{"id":1824,"date":"2021-09-10T15:45:21","date_gmt":"2021-09-10T15:45:21","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/introstatscorequisite\/?post_type=chapter&#038;p=1824"},"modified":"2022-02-07T18:47:12","modified_gmt":"2022-02-07T18:47:12","slug":"solving-quadratic-equations-by-the-square-root-property","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/introstatscorequisite\/chapter\/solving-quadratic-equations-by-the-square-root-property\/","title":{"raw":"Solving Quadratic Equations by the Square Root Property","rendered":"Solving Quadratic Equations by the Square Root Property"},"content":{"raw":"<div class=\"textbox learning-objectives\">\r\n<h3>Learning Outcomes<\/h3>\r\n<section>\r\n<ul id=\"list6234\">\r\n \t<li>Use the square root property to solve a quadratic equation<\/li>\r\n<\/ul>\r\n<\/section><\/div>\r\nThe\u00a0<strong>principal square root<\/strong> of a nonnegative number [latex]x[\/latex] is defined to be the nonnegative number [latex]a[\/latex] such that [latex]a^2=x[\/latex]. We write\r\n<p style=\"text-align: center;\">[latex]\\sqrt{x} = a [\/latex] if [latex]a^{2} = x[\/latex] where [latex]x \\geq 0, a \\geq0[\/latex].<\/p>\r\nFor example, [latex]\\sqrt{9} = 3[\/latex] since [latex]3^{2}=9[\/latex].\r\n\r\nA <strong>quadratic equation<\/strong> is an equation which can be written in the form\r\n\r\n[latex]ax^2 +bx +c =0[\/latex] where [latex]a,b,[\/latex] and [latex]c[\/latex] are constants, and [latex]a \\neq 0[\/latex].\r\n\r\nQuadratic equations which can be written in the form [latex]X^2 =k[\/latex], where [latex]X[\/latex]\u00a0is any variable expression and [latex]k[\/latex] is a nonnegative number can be solved by the <strong>square root property<\/strong>.\r\n<div class=\"textbox shaded\">\r\n<h3>The Square Root Property<\/h3>\r\nIf [latex]x^{2}=a[\/latex], then [latex] x=\\sqrt{a}[\/latex] or [latex] -\\sqrt{a}[\/latex].\r\n\r\n&nbsp;\r\n\r\nThe solutions of [latex]x^2=a[\/latex] are called the square roots of <em>a<\/em>.\r\n<ul>\r\n \t<li>When <em>a<\/em> is positive, [latex]a &gt; 0[\/latex], [latex]x^2=a[\/latex] has two solutions, [latex]+\\sqrt{a},-\\sqrt{a}[\/latex]. [latex]+\\sqrt{a}[\/latex] is the nonnegative square root of <em>a<\/em>, and [latex]-\\sqrt{a}[\/latex] is the negative square root of <em>a<\/em>.<\/li>\r\n \t<li>When <em>a<\/em> is negative, [latex]a &lt; 0[\/latex], [latex]x^2=a[\/latex] has no solutions.<\/li>\r\n \t<li>When <em>a<\/em> is zero, [latex]a = 0[\/latex], [latex]x^2=a[\/latex] has one solution: [latex]a = 0[\/latex]<\/li>\r\n<\/ul>\r\n<\/div>\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example<\/h3>\r\nSolve using the square root property. [latex]x^{2}=16[\/latex]\r\n\r\n[reveal-answer q=\"793132\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"793132\"]\r\n\r\nBy the square root property,\r\n<p style=\"text-align: center;\">[latex]x = \\pm \\sqrt{16} = \\pm 4[\/latex]<\/p>\r\n<p style=\"text-align: center;\">Then the equation has two solutions, [latex]x=4[\/latex] and [latex]x=-4[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nIn the example above, you can take the square root of both sides easily because there is only one term on each side. In some equations, you may need to isolate the second-degree (squared) expression before applying the square root property.\r\n\r\nIn our first video, we will show more examples of using the square root property to solve a quadratic equation.\r\n\r\nhttps:\/\/youtu.be\/Fj-BP7uaWrI\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example<\/h3>\r\nSolve [latex]3x^2-1=74[\/latex].\r\n\r\n[reveal-answer q=\"116387\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"116387\"]\r\n\r\nFirst, isolate [latex]x^2[\/latex].\r\n<p style=\"text-align: center;\">[latex]3x^2-1=74[\/latex]<\/p>\r\nAdd [latex]1[\/latex] to each side.\r\n<p style=\"text-align: center;\">[latex]3x^2=75[\/latex]<\/p>\r\nDivide each side by [latex]3[\/latex].\r\n<p style=\"text-align: center;\">[latex]\\frac{3x^2}{3} = \\frac{75}{3}[\/latex]<\/p>\r\nSimplify.\r\n<p style=\"text-align: center;\">[latex]x^2=25[\/latex]<\/p>\r\nApply the square root property.\r\n<p style=\"text-align: center;\">[latex]x = \\pm \\sqrt{25} = \\pm 5[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<div class=\"textbox key-takeaways\">\r\n<h3>Try It<\/h3>\r\n[ohm_question]197330[\/ohm_question]\r\n\r\n<\/div>\r\nSometimes more than just a single variable is being squared.\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example<\/h3>\r\nSolve [latex](x-1)^2=16[\/latex].\r\n\r\n[reveal-answer q=\"3817\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"3817\"]\r\n\r\nSince the equation has the second-degree expression isolated, we can begin by applying the\u00a0square root property.\r\n<p style=\"text-align: center;\">[latex]x-1= \\pm \\sqrt{16}[\/latex]<\/p>\r\n<p style=\"text-align: center;\">[latex]x-1= \\pm4[\/latex]<\/p>\r\nThis gives two equations:\r\n<p style=\"text-align: center;\">[latex]x-1=4[\/latex] or [latex]x-1=-4[\/latex]<\/p>\r\nWe solve each equation by adding [latex]1[\/latex] to each side.\r\n<p style=\"text-align: center;\">[latex]x=5[\/latex] or [latex]x=-3[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nIn the next video, you will see more examples of using square roots to solve quadratic equations.\r\n\r\nhttps:\/\/youtu.be\/4H5qZ_-8YM4","rendered":"<div class=\"textbox learning-objectives\">\n<h3>Learning Outcomes<\/h3>\n<section>\n<ul id=\"list6234\">\n<li>Use the square root property to solve a quadratic equation<\/li>\n<\/ul>\n<\/section>\n<\/div>\n<p>The\u00a0<strong>principal square root<\/strong> of a nonnegative number [latex]x[\/latex] is defined to be the nonnegative number [latex]a[\/latex] such that [latex]a^2=x[\/latex]. We write<\/p>\n<p style=\"text-align: center;\">[latex]\\sqrt{x} = a[\/latex] if [latex]a^{2} = x[\/latex] where [latex]x \\geq 0, a \\geq0[\/latex].<\/p>\n<p>For example, [latex]\\sqrt{9} = 3[\/latex] since [latex]3^{2}=9[\/latex].<\/p>\n<p>A <strong>quadratic equation<\/strong> is an equation which can be written in the form<\/p>\n<p>[latex]ax^2 +bx +c =0[\/latex] where [latex]a,b,[\/latex] and [latex]c[\/latex] are constants, and [latex]a \\neq 0[\/latex].<\/p>\n<p>Quadratic equations which can be written in the form [latex]X^2 =k[\/latex], where [latex]X[\/latex]\u00a0is any variable expression and [latex]k[\/latex] is a nonnegative number can be solved by the <strong>square root property<\/strong>.<\/p>\n<div class=\"textbox shaded\">\n<h3>The Square Root Property<\/h3>\n<p>If [latex]x^{2}=a[\/latex], then [latex]x=\\sqrt{a}[\/latex] or [latex]-\\sqrt{a}[\/latex].<\/p>\n<p>&nbsp;<\/p>\n<p>The solutions of [latex]x^2=a[\/latex] are called the square roots of <em>a<\/em>.<\/p>\n<ul>\n<li>When <em>a<\/em> is positive, [latex]a > 0[\/latex], [latex]x^2=a[\/latex] has two solutions, [latex]+\\sqrt{a},-\\sqrt{a}[\/latex]. [latex]+\\sqrt{a}[\/latex] is the nonnegative square root of <em>a<\/em>, and [latex]-\\sqrt{a}[\/latex] is the negative square root of <em>a<\/em>.<\/li>\n<li>When <em>a<\/em> is negative, [latex]a < 0[\/latex], [latex]x^2=a[\/latex] has no solutions.<\/li>\n<li>When <em>a<\/em> is zero, [latex]a = 0[\/latex], [latex]x^2=a[\/latex] has one solution: [latex]a = 0[\/latex]<\/li>\n<\/ul>\n<\/div>\n<div class=\"bcc-box bcc-info\">\n<h3>Example<\/h3>\n<p>Solve using the square root property. [latex]x^{2}=16[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q793132\">Show Solution<\/span><\/p>\n<div id=\"q793132\" class=\"hidden-answer\" style=\"display: none\">\n<p>By the square root property,<\/p>\n<p style=\"text-align: center;\">[latex]x = \\pm \\sqrt{16} = \\pm 4[\/latex]<\/p>\n<p style=\"text-align: center;\">Then the equation has two solutions, [latex]x=4[\/latex] and [latex]x=-4[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>In the example above, you can take the square root of both sides easily because there is only one term on each side. In some equations, you may need to isolate the second-degree (squared) expression before applying the square root property.<\/p>\n<p>In our first video, we will show more examples of using the square root property to solve a quadratic equation.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Ex 1:  Solving Quadratic Equations Using Square Roots\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/Fj-BP7uaWrI?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Example<\/h3>\n<p>Solve [latex]3x^2-1=74[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q116387\">Show Answer<\/span><\/p>\n<div id=\"q116387\" class=\"hidden-answer\" style=\"display: none\">\n<p>First, isolate [latex]x^2[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]3x^2-1=74[\/latex]<\/p>\n<p>Add [latex]1[\/latex] to each side.<\/p>\n<p style=\"text-align: center;\">[latex]3x^2=75[\/latex]<\/p>\n<p>Divide each side by [latex]3[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]\\frac{3x^2}{3} = \\frac{75}{3}[\/latex]<\/p>\n<p>Simplify.<\/p>\n<p style=\"text-align: center;\">[latex]x^2=25[\/latex]<\/p>\n<p>Apply the square root property.<\/p>\n<p style=\"text-align: center;\">[latex]x = \\pm \\sqrt{25} = \\pm 5[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox key-takeaways\">\n<h3>Try It<\/h3>\n<p><iframe loading=\"lazy\" id=\"ohm197330\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=197330&theme=oea&iframe_resize_id=ohm197330&show_question_numbers\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<\/div>\n<p>Sometimes more than just a single variable is being squared.<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Example<\/h3>\n<p>Solve [latex](x-1)^2=16[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q3817\">Show Answer<\/span><\/p>\n<div id=\"q3817\" class=\"hidden-answer\" style=\"display: none\">\n<p>Since the equation has the second-degree expression isolated, we can begin by applying the\u00a0square root property.<\/p>\n<p style=\"text-align: center;\">[latex]x-1= \\pm \\sqrt{16}[\/latex]<\/p>\n<p style=\"text-align: center;\">[latex]x-1= \\pm4[\/latex]<\/p>\n<p>This gives two equations:<\/p>\n<p style=\"text-align: center;\">[latex]x-1=4[\/latex] or [latex]x-1=-4[\/latex]<\/p>\n<p>We solve each equation by adding [latex]1[\/latex] to each side.<\/p>\n<p style=\"text-align: center;\">[latex]x=5[\/latex] or [latex]x=-3[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>In the next video, you will see more examples of using square roots to solve quadratic equations.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Ex 2:  Solving Quadratic Equations Using Square Roots\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/4H5qZ_-8YM4?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1824\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li>Revision and Adaptation. <strong>Provided by<\/strong>: Lumen Learning. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Question ID: 197330. <strong>Provided by<\/strong>: Lumen Learning. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>College Algebra. <strong>Authored by<\/strong>: Abramson, Jay, et al. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/openstax.org\/books\/college-algebra\/pages\/1-introduction-to-prerequisites\">https:\/\/openstax.org\/books\/college-algebra\/pages\/1-introduction-to-prerequisites<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Access for free at https:\/\/openstax.org\/books\/college-algebra\/pages\/1-introduction-to-prerequisites<\/li><li>Ex 1: Solving Quadratic Equations Using Square Roots. <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com) for Lumen Learning. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/Fj-BP7uaWrI\">https:\/\/youtu.be\/Fj-BP7uaWrI<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Ex 2: Solving Quadratic Equations Using Square Roots. <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com) for Lumen Learning. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/4H5qZ_-8YM4\">https:\/\/youtu.be\/4H5qZ_-8YM4<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":169134,"menu_order":4,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"College Algebra\",\"author\":\"Abramson, Jay, et 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Learning\",\"organization\":\"\",\"url\":\"https:\/\/youtu.be\/4H5qZ_-8YM4\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"original\",\"description\":\"Question ID: 197330\",\"author\":\"\",\"organization\":\"Lumen 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