Many real-world applications (problems that can be modeled by a mathematical equation and solved for an unknown quantity) involve formulas that describe relationships between quantities. For example, wall-to-wall carpeting is sold by the square foot. To find out how much carpeting would cover the floor of a 12′ x 15′ foot room, we can multiply the length and width of the room to discover how many square feet of carpeting is required.  [latex]12 \times 15 = 180[/latex]. So, we would need to purchase 180 square feet of carpeting. Examples of formulas that commonly occur in applications include:

• the perimeter of a rectangle of length L and width W
  • [latex]P=2L+2W[/latex]
• the area of a rectangular region of length L and width W
  • [latex]A=LW[/latex]
• the volume of a rectangular solid with length L, width W, and height H
  • [latex]V=LWH[/latex]
• the distance [latex]d[/latex] covered when traveling at a constant rate [latex]r[/latex] for some time [latex]t[/latex]
  • [latex]d=rt[/latex].

Formulas such as these may be used to solve problems by substituting known values and solving for an unknown value. You should know these formulas and be able to recognize when to apply them to a problem.

Isolate Variables in Formulas

Sometimes, we need to isolate one of the variables in a formula in order to solve for the unknown. In the carpeting example above, we found that it would take 180 square feet of carpet to cover a 12′ x 15′ room. We knew the dimensions of the room and solved for how many square feet of carpet we needed, But what if, instead, we had tiles that we could use to cover the floor and we knew the length of the room, but needed to know what width room could be fully tiled?

Let’s say you have a banquet hall with one wall that can slide to create a room of variable width. The length of the room (the length of the movable wall) is 85 feet. If you have 4,590 square feet of tile, what must the width be to ensure the entire room is fully tiled?

Use the formula [latex]A=LW[/latex], but solve it for W, width. [latex]\dfrac{A}{L}=W[/latex]. Then, substitute what you know:

[latex]\dfrac{4590}{85} = W = 54[/latex]. It looks like we need to slide the wall out to create a width of 54 feet in order to use all the tile. .

This technique, isolating a variable of choice in any formula, is especially helpful if you have to perform the same calculation repeatedly, or you are having a computer perform the calculation repeatedly, for different values of the unknown variable.

Hopefully, you can see the value in being able to isolate a variable of interest! Here is another formula for which the skill is particularly useful.

The formula for converting from the Fahrenheit temperature scale to the Celsius scale is given by [latex]C=\left(F--32\right)\cdot\Large\frac{5}{9}[/latex]. This formula takes a temperature in Fahrenheit, [latex]F[/latex], and coverts it to an equivalent temperature in Celsius, [latex]C[/latex].

But what if we have the temperature in Celsius already, and wish to convert it to Fahrenheit? We can solve the formula for [latex]F[/latex]. This will give us a formula that takes a temperature on the Celsius scale and converts it to an equivalent Fahrenheit temperature.