{"id":8265,"date":"2017-05-25T19:44:05","date_gmt":"2017-05-25T19:44:05","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/prealgebra\/?post_type=chapter&#038;p=8265"},"modified":"2019-05-27T05:49:35","modified_gmt":"2019-05-27T05:49:35","slug":"solve-geometry-applications-volume-and-surface-area","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/csn-prealgebra\/chapter\/solve-geometry-applications-volume-and-surface-area\/","title":{"raw":"Introduction to Solving Problems Using Volume and Surface Area","rendered":"Introduction to Solving Problems Using Volume and Surface Area"},"content":{"raw":"<h2>What you'll learn to do: Solve problems using the volume and surface area of solid figures<\/h2>\r\n<a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/05\/20162509\/UNICEF_DSC_9422_21243407812-1.jpg\"><img class=\"wp-image-12285 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/05\/20162509\/UNICEF_DSC_9422_21243407812-1-300x199.jpg\" alt=\"\" width=\"715\" height=\"474\" \/><\/a>\r\n\r\nJosie is a kindergarten teacher and wants to make felt toys for her students. These felt toys will be cylinders, meant to replicate cans. She wants to put the felt toys in the new play kitchen in her classroom. To find the amount of felt she needs, Josie will need to calculate the surface area of the cans she plans to make. This chapter will explain how to find surface area of different objects, including cylinders.\r\n\r\nBefore you get started in this module, try a few practice problems and review\u00a0prior\u00a0concepts.\r\n<div class=\"textbox examples\">\r\n<h3>readiness quiz<\/h3>\r\n1)\r\n\r\n[ohm_question]144879[\/ohm_question]\r\n\r\nIf you missed this problem, review these examples.\r\n<div class=\"textbox shaded\">\r\n\r\nEvaluate [latex]{x}^{2}[\/latex] when [latex]x=10[\/latex].\r\n\r\n[reveal-answer q=\"729694\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"729694\"]\r\n\r\nSolution\r\n\r\nWe substitute [latex]10[\/latex] for [latex]x[\/latex], and then simplify the expression.\r\n<table id=\"eip-id1168468538199\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression x squared. Substitute 10 for x. The expression becomes 10 squared. By the definition of exponents, 10 squared is 10 times 10. Multiply to get 100.\" data-label=\"\">\r\n<tbody>\r\n<tr>\r\n<td>[latex]x^2[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Substitute [latex]\\color{red}{10}[\/latex] for x.<\/td>\r\n<td>[latex]{\\color{red}{10}}^{2}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Use the definition of exponent.<\/td>\r\n<td>[latex]10\\cdot 10[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Multiply.<\/td>\r\n<td>[latex]100[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nWhen [latex]x=10[\/latex], the expression [latex]{x}^{2}[\/latex] has a value of [latex]100[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n\r\n[latex]\\text{Evaluate }{2}^{x}\\text{ when }x=5[\/latex].\r\n\r\n[reveal-answer q=\"920379\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"920379\"]\r\n\r\nSolution\r\nIn this expression, the variable is an exponent.\r\n<table id=\"eip-id1168469574741\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression 2 to the power of x. Substitute 5 for x. The expression becomes 2 to the fifth power. By the definition of exponents, 2 to the fifth power is 2 times 2 times 2 times 2 times 2, or 5 factors of 2. Multiply from left to right to get 32.\" data-label=\"\">\r\n<tbody>\r\n<tr>\r\n<td>[latex]2^x[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Substitute [latex]\\color{red}{5}[\/latex] for x.<\/td>\r\n<td>[latex]{2}^{\\color{red}{5}}[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Use the definition of exponent.<\/td>\r\n<td>[latex]2\\cdot2\\cdot2\\cdot2\\cdot2[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Multiply.<\/td>\r\n<td>[latex]32[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nWhen [latex]x=5[\/latex], the expression [latex]{2}^{x}[\/latex] has a value of [latex]32[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n2)\r\n\r\n[ohm_question]146611[\/ohm_question]\r\n\r\nIf you missed this problem, review the videos below.\r\n\r\nhttps:\/\/youtu.be\/sHtsnC2Mgnk\r\n\r\nhttps:\/\/youtu.be\/SIKkWLqt2mQ\r\n\r\n<\/div>\r\nIn this section, we will finish our study of geometry applications. We find the volume and surface area of some three-dimensional figures. Since we will be solving applications, we will once again show our Problem-Solving Strategy for Geometry Applications.\r\n\r\nProblem Solving Strategy for Geometry Applications\r\n<ol class=\"stepwise\" data-number-style=\"arabic\">\r\n \t<li><strong>Read<\/strong> the problem and make sure you understand all the words and ideas. Draw the figure and label it with the given information.<\/li>\r\n \t<li><strong>Identify<\/strong> what you are looking for.<\/li>\r\n \t<li><strong>Name<\/strong> what you are looking for. Choose a variable to represent that quantity.<\/li>\r\n \t<li><strong>Translate<\/strong> into an equation by writing the appropriate formula or model for the situation. Substitute in the given information.<\/li>\r\n \t<li><strong>Solve<\/strong> the equation using good algebra techniques.<\/li>\r\n \t<li><strong>Check<\/strong> the answer in the problem and make sure it makes sense.<\/li>\r\n \t<li><strong>Answer<\/strong> the question with a complete sentence.<\/li>\r\n<\/ol>","rendered":"<h2>What you&#8217;ll learn to do: Solve problems using the volume and surface area of solid figures<\/h2>\n<p><a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/05\/20162509\/UNICEF_DSC_9422_21243407812-1.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-12285 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/05\/20162509\/UNICEF_DSC_9422_21243407812-1-300x199.jpg\" alt=\"\" width=\"715\" height=\"474\" \/><\/a><\/p>\n<p>Josie is a kindergarten teacher and wants to make felt toys for her students. These felt toys will be cylinders, meant to replicate cans. She wants to put the felt toys in the new play kitchen in her classroom. To find the amount of felt she needs, Josie will need to calculate the surface area of the cans she plans to make. This chapter will explain how to find surface area of different objects, including cylinders.<\/p>\n<p>Before you get started in this module, try a few practice problems and review\u00a0prior\u00a0concepts.<\/p>\n<div class=\"textbox examples\">\n<h3>readiness quiz<\/h3>\n<p>1)<\/p>\n<p><iframe loading=\"lazy\" id=\"ohm144879\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=144879&theme=oea&iframe_resize_id=ohm144879&show_question_numbers\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<p>If you missed this problem, review these examples.<\/p>\n<div class=\"textbox shaded\">\n<p>Evaluate [latex]{x}^{2}[\/latex] when [latex]x=10[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q729694\">Show Solution<\/span><\/p>\n<div id=\"q729694\" class=\"hidden-answer\" style=\"display: none\">\n<p>Solution<\/p>\n<p>We substitute [latex]10[\/latex] for [latex]x[\/latex], and then simplify the expression.<\/p>\n<table id=\"eip-id1168468538199\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression x squared. Substitute 10 for x. The expression becomes 10 squared. By the definition of exponents, 10 squared is 10 times 10. Multiply to get 100.\" data-label=\"\">\n<tbody>\n<tr>\n<td>[latex]x^2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Substitute [latex]\\color{red}{10}[\/latex] for x.<\/td>\n<td>[latex]{\\color{red}{10}}^{2}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Use the definition of exponent.<\/td>\n<td>[latex]10\\cdot 10[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Multiply.<\/td>\n<td>[latex]100[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>When [latex]x=10[\/latex], the expression [latex]{x}^{2}[\/latex] has a value of [latex]100[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox shaded\">\n<p>[latex]\\text{Evaluate }{2}^{x}\\text{ when }x=5[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q920379\">Show Solution<\/span><\/p>\n<div id=\"q920379\" class=\"hidden-answer\" style=\"display: none\">\n<p>Solution<br \/>\nIn this expression, the variable is an exponent.<\/p>\n<table id=\"eip-id1168469574741\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression 2 to the power of x. Substitute 5 for x. The expression becomes 2 to the fifth power. By the definition of exponents, 2 to the fifth power is 2 times 2 times 2 times 2 times 2, or 5 factors of 2. Multiply from left to right to get 32.\" data-label=\"\">\n<tbody>\n<tr>\n<td>[latex]2^x[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Substitute [latex]\\color{red}{5}[\/latex] for x.<\/td>\n<td>[latex]{2}^{\\color{red}{5}}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Use the definition of exponent.<\/td>\n<td>[latex]2\\cdot2\\cdot2\\cdot2\\cdot2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Multiply.<\/td>\n<td>[latex]32[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>When [latex]x=5[\/latex], the expression [latex]{2}^{x}[\/latex] has a value of [latex]32[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>2)<\/p>\n<p><iframe loading=\"lazy\" id=\"ohm146611\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=146611&theme=oea&iframe_resize_id=ohm146611&show_question_numbers\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<p>If you missed this problem, review the videos below.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Examples:  Determine the Circumference of a Circle\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/sHtsnC2Mgnk?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Example:  Determine the Area of a Circle\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/SIKkWLqt2mQ?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<\/div>\n<p>In this section, we will finish our study of geometry applications. We find the volume and surface area of some three-dimensional figures. Since we will be solving applications, we will once again show our Problem-Solving Strategy for Geometry Applications.<\/p>\n<p>Problem Solving Strategy for Geometry Applications<\/p>\n<ol class=\"stepwise\" data-number-style=\"arabic\">\n<li><strong>Read<\/strong> the problem and make sure you understand all the words and ideas. Draw the figure and label it with the given information.<\/li>\n<li><strong>Identify<\/strong> what you are looking for.<\/li>\n<li><strong>Name<\/strong> what you are looking for. Choose a variable to represent that quantity.<\/li>\n<li><strong>Translate<\/strong> into an equation by writing the appropriate formula or model for the situation. Substitute in the given information.<\/li>\n<li><strong>Solve<\/strong> the equation using good algebra techniques.<\/li>\n<li><strong>Check<\/strong> the answer in the problem and make sure it makes sense.<\/li>\n<li><strong>Answer<\/strong> the question with a complete sentence.<\/li>\n<\/ol>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-8265\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Kindergarteners Playing. <strong>Authored by<\/strong>: UNICEF Ukraine. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/commons.wikimedia.org\/wiki\/File:UNICEF_DSC_9422_(21243407812).jpg\">https:\/\/commons.wikimedia.org\/wiki\/File:UNICEF_DSC_9422_(21243407812).jpg<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Examples: Determine the Circumference of a Circle. <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com). <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/sHtsnC2Mgnk\">https:\/\/youtu.be\/sHtsnC2Mgnk<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Example: Determine the Area of a Circle. <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com). <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/SIKkWLqt2mQ\">https:\/\/youtu.be\/SIKkWLqt2mQ<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Question ID: 144879, 146611. <strong>Authored by<\/strong>: Lumen Learning. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: IMathAS Community License CC-BY + GPL<\/li><\/ul><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>Prealgebra. <strong>Provided by<\/strong>: OpenStax. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at http:\/\/cnx.org\/contents\/caa57dab-41c7-455e-bd6f-f443cda5519c@9.757<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":21,"menu_order":17,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Kindergarteners Playing\",\"author\":\"UNICEF Ukraine\",\"organization\":\"\",\"url\":\"https:\/\/commons.wikimedia.org\/wiki\/File:UNICEF_DSC_9422_(21243407812).jpg\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"cc-attribution\",\"description\":\"Prealgebra\",\"author\":\"\",\"organization\":\"OpenStax\",\"url\":\"\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at http:\/\/cnx.org\/contents\/caa57dab-41c7-455e-bd6f-f443cda5519c@9.757\"},{\"type\":\"cc\",\"description\":\"Examples: Determine the Circumference of a Circle\",\"author\":\"James Sousa (Mathispower4u.com)\",\"organization\":\"\",\"url\":\"https:\/\/youtu.be\/sHtsnC2Mgnk\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"cc\",\"description\":\"Example: Determine the Area of a Circle\",\"author\":\"James Sousa 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