Chapter 9 Solutions to Odd-Numbered Problems

Section 9.1 Solutions

1. The value of the function, the output, at x=ax=a is f(a)f(a). When the limxaf(x)limxaf(x) is taken, the values of xx get infinitely close to aa but never equal aa. As the values of xx approach aa from the left and right, the limit is the value that the function is approaching.

3. –4

5. –4

7. 2

9. does not exist

11. 4

13. does not exist

15. Answers will vary.

17. Answers will vary.

19. Answers will vary.

21. Answers will vary.

23. 7.38906

25. 54.59815

27. e6403.428794e6403.428794, e71096.633158e71096.633158, enen

29. limx2f(x)=1limx2f(x)=1

31. limx3(x2x6x29)=560.83limx3(x2x6x29)=560.83

33. limx1(x21x23x+2)=2.00limx1(x21x23x+2)=2.00

35. limx1(1010x2x23x+2)=20.00limx1(1010x2x23x+2)=20.00

37. limx12(x4x2+4x+1)limx12(x4x2+4x+1) does not exist. Function values decrease without bound as xx approaches –0.5 from either left or right.

39. limx07tanx3x=73limx07tanx3x=73
Table shows as the function approaches 0, the value is 7 over 3 but the function is undefined at 0.

41. limx02sinx4tanx=12limx02sinx4tanx=12
Table shows as the function approaches 0, the value is 1 over 2, but the function is undefined at 0.

43. limx0ee 1x2=1.0limx0ee 1x2=1.0

45. limx1|x+1|x+1=(x+1)(x+1)=1limx1|x+1|x+1=(x+1)(x+1)=1 and limx1+|x+1|x+1=(x+1)(x+1)=1limx1+|x+1|x+1=(x+1)(x+1)=1; since the right-hand limit does not equal the left-hand limit, limx1|x+1|x+1limx1|x+1|x+1 does not exist.

47. limx11(x+1)2limx11(x+1)2 does not exist. The function increases without bound as xx approaches 11 from either side.

49. limx051e2xlimx051e2x does not exist. Function values approach 5 from the left and approach 0 from the right.

51. Through examination of the postulates and an understanding of relativistic physics, as vcvc, mm. Take this one step further to the solution,

limvcm=limvcmo1(v2/c2)=limvcm=limvcmo1(v2/c2)=

Section 9.2 Solutions

1. If ff is a polynomial function, the limit of a polynomial function as xx approaches aa will always be f(a)f(a).

3. It could mean either (1) the values of the function increase or decrease without bound as xx approaches cc, or (2) the left and right-hand limits are not equal.

5. 103103

7. 6

9. 1212

11. 6

13. does not exist

15. 1212

17. 510510

19. 108108

21. 1

23. 6

25. 1

27. 1

29. does not exist

31. 6+56+5

33. 3535

35. 0

37. 33

39. does not exist; right-hand limit is not the same as the left-hand limit.

41. Limit does not exist; limit approaches infinity.

43. 4x+2h4x+2h

45. 2x+h+42x+h+4

47. cos(x+h)cos(x)hcos(x+h)cos(x)h

49. 1x(x+h)1x(x+h)

51. 1x+h+x1x+h+x

53. f(x)=x2+5x+6x+3f(x)=x2+5x+6x+3

55. does not exist

57. 52

Section 9.3 Solutions

1. Informally, if a function is continuous at x=cx=c, then there is no break in the graph of the function at f(c)f(c), and f(c)f(c) is defined.

3. discontinuous at a=3a=3 ; f(3)f(3) does not exist

5. removable discontinuity at a=4a=4 ; f(4)f(4) is not defined

7. discontinuous at a=3a=3 ; limx3f(x)=3limx3f(x)=3, but f(3)=6f(3)=6, which is not equal to the limit.

9. limx2f(x)limx2f(x) does not exist.

11. limx1f(x)=4;limx1+f(x)=1limx1f(x)=4;limx1+f(x)=1 . Therefore, limx1f(x)limx1f(x) does not exist.

13. limx1f(x)=5limx1+f(x)=1limx1f(x)=5limx1+f(x)=1 . Thus limx1f(x)limx1f(x) does not exist.

15. limx3f(x)=6limx3f(x)=6 , limx3+f(x)=13limx3+f(x)=13

Therefore, limx3f(x)limx3f(x) does not exist.

17. f(2)f(2) is not defined.

19. f(3)f(3) is not defined.

21. f(0)f(0) is not defined.

23. Continuous on (,)(,)

25. Continuous on (,)(,)

27. Discontinuous at x=0x=0 and x=2x=2

29. Discontinuous at x=0x=0

31. Continuous on (0,)(0,)

33. Continuous on [4,)[4,)

35. Continuous on (,)(,) .

37. 1, but not 2 or 3

39. 1 and 2, but not 3

41. f(0)f(0) is undefined.

43. (,0)(0,)(,0)(0,)

45. At x=1x=1, the limit does not exist. At x=1x=1, f(1)f(1) does not exist.
At x=2x=2, there appears to be a vertical asymptote, and the limit does not exist.

47. x3+6x27x(x+7)(x1)x3+6x27x(x+7)(x1)

49. fx={x2+4x12x=1fx={x2+4x12x=1

Section 9.4 Solutions

1. The slope of a linear function stays the same. The derivative of a general function varies according to xx. Both the slope of a line and the derivative at a point measure the rate of change of the function.

3. Average velocity is 55 miles per hour. The instantaneous velocity at 2:30 p.m. is 62 miles per hour. The instantaneous velocity measures the velocity of the car at an instant of time whereas the average velocity gives the velocity of the car over an interval.

5. The average rate of change of the amount of water in the tank is 45 gallons per minute. If f(x)f(x) is the function giving the amount of water in the tank at any time tt, then the average rate of change of f(x)f(x) between t=at=a and t=bt=b is f(a)+45(ba)f(a)+45(ba).

7. f(x)=2

9. f(x)=4x+1

11. f(x)=1(x2)2

13. 16(3+2x)2

15. f(x)=9x22x+2

17. f(x)=0

19. 13

21. undefined

23. f(x)=6x7

25. f(x)=9x2+4x+1

27. y=12x15

29. k=10 or k=2

31. Discontinuous at x=2 and x=0. Not differentiable at –2, 0, 2.

33. Discontinuous at x=5. Not differentiable at -4, –2, 0, 1, 3, 4, 5.

35. f(0)=2

37. f(2)=6

39. f(1)=9

41. f(1)=3

43. f(3)=9

45. Answers vary. The slope of the tangent line near x=1 is 2.

47. At 12:30 p.m., the rate of change of the number of gallons in the tank is –20 gallons per minute. That is, the tank is losing 20 gallons per minute.

49. At 200 minutes after noon, the volume of gallons in the tank is changing at the rate of 30 gallons per minute.

51. The height of the projectile after 2 seconds is 96 feet.

53. The height of the projectile at t=3 seconds is 96 feet.

55. The height of the projectile is zero at t=0 and again at t=5. In other words, the projectile starts on the ground and falls to earth again after 5 seconds.

57. 36π

59. $50.00 per unit, which is the instantaneous rate of change of revenue when exactly 10 units are sold.

61. $21 per unit

63. $36

65. f'(x)=10a1

67. 4(3x)2