{"id":238,"date":"2023-02-01T00:03:42","date_gmt":"2023-02-01T00:03:42","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/chapter\/putting-it-together-voting-theory\/"},"modified":"2023-02-01T00:03:42","modified_gmt":"2023-02-01T00:03:42","slug":"putting-it-together-voting-theory","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/chapter\/putting-it-together-voting-theory\/","title":{"raw":"Putting It Together: Voting Theory","rendered":"Putting It Together: Voting Theory"},"content":{"raw":"\nThere are four candidates for senior class president, Garcia, Lee, Nguyen, and Smith. &nbsp;Using a preference ballot, [latex]75[\/latex] ballots were cast, and the votes are shown below.\n<div>\n<table style=\"width: 70%;\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]20[\/latex]<\/td>\n<td>[latex]3[\/latex]<\/td>\n<td>[latex]8[\/latex]<\/td>\n<td>[latex]16[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>1st choice<\/td>\n<td>Garcia<\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>2nd choice<\/td>\n<td>Lee<\/td>\n<td>Nguyen<\/td>\n<td>Nguyen<\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<\/tr>\n<tr>\n<td>3rd choice<\/td>\n<td>Nguyen<\/td>\n<td>Lee<\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<td>Garcia<\/td>\n<\/tr>\n<tr>\n<td>4th choice<\/td>\n<td>Smith<\/td>\n<td>Smith<\/td>\n<td>Smith<\/td>\n<td>Smith<\/td>\n<td>Nguyen<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n&nbsp;\n<p style=\"text-align: center;\"><em>Now that the votes are in, it should be a simple matter to find out who won the election, right? <\/em><\/p>\n<p style=\"text-align: center;\"><em>Well that depends on which voting system you choose.<\/em><\/p>\n&nbsp;\n\nUsing plurality method, Smith wins. &nbsp;This is because Smith got [latex]28[\/latex] first place votes, while Garcia received [latex]20+3=23[\/latex], Lee [latex]8[\/latex], and Nguyen [latex]16[\/latex]. &nbsp;However, Smith was the very last choice for the majority of the students! &nbsp;This seems rather unfair, so let\u2019s explore another method.\n\n&nbsp;\n\nThe Borda count assigns points based on the ranking: 4 points for first place, 3 for second, 2 for third, and 1 for last.\n<div>\n<table>\n<tbody>\n<tr>\n<td><\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>1st choice (4 pts)<\/td>\n<td>[latex]23\\times4=92[\/latex]<\/td>\n<td>[latex]8\\times4=32[\/latex]<\/td>\n<td>[latex]16\\times4=64[\/latex]<\/td>\n<td>[latex]28\\times4=112[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>2nd choice (3 pts)<\/td>\n<td>[latex]16\\times3=48[\/latex]<\/td>\n<td>[latex]48\\times3=144[\/latex]<\/td>\n<td>[latex]11\\times3=33[\/latex]<\/td>\n<td>[latex]0\\times3=0[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>3rd choice (2 pts)<\/td>\n<td>[latex]36\\times2=72[\/latex]<\/td>\n<td>[latex]19\\times2=38[\/latex]<\/td>\n<td>[latex]20\\times2=40[\/latex]<\/td>\n<td>[latex]0\\times2=0[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>4th choice (1 pt)<\/td>\n<td>[latex]0\\times1=0[\/latex]<\/td>\n<td>[latex]0\\times1=0[\/latex]<\/td>\n<td>[latex]28\\times1=28[\/latex]<\/td>\n<td>[latex]47\\times1=47[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Total&nbsp;Points<\/td>\n<td>[latex]212[\/latex]<\/td>\n<td>[latex]214[\/latex]<\/td>\n<td>[latex]165[\/latex]<\/td>\n<td>[latex]159[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n&nbsp;\n\nThis time Smith comes in last and Lee is the winner. &nbsp;However the preference votes indicate that Lee is a lukewarm choice for most people. &nbsp;Only [latex]8[\/latex] students chose Lee as their first choice. &nbsp;Perhaps another voting method will reflect the students\u2019 preferences better.\n\n&nbsp;\n\nLet\u2019s try instant runoff voting (IRV). &nbsp;This method proceeds in rounds, eliminating the candidate with the least number of first place votes at each round (with votes redistributed to voters\u2019 next choices) until a majority winner emerges. &nbsp;In the first round, Lee is immediately eliminated.\n<div>\n<table style=\"width: 70%;\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]20+3=23[\/latex]<\/td>\n<td>[latex]8+16=24[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>1st choice<\/td>\n<td>Garcia<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>2nd choice<\/td>\n<td>Nguyen<\/td>\n<td>Garcia<\/td>\n<td>Garcia<\/td>\n<\/tr>\n<tr>\n<td>3rd choice<\/td>\n<td>Smith<\/td>\n<td>Smith<\/td>\n<td>Nguyen<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\nThere is still no majority winner. &nbsp;Garcia is eliminated next, which gives the election to Nguyen.\n<div>\n<table style=\"width: 70%;\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]23+24=47[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>1st choice<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>2nd choice<\/td>\n<td>Smith<\/td>\n<td>Nguyen<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n&nbsp;\n\nFinally, let\u2019s see if there is a Condorcet winner. &nbsp;We examine all one-on-one contests based on the original preference schedule. &nbsp;The table below summarizes the results. &nbsp;Each column shows the total number of ballots in which that candidate beats the candidate listed in each row. &nbsp;Remember, a majority of the [latex]75[\/latex] votes would be at least [latex]38[\/latex] (majority votes are highlighted in blue).\n<div>\n<table style=\"width: 70%;\">\n<tbody>\n<tr>\n<td><\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>Garcia<\/td>\n<td><\/td>\n<td>[latex]36[\/latex]<\/td>\n<td>[latex]24[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Lee<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]39[\/latex]<\/td>\n<td><\/td>\n<td>[latex]19[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Nguyen<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]51[\/latex]<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]56[\/latex]<\/td>\n<td><\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Smith<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]47[\/latex]<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]47[\/latex]<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]47[\/latex]<\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\nGarcia is the Condorcet winner with [latex]39[\/latex], [latex]51[\/latex], and [latex]47[\/latex] votes against Lee, Nguyen, and Smith, respectively.\n\n&nbsp;\n\nWhich voting method do you think is the most fair? &nbsp;The same voting preference schedule produced four different \u201cwinners.\u201d &nbsp;In a close election with many competing preferences, perhaps there is no clear winner. &nbsp;However a decision must be made.\n\n&nbsp;\n\nThis small example serves to show why understanding voting theory helps to put the election process in perspective. &nbsp;At the end of the day, one voting method must be selected and the winner decided according to those agreed-upon rules. &nbsp;Try out some other voting methods and see if you can make a case for who should be the senior class president!\n","rendered":"<p>There are four candidates for senior class president, Garcia, Lee, Nguyen, and Smith. &nbsp;Using a preference ballot, [latex]75[\/latex] ballots were cast, and the votes are shown below.<\/p>\n<div>\n<table style=\"width: 70%;\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]20[\/latex]<\/td>\n<td>[latex]3[\/latex]<\/td>\n<td>[latex]8[\/latex]<\/td>\n<td>[latex]16[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>1st choice<\/td>\n<td>Garcia<\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>2nd choice<\/td>\n<td>Lee<\/td>\n<td>Nguyen<\/td>\n<td>Nguyen<\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<\/tr>\n<tr>\n<td>3rd choice<\/td>\n<td>Nguyen<\/td>\n<td>Lee<\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<td>Garcia<\/td>\n<\/tr>\n<tr>\n<td>4th choice<\/td>\n<td>Smith<\/td>\n<td>Smith<\/td>\n<td>Smith<\/td>\n<td>Smith<\/td>\n<td>Nguyen<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>&nbsp;<\/p>\n<p style=\"text-align: center;\"><em>Now that the votes are in, it should be a simple matter to find out who won the election, right? <\/em><\/p>\n<p style=\"text-align: center;\"><em>Well that depends on which voting system you choose.<\/em><\/p>\n<p>&nbsp;<\/p>\n<p>Using plurality method, Smith wins. &nbsp;This is because Smith got [latex]28[\/latex] first place votes, while Garcia received [latex]20+3=23[\/latex], Lee [latex]8[\/latex], and Nguyen [latex]16[\/latex]. &nbsp;However, Smith was the very last choice for the majority of the students! &nbsp;This seems rather unfair, so let\u2019s explore another method.<\/p>\n<p>&nbsp;<\/p>\n<p>The Borda count assigns points based on the ranking: 4 points for first place, 3 for second, 2 for third, and 1 for last.<\/p>\n<div>\n<table>\n<tbody>\n<tr>\n<td><\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>1st choice (4 pts)<\/td>\n<td>[latex]23\\times4=92[\/latex]<\/td>\n<td>[latex]8\\times4=32[\/latex]<\/td>\n<td>[latex]16\\times4=64[\/latex]<\/td>\n<td>[latex]28\\times4=112[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>2nd choice (3 pts)<\/td>\n<td>[latex]16\\times3=48[\/latex]<\/td>\n<td>[latex]48\\times3=144[\/latex]<\/td>\n<td>[latex]11\\times3=33[\/latex]<\/td>\n<td>[latex]0\\times3=0[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>3rd choice (2 pts)<\/td>\n<td>[latex]36\\times2=72[\/latex]<\/td>\n<td>[latex]19\\times2=38[\/latex]<\/td>\n<td>[latex]20\\times2=40[\/latex]<\/td>\n<td>[latex]0\\times2=0[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>4th choice (1 pt)<\/td>\n<td>[latex]0\\times1=0[\/latex]<\/td>\n<td>[latex]0\\times1=0[\/latex]<\/td>\n<td>[latex]28\\times1=28[\/latex]<\/td>\n<td>[latex]47\\times1=47[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Total&nbsp;Points<\/td>\n<td>[latex]212[\/latex]<\/td>\n<td>[latex]214[\/latex]<\/td>\n<td>[latex]165[\/latex]<\/td>\n<td>[latex]159[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>&nbsp;<\/p>\n<p>This time Smith comes in last and Lee is the winner. &nbsp;However the preference votes indicate that Lee is a lukewarm choice for most people. &nbsp;Only [latex]8[\/latex] students chose Lee as their first choice. &nbsp;Perhaps another voting method will reflect the students\u2019 preferences better.<\/p>\n<p>&nbsp;<\/p>\n<p>Let\u2019s try instant runoff voting (IRV). &nbsp;This method proceeds in rounds, eliminating the candidate with the least number of first place votes at each round (with votes redistributed to voters\u2019 next choices) until a majority winner emerges. &nbsp;In the first round, Lee is immediately eliminated.<\/p>\n<div>\n<table style=\"width: 70%;\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]20+3=23[\/latex]<\/td>\n<td>[latex]8+16=24[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>1st choice<\/td>\n<td>Garcia<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>2nd choice<\/td>\n<td>Nguyen<\/td>\n<td>Garcia<\/td>\n<td>Garcia<\/td>\n<\/tr>\n<tr>\n<td>3rd choice<\/td>\n<td>Smith<\/td>\n<td>Smith<\/td>\n<td>Nguyen<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>There is still no majority winner. &nbsp;Garcia is eliminated next, which gives the election to Nguyen.<\/p>\n<div>\n<table style=\"width: 70%;\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]23+24=47[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>1st choice<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>2nd choice<\/td>\n<td>Smith<\/td>\n<td>Nguyen<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>&nbsp;<\/p>\n<p>Finally, let\u2019s see if there is a Condorcet winner. &nbsp;We examine all one-on-one contests based on the original preference schedule. &nbsp;The table below summarizes the results. &nbsp;Each column shows the total number of ballots in which that candidate beats the candidate listed in each row. &nbsp;Remember, a majority of the [latex]75[\/latex] votes would be at least [latex]38[\/latex] (majority votes are highlighted in blue).<\/p>\n<div>\n<table style=\"width: 70%;\">\n<tbody>\n<tr>\n<td><\/td>\n<td>Garcia<\/td>\n<td>Lee<\/td>\n<td>Nguyen<\/td>\n<td>Smith<\/td>\n<\/tr>\n<tr>\n<td>Garcia<\/td>\n<td><\/td>\n<td>[latex]36[\/latex]<\/td>\n<td>[latex]24[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Lee<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]39[\/latex]<\/td>\n<td><\/td>\n<td>[latex]19[\/latex]<\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Nguyen<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]51[\/latex]<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]56[\/latex]<\/td>\n<td><\/td>\n<td>[latex]28[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Smith<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]47[\/latex]<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]47[\/latex]<\/td>\n<td style=\"background-color: #00a8e8;\">[latex]47[\/latex]<\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>Garcia is the Condorcet winner with [latex]39[\/latex], [latex]51[\/latex], and [latex]47[\/latex] votes against Lee, Nguyen, and Smith, respectively.<\/p>\n<p>&nbsp;<\/p>\n<p>Which voting method do you think is the most fair? &nbsp;The same voting preference schedule produced four different \u201cwinners.\u201d &nbsp;In a close election with many competing preferences, perhaps there is no clear winner. &nbsp;However a decision must be made.<\/p>\n<p>&nbsp;<\/p>\n<p>This small example serves to show why understanding voting theory helps to put the election process in perspective. &nbsp;At the end of the day, one voting method must be selected and the winner decided according to those agreed-upon rules. &nbsp;Try out some other voting methods and see if you can make a case for who should be the senior class president!<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-238\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li>Putting It Together: Voting Theory. <strong>Provided by<\/strong>: Lumen Learning. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":538461,"menu_order":23,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"Putting It Together: Voting Theory\",\"author\":\"\",\"organization\":\"Lumen Learning\",\"url\":\"\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"42132604-07d1-404d-9e8b-32b0fe50aac2","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-238","chapter","type-chapter","status-publish","hentry"],"part":215,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/pressbooks\/v2\/chapters\/238","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/wp\/v2\/users\/538461"}],"version-history":[{"count":0,"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/pressbooks\/v2\/chapters\/238\/revisions"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/pressbooks\/v2\/parts\/215"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/pressbooks\/v2\/chapters\/238\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/wp\/v2\/media?parent=238"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/pressbooks\/v2\/chapter-type?post=238"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/wp\/v2\/contributor?post=238"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ct-state-quantitative-reasoning\/wp-json\/wp\/v2\/license?post=238"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}