{"id":2068,"date":"2015-11-12T18:30:42","date_gmt":"2015-11-12T18:30:42","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&p=2068"},"modified":"2017-04-03T19:32:46","modified_gmt":"2017-04-03T19:32:46","slug":"using-summation-notation","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/chapter\/using-summation-notation\/","title":{"raw":"Using Summation Notation","rendered":"Using Summation Notation"},"content":{"raw":"

To find the total amount of money in the college fund and the sum of the amounts deposited, we need to add the amounts deposited each month and the amounts earned monthly. The sum of the terms of a sequence is called a series<\/strong>. Consider, for example, the following series.\r\n<\/p>

[latex]3+7+11+15+19+..[\/latex].<\/div>\r\nThe [latex]n\\text{th }[\/latex] partial sum<\/strong> of a series is the sum of a finite number of consecutive terms beginning with the first term. The notation [latex]\\text{ }{S}_{n}\\text{ }[\/latex] represents the partial sum.\r\n
[latex]\\begin{array}{l}{S}_{1}=3\\\\ {S}_{2}=3+7=10\\\\ {S}_{3}=3+7+11=21\\\\ {S}_{4}=3+7+11+15=36\\end{array}[\/latex]<\/div>\r\nSummation notation <\/strong>is used to represent series. Summation notation is often known as sigma notation because it uses the Greek capital letter sigma<\/strong>, [latex]\\sum[\/latex], to represent the sum. Summation notation includes an explicit formula and specifies the first and last terms in the series. An explicit formula for each term of the series is given to the right of the sigma. A variable called the index of summation <\/strong>is written below the sigma. The index of summation is set equal to the lower limit of summation<\/strong>, which is the number used to generate the first term in the series. The number above the sigma, called the upper limit of summation<\/strong>, is the number used to generate the last term in a series.\r\n\r\n\"Explanation\r\n\r\nIf we interpret the given notation, we see that it asks us to find the sum of the terms in the series [latex]{a}_{k}=2k[\/latex] for [latex]k=1[\/latex] through [latex]k=5[\/latex]. We can begin by substituting the terms for [latex]k[\/latex] and listing out the terms of this series.\r\n
[latex]\\begin{array}{l}\\begin{array}{l}\\\\ {a}_{1}=2\\left(1\\right)=2\\end{array}\\hfill \\\\ {a}_{2}=2\\left(2\\right)=4\\hfill \\\\ {a}_{3}=2\\left(3\\right)=6\\hfill \\\\ {a}_{4}=2\\left(4\\right)=8\\hfill \\\\ {a}_{5}=2\\left(5\\right)=10\\hfill \\end{array}[\/latex]<\/div>\r\nWe can find the sum of the series by adding the terms:\r\n
[latex]\\sum _{k=1}^{5}2k=2+4+6+8+10=30[\/latex]<\/div>\r\n
\r\n

A General Note: Summation Notation<\/h3>\r\nThe sum of the first [latex]n[\/latex] terms of a series <\/strong>can be expressed in summation notation<\/strong> as follows:\r\n
[latex]\\sum _{k=1}^{n}{a}_{k}[\/latex]<\/div>\r\nThis notation tells us to find the sum of [latex]{a}_{k}[\/latex] from [latex]k=1[\/latex] to [latex]k=n[\/latex].\r\n\r\n[latex]k[\/latex] is called the index of summation<\/strong>, 1 is the lower limit of summation<\/strong>, and [latex]n[\/latex] is the upper limit of summation<\/strong>.\r\n\r\n<\/div>\r\n
\r\n

Q & A<\/h3>\r\n

Does the lower limit of summation have to be 1?<\/h3>\r\nNo. The lower limit of summation can be any number, but 1 is frequently used. We will look at examples with lower limits of summation other than 1.<\/em>\r\n\r\n<\/div>\r\n
\r\n

How To: Given summation notation for a series, evaluate the value.<\/h3>\r\n
  1. Identify the lower limit of summation.<\/li>\r\n\t
  2. Identify the upper limit of summation.<\/li>\r\n\t
  3. Substitute each value of [latex]k[\/latex] from the lower limit to the upper limit into the formula.<\/li>\r\n\t
  4. Add to find the sum.<\/li>\r\n<\/ol><\/div>\r\n
    \r\n

    Example 1: Using Summation Notation<\/h3>\r\nEvaluate [latex]\\sum _{k=3}^{7}{k}^{2}[\/latex].\r\n\r\n<\/div>\r\n
    \r\n

    Solution<\/h3>\r\nAccording to the notation, the lower limit of summation is 3 and the upper limit is 7. So we need to find the sum of [latex]{k}^{2}[\/latex] from [latex]k=3[\/latex] to [latex]k=7[\/latex]. We find the terms of the series by substituting [latex]k=3\\text{,}4\\text{,}5\\text{,}6[\/latex], and [latex]7[\/latex] into the function [latex]{k}^{2}[\/latex]. We add the terms to find the sum.\r\n
    [latex]\\begin{array}{ll}\\sum _{k=3}^{7}{k}^{2}\\hfill & ={3}^{2}+{4}^{2}+{5}^{2}+{6}^{2}+{7}^{2}\\hfill \\\\ \\hfill & =9+16+25+36+49\\hfill \\\\ \\hfill & =135\\hfill \\end{array}[\/latex]<\/div>\r\n<\/div>\r\n
    \r\n

    Try It 1<\/h3>\r\nEvaluate [latex]\\sum _{k=2}^{5}\\left(3k - 1\\right)[\/latex].\r\n\r\nSolution<\/a>\r\n\r\n<\/div>","rendered":"

    To find the total amount of money in the college fund and the sum of the amounts deposited, we need to add the amounts deposited each month and the amounts earned monthly. The sum of the terms of a sequence is called a series<\/strong>. Consider, for example, the following series.\n<\/p>\n

    [latex]3+7+11+15+19+..[\/latex].<\/div>\n

    The [latex]n\\text{th }[\/latex] partial sum<\/strong> of a series is the sum of a finite number of consecutive terms beginning with the first term. The notation [latex]\\text{ }{S}_{n}\\text{ }[\/latex] represents the partial sum.<\/p>\n

    [latex]\\begin{array}{l}{S}_{1}=3\\\\ {S}_{2}=3+7=10\\\\ {S}_{3}=3+7+11=21\\\\ {S}_{4}=3+7+11+15=36\\end{array}[\/latex]<\/div>\n

    Summation notation <\/strong>is used to represent series. Summation notation is often known as sigma notation because it uses the Greek capital letter sigma<\/strong>, [latex]\\sum[\/latex], to represent the sum. Summation notation includes an explicit formula and specifies the first and last terms in the series. An explicit formula for each term of the series is given to the right of the sigma. A variable called the index of summation <\/strong>is written below the sigma. The index of summation is set equal to the lower limit of summation<\/strong>, which is the number used to generate the first term in the series. The number above the sigma, called the upper limit of summation<\/strong>, is the number used to generate the last term in a series.<\/p>\n

    \"Explanation<\/p>\n

    If we interpret the given notation, we see that it asks us to find the sum of the terms in the series [latex]{a}_{k}=2k[\/latex] for [latex]k=1[\/latex] through [latex]k=5[\/latex]. We can begin by substituting the terms for [latex]k[\/latex] and listing out the terms of this series.<\/p>\n

    [latex]\\begin{array}{l}\\begin{array}{l}\\\\ {a}_{1}=2\\left(1\\right)=2\\end{array}\\hfill \\\\ {a}_{2}=2\\left(2\\right)=4\\hfill \\\\ {a}_{3}=2\\left(3\\right)=6\\hfill \\\\ {a}_{4}=2\\left(4\\right)=8\\hfill \\\\ {a}_{5}=2\\left(5\\right)=10\\hfill \\end{array}[\/latex]<\/div>\n

    We can find the sum of the series by adding the terms:<\/p>\n

    [latex]\\sum _{k=1}^{5}2k=2+4+6+8+10=30[\/latex]<\/div>\n
    \n

    A General Note: Summation Notation<\/h3>\n

    The sum of the first [latex]n[\/latex] terms of a series <\/strong>can be expressed in summation notation<\/strong> as follows:<\/p>\n

    [latex]\\sum _{k=1}^{n}{a}_{k}[\/latex]<\/div>\n

    This notation tells us to find the sum of [latex]{a}_{k}[\/latex] from [latex]k=1[\/latex] to [latex]k=n[\/latex].<\/p>\n

    [latex]k[\/latex] is called the index of summation<\/strong>, 1 is the lower limit of summation<\/strong>, and [latex]n[\/latex] is the upper limit of summation<\/strong>.<\/p>\n<\/div>\n

    \n

    Q & A<\/h3>\n

    Does the lower limit of summation have to be 1?<\/h3>\n

    No. The lower limit of summation can be any number, but 1 is frequently used. We will look at examples with lower limits of summation other than 1.<\/em><\/p>\n<\/div>\n

    \n

    How To: Given summation notation for a series, evaluate the value.<\/h3>\n
      \n
    1. Identify the lower limit of summation.<\/li>\n
    2. Identify the upper limit of summation.<\/li>\n
    3. Substitute each value of [latex]k[\/latex] from the lower limit to the upper limit into the formula.<\/li>\n
    4. Add to find the sum.<\/li>\n<\/ol>\n<\/div>\n
      \n

      Example 1: Using Summation Notation<\/h3>\n

      Evaluate [latex]\\sum _{k=3}^{7}{k}^{2}[\/latex].<\/p>\n<\/div>\n

      \n

      Solution<\/h3>\n

      According to the notation, the lower limit of summation is 3 and the upper limit is 7. So we need to find the sum of [latex]{k}^{2}[\/latex] from [latex]k=3[\/latex] to [latex]k=7[\/latex]. We find the terms of the series by substituting [latex]k=3\\text{,}4\\text{,}5\\text{,}6[\/latex], and [latex]7[\/latex] into the function [latex]{k}^{2}[\/latex]. We add the terms to find the sum.<\/p>\n

      [latex]\\begin{array}{ll}\\sum _{k=3}^{7}{k}^{2}\\hfill & ={3}^{2}+{4}^{2}+{5}^{2}+{6}^{2}+{7}^{2}\\hfill \\\\ \\hfill & =9+16+25+36+49\\hfill \\\\ \\hfill & =135\\hfill \\end{array}[\/latex]<\/div>\n<\/div>\n
      \n

      Try It 1<\/h3>\n

      Evaluate [latex]\\sum _{k=2}^{5}\\left(3k - 1\\right)[\/latex].<\/p>\n

      Solution<\/a><\/p>\n<\/div>\n\n\t\t\t

      \n\t\t\t

      Candela Citations<\/h3>\n\t\t\t\t\t
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