Solutions to Try Its
1. End behavior: as x→±∞,f(x)→0x→±∞,f(x)→0; Local behavior: as x→0,f(x)→∞x→0,f(x)→∞ (there are no x– or y-intercepts)
2. The function and the asymptotes are shifted 3 units right and 4 units down. As x→3,f(x)→∞, and as x→±∞,f(x)→−4.
The function is f(x)=1(x−3)2−4.
3. 1211
4. The domain is all real numbers except x=1 and x=5.
5. Removable discontinuity at x=5. Vertical asymptotes: x=0, x=1.
6. Vertical asymptotes at x=2 and x=−3; horizontal asymptote at y=4.
7. For the transformed reciprocal squared function, we find the rational form. f(x)=1(x−3)2−4=1−4(x−3)2(x−3)2=1−4(x2−6x+9)(x−3)(x−3)=−4x2+24x−35x2−6x+9
Because the numerator is the same degree as the denominator we know that as x→±∞,f(x)→−4;so y=−4 is the horizontal asymptote. Next, we set the denominator equal to zero, and find that the vertical asymptote is x=3, because as x→3,f(x)→∞. We then set the numerator equal to 0 and find the x-intercepts are at (2.5,0) and (3.5,0). Finally, we evaluate the function at 0 and find the y-intercept to be at (0,−359).
8. Horizontal asymptote at y=12. Vertical asymptotes at x=1andx=3. y-intercept at (0,43.)
x-intercepts at (2,0) and (−2,0). (−2,0) is a zero with multiplicity 2, and the graph bounces off the x-axis at this point. (2,0) is a single zero and the graph crosses the axis at this point.
Solutions to Try Its
1. The rational function will be represented by a quotient of polynomial functions.
3. The numerator and denominator must have a common factor.
5. Yes. The numerator of the formula of the functions would have only complex roots and/or factors common to both the numerator and denominator.
7. All reals x≠−1,1
9. All reals x≠−1,−2,1,2
11. V.A. at x=−25; H.A. at y=0; Domain is all reals x≠−25
13. V.A. at x=4,−9; H.A. at y=0; Domain is all reals x≠4,−9
15. V.A. at x=0,4,−4; H.A. at y=0; Domain is all reals x≠0,4,−4
17. V.A. at x=−5; H.A. at y=0; Domain is all reals x≠5,−5
19. V.A. at x=13; H.A. at y=−23; Domain is all reals x≠13.
21. none
23. x-intercepts none, y-intercept (0,14)
25. Local behavior: x→−12+,f(x)→−∞,x→−12−,f(x)→∞
End behavior: x→±∞,f(x)→12
27. Local behavior: x→6+,f(x)→−∞,x→6−,f(x)→∞, End behavior: x→±∞,f(x)→−2
29. Local behavior: x→−13+,f(x)→∞,x→−13−, f(x)→−∞,x→52−,f(x)→∞,x→52+ , f(x)→−∞
End behavior: x→±∞, f(x)→13
31. y=2x+4
33. y=2x
35. V.A. x=0,H.A. y=2
37. V.A. x=2, H.A. y=0
39. V.A. x=−4, H.A. y=2;(32,0);(0,−34)
41. V.A. x=2, H.A. y=0, (0,1)
43. V.A. x=−4, x=43, H.A. y=1;(5,0);(−13,0);(0,516)
45. V.A. x=−1, H.A. y=1;(−3,0);(0,3)
47. V.A. x=4, S.A. y=2x+9;(−1,0);(12,0);(0,14)
49. V.A. x=−2, x=4, H.A. y=1,(1,0);(5,0);(−3,0);(0,−1516)
51. y=50x2−x−2x2−25
53. y=7x2+2x−24x2+9x+20
55. y=12x2−4x+4x+1
57. y=4x−3x2−x−12
59. y=−9x−2x2−9
61. y=13x2+x−6x−1
63. y=−6(x−1)2(x+3)(x−2)2
65.
x | 2.01 | 2.001 | 2.0001 | 1.99 | 1.999 |
y | 100 | 1,000 | 10,000 | –100 | –1,000 |
x | 10 | 100 | 1,000 | 10,000 | 100,000 |
y | .125 | .0102 | .001 | .0001 | .00001 |
Vertical asymptote x=2, Horizontal asymptote y=0
67.
x | –4.1 | –4.01 | –4.001 | –3.99 | –3.999 |
y | 82 | 802 | 8,002 | –798 | –7998 |
x | 10 | 100 | 1,000 | 10,000 | 100,000 |
y | 1.4286 | 1.9331 | 1.992 | 1.9992 | 1.999992 |
Vertical asymptote x=−4, Horizontal asymptote y=2
69.
x | –.9 | –.99 | –.999 | –1.1 | –1.01 |
y | 81 | 9,801 | 998,001 | 121 | 10,201 |
x | 10 | 100 | 1,000 | 10,000 | 100,000 |
y | .82645 | .9803 | .998 | .9998 |
Vertical asymptote x=−1, Horizontal asymptote y=1
71. (32,∞)
73. (−2,1)∪(4,∞)
75. (2,4)
77. (2,5)
79. (−1,1)
81. C(t)=8+2t300+20t
83. After about 6.12 hours.
85. A(x)=50x2+800x. 2 by 2 by 5 feet.
87. A(x)=πx2+100x. Radius = 2.52 meters.
Candela Citations
- Precalculus. Authored by: Jay Abramson, et al.. Provided by: OpenStax. Located at: http://cnx.org/contents/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175. License: CC BY: Attribution. License Terms: Download For Free at : http://cnx.org/contents/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.