property states that:\r\n<div style=\"text-align: center;\">[latex]\\text{if }{x}^{2}=k,\\text{then }x=\\pm \\sqrt{k}[\/latex]<\/div>\r\nwhere <em>k <\/em>is a nonzero real number.\r\n\r\n<\/div>\r\n<div class=\"textbox\">\r\n<h3>How To: Given a quadratic equation with an [latex]{x}^{2}[\/latex] term but no [latex]x[\/latex] term, use the square root property to solve it.<\/h3>\r\n<ol>\r\n\t<li>Isolate the [latex]{x}^{2}[\/latex] term on one side of the equal sign.<\/li>\r\n\t<li>Take the square root of both sides of the equation, putting a [latex]\\pm [\/latex] sign before the expression on the side opposite the squared term.<\/li>\r\n\t<li>Simplify the numbers on the side with the [latex]\\pm [\/latex] sign.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 6: Solving a Simple Quadratic Equation Using the Square Root Property<\/h3>\r\nSolve the quadratic using the square root property: [latex]{x}^{2}=8[\/latex].\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Solution<\/h3>\r\nTake the square root of both sides, and then simplify the radical. Remember to use a [latex]\\\\pm [\/latex] sign before the radical symbol.\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}{x}^{2}\\hfill&amp;=8\\hfill \\\\ x\\hfill&amp;=\\pm \\sqrt{8}\\hfill \\\\ \\hfill&amp;=\\pm 2\\sqrt{2}\\hfill \\end{array}[\/latex]<\/div>\r\nThe solutions are [latex]x=2\\sqrt{2}[\/latex], [latex]x=-2\\sqrt{2}[\/latex].\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 7: Solving a Quadratic Equation Using the Square Root Property<\/h3>\r\nSolve the quadratic equation: [latex]4{x}^{2}+1=7[\/latex]\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Solution<\/h3>\r\nFirst, isolate the [latex]{x}^{2}[\/latex] term. Then take the square root of both sides.\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}4{x}^{2}+1=7\\hfill \\\\ 4{x}^{2}=6\\hfill \\\\ {x}^{2}=\\frac{6}{4}\\hfill \\\\ x=\\pm \\frac{\\sqrt{6}}{2}\\hfill \\end{array}[\/latex]<\/div>\r\nThe solutions are [latex]x=\\frac{\\sqrt{6}}{2}[\/latex], [latex]x=-\\frac{\\sqrt{6}}{2}[\/latex].\r\n\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 6<\/h3>\r\nSolve the quadratic equation using the square root property: [latex]3{\\left(x - 4\\right)}^{2}=15[\/latex].\r\n\r\n<a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-to-selected-exercises-2\/\" target=\"_blank\">Solution<\/a>\r\n\r\n<\/div>","rendered":"<p>When there is no linear term in the equation, another method of solving a quadratic equation is by using the <strong>square root property<\/strong>, in which we isolate the [latex]{x}^{2}[\/latex] term and take the square root of the number on the other side of the equals sign. Keep in mind that sometimes we may have to manipulate the equation to isolate the [latex]{x}^{2}[\/latex] term so that the square root property can be used.<\/p>\n<div class=\"textbox\">\n<h3>A General Note: The Square Root Property<\/h3>\n<p>With the [latex]{x}^{2}[\/latex] term isolated, the square root property states that:<\/p>\n<div style=\"text-align: center;\">[latex]\\text{if }{x}^{2}=k,\\text{then }x=\\pm \\sqrt{k}[\/latex]<\/div>\n<p>where <em>k <\/em>is a nonzero real number.<\/p>\n<\/div>\n<div class=\"textbox\">\n<h3>How To: Given a quadratic equation with an [latex]{x}^{2}[\/latex] term but no [latex]x[\/latex] term, use the square root property to solve it.<\/h3>\n<ol>\n<li>Isolate the [latex]{x}^{2}[\/latex] term on one side of the equal sign.<\/li>\n<li>Take the square root of both sides of the equation, putting a [latex]\\pm[\/latex] sign before the expression on the side opposite the squared term.<\/li>\n<li>Simplify the numbers on the side with the [latex]\\pm[\/latex] sign.<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 6: Solving a Simple Quadratic Equation Using the Square Root Property<\/h3>\n<p>Solve the quadratic using the square root property: [latex]{x}^{2}=8[\/latex].<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<p>Take the square root of both sides, and then simplify the radical. Remember to use a [latex]\\\\pm[\/latex] sign before the radical symbol.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}{x}^{2}\\hfill&=8\\hfill \\\\ x\\hfill&=\\pm \\sqrt{8}\\hfill \\\\ \\hfill&=\\pm 2\\sqrt{2}\\hfill \\end{array}[\/latex]<\/div>\n<p>The solutions are [latex]x=2\\sqrt{2}[\/latex], [latex]x=-2\\sqrt{2}[\/latex].<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 7: Solving a Quadratic Equation Using the Square Root Property<\/h3>\n<p>Solve the quadratic equation: [latex]4{x}^{2}+1=7[\/latex]<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<p>First, isolate the [latex]{x}^{2}[\/latex] term. Then take the square root of both sides.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}4{x}^{2}+1=7\\hfill \\\\ 4{x}^{2}=6\\hfill \\\\ {x}^{2}=\\frac{6}{4}\\hfill \\\\ x=\\pm \\frac{\\sqrt{6}}{2}\\hfill \\end{array}[\/latex]<\/div>\n<p>The solutions are [latex]x=\\frac{\\sqrt{6}}{2}[\/latex], [latex]x=-\\frac{\\sqrt{6}}{2}[\/latex].<\/p>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 6<\/h3>\n<p>Solve the quadratic equation using the square root property: [latex]3{\\left(x - 4\\right)}^{2}=15[\/latex].<\/p>\n<p><a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-to-selected-exercises-2\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-390\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>College Algebra. <strong>Authored by<\/strong>: OpenStax College Algebra. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\">http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":3,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"College Algebra\",\"author\":\"OpenStax College Algebra\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-390","chapter","type-chapter","status-web-only","hentry"],"part":211,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/390","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":3,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/390\/revisions"}],"predecessor-version":[{"id":673,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/390\/revisions\/673"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/211"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/390\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/media?parent=390"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=390"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/contributor?post=390"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/atd-sanjac-collegealgebra\/wp-json\/wp\/v2\/license?post=390"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}