{"id":1227,"date":"2022-04-07T22:43:36","date_gmt":"2022-04-07T22:43:36","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/?post_type=chapter&#038;p=1227"},"modified":"2022-05-20T21:43:55","modified_gmt":"2022-05-20T21:43:55","slug":"comparing-variability-of-data-sets-what-to-know-4","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/chapter\/comparing-variability-of-data-sets-what-to-know-4\/","title":{"raw":"Comparing Variability of Data Sets: What to Know 4","rendered":"Comparing Variability of Data Sets: What to Know 4"},"content":{"raw":"<div class=\"textbox tryit\">\r\n<h3>Standard Deviation<\/h3>\r\n<span style=\"background-color: #99cc00;\">[perspective video -- a 3-instructor video showing how to think about standard deviation as a measure of variability. Cover the parts of the formula (go into\u00a0why squaring, why\u00a0<em>df<\/em> if desired) but emphasize the concept of variability from std dev and variance more so than the technical use of the formula.]<\/span>\r\n\r\n<\/div>\r\n<h3>Standard Deviation<\/h3>\r\n<strong>Standard deviation<\/strong> is a measure of how spread out observations are from the mean. The symbol we use to denote standard deviation differs depending on whether we are discussing a sample or a population. We use the Greek letter [latex]\\sigma[\/latex] (sigma) to denote the standard deviation of a population of observations.\u00a0We use the Latin letter\u00a0[latex]s[\/latex]\u00a0to denote the standard deviation of a sample of observations.\r\n<div class=\"textbox shaded\">\r\n<h3 style=\"text-align: center;\">Standard Deviation<\/h3>\r\nThe following formulas are used to calculate the standard deviation of a population and a sample:\r\n<p style=\"padding-left: 30px;\"><strong>Standard deviation of a population<\/strong>: [latex]\\sigma = \\sqrt{\\dfrac{\\sum \\left(x-\\mu\\right)^2}{n}}[\/latex], where [latex]\\mu[\/latex] represents the population mean.<\/p>\r\n<p style=\"padding-left: 30px;\"><strong>Standard deviation of a sample<\/strong>: [latex]s=\\sqrt{\\dfrac{\\sum \\left(x-\\bar{x}\\right)^2}{n-1}} [\/latex], where [latex]\\bar{x}[\/latex] represents the sample mean.<\/p>\r\n\r\n<\/div>\r\n<span style=\"font-size: 1rem; text-align: initial;\">The following steps can be applied to calculate a standard deviation by hand.<\/span>\r\n<ol>\r\n \t<li>Calculate the mean of the population or sample.<\/li>\r\n \t<li>Take the difference between each data value and the mean. Then square each difference.<\/li>\r\n \t<li>Add up all the squared differences<\/li>\r\n \t<li>Divide by either the total number of observations in the case of a population or by 1 fewer than the total in the case of a sample.<\/li>\r\n \t<li>Take the square root of the result of the division in step 4.<\/li>\r\n<\/ol>\r\n<div class=\"textbox exercises\">\r\n<h3>example<\/h3>\r\nA sample of observations is listed below. Find its standard deviation.\r\n<p style=\"padding-left: 30px;\">[latex]8, 7, 13, 15, 23, 18[\/latex]<\/p>\r\n[reveal-answer q=\"911375\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"911375\"]\r\n\r\nFirst, calculate the mean of the sample observations.\r\n\r\n[latex]\\bar{x}=\\frac{84}{6}=14[\/latex]\r\n\r\nIdentify all the squared differences.\r\n\r\n[latex]\\left(8-14\\right)^{2}=36\\text{, } \\left(7-14\\right)^{2}=49\\text{, } \\left(13-14\\right)^{2}=1\\text{, } \\left(15-14\\right)^{2}=1\\text{, } \\left(23-14\\right)^{2}=81\\text{, } \\left(18-14\\right)^{2}=16\\\\ [\/latex]\r\n\r\nThen, take the square root of the sum of the squared differences divided by 1 less than the sample size.\r\n\r\n[latex]\\sqrt{\\dfrac{26+49+1+1+81+16}{6-1}}=\\sqrt{\\dfrac{184}{5}}\\approx{6.07}[\/latex]\r\n\r\nThis process would be too tedious for large samples or populations! We'll use technology to calculate standard deviation from now on. Try it now using the\u00a0<em>Describing and Exploring Quantitative Variables<\/em> tool at\u00a0<a href=\"https:\/\/dcmathpathways.shinyapps.io\/EDA_quantitative\/\" target=\"_blank\" rel=\"noopener\">https:\/\/dcmathpathways.shinyapps.io\/EDA_quantitative\/<\/a>.\u00a0 Choose \"Your Own\" under \"Enter Data\" and enter the observations\u00a0[latex]8, 7, 13, 15, 23, 18[\/latex] to read the Std. Dev. from Descriptive Statistics.\r\n\r\nDid you obtain the same result? That was much better than calculating it by hand!\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nHere is a breakdown of the formula for standard deviation of a sample, [latex]s[\/latex].\r\n<p style=\"text-align: center;\">[latex]s=\\sqrt{\\dfrac{\\sum \\left(x-\\bar{x}\\right)^2}{n-1}} [\/latex]<\/p>\r\n\r\n<ul>\r\n \t<li style=\"text-align: left;\">The distance from each observation to the mean is known as a <strong>deviation from the mean<\/strong> and is expressed as [latex]\\left(x-\\bar{x}\\right)[\/latex]<\/li>\r\n \t<li style=\"text-align: left;\"><strong>The deviations from the mean are squared<\/strong> in the formula because some observations are above the mean, thus [latex]\\left(x-\\bar{x}\\right)&gt;0[\/latex] (the difference is positive), and some observations are below the mean, thus [latex]\\left(x-\\bar{x}\\right)&lt;0[\/latex] (the difference is negative). Squaring ensures the differences will each be expressed as positive distances and won't cancel each other out when summed up.<\/li>\r\n \t<li style=\"text-align: left;\"><strong>The [latex]\\sum[\/latex] symbol sums up<\/strong> the squared deviations for all [latex]n[\/latex] observations.<span style=\"background-color: #00ffff;\">\r\n<\/span><\/li>\r\n \t<li><strong>The denominator in the formula for a sample standard deviation is [latex]\\left(n-1\\right)[\/latex]<\/strong> rather than [latex]n[\/latex] as in the formula for the population standard deviation.\r\n<ul>\r\n \t<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 1rem; orphans: 1; text-align: initial;\">Why do we divide by 1 fewer than the sample size, <strong>[latex]\\left(n-1\\right)[\/latex]<\/strong>?<\/span>\r\n<ul>\r\n \t<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 1rem; orphans: 1; text-align: initial;\">[reveal-answer q=\"329088\"]The answer to that is complicated but here are some ideas that may help[\/reveal-answer]<\/span><\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ul>\r\n<\/li>\r\n<\/ul>\r\n<p style=\"padding-left: 30px;\">[hidden-answer a=\"329088\"]<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<p style=\"padding-left: 30px;\"><strong>Why do we divide by [latex]\\left(n-1\\right)[\/latex]?\u00a0<\/strong><\/p>\r\n\r\n<ul>\r\n \t<li><strong>Because the sample standard deviation is an underestimation.\u00a0<\/strong>Recall that a sample is representative of a population if the characteristics of the sample tend to be similar to the characteristics of the population from which it was obtained. But the sample standard deviation tends to underestimate the population standard deviation\u00a0(this can be shown mathematically but its beyond the scope of what we need here). We can fix that by increasing the size of our sample standard deviation if we divide by [latex]\\left(n-1\\right)[\/latex] in the sample standard deviation formula rather than by [latex]n[\/latex].<\/li>\r\n \t<li><strong>Because we are using\u00a0<em>degrees of freedom<\/em> in the denominator.\u00a0<\/strong>You may have heard that the denominator in the standard deviation formula is called the\u00a0<em>degrees of freedom<\/em>, abbreviated <em>df<\/em>. That's true, and it helps us to compensate for the underestimation that crops up when we divide strictly by sample size. There's a lot going on here mathematically, but we can think of it this way: dividing by [latex]\\left(n-1\\right)[\/latex] instead of [latex]n[\/latex]\u00a0helps our sample standard deviation more closely resemble the true (usually unknowable) population standard deviation. This will help make our statistical analysis more reasonable.<\/li>\r\n \t<li><strong>What are degrees of freedom, anyway?<\/strong> A nice way to think of degrees of freedom, [latex]\\left(n-1\\right)[\/latex] is to imagine a set of three numbers whose mean is\u00a0[latex]5[\/latex]: say,\u00a0[latex]4, 5[\/latex], and\u00a0[latex]6[\/latex]. If those three numbers were written on pieces of paper in a hat, and you chose two of them, say\u00a0[latex]4[\/latex] and [latex]5[\/latex], first, then the only way to get a mean of\u00a0[latex]5[\/latex] from the numbers on three scraps of paper would be that the next choice must have a\u00a0[latex]6[\/latex] on it. We could say that the first two scraps were <em>free to vary<\/em>; they could have been\u00a0[latex]4[\/latex] or\u00a0[latex]5[\/latex] or\u00a0[latex]6[\/latex] as they pleased. But the third pick couldn't vary. After choosing the\u00a0[latex]4[\/latex] and the\u00a0[latex]5[\/latex] freely first, there was no freedom for the choice of the third in order to obtain the desired mean. Only two of our choices had a degree of freedom, so we say that the degrees of freedom of a sample size of\u00a0[latex]3[\/latex] is [latex]\\left(3-1\\right)=2[\/latex].<\/li>\r\n \t<li><span style=\"background-color: #ffff99;\">Insert video explanation of the idea of n-1 as degrees of freedom. DC suggested this one:\u00a0<\/span>For a more detailed discussion, see <a href=\"https:\/\/www.khanacademy.org\/math\/ap-statistics\/summarizing-quantitative-data-ap\/more-standard-deviation\/v\/review-and-intuition-why-we-divide-by-n-1-for-the-unbiased-sample-variance\">https:\/\/www.khanacademy.org\/math\/ap-statistics\/summarizing-quantitative-data-ap\/more-standard-deviation\/v\/review-and-intuition-why-we-divide-by-n-1-for-the-unbiased-sample-variance<\/a><\/li>\r\n<\/ul>\r\n<\/div>\r\n<span style=\"font-size: 1rem; orphans: 1; text-align: initial;\">[\/hidden-answer]<\/span>\r\n<ul>\r\n \t<li><span style=\"font-size: 1em;\"><strong>The square root is taken<\/strong> in order to express the spread in terms of the units of the observations.\u00a0<\/span>Recall that we squared the differences to express them as positive distances, which resulted in squared observation units. Taking the square root can be thought of as \"undoing\" the earlier squaring.\u00a0For example, assume that within the context in which you are working, the data are in terms of dollars. If we do not take the square root, the standard deviation will be\u00a0in terms of dollars squared, which is not something commonly used.<\/li>\r\n \t<li><strong>The standard deviation, [latex]s[\/latex], represents the \u201ctypical\u201d distance of an observation from the mean of the data set.<\/strong><\/li>\r\n<\/ul>\r\nDon\u2019t worry. We will be using the\u00a0data analysis tool to calculate standard deviation for us!\r\n\r\nLet's practice using the tool by finding the standard deviation of the variable Average Sleep in the Sleep Study data set.\r\n<div class=\"textbox tryit\">\r\n<h3>Use a data analysis tool to identify the standard deviation of a data set<\/h3>\r\n<span style=\"background-color: #99cc00;\">[Worked example video - a 3-instructor video showing how to use the tool as in Questions 6 - 8 to calculate standard deviation, variance, and range with commentary on what these values imply for there being \"more\" or \"less\" variability in the data. <\/span>\r\n\r\n<\/div>\r\n<div class=\"textbox\">\r\n\r\nGo to the <em>Describing and Exploring Quantitative Variables<\/em> tool at <a href=\"https:\/\/dcmathpathways.shinyapps.io\/EDA_quantitative\/\" target=\"_blank\" rel=\"noopener\">https:\/\/dcmathpathways.shinyapps.io\/EDA_quantitative\/<\/a>.\r\n<p style=\"padding-left: 30px;\">Step 1) Select the <strong>Single Group<\/strong> tab.<\/p>\r\n<p style=\"padding-left: 30px;\">Step 2) Locate the drop-down menu under <strong>Enter Data<\/strong> and select <strong>From Textbook<\/strong>.<\/p>\r\n<p style=\"padding-left: 30px;\">Step 3) Locate the drop-down menu under <strong>Data Set<\/strong> and select <strong>Sleep Study: Average Sleep<\/strong>.<\/p>\r\n\r\n<\/div>\r\n<div class=\"textbox key-takeaways\">\r\n<h3>question 6<\/h3>\r\n[ohm_question hide_question_numbers=1]241060[\/ohm_question]\r\n\r\n[reveal-answer q=\"805189\"]Hint[\/reveal-answer]\r\n[hidden-answer a=\"805189\"]In the tool, look for \u201cStd. Dev.\u201d in the table under Descriptive Statistics.[\/hidden-answer]\r\n\r\n<\/div>\r\nOn the next page, you will continue to explore the measures of variability (spread) by taking a look at variance and range.","rendered":"<div class=\"textbox tryit\">\n<h3>Standard Deviation<\/h3>\n<p><span style=\"background-color: #99cc00;\">[perspective video &#8212; a 3-instructor video showing how to think about standard deviation as a measure of variability. Cover the parts of the formula (go into\u00a0why squaring, why\u00a0<em>df<\/em> if desired) but emphasize the concept of variability from std dev and variance more so than the technical use of the formula.]<\/span><\/p>\n<\/div>\n<h3>Standard Deviation<\/h3>\n<p><strong>Standard deviation<\/strong> is a measure of how spread out observations are from the mean. The symbol we use to denote standard deviation differs depending on whether we are discussing a sample or a population. We use the Greek letter [latex]\\sigma[\/latex] (sigma) to denote the standard deviation of a population of observations.\u00a0We use the Latin letter\u00a0[latex]s[\/latex]\u00a0to denote the standard deviation of a sample of observations.<\/p>\n<div class=\"textbox shaded\">\n<h3 style=\"text-align: center;\">Standard Deviation<\/h3>\n<p>The following formulas are used to calculate the standard deviation of a population and a sample:<\/p>\n<p style=\"padding-left: 30px;\"><strong>Standard deviation of a population<\/strong>: [latex]\\sigma = \\sqrt{\\dfrac{\\sum \\left(x-\\mu\\right)^2}{n}}[\/latex], where [latex]\\mu[\/latex] represents the population mean.<\/p>\n<p style=\"padding-left: 30px;\"><strong>Standard deviation of a sample<\/strong>: [latex]s=\\sqrt{\\dfrac{\\sum \\left(x-\\bar{x}\\right)^2}{n-1}}[\/latex], where [latex]\\bar{x}[\/latex] represents the sample mean.<\/p>\n<\/div>\n<p><span style=\"font-size: 1rem; text-align: initial;\">The following steps can be applied to calculate a standard deviation by hand.<\/span><\/p>\n<ol>\n<li>Calculate the mean of the population or sample.<\/li>\n<li>Take the difference between each data value and the mean. Then square each difference.<\/li>\n<li>Add up all the squared differences<\/li>\n<li>Divide by either the total number of observations in the case of a population or by 1 fewer than the total in the case of a sample.<\/li>\n<li>Take the square root of the result of the division in step 4.<\/li>\n<\/ol>\n<div class=\"textbox exercises\">\n<h3>example<\/h3>\n<p>A sample of observations is listed below. Find its standard deviation.<\/p>\n<p style=\"padding-left: 30px;\">[latex]8, 7, 13, 15, 23, 18[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q911375\">Show Solution<\/span><\/p>\n<div id=\"q911375\" class=\"hidden-answer\" style=\"display: none\">\n<p>First, calculate the mean of the sample observations.<\/p>\n<p>[latex]\\bar{x}=\\frac{84}{6}=14[\/latex]<\/p>\n<p>Identify all the squared differences.<\/p>\n<p>[latex]\\left(8-14\\right)^{2}=36\\text{, } \\left(7-14\\right)^{2}=49\\text{, } \\left(13-14\\right)^{2}=1\\text{, } \\left(15-14\\right)^{2}=1\\text{, } \\left(23-14\\right)^{2}=81\\text{, } \\left(18-14\\right)^{2}=16\\\\[\/latex]<\/p>\n<p>Then, take the square root of the sum of the squared differences divided by 1 less than the sample size.<\/p>\n<p>[latex]\\sqrt{\\dfrac{26+49+1+1+81+16}{6-1}}=\\sqrt{\\dfrac{184}{5}}\\approx{6.07}[\/latex]<\/p>\n<p>This process would be too tedious for large samples or populations! We&#8217;ll use technology to calculate standard deviation from now on. Try it now using the\u00a0<em>Describing and Exploring Quantitative Variables<\/em> tool at\u00a0<a href=\"https:\/\/dcmathpathways.shinyapps.io\/EDA_quantitative\/\" target=\"_blank\" rel=\"noopener\">https:\/\/dcmathpathways.shinyapps.io\/EDA_quantitative\/<\/a>.\u00a0 Choose &#8220;Your Own&#8221; under &#8220;Enter Data&#8221; and enter the observations\u00a0[latex]8, 7, 13, 15, 23, 18[\/latex] to read the Std. Dev. from Descriptive Statistics.<\/p>\n<p>Did you obtain the same result? That was much better than calculating it by hand!<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>Here is a breakdown of the formula for standard deviation of a sample, [latex]s[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]s=\\sqrt{\\dfrac{\\sum \\left(x-\\bar{x}\\right)^2}{n-1}}[\/latex]<\/p>\n<ul>\n<li style=\"text-align: left;\">The distance from each observation to the mean is known as a <strong>deviation from the mean<\/strong> and is expressed as [latex]\\left(x-\\bar{x}\\right)[\/latex]<\/li>\n<li style=\"text-align: left;\"><strong>The deviations from the mean are squared<\/strong> in the formula because some observations are above the mean, thus [latex]\\left(x-\\bar{x}\\right)>0[\/latex] (the difference is positive), and some observations are below the mean, thus [latex]\\left(x-\\bar{x}\\right)<0[\/latex] (the difference is negative). Squaring ensures the differences will each be expressed as positive distances and won&#8217;t cancel each other out when summed up.<\/li>\n<li style=\"text-align: left;\"><strong>The [latex]\\sum[\/latex] symbol sums up<\/strong> the squared deviations for all [latex]n[\/latex] observations.<span style=\"background-color: #00ffff;\"><br \/>\n<\/span><\/li>\n<li><strong>The denominator in the formula for a sample standard deviation is [latex]\\left(n-1\\right)[\/latex]<\/strong> rather than [latex]n[\/latex] as in the formula for the population standard deviation.\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 1rem; orphans: 1; text-align: initial;\">Why do we divide by 1 fewer than the sample size, <strong>[latex]\\left(n-1\\right)[\/latex]<\/strong>?<\/span>\n<ul>\n<li style=\"font-weight: 400;\" aria-level=\"1\"><span style=\"font-size: 1rem; orphans: 1; text-align: initial;\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q329088\">The answer to that is complicated but here are some ideas that may help<\/span><\/span><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<p style=\"padding-left: 30px;\">\n<div id=\"q329088\" class=\"hidden-answer\" style=\"display: none\">\n<div class=\"textbox shaded\">\n<p style=\"padding-left: 30px;\"><strong>Why do we divide by [latex]\\left(n-1\\right)[\/latex]?\u00a0<\/strong><\/p>\n<ul>\n<li><strong>Because the sample standard deviation is an underestimation.\u00a0<\/strong>Recall that a sample is representative of a population if the characteristics of the sample tend to be similar to the characteristics of the population from which it was obtained. But the sample standard deviation tends to underestimate the population standard deviation\u00a0(this can be shown mathematically but its beyond the scope of what we need here). We can fix that by increasing the size of our sample standard deviation if we divide by [latex]\\left(n-1\\right)[\/latex] in the sample standard deviation formula rather than by [latex]n[\/latex].<\/li>\n<li><strong>Because we are using\u00a0<em>degrees of freedom<\/em> in the denominator.\u00a0<\/strong>You may have heard that the denominator in the standard deviation formula is called the\u00a0<em>degrees of freedom<\/em>, abbreviated <em>df<\/em>. That&#8217;s true, and it helps us to compensate for the underestimation that crops up when we divide strictly by sample size. There&#8217;s a lot going on here mathematically, but we can think of it this way: dividing by [latex]\\left(n-1\\right)[\/latex] instead of [latex]n[\/latex]\u00a0helps our sample standard deviation more closely resemble the true (usually unknowable) population standard deviation. This will help make our statistical analysis more reasonable.<\/li>\n<li><strong>What are degrees of freedom, anyway?<\/strong> A nice way to think of degrees of freedom, [latex]\\left(n-1\\right)[\/latex] is to imagine a set of three numbers whose mean is\u00a0[latex]5[\/latex]: say,\u00a0[latex]4, 5[\/latex], and\u00a0[latex]6[\/latex]. If those three numbers were written on pieces of paper in a hat, and you chose two of them, say\u00a0[latex]4[\/latex] and [latex]5[\/latex], first, then the only way to get a mean of\u00a0[latex]5[\/latex] from the numbers on three scraps of paper would be that the next choice must have a\u00a0[latex]6[\/latex] on it. We could say that the first two scraps were <em>free to vary<\/em>; they could have been\u00a0[latex]4[\/latex] or\u00a0[latex]5[\/latex] or\u00a0[latex]6[\/latex] as they pleased. But the third pick couldn&#8217;t vary. After choosing the\u00a0[latex]4[\/latex] and the\u00a0[latex]5[\/latex] freely first, there was no freedom for the choice of the third in order to obtain the desired mean. Only two of our choices had a degree of freedom, so we say that the degrees of freedom of a sample size of\u00a0[latex]3[\/latex] is [latex]\\left(3-1\\right)=2[\/latex].<\/li>\n<li><span style=\"background-color: #ffff99;\">Insert video explanation of the idea of n-1 as degrees of freedom. DC suggested this one:\u00a0<\/span>For a more detailed discussion, see <a href=\"https:\/\/www.khanacademy.org\/math\/ap-statistics\/summarizing-quantitative-data-ap\/more-standard-deviation\/v\/review-and-intuition-why-we-divide-by-n-1-for-the-unbiased-sample-variance\">https:\/\/www.khanacademy.org\/math\/ap-statistics\/summarizing-quantitative-data-ap\/more-standard-deviation\/v\/review-and-intuition-why-we-divide-by-n-1-for-the-unbiased-sample-variance<\/a><\/li>\n<\/ul>\n<\/div>\n<p><span style=\"font-size: 1rem; orphans: 1; text-align: initial;\"><\/div>\n<\/div>\n<p><\/span><\/p>\n<ul>\n<li><span style=\"font-size: 1em;\"><strong>The square root is taken<\/strong> in order to express the spread in terms of the units of the observations.\u00a0<\/span>Recall that we squared the differences to express them as positive distances, which resulted in squared observation units. Taking the square root can be thought of as &#8220;undoing&#8221; the earlier squaring.\u00a0For example, assume that within the context in which you are working, the data are in terms of dollars. If we do not take the square root, the standard deviation will be\u00a0in terms of dollars squared, which is not something commonly used.<\/li>\n<li><strong>The standard deviation, [latex]s[\/latex], represents the \u201ctypical\u201d distance of an observation from the mean of the data set.<\/strong><\/li>\n<\/ul>\n<p>Don\u2019t worry. We will be using the\u00a0data analysis tool to calculate standard deviation for us!<\/p>\n<p>Let&#8217;s practice using the tool by finding the standard deviation of the variable Average Sleep in the Sleep Study data set.<\/p>\n<div class=\"textbox tryit\">\n<h3>Use a data analysis tool to identify the standard deviation of a data set<\/h3>\n<p><span style=\"background-color: #99cc00;\">[Worked example video &#8211; a 3-instructor video showing how to use the tool as in Questions 6 &#8211; 8 to calculate standard deviation, variance, and range with commentary on what these values imply for there being &#8220;more&#8221; or &#8220;less&#8221; variability in the data. <\/span><\/p>\n<\/div>\n<div class=\"textbox\">\n<p>Go to the <em>Describing and Exploring Quantitative Variables<\/em> tool at <a href=\"https:\/\/dcmathpathways.shinyapps.io\/EDA_quantitative\/\" target=\"_blank\" rel=\"noopener\">https:\/\/dcmathpathways.shinyapps.io\/EDA_quantitative\/<\/a>.<\/p>\n<p style=\"padding-left: 30px;\">Step 1) Select the <strong>Single Group<\/strong> tab.<\/p>\n<p style=\"padding-left: 30px;\">Step 2) Locate the drop-down menu under <strong>Enter Data<\/strong> and select <strong>From Textbook<\/strong>.<\/p>\n<p style=\"padding-left: 30px;\">Step 3) Locate the drop-down menu under <strong>Data Set<\/strong> and select <strong>Sleep Study: Average Sleep<\/strong>.<\/p>\n<\/div>\n<div class=\"textbox key-takeaways\">\n<h3>question 6<\/h3>\n<p><iframe loading=\"lazy\" id=\"ohm241060\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=241060&theme=oea&iframe_resize_id=ohm241060\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q805189\">Hint<\/span><\/p>\n<div id=\"q805189\" class=\"hidden-answer\" style=\"display: none\">In the tool, look for \u201cStd. Dev.\u201d in the table under Descriptive Statistics.<\/div>\n<\/div>\n<\/div>\n<p>On the next page, you will continue to explore the measures of variability (spread) by taking a look at variance and range.<\/p>\n","protected":false},"author":493460,"menu_order":39,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1227","chapter","type-chapter","status-publish","hentry"],"part":1252,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/pressbooks\/v2\/chapters\/1227","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/wp\/v2\/users\/493460"}],"version-history":[{"count":5,"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/pressbooks\/v2\/chapters\/1227\/revisions"}],"predecessor-version":[{"id":1267,"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/pressbooks\/v2\/chapters\/1227\/revisions\/1267"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/pressbooks\/v2\/parts\/1252"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/pressbooks\/v2\/chapters\/1227\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/wp\/v2\/media?parent=1227"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/pressbooks\/v2\/chapter-type?post=1227"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/wp\/v2\/contributor?post=1227"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/exemplarstatistics\/wp-json\/wp\/v2\/license?post=1227"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}