{"id":15280,"date":"2021-10-11T22:48:51","date_gmt":"2021-10-11T22:48:51","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/problem-set-30-systems-of-linear-equations-three-variables\/"},"modified":"2022-01-09T19:52:38","modified_gmt":"2022-01-09T19:52:38","slug":"problem-set-systems-of-linear-equations-three-variables","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/problem-set-systems-of-linear-equations-three-variables\/","title":{"raw":"Problem Set: Systems of Linear Equations in Three Variables","rendered":"Problem Set: Systems of Linear Equations in Three Variables"},"content":{"raw":"1. Can a linear system of three equations have exactly two solutions? Explain why or why not\r\n\r\n2.\u00a0If a given ordered triple solves the system of equations, is that solution unique? If so, explain why. If not, give an example where it is not unique.\r\n\r\n3. If a given ordered triple does not solve the system of equations, is there no solution? If so, explain why. If not, give an example.\r\n\r\n4. Using the method of addition, is there only one way to solve the system?\r\n\r\n5. Can you explain whether there can be only one method to solve a linear system of equations? If yes, give an example of such a system of equations. If not, explain why not.\r\n\r\nFor the following exercises, determine whether the ordered triple given is the solution to the system of equations.\r\n\r\n6. [latex]\\begin{align}2x - 6y+6z&amp;=-12\\\\x+4y+5z&amp;=-1 \\\\ -x+2y+3z&amp;=-1 \\end{align}[\/latex] and [latex]\\left(0,1,-1\\right)[\/latex]\r\n\r\n7. [latex]\\begin{align}6x-y+3z&amp;=6 \\\\ 3x+5y+2z&amp;=0 \\\\ x+y&amp;=0 \\end{align}[\/latex] and [latex]\\left(3,-3,-5\\right)[\/latex]\r\n\r\n8.\u00a0[latex]\\begin{align}6x - 7y+z&amp;=2 \\\\ -x-y+3z&amp;=4 \\\\ 2x+y-z&amp;=1 \\end{align}[\/latex] and [latex]\\left(4,2,-6\\right)[\/latex]\r\n\r\n9. [latex]\\begin{align}x-y&amp;=0 \\\\ x-z&amp;=5 \\\\ x-y+z&amp;=-1 \\end{align}[\/latex] and [latex]\\left(4,4,-1\\right)[\/latex]\r\n\r\n10. [latex]\\begin{align} -x-y+2z&amp;=3 \\\\ 5x+8y - 3z&amp;=4 \\\\ -x+3y - 5z&amp;=-5 \\end{align}[\/latex] and [latex]\\left(4,1,-7\\right)[\/latex]\r\n\r\nFor the following exercises, solve each system by substitution.\r\n\r\n11. [latex]\\begin{align}3x - 4y+2z&amp;=-15 \\\\ 2x+4y+z&amp;=16 \\\\ 2x+3y+5z&amp;=20 \\end{align}[\/latex]\r\n\r\n12.\u00a0[latex]\\begin{align}5x - 2y+3z&amp;=20 \\\\ 2x - 4y - 3z&amp;=-9 \\\\ x+6y - 8z&amp;=21 \\end{align}[\/latex]\r\n\r\n13. [latex]\\begin{align}5x+2y+4z&amp;=9 \\\\ -3x+2y+z&amp;=10 \\\\ 4x - 3y+5z&amp;=-3 \\end{align}[\/latex]\r\n\r\n14.\u00a0[latex]\\begin{align}4x - 3y+5z&amp;=31 \\\\ -x+2y+4z&amp;=20 \\\\ x+5y - 2z&amp;=-29 \\end{align}[\/latex]\r\n\r\n15. [latex]\\begin{align}5x - 2y+3z&amp;=4 \\\\ -4x+6y - 7z&amp;=-1 \\\\ 3x+2y-z&amp;=4\\end{align}[\/latex]\r\n\r\n16.\u00a0[latex]\\begin{align} 4x+6y+9z&amp;=0 \\\\ -5x+2y - 6z&amp;=3 \\\\ 7x - 4y+3z&amp;=-3 \\end{align}[\/latex]\r\n\r\nFor the following exercises, solve each system by Gaussian elimination.\r\n\r\n17. [latex]\\begin{align}2x-y+3z&amp;=17 \\\\ -5x+4y - 2z&amp;=-46 \\\\ 2y+5z&amp;=-7 \\end{align}[\/latex]\r\n\r\n18.\u00a0[latex]\\begin{align}5x - 6y+3z&amp;=50 \\\\ -x+4y&amp;=10 \\\\ 2x-z&amp;=10 \\end{align}[\/latex]\r\n\r\n19. [latex]\\begin{align}2x+3y - 6z&amp;=1 \\\\ -4x - 6y+12z&amp;=-2 \\\\ x+2y+5z&amp;=10 \\end{align}[\/latex]\r\n\r\n20.\u00a0[latex]\\begin{align}4x+6y - 2z&amp;=8 \\\\ 6x+9y - 3z&amp;=12 \\\\ -2x - 3y+z&amp;=-4 \\end{align}[\/latex]\r\n\r\n21. [latex]\\begin{align}2x+3y - 4z&amp;=5 \\\\ -3x+2y+z&amp;=11 \\\\ -x+5y+3z&amp;=4 \\end{align}[\/latex]\r\n\r\n22.\u00a0[latex]\\begin{align}10x+2y - 14z&amp;=8 \\\\ -x-2y - 4z&amp;=-1 \\\\ -12x - 6y+6z&amp;=-12 \\end{align}[\/latex]\r\n\r\n23. [latex]\\begin{align}x+y+z&amp;=14 \\\\ 2y+3z&amp;=-14 \\\\ -16y - 24z&amp;=-112 \\end{align}[\/latex]\r\n\r\n24.\u00a0[latex]\\begin{align}5x - 3y+4z&amp;=-1 \\\\ -4x+2y - 3z&amp;=0 \\\\ -x+5y+7z&amp;=-11 \\end{align}[\/latex]\r\n\r\n25. [latex]\\begin{align}x+y+z&amp;=0 \\\\ 2x-y+3z&amp;=0 \\\\ x-z&amp;=0 \\end{align}[\/latex]\r\n\r\n26.\u00a0[latex]\\begin{align}3x+2y - 5z&amp;=6\\\\ 5x - 4y+3z&amp;=-12\\\\ 4x+5y - 2z&amp;=15\\end{align}[\/latex]\r\n\r\n27. [latex]\\begin{align}x+y+z&amp;=0\\\\ 2x-y+3z&amp;=0 \\\\ x-z&amp;=1 \\end{align}[\/latex]\r\n\r\n28.\u00a0[latex]\\begin{align} 3x-\\frac{1}{2}y-z&amp;=-\\frac{1}{2} \\\\ 4x+z&amp;=3 \\\\ -x+\\frac{3}{2}y&amp;=\\frac{5}{2} \\end{align}[\/latex]\r\n\r\n29. [latex]\\begin{align}6x - 5y+6z&amp;=38 \\\\ \\frac{1}{5}x-\\frac{1}{2}y+\\frac{3}{5}z&amp;=1 \\\\ -4x-\\frac{3}{2}y-z&amp;=-74 \\end{align}[\/latex]\r\n\r\n30.\u00a0[latex]\\begin{align}\\frac{1}{2}x-\\frac{1}{5}y+\\frac{2}{5}z&amp;=-\\frac{13}{10} \\\\ \\frac{1}{4}x-\\frac{2}{5}y-\\frac{1}{5}z&amp;=-\\frac{7}{20} \\\\ -\\frac{1}{2}x-\\frac{3}{4}y-\\frac{1}{2}z&amp;=-\\frac{5}{4} \\end{align}[\/latex]\r\n\r\n31. [latex]\\begin{align} -\\frac{1}{3}x-\\frac{1}{2}y-\\frac{1}{4}z&amp;=\\frac{3}{4} \\\\ -\\frac{1}{2}x-\\frac{1}{4}y-\\frac{1}{2}z&amp;=2 \\\\ -\\frac{1}{4}x-\\frac{3}{4}y-\\frac{1}{2}z&amp;=-\\frac{1}{2} \\end{align}[\/latex]\r\n\r\n32.\u00a0[latex]\\begin{align}\\frac{1}{2}x-\\frac{1}{4}y+\\frac{3}{4}z&amp;=0\\\\ \\frac{1}{4}x-\\frac{1}{10}y+\\frac{2}{5}z&amp;=-2\\\\ \\frac{1}{8}x+\\frac{1}{5}y-\\frac{1}{8}z&amp;=2\\end{align}[\/latex]\r\n\r\n33. [latex]\\begin{align}\\frac{4}{5}x-\\frac{7}{8}y+\\frac{1}{2}z&amp;=1 \\\\ -\\frac{4}{5}x-\\frac{3}{4}y+\\frac{1}{3}z&amp;=-8 \\\\ -\\frac{2}{5}x-\\frac{7}{8}y+\\frac{1}{2}z&amp;=-5 \\end{align}[\/latex]\r\n\r\n34.\u00a0[latex]\\begin{align} -\\frac{1}{3}x-\\frac{1}{8}y+\\frac{1}{6}z&amp;=-\\frac{4}{3} \\\\ -\\frac{2}{3}x-\\frac{7}{8}y+\\frac{1}{3}z&amp;=-\\frac{23}{3} \\\\ -\\frac{1}{3}x-\\frac{5}{8}y+\\frac{5}{6}z&amp;=0 \\end{align}[\/latex]\r\n\r\n35. [latex]\\begin{align} -\\frac{1}{4}x-\\frac{5}{4}y+\\frac{5}{2}z&amp;=-5 \\\\ -\\frac{1}{2}x-\\frac{5}{3}y+\\frac{5}{4}z&amp;=\\frac{55}{12} \\\\ -\\frac{1}{3}x-\\frac{1}{3}y+\\frac{1}{3}z&amp;=\\frac{5}{3} \\end{align}[\/latex]\r\n\r\n36.\u00a0[latex]\\begin{align}\\frac{1}{40}x+\\frac{1}{60}y+\\frac{1}{80}z&amp;=\\frac{1}{100} \\\\ -\\frac{1}{2}x-\\frac{1}{3}y-\\frac{1}{4}z&amp;=-\\frac{1}{5} \\\\ \\frac{3}{8}x+\\frac{3}{12}y+\\frac{3}{16}z&amp;=\\frac{3}{20} \\end{align}[\/latex]\r\n\r\n37. [latex]\\begin{align}0.1x - 0.2y+0.3z&amp;=2\\\\ 0.5x - 0.1y+0.4z&amp;=8\\\\ 0.7x - 0.2y+0.3z&amp;=8\\end{align}[\/latex]\r\n\r\n38.\u00a0[latex]\\begin{align}0.2x+0.1y - 0.3z&amp;=0.2\\\\ 0.8x+0.4y - 1.2z&amp;=0.1\\\\ 1.6x+0.8y - 2.4z&amp;=0.2\\end{align}[\/latex]\r\n\r\n39. [latex]\\begin{align}1.1x+0.7y - 3.1z&amp;=-1.79\\\\ 2.1x+0.5y - 1.6z&amp;=-0.13\\\\ 0.5x+0.4y - 0.5z&amp;=-0.07\\end{align}[\/latex]\r\n\r\n40.\u00a0[latex]\\begin{align}0.5x - 0.5y+0.5z&amp;=10\\\\ 0.2x - 0.2y+0.2z&amp;=4\\\\ 0.1x - 0.1y+0.1z&amp;=2\\end{align}[\/latex]\r\n\r\n41. [latex]\\begin{align}0.1x+0.2y+0.3z&amp;=0.37\\\\ 0.1x - 0.2y - 0.3z&amp;=-0.27\\\\ 0.5x - 0.1y - 0.3z&amp;=-0.03\\end{align}[\/latex]\r\n\r\n42.\u00a0[latex]\\begin{align}0.5x - 0.5y - 0.3z&amp;=0.13\\\\ 0.4x - 0.1y - 0.3z&amp;=0.11\\\\ 0.2x - 0.8y - 0.9z&amp;=-0.32\\end{align}[\/latex]\r\n\r\n43. [latex]\\begin{align}0.5x+0.2y - 0.3z&amp;=1\\\\ 0.4x - 0.6y+0.7z&amp;=0.8\\\\ 0.3x - 0.1y - 0.9z&amp;=0.6\\end{align}[\/latex]\r\n\r\n44.\u00a0[latex]\\begin{align}0.3x+0.3y+0.5z&amp;=0.6\\\\ 0.4x+0.4y+0.4z&amp;=1.8\\\\ 0.4x+0.2y+0.1z&amp;=1.6\\end{align}[\/latex]\r\n\r\n45. [latex]\\begin{align}0.8x+0.8y+0.8z&amp;=2.4\\\\ 0.3x - 0.5y+0.2z&amp;=0\\\\ 0.1x+0.2y+0.3z&amp;=0.6\\end{align}[\/latex]\r\n\r\nFor the following exercises, solve the system for [latex]x,y[\/latex], and [latex]z[\/latex].\r\n\r\n46. [latex]\\begin{align}x+y+z&amp;=3 \\\\ \\frac{x - 1}{2}+\\frac{y - 3}{2}+\\frac{z+1}{2}&amp;=0 \\\\ \\frac{x - 2}{3}+\\frac{y+4}{3}+\\frac{z - 3}{3}&amp;=\\frac{2}{3} \\end{align}[\/latex]\r\n\r\n47. [latex]\\begin{align}5x - 3y-\\frac{z+1}{2}&amp;=\\frac{1}{2} \\\\ 6x+\\frac{y - 9}{2}+2z&amp;=-3 \\\\ \\frac{x+8}{2}-4y+z&amp;=4 \\end{align}[\/latex]\r\n\r\n48.\u00a0[latex]\\begin{align}\\frac{x+4}{7}-\\frac{y - 1}{6}+\\frac{z+2}{3}&amp;=1\\\\ \\frac{x - 2}{4}+\\frac{y+1}{8}-\\frac{z+8}{12}&amp;=0\\\\ \\frac{x+6}{3}-\\frac{y+2}{3}+\\frac{z+4}{2}7&amp;=3\\end{align}[\/latex]\r\n\r\n49. [latex]\\begin{align}\\frac{x - 3}{6}+\\frac{y+2}{2}-\\frac{z - 3}{3}&amp;=2\\\\ \\frac{x+2}{4}+\\frac{y - 5}{2}+\\frac{z+4}{2}&amp;=1\\\\ \\frac{x+6}{2}-\\frac{y - 3}{2}+z+1&amp;=9\\end{align}[\/latex]\r\n\r\n50.\u00a0[latex]\\begin{align}\\frac{x - 1}{3}+\\frac{y+3}{4}+\\frac{z+2}{6}&amp;=1 \\\\ 4x+3y - 2z&amp;=11 \\\\ 0.02x+0.015y - 0.01z&amp;=0.065 \\end{align}[\/latex]","rendered":"<p>1. Can a linear system of three equations have exactly two solutions? Explain why or why not<\/p>\n<p>2.\u00a0If a given ordered triple solves the system of equations, is that solution unique? If so, explain why. If not, give an example where it is not unique.<\/p>\n<p>3. If a given ordered triple does not solve the system of equations, is there no solution? If so, explain why. If not, give an example.<\/p>\n<p>4. Using the method of addition, is there only one way to solve the system?<\/p>\n<p>5. Can you explain whether there can be only one method to solve a linear system of equations? If yes, give an example of such a system of equations. If not, explain why not.<\/p>\n<p>For the following exercises, determine whether the ordered triple given is the solution to the system of equations.<\/p>\n<p>6. [latex]\\begin{align}2x - 6y+6z&=-12\\\\x+4y+5z&=-1 \\\\ -x+2y+3z&=-1 \\end{align}[\/latex] and [latex]\\left(0,1,-1\\right)[\/latex]<\/p>\n<p>7. [latex]\\begin{align}6x-y+3z&=6 \\\\ 3x+5y+2z&=0 \\\\ x+y&=0 \\end{align}[\/latex] and [latex]\\left(3,-3,-5\\right)[\/latex]<\/p>\n<p>8.\u00a0[latex]\\begin{align}6x - 7y+z&=2 \\\\ -x-y+3z&=4 \\\\ 2x+y-z&=1 \\end{align}[\/latex] and [latex]\\left(4,2,-6\\right)[\/latex]<\/p>\n<p>9. [latex]\\begin{align}x-y&=0 \\\\ x-z&=5 \\\\ x-y+z&=-1 \\end{align}[\/latex] and [latex]\\left(4,4,-1\\right)[\/latex]<\/p>\n<p>10. [latex]\\begin{align} -x-y+2z&=3 \\\\ 5x+8y - 3z&=4 \\\\ -x+3y - 5z&=-5 \\end{align}[\/latex] and [latex]\\left(4,1,-7\\right)[\/latex]<\/p>\n<p>For the following exercises, solve each system by substitution.<\/p>\n<p>11. [latex]\\begin{align}3x - 4y+2z&=-15 \\\\ 2x+4y+z&=16 \\\\ 2x+3y+5z&=20 \\end{align}[\/latex]<\/p>\n<p>12.\u00a0[latex]\\begin{align}5x - 2y+3z&=20 \\\\ 2x - 4y - 3z&=-9 \\\\ x+6y - 8z&=21 \\end{align}[\/latex]<\/p>\n<p>13. [latex]\\begin{align}5x+2y+4z&=9 \\\\ -3x+2y+z&=10 \\\\ 4x - 3y+5z&=-3 \\end{align}[\/latex]<\/p>\n<p>14.\u00a0[latex]\\begin{align}4x - 3y+5z&=31 \\\\ -x+2y+4z&=20 \\\\ x+5y - 2z&=-29 \\end{align}[\/latex]<\/p>\n<p>15. [latex]\\begin{align}5x - 2y+3z&=4 \\\\ -4x+6y - 7z&=-1 \\\\ 3x+2y-z&=4\\end{align}[\/latex]<\/p>\n<p>16.\u00a0[latex]\\begin{align} 4x+6y+9z&=0 \\\\ -5x+2y - 6z&=3 \\\\ 7x - 4y+3z&=-3 \\end{align}[\/latex]<\/p>\n<p>For the following exercises, solve each system by Gaussian elimination.<\/p>\n<p>17. [latex]\\begin{align}2x-y+3z&=17 \\\\ -5x+4y - 2z&=-46 \\\\ 2y+5z&=-7 \\end{align}[\/latex]<\/p>\n<p>18.\u00a0[latex]\\begin{align}5x - 6y+3z&=50 \\\\ -x+4y&=10 \\\\ 2x-z&=10 \\end{align}[\/latex]<\/p>\n<p>19. [latex]\\begin{align}2x+3y - 6z&=1 \\\\ -4x - 6y+12z&=-2 \\\\ x+2y+5z&=10 \\end{align}[\/latex]<\/p>\n<p>20.\u00a0[latex]\\begin{align}4x+6y - 2z&=8 \\\\ 6x+9y - 3z&=12 \\\\ -2x - 3y+z&=-4 \\end{align}[\/latex]<\/p>\n<p>21. [latex]\\begin{align}2x+3y - 4z&=5 \\\\ -3x+2y+z&=11 \\\\ -x+5y+3z&=4 \\end{align}[\/latex]<\/p>\n<p>22.\u00a0[latex]\\begin{align}10x+2y - 14z&=8 \\\\ -x-2y - 4z&=-1 \\\\ -12x - 6y+6z&=-12 \\end{align}[\/latex]<\/p>\n<p>23. [latex]\\begin{align}x+y+z&=14 \\\\ 2y+3z&=-14 \\\\ -16y - 24z&=-112 \\end{align}[\/latex]<\/p>\n<p>24.\u00a0[latex]\\begin{align}5x - 3y+4z&=-1 \\\\ -4x+2y - 3z&=0 \\\\ -x+5y+7z&=-11 \\end{align}[\/latex]<\/p>\n<p>25. [latex]\\begin{align}x+y+z&=0 \\\\ 2x-y+3z&=0 \\\\ x-z&=0 \\end{align}[\/latex]<\/p>\n<p>26.\u00a0[latex]\\begin{align}3x+2y - 5z&=6\\\\ 5x - 4y+3z&=-12\\\\ 4x+5y - 2z&=15\\end{align}[\/latex]<\/p>\n<p>27. [latex]\\begin{align}x+y+z&=0\\\\ 2x-y+3z&=0 \\\\ x-z&=1 \\end{align}[\/latex]<\/p>\n<p>28.\u00a0[latex]\\begin{align} 3x-\\frac{1}{2}y-z&=-\\frac{1}{2} \\\\ 4x+z&=3 \\\\ -x+\\frac{3}{2}y&=\\frac{5}{2} \\end{align}[\/latex]<\/p>\n<p>29. [latex]\\begin{align}6x - 5y+6z&=38 \\\\ \\frac{1}{5}x-\\frac{1}{2}y+\\frac{3}{5}z&=1 \\\\ -4x-\\frac{3}{2}y-z&=-74 \\end{align}[\/latex]<\/p>\n<p>30.\u00a0[latex]\\begin{align}\\frac{1}{2}x-\\frac{1}{5}y+\\frac{2}{5}z&=-\\frac{13}{10} \\\\ \\frac{1}{4}x-\\frac{2}{5}y-\\frac{1}{5}z&=-\\frac{7}{20} \\\\ -\\frac{1}{2}x-\\frac{3}{4}y-\\frac{1}{2}z&=-\\frac{5}{4} \\end{align}[\/latex]<\/p>\n<p>31. [latex]\\begin{align} -\\frac{1}{3}x-\\frac{1}{2}y-\\frac{1}{4}z&=\\frac{3}{4} \\\\ -\\frac{1}{2}x-\\frac{1}{4}y-\\frac{1}{2}z&=2 \\\\ -\\frac{1}{4}x-\\frac{3}{4}y-\\frac{1}{2}z&=-\\frac{1}{2} \\end{align}[\/latex]<\/p>\n<p>32.\u00a0[latex]\\begin{align}\\frac{1}{2}x-\\frac{1}{4}y+\\frac{3}{4}z&=0\\\\ \\frac{1}{4}x-\\frac{1}{10}y+\\frac{2}{5}z&=-2\\\\ \\frac{1}{8}x+\\frac{1}{5}y-\\frac{1}{8}z&=2\\end{align}[\/latex]<\/p>\n<p>33. [latex]\\begin{align}\\frac{4}{5}x-\\frac{7}{8}y+\\frac{1}{2}z&=1 \\\\ -\\frac{4}{5}x-\\frac{3}{4}y+\\frac{1}{3}z&=-8 \\\\ -\\frac{2}{5}x-\\frac{7}{8}y+\\frac{1}{2}z&=-5 \\end{align}[\/latex]<\/p>\n<p>34.\u00a0[latex]\\begin{align} -\\frac{1}{3}x-\\frac{1}{8}y+\\frac{1}{6}z&=-\\frac{4}{3} \\\\ -\\frac{2}{3}x-\\frac{7}{8}y+\\frac{1}{3}z&=-\\frac{23}{3} \\\\ -\\frac{1}{3}x-\\frac{5}{8}y+\\frac{5}{6}z&=0 \\end{align}[\/latex]<\/p>\n<p>35. [latex]\\begin{align} -\\frac{1}{4}x-\\frac{5}{4}y+\\frac{5}{2}z&=-5 \\\\ -\\frac{1}{2}x-\\frac{5}{3}y+\\frac{5}{4}z&=\\frac{55}{12} \\\\ -\\frac{1}{3}x-\\frac{1}{3}y+\\frac{1}{3}z&=\\frac{5}{3} \\end{align}[\/latex]<\/p>\n<p>36.\u00a0[latex]\\begin{align}\\frac{1}{40}x+\\frac{1}{60}y+\\frac{1}{80}z&=\\frac{1}{100} \\\\ -\\frac{1}{2}x-\\frac{1}{3}y-\\frac{1}{4}z&=-\\frac{1}{5} \\\\ \\frac{3}{8}x+\\frac{3}{12}y+\\frac{3}{16}z&=\\frac{3}{20} \\end{align}[\/latex]<\/p>\n<p>37. [latex]\\begin{align}0.1x - 0.2y+0.3z&=2\\\\ 0.5x - 0.1y+0.4z&=8\\\\ 0.7x - 0.2y+0.3z&=8\\end{align}[\/latex]<\/p>\n<p>38.\u00a0[latex]\\begin{align}0.2x+0.1y - 0.3z&=0.2\\\\ 0.8x+0.4y - 1.2z&=0.1\\\\ 1.6x+0.8y - 2.4z&=0.2\\end{align}[\/latex]<\/p>\n<p>39. [latex]\\begin{align}1.1x+0.7y - 3.1z&=-1.79\\\\ 2.1x+0.5y - 1.6z&=-0.13\\\\ 0.5x+0.4y - 0.5z&=-0.07\\end{align}[\/latex]<\/p>\n<p>40.\u00a0[latex]\\begin{align}0.5x - 0.5y+0.5z&=10\\\\ 0.2x - 0.2y+0.2z&=4\\\\ 0.1x - 0.1y+0.1z&=2\\end{align}[\/latex]<\/p>\n<p>41. [latex]\\begin{align}0.1x+0.2y+0.3z&=0.37\\\\ 0.1x - 0.2y - 0.3z&=-0.27\\\\ 0.5x - 0.1y - 0.3z&=-0.03\\end{align}[\/latex]<\/p>\n<p>42.\u00a0[latex]\\begin{align}0.5x - 0.5y - 0.3z&=0.13\\\\ 0.4x - 0.1y - 0.3z&=0.11\\\\ 0.2x - 0.8y - 0.9z&=-0.32\\end{align}[\/latex]<\/p>\n<p>43. [latex]\\begin{align}0.5x+0.2y - 0.3z&=1\\\\ 0.4x - 0.6y+0.7z&=0.8\\\\ 0.3x - 0.1y - 0.9z&=0.6\\end{align}[\/latex]<\/p>\n<p>44.\u00a0[latex]\\begin{align}0.3x+0.3y+0.5z&=0.6\\\\ 0.4x+0.4y+0.4z&=1.8\\\\ 0.4x+0.2y+0.1z&=1.6\\end{align}[\/latex]<\/p>\n<p>45. [latex]\\begin{align}0.8x+0.8y+0.8z&=2.4\\\\ 0.3x - 0.5y+0.2z&=0\\\\ 0.1x+0.2y+0.3z&=0.6\\end{align}[\/latex]<\/p>\n<p>For the following exercises, solve the system for [latex]x,y[\/latex], and [latex]z[\/latex].<\/p>\n<p>46. [latex]\\begin{align}x+y+z&=3 \\\\ \\frac{x - 1}{2}+\\frac{y - 3}{2}+\\frac{z+1}{2}&=0 \\\\ \\frac{x - 2}{3}+\\frac{y+4}{3}+\\frac{z - 3}{3}&=\\frac{2}{3} \\end{align}[\/latex]<\/p>\n<p>47. [latex]\\begin{align}5x - 3y-\\frac{z+1}{2}&=\\frac{1}{2} \\\\ 6x+\\frac{y - 9}{2}+2z&=-3 \\\\ \\frac{x+8}{2}-4y+z&=4 \\end{align}[\/latex]<\/p>\n<p>48.\u00a0[latex]\\begin{align}\\frac{x+4}{7}-\\frac{y - 1}{6}+\\frac{z+2}{3}&=1\\\\ \\frac{x - 2}{4}+\\frac{y+1}{8}-\\frac{z+8}{12}&=0\\\\ \\frac{x+6}{3}-\\frac{y+2}{3}+\\frac{z+4}{2}7&=3\\end{align}[\/latex]<\/p>\n<p>49. [latex]\\begin{align}\\frac{x - 3}{6}+\\frac{y+2}{2}-\\frac{z - 3}{3}&=2\\\\ \\frac{x+2}{4}+\\frac{y - 5}{2}+\\frac{z+4}{2}&=1\\\\ \\frac{x+6}{2}-\\frac{y - 3}{2}+z+1&=9\\end{align}[\/latex]<\/p>\n<p>50.\u00a0[latex]\\begin{align}\\frac{x - 1}{3}+\\frac{y+3}{4}+\\frac{z+2}{6}&=1 \\\\ 4x+3y - 2z&=11 \\\\ 0.02x+0.015y - 0.01z&=0.065 \\end{align}[\/latex]<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-15280\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":167848,"menu_order":17,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-15280","chapter","type-chapter","status-publish","hentry"],"part":13184,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/15280","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/users\/167848"}],"version-history":[{"count":4,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/15280\/revisions"}],"predecessor-version":[{"id":16682,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/15280\/revisions\/16682"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/parts\/13184"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/15280\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/media?parent=15280"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapter-type?post=15280"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/contributor?post=15280"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/license?post=15280"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}