We have seen how to draw vectors according to their initial and terminal points and how to find the position vector. We have also examined notation for vectors drawn specifically in the Cartesian coordinate plane using [latex]i\text{and}j[/latex]. For any of these vectors, we can calculate the magnitude. Now, we want to combine the key points, and look further at the ideas of magnitude and direction.
Calculating direction follows the same straightforward process we used for polar coordinates. We find the direction of the vector by finding the angle to the horizontal. We do this by using the basic trigonometric identities, but with [latex]|v|[/latex] replacing [latex]r[/latex].
A General Note: Vector Components in Terms of Magnitude and Direction
Given a position vector [latex]v=\langle x,y\rangle[/latex] and a direction angle [latex]\theta[/latex],
Thus, [latex]v=xi+yj=|v|\cos \theta i+|v|\sin \theta j[/latex], and magnitude is expressed as [latex]|v|=\sqrt{{x}^{2}+{y}^{2}}[/latex].
Example 13: Writing a Vector in Terms of Magnitude and Direction
Write a vector with length 7 at an angle of 135Ā° to the positiveĀ x-axis in terms of magnitude and direction.
Solution
Using the conversion formulas [latex]x=|v|\cos \theta i[/latex] and [latex]y=|v|\sin \theta j[/latex], we find that
This vector can be written as [latex]v=7\cos \left(135^\circ \right)i+7\sin \left(135^\circ \right)j[/latex] or simplified as
Try It 4
A vector travels from the origin to the point [latex]\left(3,5\right)[/latex]. Write the vector in terms of magnitude and direction.
Candela Citations
- Precalculus. Authored by: OpenStax College. Provided by: OpenStax. Located at: http://cnx.org/contents/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1/Preface. License: CC BY: Attribution