{"id":15284,"date":"2021-10-11T22:48:53","date_gmt":"2021-10-11T22:48:53","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/functions-practice-test\/"},"modified":"2021-10-25T03:12:30","modified_gmt":"2021-10-25T03:12:30","slug":"functions-practice-test","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/chapter\/functions-practice-test\/","title":{"raw":"Functions Practice Test","rendered":"Functions Practice Test"},"content":{"raw":"For the following exercises, determine whether each of the following relations is a function.\r\n\r\n1. <em>y\u00a0<\/em>= 2<em>x\u00a0<\/em>+ 8\r\n\r\n2. [latex]\\left\\{\\left(2,1\\right),\\left(3,2\\right),\\left(-1,1\\right),\\left(0,-2\\right)\\right\\}[\/latex]\r\n\r\nFor the following exercises, evaluate the function [latex]f\\left(x\\right)=-3{x}^{2}+2x[\/latex]\u00a0at the given input.\r\n\r\n3. [latex]f\\left(-2\\right)[\/latex]\r\n\r\n4.\u00a0[latex]f\\left(a\\right)[\/latex]\r\n\r\n5. Show that the function [latex]f\\left(x\\right)=-2{\\left(x - 1\\right)}^{2}+3[\/latex] is not one-to-one.\r\n\r\n6.\u00a0Write the domain of the function [latex]f\\left(x\\right)=\\sqrt{3-x}[\/latex] in interval notation.\r\n\r\n7. Given [latex]f\\left(x\\right)=2{x}^{2}-5x[\/latex], find [latex]f\\left(a+1\\right)-f\\left(1\\right)[\/latex].\r\n\r\n8.\u00a0Graph the function [latex]\\begin{cases}f\\left(x\\right) &amp; =x+1 &amp; \\text{ if }-2 &lt; x &lt; 3 \\\\ \\text{ }&amp; =-x &amp; \\text{ if }x\\ge 3\\end{cases}[\/latex]\r\n\r\nFor the following exercises, use the graph of the piecewise-defined function shown below.\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005127\/CNX_Precalc_Figure_01_07_246.jpg\" alt=\"Graph of absolute function and step function.\" data-media-type=\"image\/jpg\" \/>\r\n\r\n9.\u00a0Find [latex]f\\left(2\\right)[\/latex].\r\n\r\n10.\u00a0Find [latex]f\\left(-2\\right)[\/latex].\r\n\r\n<span style=\"font-size: 1rem; text-align: initial;\">For the following exercises, use the values listed below.<\/span>\r\n<table id=\"Table_01_07_07\" summary=\"..\">\r\n<tbody>\r\n<tr>\r\n<td data-align=\"left\"><em><strong>x<\/strong><\/em><\/td>\r\n<td data-align=\"left\"><em><strong>F<\/strong><\/em><strong>(<em>x<\/em>)<\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">0<\/td>\r\n<td data-align=\"left\">1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">1<\/td>\r\n<td data-align=\"left\">3<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">2<\/td>\r\n<td data-align=\"left\">5<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">3<\/td>\r\n<td data-align=\"left\">7<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">4<\/td>\r\n<td data-align=\"left\">9<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">5<\/td>\r\n<td data-align=\"left\">11<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">6<\/td>\r\n<td data-align=\"left\">13<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">7<\/td>\r\n<td data-align=\"left\">15<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">8<\/td>\r\n<td data-align=\"left\">17<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n11. Solve the equation [latex]F\\left(x\\right)=5[\/latex].\r\n\r\n12. Find [latex]F\\left(6\\right)[\/latex].\r\n\r\n13. Is the function represented by the table one-to-one?\r\n\r\n<span style=\"color: #0000ff;\"><em>See the next page for the solutions\u00a0to the odd-numbered problems.<\/em><\/span>","rendered":"<p>For the following exercises, determine whether each of the following relations is a function.<\/p>\n<p>1. <em>y\u00a0<\/em>= 2<em>x\u00a0<\/em>+ 8<\/p>\n<p>2. [latex]\\left\\{\\left(2,1\\right),\\left(3,2\\right),\\left(-1,1\\right),\\left(0,-2\\right)\\right\\}[\/latex]<\/p>\n<p>For the following exercises, evaluate the function [latex]f\\left(x\\right)=-3{x}^{2}+2x[\/latex]\u00a0at the given input.<\/p>\n<p>3. [latex]f\\left(-2\\right)[\/latex]<\/p>\n<p>4.\u00a0[latex]f\\left(a\\right)[\/latex]<\/p>\n<p>5. Show that the function [latex]f\\left(x\\right)=-2{\\left(x - 1\\right)}^{2}+3[\/latex] is not one-to-one.<\/p>\n<p>6.\u00a0Write the domain of the function [latex]f\\left(x\\right)=\\sqrt{3-x}[\/latex] in interval notation.<\/p>\n<p>7. Given [latex]f\\left(x\\right)=2{x}^{2}-5x[\/latex], find [latex]f\\left(a+1\\right)-f\\left(1\\right)[\/latex].<\/p>\n<p>8.\u00a0Graph the function [latex]\\begin{cases}f\\left(x\\right) & =x+1 & \\text{ if }-2 < x < 3 \\\\ \\text{ }& =-x & \\text{ if }x\\ge 3\\end{cases}[\/latex]\n\nFor the following exercises, use the graph of the piecewise-defined function shown below.\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005127\/CNX_Precalc_Figure_01_07_246.jpg\" alt=\"Graph of absolute function and step function.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>9.\u00a0Find [latex]f\\left(2\\right)[\/latex].<\/p>\n<p>10.\u00a0Find [latex]f\\left(-2\\right)[\/latex].<\/p>\n<p><span style=\"font-size: 1rem; text-align: initial;\">For the following exercises, use the values listed below.<\/span><\/p>\n<table id=\"Table_01_07_07\" summary=\"..\">\n<tbody>\n<tr>\n<td data-align=\"left\"><em><strong>x<\/strong><\/em><\/td>\n<td data-align=\"left\"><em><strong>F<\/strong><\/em><strong>(<em>x<\/em>)<\/strong><\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">0<\/td>\n<td data-align=\"left\">1<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">1<\/td>\n<td data-align=\"left\">3<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">2<\/td>\n<td data-align=\"left\">5<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">3<\/td>\n<td data-align=\"left\">7<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">4<\/td>\n<td data-align=\"left\">9<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">5<\/td>\n<td data-align=\"left\">11<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">6<\/td>\n<td data-align=\"left\">13<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">7<\/td>\n<td data-align=\"left\">15<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">8<\/td>\n<td data-align=\"left\">17<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>11. Solve the equation [latex]F\\left(x\\right)=5[\/latex].<\/p>\n<p>12. Find [latex]F\\left(6\\right)[\/latex].<\/p>\n<p>13. Is the function represented by the table one-to-one?<\/p>\n<p><span style=\"color: #0000ff;\"><em>See the next page for the solutions\u00a0to the odd-numbered problems.<\/em><\/span><\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-15284\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":167848,"menu_order":17,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-15284","chapter","type-chapter","status-publish","hentry"],"part":10705,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/15284","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/users\/167848"}],"version-history":[{"count":4,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/15284\/revisions"}],"predecessor-version":[{"id":15936,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/15284\/revisions\/15936"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/parts\/10705"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapters\/15284\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/media?parent=15284"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/pressbooks\/v2\/chapter-type?post=15284"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/contributor?post=15284"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ccbcmd-math-1\/wp-json\/wp\/v2\/license?post=15284"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}