{"id":2099,"date":"2015-11-12T18:30:42","date_gmt":"2015-11-12T18:30:42","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=2099"},"modified":"2015-11-12T18:30:42","modified_gmt":"2015-11-12T18:30:42","slug":"finding-the-number-of-permutations-of-n-non-distinct-objects","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/chapter\/finding-the-number-of-permutations-of-n-non-distinct-objects\/","title":{"raw":"Finding the Number of Permutations of n Non-Distinct Objects","rendered":"Finding the Number of Permutations of n Non-Distinct Objects"},"content":{"raw":"<p>We have studied permutations where all of the objects involved were distinct. What happens if some of the objects are indistinguishable? For example, suppose there is a sheet of 12 stickers. If all of the stickers were distinct, there would be [latex]12![\/latex] ways to order the stickers. However, 4 of the stickers are identical stars, and 3 are identical moons. Because all of the objects are not distinct, many of the [latex]12![\/latex] permutations we counted are duplicates. The general formula for this situation is as follows.\n<\/p><div style=\"text-align: center;\">[latex]\\frac{n!}{{r}_{1}!{r}_{2}!\\dots {r}_{k}!}[\/latex]<\/div>\nIn this example, we need to divide by the number of ways to order the 4 stars and the ways to order the 3 moons to find the number of unique permutations of the stickers. There are [latex]4![\/latex] ways to order the stars and [latex]3![\/latex] ways to order the moon.\n<div style=\"text-align: center;\">[latex]\\frac{12!}{4!3!}=3\\text{,}326\\text{,}400[\/latex]<\/div>\nThere are 3,326,400 ways to order the sheet of stickers.\n<div class=\"textbox\">\n<h3>A General Note: Formula for Finding the Number of Permutations of <em>n<\/em> Non-Distinct Objects<\/h3>\nIf there are [latex]n[\/latex] elements in a set and [latex]{r}_{1}[\/latex] are alike, [latex]{r}_{2}[\/latex] are alike, [latex]{r}_{3}[\/latex] are alike, and so on through [latex]{r}_{k}[\/latex], the number of permutations can be found by\n<div style=\"text-align: center;\">[latex]\\frac{n!}{{r}_{1}!{r}_{2}!\\dots {r}_{k}!}[\/latex]<\/div>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 6: Finding the Number of Permutations of <em>n<\/em> Non-Distinct Objects<\/h3>\nFind the number of rearrangements of the letters in the word DISTINCT.\n\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\nThere are 8 letters. Both I and T are repeated 2 times. Substitute [latex]n=8, {r}_{1}=2, [\/latex] and [latex] {r}_{2}=2 [\/latex] into the formula.\n<div>[latex]\\frac{8!}{2!2!}=10\\text{,}080 [\/latex]<\/div>\nThere are 10,080 arrangements.\n\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 10<\/h3>\nFind the number of rearrangements of the letters in the word CARRIER.\n\n<a href=\"https:\/\/courses.candelalearning.com\/precalctwo1xmaster\/chapter\/solutions-32\/\" target=\"_blank\">Solution<\/a>\n\n<\/div>","rendered":"<p>We have studied permutations where all of the objects involved were distinct. What happens if some of the objects are indistinguishable? For example, suppose there is a sheet of 12 stickers. If all of the stickers were distinct, there would be [latex]12![\/latex] ways to order the stickers. However, 4 of the stickers are identical stars, and 3 are identical moons. Because all of the objects are not distinct, many of the [latex]12![\/latex] permutations we counted are duplicates. The general formula for this situation is as follows.\n<\/p>\n<div style=\"text-align: center;\">[latex]\\frac{n!}{{r}_{1}!{r}_{2}!\\dots {r}_{k}!}[\/latex]<\/div>\n<p>In this example, we need to divide by the number of ways to order the 4 stars and the ways to order the 3 moons to find the number of unique permutations of the stickers. There are [latex]4![\/latex] ways to order the stars and [latex]3![\/latex] ways to order the moon.<\/p>\n<div style=\"text-align: center;\">[latex]\\frac{12!}{4!3!}=3\\text{,}326\\text{,}400[\/latex]<\/div>\n<p>There are 3,326,400 ways to order the sheet of stickers.<\/p>\n<div class=\"textbox\">\n<h3>A General Note: Formula for Finding the Number of Permutations of <em>n<\/em> Non-Distinct Objects<\/h3>\n<p>If there are [latex]n[\/latex] elements in a set and [latex]{r}_{1}[\/latex] are alike, [latex]{r}_{2}[\/latex] are alike, [latex]{r}_{3}[\/latex] are alike, and so on through [latex]{r}_{k}[\/latex], the number of permutations can be found by<\/p>\n<div style=\"text-align: center;\">[latex]\\frac{n!}{{r}_{1}!{r}_{2}!\\dots {r}_{k}!}[\/latex]<\/div>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 6: Finding the Number of Permutations of <em>n<\/em> Non-Distinct Objects<\/h3>\n<p>Find the number of rearrangements of the letters in the word DISTINCT.<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<p>There are 8 letters. Both I and T are repeated 2 times. Substitute [latex]n=8, {r}_{1}=2,[\/latex] and [latex]{r}_{2}=2[\/latex] into the formula.<\/p>\n<div>[latex]\\frac{8!}{2!2!}=10\\text{,}080[\/latex]<\/div>\n<p>There are 10,080 arrangements.<\/p>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 10<\/h3>\n<p>Find the number of rearrangements of the letters in the word CARRIER.<\/p>\n<p><a href=\"https:\/\/courses.candelalearning.com\/precalctwo1xmaster\/chapter\/solutions-32\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-2099\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: OpenStax College. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"Precalculus\",\"author\":\"OpenStax College\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-2099","chapter","type-chapter","status-publish","hentry"],"part":2078,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/2099","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":1,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/2099\/revisions"}],"predecessor-version":[{"id":2149,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/2099\/revisions\/2149"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/2078"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/2099\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/media?parent=2099"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=2099"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/contributor?post=2099"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/license?post=2099"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}