{"id":10720,"date":"2015-07-10T19:09:19","date_gmt":"2015-07-10T19:09:19","guid":{"rendered":"https:\/\/courses.candelalearning.com\/osprecalc\/?post_type=chapter&#038;p=10720"},"modified":"2022-01-09T17:03:45","modified_gmt":"2022-01-09T17:03:45","slug":"piecewise-defined-functions","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/piecewise-defined-functions\/","title":{"raw":"Piecewise-defined functions","rendered":"Piecewise-defined functions"},"content":{"raw":"Sometimes, we come across a function that requires more than one formula in order to obtain the given output. For example, in the toolkit functions, we introduced the absolute value function [latex]f\\left(x\\right)=|x|[\/latex]. With a domain of all real numbers and a range of values greater than or equal to 0, <strong>absolute value<\/strong> can be defined as the <strong>magnitude<\/strong>, or <strong>modulus<\/strong>, of a real number value regardless of sign. It is the distance from 0 on the number line. All of these definitions require the output to be greater than or equal to 0.\r\n<p id=\"fs-id1165137558775\">If we input 0, or a positive value, the output is the same as the input.<\/p>\r\n\r\n<div id=\"fs-id1165135194329\" class=\"equation unnumbered\" style=\"text-align: center;\">[latex]f\\left(x\\right)=x\\text{ if }x\\ge 0[\/latex]<\/div>\r\n<p id=\"fs-id1165137529947\">If we input a negative value, the output is the opposite of the input.<\/p>\r\n\r\n<div id=\"fs-id1165133112779\" class=\"equation unnumbered\" style=\"text-align: center;\">[latex]f\\left(x\\right)=-x\\text{ if }x&lt;0[\/latex]<\/div>\r\n<p id=\"fs-id1165137863778\">Because this requires two different processes or pieces, the absolute value function is an example of a piecewise function. A <strong>piecewise function<\/strong> is a function in which more than one formula is used to define the output over different pieces of the domain.<\/p>\r\n<p id=\"fs-id1165134042316\">We use piecewise functions to describe situations in which a rule or relationship changes as the input value crosses certain \"boundaries.\" For example, we often encounter situations in business for which the cost per piece of a certain item is discounted once the number ordered exceeds a certain value. Tax brackets are another real-world example of piecewise functions. For example, consider a simple tax system in which incomes up to $10,000 are taxed at 10%, and any additional income is taxed at 20%. The tax on a total income, S, would be\u00a00.1S if [latex]{S}\\le\\[\/latex] $10,000\u00a0and 1000 + 0.2 (S - $10,000),\u00a0if S&gt; $10,000.<\/p>\r\n\r\n<div id=\"fs-id1165137531241\" class=\"note textbox\">\r\n<h3 class=\"title\">A General Note: Piecewise Function<\/h3>\r\n<p id=\"fs-id1165135504970\">A piecewise function is a function in which more than one formula is used to define the output. Each formula has its own domain, and the domain of the function is the union of all these smaller domains. We notate this idea like this:<\/p>\r\n[latex] f\\left(x\\right)=\\begin{cases}\\text{formula 1 if x is in domain 1}\\\\ \\text{formula 2 if x is in domain 2}\\\\ \\text{formula 3 if x is in domain 3}\\end{cases} [\/latex]\r\n\r\nIn piecewise notation, the absolute value function is\r\n<div id=\"fs-id1165135190749\" class=\"equation unnumbered\" style=\"text-align: center;\">[latex]|x|=\\begin{cases}x\\text{ if }x\\ge 0\\\\ -x\\text{ if }x&lt;0\\end{cases}[\/latex]<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137768426\" class=\"note precalculus howto textbox\">\r\n<h3>How To:\u00a0Given a piecewise function, write the formula and identify the domain for each interval.<strong>\r\n<\/strong><\/h3>\r\n<ol id=\"fs-id1165135443772\">\r\n \t<li>Identify the intervals for which different rules apply.<\/li>\r\n \t<li>Determine formulas that describe how to calculate an output from an input in each interval.<\/li>\r\n \t<li>Use braces and if-statements to write the function.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example: Writing a Piecewise Function<\/h3>\r\nA museum charges $5 per person for a guided tour with a group of 1 to 9 people or a fixed $50 fee for a group of 10 or more people. Write a <strong>function<\/strong> relating the number of people, [latex]n[\/latex], to the cost, [latex]C[\/latex].\r\n\r\n[reveal-answer q=\"668439\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"668439\"]\r\n\r\nTwo different formulas will be needed. For [latex]n[\/latex]-values under 10, [latex]C=5n[\/latex]. For values of [latex]n[\/latex] that are 10 or greater, [latex]C=50[\/latex].\r\n<p style=\"text-align: center;\">[latex]C(n)=\\begin{cases}\\begin{align}{5n}&amp;\\hspace{2mm}\\text{if}\\hspace{2mm}{0}&lt;{n}&lt;{10}\\\\ 50&amp;\\hspace{2mm}\\text{if}\\hspace{2mm}{n}\\ge 10\\end{align}\\end{cases}[\/latex]<\/p>\r\n\r\n<h4>Analysis of the Solution<\/h4>\r\nThe graph is a diagonal line from [latex]n=0[\/latex] to [latex]n=10[\/latex] and a constant after that. In this example, the two formulas agree at the meeting point where [latex]n=10[\/latex], but not all piecewise functions have this property.\r\n\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18193627\/CNX_Precalc_Figure_01_02_0212.jpg\" alt=\"Graph of C(n).\" width=\"360\" height=\"294\" \/>\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n[embed]https:\/\/www.youtube.com\/watch?v=AQaKh_1poBI[\/embed]\r\n<div id=\"Example_01_02_12\" class=\"example\">\r\n<div id=\"fs-id1165135436662\" class=\"exercise\">\r\n<div id=\"fs-id1165135436664\" class=\"problem textbox shaded\">\r\n<h3>Example: Working with a Piecewise Function<\/h3>\r\n<p id=\"fs-id1165137938645\">A cell phone company uses the function below to determine the cost, [latex]C[\/latex], in dollars for [latex]g[\/latex] gigabytes of data transfer.<\/p>\r\n\r\n<div id=\"fs-id1165137660470\" class=\"equation unnumbered\" style=\"text-align: center;\">[latex]C\\left(g\\right)=\\begin{cases}{25} \\text{ if }{ 0 }&lt;{ g }&lt;{ 2 }\\\\ { 25+10 }\\left(g - 2\\right) \\text{ if }{ g}\\ge{ 2 }\\end{cases}[\/latex]<\/div>\r\n<p id=\"fs-id1165135193798\">Find the cost of using 1.5 gigabytes of data and the cost of using 4 gigabytes of data.<\/p>\r\n[reveal-answer q=\"220698\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"220698\"]\r\n\r\nTo find the cost of using 1.5 gigabytes of data, [latex]C(1.5)[\/latex], we first look to see which part of the domain our input falls in. Because 1.5 is less than 2, we use the first formula.\r\n<p style=\"text-align: center;\">[latex]C(1.5) = $25[\/latex]<\/p>\r\nTo find the cost of using 4 gigabytes of data, [latex]C(4)[\/latex], we see that our input of 4 is greater than 2, so we use the second formula.\r\n<p style=\"text-align: center;\">[latex]C(4)=25 + 10( 4-2) =$45[\/latex]<\/p>\r\n\r\n<h4>Analysis of the Solution<\/h4>\r\nWe can see where the function changes from a constant to a shifted and stretched identity at [latex]g=2[\/latex]. We plot the graphs for the different formulas on a common set of axes, making sure each formula is applied on its proper domain.\r\n\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18193630\/CNX_Precalc_Figure_01_02_0222.jpg\" alt=\"Graph of C(g)\" width=\"487\" height=\"296\" \/>\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n[embed]https:\/\/www.youtube.com\/watch?v=E2F2-gP-2qU[\/embed]\r\n\r\n[embed]https:\/\/www.youtube.com\/watch?v=trxO_6i214Y[\/embed]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137810682\" class=\"note precalculus qa textbox\">\r\n<h3>Q&amp;A<\/h3>\r\n<p id=\"fs-id1165137527804\"><strong>Can more than one formula from a piecewise function be applied to a value in the domain?<\/strong><\/p>\r\n<p id=\"fs-id1165137464467\"><em>No. Each value corresponds to one equation in a piecewise formula.<\/em><\/p>\r\n\r\n<\/div>\r\n<h2>Key Concepts<\/h2>\r\n<ul>\r\n \t<li>A piecewise function is described by more than one formula.<\/li>\r\n \t<li>A piecewise function can be graphed using each algebraic formula on its assigned subdomain.<\/li>\r\n<\/ul>","rendered":"<p>Sometimes, we come across a function that requires more than one formula in order to obtain the given output. For example, in the toolkit functions, we introduced the absolute value function [latex]f\\left(x\\right)=|x|[\/latex]. With a domain of all real numbers and a range of values greater than or equal to 0, <strong>absolute value<\/strong> can be defined as the <strong>magnitude<\/strong>, or <strong>modulus<\/strong>, of a real number value regardless of sign. It is the distance from 0 on the number line. All of these definitions require the output to be greater than or equal to 0.<\/p>\n<p id=\"fs-id1165137558775\">If we input 0, or a positive value, the output is the same as the input.<\/p>\n<div id=\"fs-id1165135194329\" class=\"equation unnumbered\" style=\"text-align: center;\">[latex]f\\left(x\\right)=x\\text{ if }x\\ge 0[\/latex]<\/div>\n<p id=\"fs-id1165137529947\">If we input a negative value, the output is the opposite of the input.<\/p>\n<div id=\"fs-id1165133112779\" class=\"equation unnumbered\" style=\"text-align: center;\">[latex]f\\left(x\\right)=-x\\text{ if }x<0[\/latex]<\/div>\n<p id=\"fs-id1165137863778\">Because this requires two different processes or pieces, the absolute value function is an example of a piecewise function. A <strong>piecewise function<\/strong> is a function in which more than one formula is used to define the output over different pieces of the domain.<\/p>\n<p id=\"fs-id1165134042316\">We use piecewise functions to describe situations in which a rule or relationship changes as the input value crosses certain &#8220;boundaries.&#8221; For example, we often encounter situations in business for which the cost per piece of a certain item is discounted once the number ordered exceeds a certain value. Tax brackets are another real-world example of piecewise functions. For example, consider a simple tax system in which incomes up to $10,000 are taxed at 10%, and any additional income is taxed at 20%. The tax on a total income, S, would be\u00a00.1S if [latex]{S}\\le\\[\/latex] $10,000\u00a0and 1000 + 0.2 (S &#8211; $10,000),\u00a0if S&gt; $10,000.<\/p>\n<div id=\"fs-id1165137531241\" class=\"note textbox\">\n<h3 class=\"title\">A General Note: Piecewise Function<\/h3>\n<p id=\"fs-id1165135504970\">A piecewise function is a function in which more than one formula is used to define the output. Each formula has its own domain, and the domain of the function is the union of all these smaller domains. We notate this idea like this:<\/p>\n<p>[latex]f\\left(x\\right)=\\begin{cases}\\text{formula 1 if x is in domain 1}\\\\ \\text{formula 2 if x is in domain 2}\\\\ \\text{formula 3 if x is in domain 3}\\end{cases}[\/latex]<\/p>\n<p>In piecewise notation, the absolute value function is<\/p>\n<div id=\"fs-id1165135190749\" class=\"equation unnumbered\" style=\"text-align: center;\">[latex]|x|=\\begin{cases}x\\text{ if }x\\ge 0\\\\ -x\\text{ if }x<0\\end{cases}[\/latex]<\/div>\n<\/div>\n<div id=\"fs-id1165137768426\" class=\"note precalculus howto textbox\">\n<h3>How To:\u00a0Given a piecewise function, write the formula and identify the domain for each interval.<strong><br \/>\n<\/strong><\/h3>\n<ol id=\"fs-id1165135443772\">\n<li>Identify the intervals for which different rules apply.<\/li>\n<li>Determine formulas that describe how to calculate an output from an input in each interval.<\/li>\n<li>Use braces and if-statements to write the function.<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example: Writing a Piecewise Function<\/h3>\n<p>A museum charges $5 per person for a guided tour with a group of 1 to 9 people or a fixed $50 fee for a group of 10 or more people. Write a <strong>function<\/strong> relating the number of people, [latex]n[\/latex], to the cost, [latex]C[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q668439\">Show Solution<\/span><\/p>\n<div id=\"q668439\" class=\"hidden-answer\" style=\"display: none\">\n<p>Two different formulas will be needed. For [latex]n[\/latex]-values under 10, [latex]C=5n[\/latex]. For values of [latex]n[\/latex] that are 10 or greater, [latex]C=50[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]C(n)=\\begin{cases}\\begin{align}{5n}&\\hspace{2mm}\\text{if}\\hspace{2mm}{0}<{n}<{10}\\\\ 50&\\hspace{2mm}\\text{if}\\hspace{2mm}{n}\\ge 10\\end{align}\\end{cases}[\/latex]<\/p>\n<h4>Analysis of the Solution<\/h4>\n<p>The graph is a diagonal line from [latex]n=0[\/latex] to [latex]n=10[\/latex] and a constant after that. In this example, the two formulas agree at the meeting point where [latex]n=10[\/latex], but not all piecewise functions have this property.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18193627\/CNX_Precalc_Figure_01_02_0212.jpg\" alt=\"Graph of C(n).\" width=\"360\" height=\"294\" \/><\/p>\n<\/div>\n<\/div>\n<\/div>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Ex 2:  Determine the Function From the Graph of a Piecewise Defined Function\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/AQaKh_1poBI?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<div id=\"Example_01_02_12\" class=\"example\">\n<div id=\"fs-id1165135436662\" class=\"exercise\">\n<div id=\"fs-id1165135436664\" class=\"problem textbox shaded\">\n<h3>Example: Working with a Piecewise Function<\/h3>\n<p id=\"fs-id1165137938645\">A cell phone company uses the function below to determine the cost, [latex]C[\/latex], in dollars for [latex]g[\/latex] gigabytes of data transfer.<\/p>\n<div id=\"fs-id1165137660470\" class=\"equation unnumbered\" style=\"text-align: center;\">[latex]C\\left(g\\right)=\\begin{cases}{25} \\text{ if }{ 0 }<{ g }<{ 2 }\\\\ { 25+10 }\\left(g - 2\\right) \\text{ if }{ g}\\ge{ 2 }\\end{cases}[\/latex]<\/div>\n<p id=\"fs-id1165135193798\">Find the cost of using 1.5 gigabytes of data and the cost of using 4 gigabytes of data.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q220698\">Show Solution<\/span><\/p>\n<div id=\"q220698\" class=\"hidden-answer\" style=\"display: none\">\n<p>To find the cost of using 1.5 gigabytes of data, [latex]C(1.5)[\/latex], we first look to see which part of the domain our input falls in. Because 1.5 is less than 2, we use the first formula.<\/p>\n<p style=\"text-align: center;\">[latex]C(1.5) = $25[\/latex]<\/p>\n<p>To find the cost of using 4 gigabytes of data, [latex]C(4)[\/latex], we see that our input of 4 is greater than 2, so we use the second formula.<\/p>\n<p style=\"text-align: center;\">[latex]C(4)=25 + 10( 4-2) =$45[\/latex]<\/p>\n<h4>Analysis of the Solution<\/h4>\n<p>We can see where the function changes from a constant to a shifted and stretched identity at [latex]g=2[\/latex]. We plot the graphs for the different formulas on a common set of axes, making sure each formula is applied on its proper domain.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/896\/2016\/10\/18193630\/CNX_Precalc_Figure_01_02_0222.jpg\" alt=\"Graph of C(g)\" width=\"487\" height=\"296\" \/><\/p>\n<\/div>\n<\/div>\n<\/div>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Ex:  Determine Function Values for a Piecewise Defined Function\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/E2F2-gP-2qU?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-3\" title=\"Ex: Determine a Piecewise Linear Cost Function\" width=\"500\" height=\"375\" src=\"https:\/\/www.youtube.com\/embed\/trxO_6i214Y?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137810682\" class=\"note precalculus qa textbox\">\n<h3>Q&amp;A<\/h3>\n<p id=\"fs-id1165137527804\"><strong>Can more than one formula from a piecewise function be applied to a value in the domain?<\/strong><\/p>\n<p id=\"fs-id1165137464467\"><em>No. Each value corresponds to one equation in a piecewise formula.<\/em><\/p>\n<\/div>\n<h2>Key Concepts<\/h2>\n<ul>\n<li>A piecewise function is described by more than one formula.<\/li>\n<li>A piecewise function can be graphed using each algebraic formula on its assigned subdomain.<\/li>\n<\/ul>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-10720\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><div class=\"license-attribution-dropdown-subheading\">All rights reserved content<\/div><ul class=\"citation-list\"><li>Ex 2: Graph a Piecewise Defined Function. <strong>Authored by<\/strong>: Mathispower4u. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/www.youtube.com\/watch?v=B1jfpiI-QQ8&#038;feature=youtu.be\">https:\/\/www.youtube.com\/watch?v=B1jfpiI-QQ8&#038;feature=youtu.be<\/a>. <strong>License<\/strong>: <em>All Rights Reserved<\/em>. <strong>License Terms<\/strong>: Standard YouTube License<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":10,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"},{\"type\":\"copyrighted_video\",\"description\":\"Ex 2: Graph a Piecewise Defined Function\",\"author\":\"Mathispower4u\",\"organization\":\"\",\"url\":\"https:\/\/www.youtube.com\/watch?v=B1jfpiI-QQ8&feature=youtu.be\",\"project\":\"\",\"license\":\"arr\",\"license_terms\":\"Standard YouTube License\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-10720","chapter","type-chapter","status-publish","hentry"],"part":10705,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/10720","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":26,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/10720\/revisions"}],"predecessor-version":[{"id":16556,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/10720\/revisions\/16556"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/parts\/10705"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/10720\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/media?parent=10720"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapter-type?post=10720"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/contributor?post=10720"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/license?post=10720"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}