{"id":589,"date":"2016-01-04T16:11:53","date_gmt":"2016-01-04T16:11:53","guid":{"rendered":"https:\/\/courses.candelalearning.com\/chemistry111labs1x1xmaster\/?post_type=chapter&#038;p=589"},"modified":"2016-01-07T01:13:23","modified_gmt":"2016-01-07T01:13:23","slug":"lab-10-worksheet","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/chapter\/lab-10-worksheet\/","title":{"raw":"Lab 10 Worksheet","rendered":"Lab 10 Worksheet"},"content":{"raw":"<div class=\"p1 textbox\"><span class=\"s1\">Download the .pdf file of the lab handout\u00a0<a href=\"https:\/\/s3-us-west-2.amazonaws.com\/textimgs\/Chem+labs\/CHM+111+Lab+10+Hess%27+Law.pdf\"><span class=\"s2\">here<\/span><\/a>.<\/span><\/div>\r\n<h2><strong>Experimental Data and Results<\/strong><\/h2>\r\n<em>*Make sure you show all work and calculations to receive full credit.<\/em>\r\n\r\nFor each problem, find the \u0394H for the target reaction below, given the following step reactions and subsequent \u0394H values:\r\n<div>\r\n<table style=\"height: 172px;\" width=\"684\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 1<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>PCl<sub>5<\/sub>(g) \u2192 PCl<sub>3<\/sub>(g) + Cl<sub>2<\/sub>(g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>P<sub>4<\/sub>(s) + 6Cl<sub>2<\/sub>(g) \u2192 4PCl<sub>3<\/sub>(g)<\/td>\r\n<td>\u0394H = -2439 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>4PCl<sub>5<\/sub>(g) \u2192 P<sub>4<\/sub>(s) + 10Cl<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = 3438 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n\r\n<\/div>\r\n<table style=\"height: 198px;\" width=\"685\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 2<\/th>\r\n<\/tr>\r\n<tr>\r\n<td height=\"\u201c70&quot;\">Target Reaction:<\/td>\r\n<td>2CO<sub>2<\/sub>(g) + H<sub>2<\/sub>O(g) \u2192 C<sub>2<\/sub>H<sub>2<\/sub>(g) + 5\/2O<sub>2<\/sub>(g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>C<sub>2<\/sub>H<sub>2<\/sub>(g) + 2H<sub>2<\/sub>(g) \u2192 C<sub>2<\/sub>H<sub>6<\/sub>(g)<\/td>\r\n<td>\u0394H = -94.5 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>H<sub>2<\/sub>O(g) \u2192 H<sub>2<\/sub>(g) + 1\/2O<sub>2<\/sub> (g)<\/td>\r\n<td>\u0394H = 71.2 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>\u00a02C<sub>2<\/sub>H<sub>6<\/sub>(g) + 7O<sub>2<\/sub>(g) \u2192 4CO<sub>2<\/sub>(g) + 6H<sub>2<\/sub>O(g)<\/td>\r\n<td>\u0394H =-566 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table>\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 3<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>N<sub>2<\/sub>H<sub>4<\/sub>(l) + H<sub>2<\/sub>(g) \u2192 2NH<sub>3<\/sub>(g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>N<sub>2<\/sub>H<sub>4<\/sub>(l) + CH<sub>4<\/sub>O(l) \u2192 CH<sub>2<\/sub>O(g) + N<sub>2<\/sub>(g) + 3H<sub>2<\/sub> (g)<\/td>\r\n<td>\u0394H = -37 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>N<sub>2<\/sub>(g) + 3H<sub>2<\/sub>(g) \u2192 2NH<sub>3<\/sub>(g)<\/td>\r\n<td>\u0394H = -46 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>CH<sub>4<\/sub>O(l) \u2192 CH<sub>2<\/sub>O(g) + H<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = -65 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table style=\"height: 188px;\" width=\"688\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 4<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>H<sub>2<\/sub>SO<sub>4<\/sub>(l) \u2192 SO<sub>3<\/sub>(g) + H<sub>2<\/sub>O(g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>H<sub>2<\/sub>S(g) + 2O2(g) \u2192 H<sub>2<\/sub>SO<sub>4<\/sub>(l)<\/td>\r\n<td>\u0394H = -235.5 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>H<sub>2<\/sub>S(g) + 2O<sub>2<\/sub>(g) \u2192 SO<sub>3<\/sub>(g) + H<sub>2<\/sub>O(l)<\/td>\r\n<td>\u0394H = -207 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>H<sub>2<\/sub>O(l) \u2192 H<sub>2<\/sub>O(g)<\/td>\r\n<td>\u0394H = 44 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table style=\"height: 156px;\" width=\"690\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 5<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>2C<sub>2<\/sub>H<sub>4<\/sub>O(l) + 2H<sub>2<\/sub>O(l) \u2192 2C<sub>2<\/sub>H<sub>6<\/sub>O(l) + O<sub>2<\/sub>(g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>C<sub>2<\/sub>H<sub>6<\/sub>O(l) + 3O<sub>2<\/sub>(g) \u2192 2CO<sub>2<\/sub>(g) + 3H<sub>2<\/sub>O(l)<\/td>\r\n<td>\u0394H = -685 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>C<sub>2<\/sub>H<sub>4<\/sub>O(l) + 5\/2O<sub>2<\/sub>(g) \u2192 2CO<sub>2<\/sub>(g) + 2H<sub>2<\/sub>O(l)<\/td>\r\n<td>\u0394H = -583.5 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table style=\"height: 187px;\" width=\"689\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 6<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>N<sub>2<\/sub>(g) + 2O<sub>2<\/sub>(g) \u2192 2NO<sub>2<\/sub>(g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>N<sub>2<\/sub>(g) + 3H<sub>2<\/sub>(g) \u2192 2NH<sub>3<\/sub>(g)<\/td>\r\n<td>\u0394H = -115 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>2NH<sub>3<\/sub>(g) + 4H<sub>2<\/sub>O(l) \u2192 2NO<sub>2<\/sub>(g) + 7H<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = -142.5 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>H<sub>2<\/sub>O(l) \u2192 H<sub>2<\/sub>(g) + 1\/2O<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = -43.7 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table style=\"height: 189px;\" width=\"690\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 7<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>CO<sub>2<\/sub>(g) \u2192 C(s) + O<sub>2<\/sub>(g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>H<sub>2<\/sub>O(l) \u2192 H<sub>2<\/sub>(g) + 1\/2O<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = 643 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>C<sub>2<\/sub>H<sub>6<\/sub>(g) \u2192 2C(s) + 3H<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = 190.6 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>2CO<sub>2<\/sub>(g) + 3H<sub>2<\/sub>O(l) \u2192 C 2H<sub>6<\/sub>(g) + 7\/2O<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = 3511.1 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table>\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 8<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>N<sub>2<\/sub>H<sub>4<\/sub>(l) + CH<sub>4<\/sub>O(l) \u2192 CH<sub>2<\/sub>O(g) + N<sub>2<\/sub>(g) + 3H<sub>2<\/sub> (g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>2NH<sub>3<\/sub>(g) \u2192 N<sub>2<\/sub>H<sub>4<\/sub>(l) + H<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = 22.5 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>2NH<sub>3<\/sub>(g) \u2192 N<sub>2<\/sub>(g) + 3H<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = 57.5 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>CH<sub>2<\/sub>O(g) + H<sub>2<\/sub>(g) \u2192 CH<sub>4<\/sub>O(l)<\/td>\r\n<td>\u0394H = 81.2 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table style=\"height: 185px;\" width=\"691\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 9<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>1\/2H<sub>2<\/sub>(g) + 1\/2Cl<sub>2<\/sub>(g) \u2192 HCl(g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>COCl<sub>2<\/sub>(g) + H<sub>2<\/sub>O(l) \u2192 CH<sub>2<\/sub>Cl<sub>2<\/sub>(l) + O<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = -47.5 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>2HCl(g) + 1\/2O<sub>2<\/sub>(g) \u2192 H<sub>2<\/sub>O(l) + Cl<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = 105 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>CH<sub>2<\/sub>Cl<sub>2<\/sub>(l) + H<sub>2<\/sub>(g) + 3\/2O<sub>2<\/sub>(g) \u2192 COCl<sub>2<\/sub>(g) + 2H<sub>2<\/sub>O(l)<\/td>\r\n<td>\u0394H = -402.5 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table style=\"height: 191px;\" width=\"695\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 10<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>C<sub>2<\/sub>H<sub>2<\/sub>(g) + 5\/2O<sub>2<\/sub>(g) \u2192 2CO<sub>2<\/sub>(g) + H<sub>2<\/sub>O(g)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>C<sub>2<\/sub>H<sub>6<\/sub>(g) \u2192 C<sub>2<\/sub>H<sub>2<\/sub>(g) + 2H<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = 283.5 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>H<sub>2<\/sub>(g) + 1\/2O<sub>2<\/sub>(g) \u2192 H<sub>2<\/sub>O(g)<\/td>\r\n<td>\u0394H = -213.7 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>2CO<sub>2<\/sub>(g) + 3H<sub>2<\/sub>O(g) \u2192 C<sub>2<\/sub>H<sub>6<\/sub>(g) + 7\/2O<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = 849 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table style=\"height: 220px;\" width=\"694\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 11<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>HCl(g) + NaNO<sub>2<\/sub>(s) \u2192 HNO<sub>2<\/sub>(l) + NaCl(s)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>2NaCl(s) + H<sub>2<\/sub>O(l) \u2192 2HCl(g) + Na<sub>2<\/sub>O(s)<\/td>\r\n<td>\u0394H = 507 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>NO(g) + NO<sub>2<\/sub>(g) + Na<sub>2<\/sub>O(s) \u2192 2NaNO<sub>2<\/sub>(s)<\/td>\r\n<td>\u0394H = -427 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>NO(g) + NO<sub>2<\/sub>(g) \u2192 N<sub>2<\/sub>O(g) + O<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = -43 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>2HNO<sub>2<\/sub>(l) \u2192 N<sub>2<\/sub>O(g) + O<sub>2<\/sub>(g) + H<sub>2<\/sub>O(l)<\/td>\r\n<td>\u0394H = 34 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;\r\n<table style=\"height: 218px;\" width=\"690\">\r\n<tbody>\r\n<tr>\r\n<th colspan=\"3\">Problem 12<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>Target Reaction:<\/td>\r\n<td>Zn(s) + 1\/8S<sub>8<\/sub>(s) + 2O<sub>2<\/sub>(g) \u2192 ZnSO<sub>4<\/sub>(s)<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Step Reactions:<\/td>\r\n<td>Zn(s) + 1\/8S<sub>8<\/sub>(s) \u2192 ZnS(s)<\/td>\r\n<td>\u0394H = -183.92 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>2ZnS(s) + 3O<sub>2<\/sub>(g) \u2192 2ZnO(s) + 2SO<sub>2<\/sub>(g)<\/td>\r\n<td>\u0394H = -927 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>2SO<sub>2<\/sub>(g) + O<sub>2<\/sub>(g) \u2192 2SO<sub>3<\/sub>(g)<\/td>\r\n<td>\u0394H = -196.04 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>ZnO(s) + SO<sub>3<\/sub>(g) \u2192 ZnSO<sub>4<\/sub> (s)<\/td>\r\n<td>\u0394H = -230.32 kJ<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>Answer______________<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n&nbsp;","rendered":"<div class=\"p1 textbox\"><span class=\"s1\">Download the .pdf file of the lab handout\u00a0<a href=\"https:\/\/s3-us-west-2.amazonaws.com\/textimgs\/Chem+labs\/CHM+111+Lab+10+Hess%27+Law.pdf\"><span class=\"s2\">here<\/span><\/a>.<\/span><\/div>\n<h2><strong>Experimental Data and Results<\/strong><\/h2>\n<p><em>*Make sure you show all work and calculations to receive full credit.<\/em><\/p>\n<p>For each problem, find the \u0394H for the target reaction below, given the following step reactions and subsequent \u0394H values:<\/p>\n<div>\n<table style=\"height: 172px; width: 684px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 1<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>PCl<sub>5<\/sub>(g) \u2192 PCl<sub>3<\/sub>(g) + Cl<sub>2<\/sub>(g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>P<sub>4<\/sub>(s) + 6Cl<sub>2<\/sub>(g) \u2192 4PCl<sub>3<\/sub>(g)<\/td>\n<td>\u0394H = -2439 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>4PCl<sub>5<\/sub>(g) \u2192 P<sub>4<\/sub>(s) + 10Cl<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = 3438 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<\/div>\n<table style=\"height: 198px; width: 685px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 2<\/th>\n<\/tr>\n<tr>\n<td style=\"height: \u201c70&quot;\">Target Reaction:<\/td>\n<td>2CO<sub>2<\/sub>(g) + H<sub>2<\/sub>O(g) \u2192 C<sub>2<\/sub>H<sub>2<\/sub>(g) + 5\/2O<sub>2<\/sub>(g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>C<sub>2<\/sub>H<sub>2<\/sub>(g) + 2H<sub>2<\/sub>(g) \u2192 C<sub>2<\/sub>H<sub>6<\/sub>(g)<\/td>\n<td>\u0394H = -94.5 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>H<sub>2<\/sub>O(g) \u2192 H<sub>2<\/sub>(g) + 1\/2O<sub>2<\/sub> (g)<\/td>\n<td>\u0394H = 71.2 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>\u00a02C<sub>2<\/sub>H<sub>6<\/sub>(g) + 7O<sub>2<\/sub>(g) \u2192 4CO<sub>2<\/sub>(g) + 6H<sub>2<\/sub>O(g)<\/td>\n<td>\u0394H =-566 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table>\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 3<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>N<sub>2<\/sub>H<sub>4<\/sub>(l) + H<sub>2<\/sub>(g) \u2192 2NH<sub>3<\/sub>(g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>N<sub>2<\/sub>H<sub>4<\/sub>(l) + CH<sub>4<\/sub>O(l) \u2192 CH<sub>2<\/sub>O(g) + N<sub>2<\/sub>(g) + 3H<sub>2<\/sub> (g)<\/td>\n<td>\u0394H = -37 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>N<sub>2<\/sub>(g) + 3H<sub>2<\/sub>(g) \u2192 2NH<sub>3<\/sub>(g)<\/td>\n<td>\u0394H = -46 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>CH<sub>4<\/sub>O(l) \u2192 CH<sub>2<\/sub>O(g) + H<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = -65 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table style=\"height: 188px; width: 688px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 4<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>H<sub>2<\/sub>SO<sub>4<\/sub>(l) \u2192 SO<sub>3<\/sub>(g) + H<sub>2<\/sub>O(g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>H<sub>2<\/sub>S(g) + 2O2(g) \u2192 H<sub>2<\/sub>SO<sub>4<\/sub>(l)<\/td>\n<td>\u0394H = -235.5 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>H<sub>2<\/sub>S(g) + 2O<sub>2<\/sub>(g) \u2192 SO<sub>3<\/sub>(g) + H<sub>2<\/sub>O(l)<\/td>\n<td>\u0394H = -207 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>H<sub>2<\/sub>O(l) \u2192 H<sub>2<\/sub>O(g)<\/td>\n<td>\u0394H = 44 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table style=\"height: 156px; width: 690px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 5<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>2C<sub>2<\/sub>H<sub>4<\/sub>O(l) + 2H<sub>2<\/sub>O(l) \u2192 2C<sub>2<\/sub>H<sub>6<\/sub>O(l) + O<sub>2<\/sub>(g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>C<sub>2<\/sub>H<sub>6<\/sub>O(l) + 3O<sub>2<\/sub>(g) \u2192 2CO<sub>2<\/sub>(g) + 3H<sub>2<\/sub>O(l)<\/td>\n<td>\u0394H = -685 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>C<sub>2<\/sub>H<sub>4<\/sub>O(l) + 5\/2O<sub>2<\/sub>(g) \u2192 2CO<sub>2<\/sub>(g) + 2H<sub>2<\/sub>O(l)<\/td>\n<td>\u0394H = -583.5 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table style=\"height: 187px; width: 689px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 6<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>N<sub>2<\/sub>(g) + 2O<sub>2<\/sub>(g) \u2192 2NO<sub>2<\/sub>(g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>N<sub>2<\/sub>(g) + 3H<sub>2<\/sub>(g) \u2192 2NH<sub>3<\/sub>(g)<\/td>\n<td>\u0394H = -115 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>2NH<sub>3<\/sub>(g) + 4H<sub>2<\/sub>O(l) \u2192 2NO<sub>2<\/sub>(g) + 7H<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = -142.5 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>H<sub>2<\/sub>O(l) \u2192 H<sub>2<\/sub>(g) + 1\/2O<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = -43.7 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table style=\"height: 189px; width: 690px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 7<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>CO<sub>2<\/sub>(g) \u2192 C(s) + O<sub>2<\/sub>(g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>H<sub>2<\/sub>O(l) \u2192 H<sub>2<\/sub>(g) + 1\/2O<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = 643 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>C<sub>2<\/sub>H<sub>6<\/sub>(g) \u2192 2C(s) + 3H<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = 190.6 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>2CO<sub>2<\/sub>(g) + 3H<sub>2<\/sub>O(l) \u2192 C 2H<sub>6<\/sub>(g) + 7\/2O<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = 3511.1 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table>\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 8<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>N<sub>2<\/sub>H<sub>4<\/sub>(l) + CH<sub>4<\/sub>O(l) \u2192 CH<sub>2<\/sub>O(g) + N<sub>2<\/sub>(g) + 3H<sub>2<\/sub> (g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>2NH<sub>3<\/sub>(g) \u2192 N<sub>2<\/sub>H<sub>4<\/sub>(l) + H<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = 22.5 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>2NH<sub>3<\/sub>(g) \u2192 N<sub>2<\/sub>(g) + 3H<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = 57.5 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>CH<sub>2<\/sub>O(g) + H<sub>2<\/sub>(g) \u2192 CH<sub>4<\/sub>O(l)<\/td>\n<td>\u0394H = 81.2 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table style=\"height: 185px; width: 691px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 9<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>1\/2H<sub>2<\/sub>(g) + 1\/2Cl<sub>2<\/sub>(g) \u2192 HCl(g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>COCl<sub>2<\/sub>(g) + H<sub>2<\/sub>O(l) \u2192 CH<sub>2<\/sub>Cl<sub>2<\/sub>(l) + O<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = -47.5 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>2HCl(g) + 1\/2O<sub>2<\/sub>(g) \u2192 H<sub>2<\/sub>O(l) + Cl<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = 105 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>CH<sub>2<\/sub>Cl<sub>2<\/sub>(l) + H<sub>2<\/sub>(g) + 3\/2O<sub>2<\/sub>(g) \u2192 COCl<sub>2<\/sub>(g) + 2H<sub>2<\/sub>O(l)<\/td>\n<td>\u0394H = -402.5 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table style=\"height: 191px; width: 695px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 10<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>C<sub>2<\/sub>H<sub>2<\/sub>(g) + 5\/2O<sub>2<\/sub>(g) \u2192 2CO<sub>2<\/sub>(g) + H<sub>2<\/sub>O(g)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>C<sub>2<\/sub>H<sub>6<\/sub>(g) \u2192 C<sub>2<\/sub>H<sub>2<\/sub>(g) + 2H<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = 283.5 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>H<sub>2<\/sub>(g) + 1\/2O<sub>2<\/sub>(g) \u2192 H<sub>2<\/sub>O(g)<\/td>\n<td>\u0394H = -213.7 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>2CO<sub>2<\/sub>(g) + 3H<sub>2<\/sub>O(g) \u2192 C<sub>2<\/sub>H<sub>6<\/sub>(g) + 7\/2O<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = 849 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table style=\"height: 220px; width: 694px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 11<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>HCl(g) + NaNO<sub>2<\/sub>(s) \u2192 HNO<sub>2<\/sub>(l) + NaCl(s)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>2NaCl(s) + H<sub>2<\/sub>O(l) \u2192 2HCl(g) + Na<sub>2<\/sub>O(s)<\/td>\n<td>\u0394H = 507 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>NO(g) + NO<sub>2<\/sub>(g) + Na<sub>2<\/sub>O(s) \u2192 2NaNO<sub>2<\/sub>(s)<\/td>\n<td>\u0394H = -427 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>NO(g) + NO<sub>2<\/sub>(g) \u2192 N<sub>2<\/sub>O(g) + O<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = -43 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>2HNO<sub>2<\/sub>(l) \u2192 N<sub>2<\/sub>O(g) + O<sub>2<\/sub>(g) + H<sub>2<\/sub>O(l)<\/td>\n<td>\u0394H = 34 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table style=\"height: 218px; width: 690px;\">\n<tbody>\n<tr>\n<th colspan=\"3\">Problem 12<\/th>\n<\/tr>\n<tr>\n<td>Target Reaction:<\/td>\n<td>Zn(s) + 1\/8S<sub>8<\/sub>(s) + 2O<sub>2<\/sub>(g) \u2192 ZnSO<sub>4<\/sub>(s)<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>Step Reactions:<\/td>\n<td>Zn(s) + 1\/8S<sub>8<\/sub>(s) \u2192 ZnS(s)<\/td>\n<td>\u0394H = -183.92 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>2ZnS(s) + 3O<sub>2<\/sub>(g) \u2192 2ZnO(s) + 2SO<sub>2<\/sub>(g)<\/td>\n<td>\u0394H = -927 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>2SO<sub>2<\/sub>(g) + O<sub>2<\/sub>(g) \u2192 2SO<sub>3<\/sub>(g)<\/td>\n<td>\u0394H = -196.04 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>ZnO(s) + SO<sub>3<\/sub>(g) \u2192 ZnSO<sub>4<\/sub> (s)<\/td>\n<td>\u0394H = -230.32 kJ<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>Answer______________<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-589\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li>College Chemistry 1. <strong>Authored by<\/strong>: Jessica Garber-Morales. <strong>Provided by<\/strong>: Tidewater Community College. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/www.tcc.edu\/\">http:\/\/www.tcc.edu\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Hess&#039;s Law of Heat Summation. <strong>Provided by<\/strong>: CK-12. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/www.ck12.org\/book\/CK-12-Chemistry-Concepts-Intermediate\/section\/17.15\/\">http:\/\/www.ck12.org\/book\/CK-12-Chemistry-Concepts-Intermediate\/section\/17.15\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em><\/li><li>Hess&#039;s Law problems. <strong>Authored by<\/strong>: CBender. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/goo.gl\/XNR1eU\">http:\/\/goo.gl\/XNR1eU<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":74,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"College Chemistry 1\",\"author\":\"Jessica Garber-Morales\",\"organization\":\"Tidewater Community College\",\"url\":\"http:\/\/www.tcc.edu\/\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"cc\",\"description\":\"Hess\\'s Law of Heat Summation\",\"author\":\"\",\"organization\":\"CK-12\",\"url\":\"http:\/\/www.ck12.org\/book\/CK-12-Chemistry-Concepts-Intermediate\/section\/17.15\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"\"},{\"type\":\"cc\",\"description\":\"Hess\\'s Law problems\",\"author\":\"CBender\",\"organization\":\"\",\"url\":\"http:\/\/goo.gl\/XNR1eU\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-589","chapter","type-chapter","status-publish","hentry"],"part":68,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/pressbooks\/v2\/chapters\/589","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/wp\/v2\/users\/74"}],"version-history":[{"count":16,"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/pressbooks\/v2\/chapters\/589\/revisions"}],"predecessor-version":[{"id":687,"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/pressbooks\/v2\/chapters\/589\/revisions\/687"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/pressbooks\/v2\/parts\/68"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/pressbooks\/v2\/chapters\/589\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/wp\/v2\/media?parent=589"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/pressbooks\/v2\/chapter-type?post=589"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/wp\/v2\/contributor?post=589"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/chemistry1labs\/wp-json\/wp\/v2\/license?post=589"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}