{"id":13747,"date":"2018-06-14T23:49:09","date_gmt":"2018-06-14T23:49:09","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/ccbcmd-math\/chapter\/finding-coterminal-angles\/"},"modified":"2021-11-22T21:10:34","modified_gmt":"2021-11-22T21:10:34","slug":"coterminal-angles","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/coterminal-angles\/","title":{"raw":"Coterminal Angles","rendered":"Coterminal Angles"},"content":{"raw":"Converting between degrees and radians can make working with angles easier in some applications. For other applications, we may need another type of conversion. Negative angles and angles greater than a full revolution are more awkward to work with than those in the range of 0\u00b0 to 360\u00b0, or 0 to [latex]2\\pi [\/latex]. It would be convenient to replace those out-of-range angles with a corresponding angle within the range of a single revolution.\r\n\r\nIt is possible for more than one angle to have the same terminal side. Look at Figure 16. The angle of 140\u00b0 is a <strong>positive angle<\/strong>, measured counterclockwise. The angle of \u2013220\u00b0 is a <strong>negative angle<\/strong>, measured clockwise. But both angles have the same terminal side. If two angles in standard position have the same terminal side, they are <strong>coterminal angles<\/strong>. Every angle greater than 360\u00b0 or less than 0\u00b0 is coterminal with an angle between 0\u00b0 and 360\u00b0, and it is often more convenient to find the coterminal angle within the range of 0\u00b0 to 360\u00b0 than to work with an angle that is outside that range.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234857\/CNX_Precalc_Figure_05_01_0202.jpg\" alt=\"A graph showing the equivalence between a 140 degree angle and a negative 220 degree angle.\" width=\"487\" height=\"383\" data-media-type=\"image\/jpg\" \/> <b>Figure 16.<\/b> An angle of 140\u00b0 and an angle of \u2013220\u00b0 are coterminal angles.[\/caption]\r\n\r\nThis video shows examples of how to determine if two angles are coterminal.\r\n\r\nhttps:\/\/www.youtube.com\/watch?v=TuyF8fFg3B0\r\n\r\nAny angle has infinitely many <strong>coterminal angles<\/strong> because each time we add 360\u00b0 to that angle\u2014or subtract 360\u00b0 from it\u2014the resulting value has a terminal side in the same location. For example, 100\u00b0 and 460\u00b0 are coterminal for this reason, as is \u2212260\u00b0. Recognizing that any angle has infinitely many coterminal angles explains the repetitive shape in the graphs of trigonometric functions.\r\n\r\nAn angle\u2019s reference angle is the measure of the smallest, positive, acute angle [latex]t[\/latex] formed by the terminal side of the angle [latex]t[\/latex] and the horizontal axis. Thus positive reference angles have terminal sides that lie in the first quadrant and can be used as models for angles in other quadrants. See Figure 17\u00a0for examples of reference angles for angles in different quadrants.<span id=\"fs-id1165137542464\" data-type=\"media\" data-alt=\"Four side by side graphs. First graph shows an angle of t in quadrant 1 in it's normal position. Second graph shows an angle of t in quadrant 2 due to a rotation of pi minus t. Third graph shows an angle of t in quadrant 3 due to a rotation of t minus pi. Fourth graph shows an angle of t in quadrant 4 due to a rotation of two pi minus t.\">\r\n<\/span>\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"975\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234900\/CNX_Precalc_Figure_05_01_0194.jpg\" alt=\"Four side by side graphs. First graph shows an angle of t in quadrant 1 in it's normal position. Second graph shows an angle of t in quadrant 2 due to a rotation of pi minus t. Third graph shows an angle of t in quadrant 3 due to a rotation of t minus pi. Fourth graph shows an angle of t in quadrant 4 due to a rotation of two pi minus t.\" width=\"975\" height=\"331\" data-media-type=\"image\/jpg\" \/> <b>Figure 17<\/b>[\/caption]\r\n\r\n&nbsp;\r\n<div class=\"textbox\">\r\n<h3>A General Note: Coterminal and Reference Angles<\/h3>\r\nCoterminal angles are two angles in standard position that have the same terminal side.\r\n\r\nAn angle\u2019s <strong>reference angle<\/strong> is the size of the smallest acute angle, [latex]{t}^{\\prime }[\/latex], formed by the terminal side of the angle [latex]t[\/latex]\u00a0and the horizontal axis.\r\n\r\n<\/div>\r\n<div class=\"textbox\">\r\n<h3>How To: Given an angle greater than 360\u00b0, find a coterminal angle between 0\u00b0 and 360\u00b0.<\/h3>\r\n<ol>\r\n \t<li>Subtract 360\u00b0 from the given angle.<\/li>\r\n \t<li>If the result is still greater than 360\u00b0, subtract 360\u00b0 again till the result is between 0\u00b0 and 360\u00b0.<\/li>\r\n \t<li>The resulting angle is coterminal with the original angle.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 5: Finding an Angle Coterminal with an Angle of Measure Greater Than 360\u00b0<\/h3>\r\nFind the least positive angle [latex]\\theta [\/latex] that is coterminal with an angle measuring 800\u00b0, where [latex]0^\\circ \\le \\theta &lt;360^\\circ [\/latex].\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Solution<\/h3>\r\nAn angle with measure 800\u00b0 is coterminal with an angle with measure 800 \u2212 360 = 440\u00b0, but 440\u00b0 is still greater than 360\u00b0, so we subtract 360\u00b0 again to find another coterminal angle: 440 \u2212 360 = 80\u00b0.\r\n\r\nThe angle [latex]\\theta =80^\\circ [\/latex] is coterminal with 800\u00b0. To put it another way, 800\u00b0 equals 80\u00b0 plus two full rotations, as shown in Figure 18.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234903\/CNX_Precalc_Figure_05_01_0212.jpg\" alt=\"A graph showing the equivalence between an 80 degree angle and an 800 degree angle.\" width=\"487\" height=\"383\" data-media-type=\"image\/jpg\" \/> <b>Figure 18<\/b>[\/caption]\r\n\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 5<\/h3>\r\nFind an angle [latex]\\alpha [\/latex] that is coterminal with an angle measuring 870\u00b0, where [latex]0^\\circ \\le \\alpha &lt;360^\\circ [\/latex].\r\n\r\n<a href=\"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/solutions-4\/\" target=\"_blank\" rel=\"noopener\">Solution<\/a>\r\n\r\n<\/div>\r\n<div class=\"textbox\">\r\n<h3>How To: Given an angle with measure less than 0\u00b0, find a coterminal angle having a measure between 0\u00b0 and 360\u00b0.<\/h3>\r\n<ol>\r\n \t<li>Add 360\u00b0 to the given angle.<\/li>\r\n \t<li>If the result is still less than 0\u00b0, add 360\u00b0 again until the result is between 0\u00b0 and 360\u00b0.<\/li>\r\n \t<li>The resulting angle is coterminal with the original angle.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 6: Finding an Angle Coterminal with an Angle Measuring Less Than 0\u00b0<\/h3>\r\nShow the angle with measure \u221245\u00b0 on a circle and find a positive coterminal angle [latex]\\alpha [\/latex] such that 0\u00b0 \u2264 <em data-effect=\"italics\">\u03b1<\/em> &lt; 360\u00b0.\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Solution<\/h3>\r\nSince 45\u00b0 is half of 90\u00b0, we can start at the positive horizontal axis and measure clockwise half of a 90\u00b0 angle.\r\n\r\nBecause we can find coterminal angles by adding or subtracting a full rotation of 360\u00b0, we can find a positive coterminal angle here by adding 360\u00b0:\r\n<div style=\"text-align: center;\">[latex]-45^\\circ +360^\\circ =315^\\circ [\/latex]<\/div>\r\nWe can then show the angle on a circle, as in Figure 19.<span data-type=\"media\" data-alt=\"A graph showing the equivalence of a 315 degree angle and a negative 45 degree angle.\">\r\n<\/span>\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234905\/CNX_Precalc_Figure_05_01_0222.jpg\" alt=\"A graph showing the equivalence of a 315 degree angle and a negative 45 degree angle.\" width=\"487\" height=\"383\" data-media-type=\"image\/jpg\" \/> <strong>Figure 19<\/strong>[\/caption]\r\n\r\n<\/div>\r\n<div>\r\n\r\nWatch this video for another example of how to determine positive and negative coterminal angles.\r\n\r\nhttps:\/\/www.youtube.com\/watch?v=m7jTGVVzb0s\r\n\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 6<\/h3>\r\nFind an angle [latex]\\beta [\/latex] that is coterminal with an angle measuring \u2212300\u00b0 such that [latex]0^\\circ \\le \\beta &lt;360^\\circ [\/latex].\r\n\r\n<a href=\"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/solutions-4\/\" target=\"_blank\" rel=\"noopener\">Solution<\/a>\r\n\r\n<\/div>\r\n<h2 data-type=\"title\">Finding Coterminal Angles Measured in Radians<\/h2>\r\nWe can find <strong>coterminal angles<\/strong> measured in radians in much the same way as we have found them using degrees. In both cases, we find coterminal angles by adding or subtracting one or more full rotations.\r\n<div>\r\n\r\n<strong>Given an angle greater than<\/strong> [latex]2\\pi [\/latex], <strong>find a coterminal angle between 0 and<\/strong> [latex]2\\pi [\/latex].\r\n<ol>\r\n \t<li>Subtract [latex]2\\pi [\/latex] from the given angle.<\/li>\r\n \t<li>If the result is still greater than [latex]2\\pi [\/latex], subtract [latex]2\\pi [\/latex] again until the result is between [latex]0[\/latex] and [latex]2\\pi [\/latex].<\/li>\r\n \t<li>The resulting angle is coterminal with the original angle.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 7: Finding Coterminal Angles Using Radians<\/h3>\r\nFind an angle [latex]\\beta [\/latex] that is coterminal with [latex]\\frac{19\\pi }{4}[\/latex], where [latex]0\\le \\beta &lt;2\\pi [\/latex].\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Solution<\/h3>\r\nWhen working in degrees, we found coterminal angles by adding or subtracting 360 degrees, a full rotation. Likewise, in radians, we can find coterminal angles by adding or subtracting full rotations of [latex]2\\pi [\/latex] radians:\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}\\frac{19\\pi }{4}-2\\pi =\\frac{19\\pi }{4}-\\frac{8\\pi }{4}\\hfill \\\\ =\\frac{11\\pi }{4}\\hfill \\end{array}[\/latex]<\/div>\r\nThe angle [latex]\\frac{11\\pi }{4}[\/latex] is coterminal, but not less than [latex]2\\pi [\/latex], so we subtract another rotation:\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}\\frac{11\\pi }{4}-2\\pi =\\frac{11\\pi }{4}-\\frac{8\\pi }{4}\\hfill \\\\ =\\frac{3\\pi }{4}\\hfill \\end{array}[\/latex]<\/div>\r\nThe angle [latex]\\frac{3\\pi }{4}[\/latex] is coterminal with [latex]\\frac{19\\pi }{4}[\/latex], as shown in Figure 20.<span data-type=\"media\" data-alt=\"A graph showing a circle and the equivalence between angles of 3pi\/4 radians and 19pi\/4 radians.\">\r\n<\/span>\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234908\/CNX_Precalc_Figure_05_01_0232.jpg\" alt=\"A graph showing a circle and the equivalence between angles of 3pi\/4 radians and 19pi\/4 radians.\" width=\"487\" height=\"383\" data-media-type=\"image\/jpg\" \/> <b>Figure 20<\/b>[\/caption]\r\n\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 7<\/h3>\r\nFind an angle of measure [latex]\\theta [\/latex] that is coterminal with an angle of measure [latex]-\\frac{17\\pi }{6}[\/latex] where [latex]0\\le \\theta &lt;2\\pi [\/latex].\r\n\r\n<a href=\"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/solutions-4\/\" target=\"_blank\" rel=\"noopener\">Solution<\/a>\r\n\r\n<\/div>","rendered":"<p>Converting between degrees and radians can make working with angles easier in some applications. For other applications, we may need another type of conversion. Negative angles and angles greater than a full revolution are more awkward to work with than those in the range of 0\u00b0 to 360\u00b0, or 0 to [latex]2\\pi[\/latex]. It would be convenient to replace those out-of-range angles with a corresponding angle within the range of a single revolution.<\/p>\n<p>It is possible for more than one angle to have the same terminal side. Look at Figure 16. The angle of 140\u00b0 is a <strong>positive angle<\/strong>, measured counterclockwise. The angle of \u2013220\u00b0 is a <strong>negative angle<\/strong>, measured clockwise. But both angles have the same terminal side. If two angles in standard position have the same terminal side, they are <strong>coterminal angles<\/strong>. Every angle greater than 360\u00b0 or less than 0\u00b0 is coterminal with an angle between 0\u00b0 and 360\u00b0, and it is often more convenient to find the coterminal angle within the range of 0\u00b0 to 360\u00b0 than to work with an angle that is outside that range.<\/p>\n<div style=\"width: 497px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234857\/CNX_Precalc_Figure_05_01_0202.jpg\" alt=\"A graph showing the equivalence between a 140 degree angle and a negative 220 degree angle.\" width=\"487\" height=\"383\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\"><b>Figure 16.<\/b> An angle of 140\u00b0 and an angle of \u2013220\u00b0 are coterminal angles.<\/p>\n<\/div>\n<p>This video shows examples of how to determine if two angles are coterminal.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Example:  Determine if Two Angles Are Coterminal\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/TuyF8fFg3B0?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<p>Any angle has infinitely many <strong>coterminal angles<\/strong> because each time we add 360\u00b0 to that angle\u2014or subtract 360\u00b0 from it\u2014the resulting value has a terminal side in the same location. For example, 100\u00b0 and 460\u00b0 are coterminal for this reason, as is \u2212260\u00b0. Recognizing that any angle has infinitely many coterminal angles explains the repetitive shape in the graphs of trigonometric functions.<\/p>\n<p>An angle\u2019s reference angle is the measure of the smallest, positive, acute angle [latex]t[\/latex] formed by the terminal side of the angle [latex]t[\/latex] and the horizontal axis. Thus positive reference angles have terminal sides that lie in the first quadrant and can be used as models for angles in other quadrants. See Figure 17\u00a0for examples of reference angles for angles in different quadrants.<span id=\"fs-id1165137542464\" data-type=\"media\" data-alt=\"Four side by side graphs. First graph shows an angle of t in quadrant 1 in it's normal position. Second graph shows an angle of t in quadrant 2 due to a rotation of pi minus t. Third graph shows an angle of t in quadrant 3 due to a rotation of t minus pi. Fourth graph shows an angle of t in quadrant 4 due to a rotation of two pi minus t.\"><br \/>\n<\/span><\/p>\n<div style=\"width: 985px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234900\/CNX_Precalc_Figure_05_01_0194.jpg\" alt=\"Four side by side graphs. First graph shows an angle of t in quadrant 1 in it's normal position. Second graph shows an angle of t in quadrant 2 due to a rotation of pi minus t. Third graph shows an angle of t in quadrant 3 due to a rotation of t minus pi. Fourth graph shows an angle of t in quadrant 4 due to a rotation of two pi minus t.\" width=\"975\" height=\"331\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\"><b>Figure 17<\/b><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"textbox\">\n<h3>A General Note: Coterminal and Reference Angles<\/h3>\n<p>Coterminal angles are two angles in standard position that have the same terminal side.<\/p>\n<p>An angle\u2019s <strong>reference angle<\/strong> is the size of the smallest acute angle, [latex]{t}^{\\prime }[\/latex], formed by the terminal side of the angle [latex]t[\/latex]\u00a0and the horizontal axis.<\/p>\n<\/div>\n<div class=\"textbox\">\n<h3>How To: Given an angle greater than 360\u00b0, find a coterminal angle between 0\u00b0 and 360\u00b0.<\/h3>\n<ol>\n<li>Subtract 360\u00b0 from the given angle.<\/li>\n<li>If the result is still greater than 360\u00b0, subtract 360\u00b0 again till the result is between 0\u00b0 and 360\u00b0.<\/li>\n<li>The resulting angle is coterminal with the original angle.<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 5: Finding an Angle Coterminal with an Angle of Measure Greater Than 360\u00b0<\/h3>\n<p>Find the least positive angle [latex]\\theta[\/latex] that is coterminal with an angle measuring 800\u00b0, where [latex]0^\\circ \\le \\theta <360^\\circ[\/latex].\n\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<p>An angle with measure 800\u00b0 is coterminal with an angle with measure 800 \u2212 360 = 440\u00b0, but 440\u00b0 is still greater than 360\u00b0, so we subtract 360\u00b0 again to find another coterminal angle: 440 \u2212 360 = 80\u00b0.<\/p>\n<p>The angle [latex]\\theta =80^\\circ[\/latex] is coterminal with 800\u00b0. To put it another way, 800\u00b0 equals 80\u00b0 plus two full rotations, as shown in Figure 18.<\/p>\n<div style=\"width: 497px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234903\/CNX_Precalc_Figure_05_01_0212.jpg\" alt=\"A graph showing the equivalence between an 80 degree angle and an 800 degree angle.\" width=\"487\" height=\"383\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\"><b>Figure 18<\/b><\/p>\n<\/div>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 5<\/h3>\n<p>Find an angle [latex]\\alpha[\/latex] that is coterminal with an angle measuring 870\u00b0, where [latex]0^\\circ \\le \\alpha <360^\\circ[\/latex].\n\n<a href=\"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/solutions-4\/\" target=\"_blank\" rel=\"noopener\">Solution<\/a><\/p>\n<\/div>\n<div class=\"textbox\">\n<h3>How To: Given an angle with measure less than 0\u00b0, find a coterminal angle having a measure between 0\u00b0 and 360\u00b0.<\/h3>\n<ol>\n<li>Add 360\u00b0 to the given angle.<\/li>\n<li>If the result is still less than 0\u00b0, add 360\u00b0 again until the result is between 0\u00b0 and 360\u00b0.<\/li>\n<li>The resulting angle is coterminal with the original angle.<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 6: Finding an Angle Coterminal with an Angle Measuring Less Than 0\u00b0<\/h3>\n<p>Show the angle with measure \u221245\u00b0 on a circle and find a positive coterminal angle [latex]\\alpha[\/latex] such that 0\u00b0 \u2264 <em data-effect=\"italics\">\u03b1<\/em> &lt; 360\u00b0.<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<p>Since 45\u00b0 is half of 90\u00b0, we can start at the positive horizontal axis and measure clockwise half of a 90\u00b0 angle.<\/p>\n<p>Because we can find coterminal angles by adding or subtracting a full rotation of 360\u00b0, we can find a positive coterminal angle here by adding 360\u00b0:<\/p>\n<div style=\"text-align: center;\">[latex]-45^\\circ +360^\\circ =315^\\circ[\/latex]<\/div>\n<p>We can then show the angle on a circle, as in Figure 19.<span data-type=\"media\" data-alt=\"A graph showing the equivalence of a 315 degree angle and a negative 45 degree angle.\"><br \/>\n<\/span><\/p>\n<div style=\"width: 497px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234905\/CNX_Precalc_Figure_05_01_0222.jpg\" alt=\"A graph showing the equivalence of a 315 degree angle and a negative 45 degree angle.\" width=\"487\" height=\"383\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\"><strong>Figure 19<\/strong><\/p>\n<\/div>\n<\/div>\n<div>\n<p>Watch this video for another example of how to determine positive and negative coterminal angles.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Example:  Determine Positive and Negative Coterminal Angles\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/m7jTGVVzb0s?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 6<\/h3>\n<p>Find an angle [latex]\\beta[\/latex] that is coterminal with an angle measuring \u2212300\u00b0 such that [latex]0^\\circ \\le \\beta <360^\\circ[\/latex].\n\n<a href=\"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/solutions-4\/\" target=\"_blank\" rel=\"noopener\">Solution<\/a><\/p>\n<\/div>\n<h2 data-type=\"title\">Finding Coterminal Angles Measured in Radians<\/h2>\n<p>We can find <strong>coterminal angles<\/strong> measured in radians in much the same way as we have found them using degrees. In both cases, we find coterminal angles by adding or subtracting one or more full rotations.<\/p>\n<div>\n<p><strong>Given an angle greater than<\/strong> [latex]2\\pi[\/latex], <strong>find a coterminal angle between 0 and<\/strong> [latex]2\\pi[\/latex].<\/p>\n<ol>\n<li>Subtract [latex]2\\pi[\/latex] from the given angle.<\/li>\n<li>If the result is still greater than [latex]2\\pi[\/latex], subtract [latex]2\\pi[\/latex] again until the result is between [latex]0[\/latex] and [latex]2\\pi[\/latex].<\/li>\n<li>The resulting angle is coterminal with the original angle.<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 7: Finding Coterminal Angles Using Radians<\/h3>\n<p>Find an angle [latex]\\beta[\/latex] that is coterminal with [latex]\\frac{19\\pi }{4}[\/latex], where [latex]0\\le \\beta <2\\pi[\/latex].\n\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<p>When working in degrees, we found coterminal angles by adding or subtracting 360 degrees, a full rotation. Likewise, in radians, we can find coterminal angles by adding or subtracting full rotations of [latex]2\\pi[\/latex] radians:<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}\\frac{19\\pi }{4}-2\\pi =\\frac{19\\pi }{4}-\\frac{8\\pi }{4}\\hfill \\\\ =\\frac{11\\pi }{4}\\hfill \\end{array}[\/latex]<\/div>\n<p>The angle [latex]\\frac{11\\pi }{4}[\/latex] is coterminal, but not less than [latex]2\\pi[\/latex], so we subtract another rotation:<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}\\frac{11\\pi }{4}-2\\pi =\\frac{11\\pi }{4}-\\frac{8\\pi }{4}\\hfill \\\\ =\\frac{3\\pi }{4}\\hfill \\end{array}[\/latex]<\/div>\n<p>The angle [latex]\\frac{3\\pi }{4}[\/latex] is coterminal with [latex]\\frac{19\\pi }{4}[\/latex], as shown in Figure 20.<span data-type=\"media\" data-alt=\"A graph showing a circle and the equivalence between angles of 3pi\/4 radians and 19pi\/4 radians.\"><br \/>\n<\/span><\/p>\n<div style=\"width: 497px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14234908\/CNX_Precalc_Figure_05_01_0232.jpg\" alt=\"A graph showing a circle and the equivalence between angles of 3pi\/4 radians and 19pi\/4 radians.\" width=\"487\" height=\"383\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\"><b>Figure 20<\/b><\/p>\n<\/div>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 7<\/h3>\n<p>Find an angle of measure [latex]\\theta[\/latex] that is coterminal with an angle of measure [latex]-\\frac{17\\pi }{6}[\/latex] where [latex]0\\le \\theta <2\\pi[\/latex].\n\n<a href=\"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/solutions-4\/\" target=\"_blank\" rel=\"noopener\">Solution<\/a><\/p>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-13747\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: OpenStax College. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><div class=\"license-attribution-dropdown-subheading\">All rights reserved content<\/div><ul class=\"citation-list\"><li>Example: Determine if Two Angles Are Coterminal. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/www.youtube.com\/watch?v=TuyF8fFg3B0\">https:\/\/www.youtube.com\/watch?v=TuyF8fFg3B0<\/a>. <strong>License<\/strong>: <em>All Rights Reserved<\/em>. <strong>License Terms<\/strong>: Standard YouTube License<\/li><li>Example: Determine Positive and Negative Coterminal Angles. <strong>Authored by<\/strong>: Mathispower4u. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/www.youtube.com\/watch?v=m7jTGVVzb0s\">https:\/\/www.youtube.com\/watch?v=m7jTGVVzb0s<\/a>. <strong>License<\/strong>: <em>All Rights Reserved<\/em>. <strong>License Terms<\/strong>: Standard YouTube License<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":23485,"menu_order":4,"template":"","meta":{"_candela_citation":"[{\"type\":\"copyrighted_video\",\"description\":\"Example: Determine if Two Angles Are Coterminal\",\"author\":\"\",\"organization\":\"\",\"url\":\"https:\/\/www.youtube.com\/watch?v=TuyF8fFg3B0\",\"project\":\"\",\"license\":\"arr\",\"license_terms\":\"Standard YouTube License\"},{\"type\":\"copyrighted_video\",\"description\":\"Example: Determine Positive and Negative Coterminal Angles\",\"author\":\"Mathispower4u\",\"organization\":\"\",\"url\":\"https:\/\/www.youtube.com\/watch?v=m7jTGVVzb0s\",\"project\":\"\",\"license\":\"arr\",\"license_terms\":\"Standard YouTube License\"},{\"type\":\"cc-attribution\",\"description\":\"Precalculus\",\"author\":\"OpenStax College\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-13747","chapter","type-chapter","status-publish","hentry"],"part":13723,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/13747","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/users\/23485"}],"version-history":[{"count":3,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/13747\/revisions"}],"predecessor-version":[{"id":16442,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/13747\/revisions\/16442"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/parts\/13723"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/13747\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/media?parent=13747"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapter-type?post=13747"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/contributor?post=13747"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/license?post=13747"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}