Problem Set: Calculus of the Hyperbolic Functions

1. [T] Find expressions for coshx+sinhxcoshx+sinhx and coshxsinhx.coshxsinhx. Use a calculator to graph these functions and ensure your expression is correct.

2. From the definitions of cosh(x)cosh(x) and sinh(x),sinh(x), find their antiderivatives.

3. Show that cosh(x)cosh(x) and sinh(x)sinh(x) satisfy y=y.

4. Use the quotient rule to verify that tanh(x)=sech2(x).

5. Derive cosh2(x)+sinh2(x)=cosh(2x) from the definition.

6. Take the derivative of the previous expression to find an expression for sinh(2x).

7. Prove sinh(x+y)=sinh(x)cosh(y)+cosh(x)sinh(y) by changing the expression to exponentials.

8. Take the derivative of the previous expression to find an expression for cosh(x+y).

For the following exercises (9-18), find the derivatives of the given functions and graph along with the function to ensure your answer is correct.

9. [T] cosh(3x+1)

10. [T] sinh(x2)

11. [T] 1cosh(x)

12. [T] sinh(ln(x))

13. [T] cosh2(x)+sinh2(x)

14. [T] cosh2(x)sinh2(x)

15. [T] tanh(x2+1)

16. [T] 1+tanh(x)1tanh(x)

17. [T] sinh6(x)

18. [T] ln(sech(x)+tanh(x))

For the following exercises (19-29), find the antiderivatives for the given functions.

19. cosh(2x+1)

20. tanh(3x+2)

21. xcosh(x2)

23. 3x3tanh(x4)

24. cosh2(x)sinh(x)

25. tanh2(x)sech2(x)

26. sinh(x)1+cosh(x)

27. coth(x)

28. cosh(x)+sinh(x)

29. (cosh(x)+sinh(x))n

For the following exercises (30-36), find the derivatives for the functions.

30. tanh1(4x)

31. sinh1(x2)

32. sinh1(cosh(x))

33. cosh1(x3)

34. tanh1(cos(x))

35. esinh1(x)

36. ln(tanh1(x))

For the following exercises (37-43), find the antiderivatives for the functions.

37. dx4x2

38. dxa2x2

39. dxx2+1

40. xdxx2+1

41. dxx1x2

42. exe2x1

43. 2xx41

For the following exercises (44-46), use the fact that a falling body with friction equal to velocity squared obeys the equation dv/dt=gv2.

44. Show that v(t)=gtanh(gt) satisfies this equation.

45. Derive the previous expression for v(t) by integrating dvgv2=dt.

46. [T] Estimate how far a body has fallen in 12 seconds by finding the area underneath the curve of v(t).

For the following exercises (47-49), use this scenario: A cable hanging under its own weight has a slope S=dy/dx that satisfies dS/dx=c1+S2. The constant c is the ratio of cable density to tension.

47. Show that S=sinh(cx) satisfies this equation.

48. Integrate dy/dx=sinh(cx) to find the cable height y(x) if y(0)=1/c.

49. Sketch the cable and determine how far down it sags at x=0.

For the following exercises (50-53), solve each problem.

50. [T] A chain hangs from two posts 2 m apart to form a catenary described by the equation y=2cosh(x/2)1. Find the slope of the catenary at the left fence post.

51. [T] A chain hangs from two posts four meters apart to form a catenary described by the equation y=4cosh(x/4)3. Find the total length of the catenary (arc length).

52. [T] A high-voltage power line is a catenary described by y=10cosh(x/10). Find the ratio of the area under the catenary to its arc length. What do you notice?

53. A telephone line is a catenary described by y=acosh(x/a). Find the ratio of the area under the catenary to its arc length. Does this confirm your answer for the previous question?

54. Prove the formula for the derivative of y=sinh1(x) by differentiating x=sinh(y). (Hint: Use hyperbolic trigonometric identities.)

55. Prove the formula for the derivative of y=cosh1(x) by differentiating x=cosh(y).

(Hint: Use hyperbolic trigonometric identities.)

56. Prove the formula for the derivative of y=sech1(x) by differentiating x=sech(y). (Hint: Use hyperbolic trigonometric identities.)

57. Prove that (cosh(x)+sinh(x))n=cosh(nx)+sinh(nx).

58. Prove the expression for sinh1(x). Multiply x=sinh(y)=(1/2)(eyey) by 2ey and solve for y. Does your expression match the textbook?

59. Prove the expression for cosh1(x). Multiply x=cosh(y)=(1/2)(eyey) by 2ey and solve for y. Does your expression match the textbook?