{"id":13857,"date":"2018-06-14T23:52:45","date_gmt":"2018-06-14T23:52:45","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/ccbcmd-math\/chapter\/solutions-15\/"},"modified":"2021-11-22T22:01:00","modified_gmt":"2021-11-22T22:01:00","slug":"solutions-right-triangle-trig","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/solutions-right-triangle-trig\/","title":{"raw":"Solutions: Right Triangle Trigonometry","rendered":"Solutions: Right Triangle Trigonometry"},"content":{"raw":"<h2>Solutions to Try Its<\/h2>\r\n1.\u00a0[latex]\\frac{7}{25}[\/latex]\r\n\r\n2.\u00a0[latex]\\begin{array}{l}sin t=\\frac{33}{65},\\cos t=\\frac{56}{65},tan t=\\frac{33}{56},\\hfill \\\\ \\sec t=\\frac{65}{56},\\csc t=\\frac{65}{33},\\cot t=\\frac{56}{33}\\hfill \\end{array}[\/latex]\r\n\r\n3.\u00a0[latex]\\sin \\left(\\frac{\\pi }{4}\\right)=\\frac{\\sqrt{2}}{2},\\cos \\left(\\frac{\\pi }{4}\\right)=\\frac{\\sqrt{2}}{2},\\tan \\left(\\frac{\\pi }{4}\\right)=1[\/latex],\r\n[latex]\\sec \\left(\\frac{\\pi }{4}\\right)=\\sqrt{2},csc\\left(\\frac{\\pi }{4}\\right)=\\sqrt{2},\\cot \\left(\\frac{\\pi }{4}\\right)=1[\/latex]\r\n\r\n4. 2\r\n\r\n5.\u00a0[latex]\\text{adjacent}=10[\/latex]; [latex]\\text{opposite}=10\\sqrt{3}[\/latex] ; missing angle is [latex]\\frac{\\pi }{6}[\/latex]\r\n\r\n6.\u00a0About 52 ft\r\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\r\n1.\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14235244\/CNX_Precalc_Figure_05_04_2022.jpg\" alt=\"A right triangle with side opposite, adjacent, and hypotenuse labeled.\" \/>\r\n\r\n3. The tangent of an angle is the ratio of the opposite side to the adjacent side.\r\n\r\n5.\u00a0For example, the sine of an angle is equal to the cosine of its complement; the cosine of an angle is equal to the sine of its complement.\r\n\r\n7.\u00a0[latex]\\frac{\\pi }{6}[\/latex]\r\n\r\n9.\u00a0[latex]\\frac{\\pi }{4}[\/latex]\r\n\r\n11.\u00a0[latex]b=\\frac{20\\sqrt{3}}{3},c=\\frac{40\\sqrt{3}}{3}[\/latex]\r\n\r\n13.\u00a0[latex]a=10,000,c=10,000.5[\/latex]\r\n\r\n15.\u00a0[latex]b=\\frac{5\\sqrt{3}}{3},c=\\frac{10\\sqrt{3}}{3}[\/latex]\r\n\r\n17.\u00a0[latex]\\frac{5\\sqrt{29}}{29}[\/latex]\r\n\r\n19.\u00a0[latex]\\frac{5}{2}[\/latex]\r\n\r\n21.\u00a0[latex]\\frac{\\sqrt{29}}{2}[\/latex]\r\n\r\n23.\u00a0[latex]\\frac{5\\sqrt{41}}{41}[\/latex]\r\n\r\n25.\u00a0[latex]\\frac{5}{4}[\/latex]\r\n\r\n27.\u00a0[latex]\\frac{\\sqrt{41}}{4}[\/latex]\r\n\r\n29.\u00a0[latex]c=14, b=7\\sqrt{3}[\/latex]\r\n\r\n31.\u00a0[latex]a=15, b=15[\/latex]\r\n\r\n33.\u00a0[latex]b=9.9970, c=12.2041[\/latex]\r\n\r\n35.\u00a0[latex]a=2.0838, b=11.8177[\/latex]\r\n\r\n37.\u00a0[latex]a=55.9808,c=57.9555[\/latex]\r\n\r\n39.\u00a0[latex]a=46.6790,b=17.9184[\/latex]\r\n\r\n41.\u00a0[latex]a=16.4662,c=16.8341[\/latex]\r\n\r\n43.\u00a0188.3159\r\n\r\n45.\u00a0200.6737\r\n\r\n47.\u00a0498.3471 ft\r\n\r\n49.\u00a01060.09 ft\r\n\r\n51.\u00a027.372 ft\r\n\r\n53.\u00a022.6506 ft\r\n\r\n55.\u00a0368.7633 ft\r\n\r\n56.\u00a0[latex]{7.2}^{\\circ }[\/latex]\r\n\r\n58.\u00a0[latex]{5.7}^{\\circ }[\/latex]\r\n\r\n60.\u00a0[latex]{82.4}^{\\circ }[\/latex]\r\n\r\n62.\u00a0[latex]{31.0}^{\\circ }[\/latex]\r\n\r\n64.\u00a0[latex]{88.7}^{\\circ }[\/latex]\r\n\r\n66.\u00a0[latex]{59.0}^{\\circ }[\/latex]\r\n\r\n68.\u00a0[latex]{36.9}^{\\circ }[\/latex]","rendered":"<h2>Solutions to Try Its<\/h2>\n<p>1.\u00a0[latex]\\frac{7}{25}[\/latex]<\/p>\n<p>2.\u00a0[latex]\\begin{array}{l}sin t=\\frac{33}{65},\\cos t=\\frac{56}{65},tan t=\\frac{33}{56},\\hfill \\\\ \\sec t=\\frac{65}{56},\\csc t=\\frac{65}{33},\\cot t=\\frac{56}{33}\\hfill \\end{array}[\/latex]<\/p>\n<p>3.\u00a0[latex]\\sin \\left(\\frac{\\pi }{4}\\right)=\\frac{\\sqrt{2}}{2},\\cos \\left(\\frac{\\pi }{4}\\right)=\\frac{\\sqrt{2}}{2},\\tan \\left(\\frac{\\pi }{4}\\right)=1[\/latex],<br \/>\n[latex]\\sec \\left(\\frac{\\pi }{4}\\right)=\\sqrt{2},csc\\left(\\frac{\\pi }{4}\\right)=\\sqrt{2},\\cot \\left(\\frac{\\pi }{4}\\right)=1[\/latex]<\/p>\n<p>4. 2<\/p>\n<p>5.\u00a0[latex]\\text{adjacent}=10[\/latex]; [latex]\\text{opposite}=10\\sqrt{3}[\/latex] ; missing angle is [latex]\\frac{\\pi }{6}[\/latex]<\/p>\n<p>6.\u00a0About 52 ft<\/p>\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\n<p>1.<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3360\/2018\/06\/14235244\/CNX_Precalc_Figure_05_04_2022.jpg\" alt=\"A right triangle with side opposite, adjacent, and hypotenuse labeled.\" \/><\/p>\n<p>3. The tangent of an angle is the ratio of the opposite side to the adjacent side.<\/p>\n<p>5.\u00a0For example, the sine of an angle is equal to the cosine of its complement; the cosine of an angle is equal to the sine of its complement.<\/p>\n<p>7.\u00a0[latex]\\frac{\\pi }{6}[\/latex]<\/p>\n<p>9.\u00a0[latex]\\frac{\\pi }{4}[\/latex]<\/p>\n<p>11.\u00a0[latex]b=\\frac{20\\sqrt{3}}{3},c=\\frac{40\\sqrt{3}}{3}[\/latex]<\/p>\n<p>13.\u00a0[latex]a=10,000,c=10,000.5[\/latex]<\/p>\n<p>15.\u00a0[latex]b=\\frac{5\\sqrt{3}}{3},c=\\frac{10\\sqrt{3}}{3}[\/latex]<\/p>\n<p>17.\u00a0[latex]\\frac{5\\sqrt{29}}{29}[\/latex]<\/p>\n<p>19.\u00a0[latex]\\frac{5}{2}[\/latex]<\/p>\n<p>21.\u00a0[latex]\\frac{\\sqrt{29}}{2}[\/latex]<\/p>\n<p>23.\u00a0[latex]\\frac{5\\sqrt{41}}{41}[\/latex]<\/p>\n<p>25.\u00a0[latex]\\frac{5}{4}[\/latex]<\/p>\n<p>27.\u00a0[latex]\\frac{\\sqrt{41}}{4}[\/latex]<\/p>\n<p>29.\u00a0[latex]c=14, b=7\\sqrt{3}[\/latex]<\/p>\n<p>31.\u00a0[latex]a=15, b=15[\/latex]<\/p>\n<p>33.\u00a0[latex]b=9.9970, c=12.2041[\/latex]<\/p>\n<p>35.\u00a0[latex]a=2.0838, b=11.8177[\/latex]<\/p>\n<p>37.\u00a0[latex]a=55.9808,c=57.9555[\/latex]<\/p>\n<p>39.\u00a0[latex]a=46.6790,b=17.9184[\/latex]<\/p>\n<p>41.\u00a0[latex]a=16.4662,c=16.8341[\/latex]<\/p>\n<p>43.\u00a0188.3159<\/p>\n<p>45.\u00a0200.6737<\/p>\n<p>47.\u00a0498.3471 ft<\/p>\n<p>49.\u00a01060.09 ft<\/p>\n<p>51.\u00a027.372 ft<\/p>\n<p>53.\u00a022.6506 ft<\/p>\n<p>55.\u00a0368.7633 ft<\/p>\n<p>56.\u00a0[latex]{7.2}^{\\circ }[\/latex]<\/p>\n<p>58.\u00a0[latex]{5.7}^{\\circ }[\/latex]<\/p>\n<p>60.\u00a0[latex]{82.4}^{\\circ }[\/latex]<\/p>\n<p>62.\u00a0[latex]{31.0}^{\\circ }[\/latex]<\/p>\n<p>64.\u00a0[latex]{88.7}^{\\circ }[\/latex]<\/p>\n<p>66.\u00a0[latex]{59.0}^{\\circ }[\/latex]<\/p>\n<p>68.\u00a0[latex]{36.9}^{\\circ }[\/latex]<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-13857\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: OpenStax College. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":23485,"menu_order":7,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"Precalculus\",\"author\":\"OpenStax 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