{"id":335,"date":"2015-09-18T22:14:54","date_gmt":"2015-09-18T22:14:54","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=335"},"modified":"2015-11-04T20:55:38","modified_gmt":"2015-11-04T20:55:38","slug":"solutions-6","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/chapter\/solutions-6\/","title":{"raw":"Solutions","rendered":"Solutions"},"content":{"raw":"<h2>Solutions to Try Its<\/h2>\r\n1.\u00a0[latex]\\frac{1}{x+6}[\/latex]\r\n\r\n2.\u00a0[latex]\\frac{\\left(x+5\\right)\\left(x+6\\right)}{\\left(x+2\\right)\\left(x+4\\right)}[\/latex]\r\n\r\n3.\u00a0[latex]1[\/latex]\r\n\r\n4.\u00a0[latex]\\frac{2\\left(x - 7\\right)}{\\left(x+5\\right)\\left(x - 3\\right)}[\/latex]\r\n\r\n5.\u00a0[latex]\\frac{{x}^{2}-{y}^{2}}{x{y}^{2}}[\/latex]\r\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\r\n1.\u00a0You can factor the numerator and denominator to see if any of the terms can cancel one another out.\r\n\r\n3.\u00a0True. Multiplication and division do not require finding the LCD because the denominators can be combined through those operations, whereas addition and subtraction require like terms.\r\n\r\n5.\u00a0[latex]\\frac{y+5}{y+6}[\/latex]\r\n\r\n7.\u00a0[latex]3b+3[\/latex]\r\n\r\n9.\u00a0[latex]\\frac{x+4}{2x+2}[\/latex]\r\n\r\n11.\u00a0[latex]\\frac{a+3}{a - 3}[\/latex]\r\n\r\n13.\u00a0[latex]\\frac{3n - 8}{7n - 3}[\/latex]\r\n\r\n15.\u00a0[latex]\\frac{c - 6}{c+6}[\/latex]\r\n\r\n17.\u00a0[latex]1[\/latex]\r\n\r\n19.\u00a0[latex]\\frac{{d}^{2}-25}{25{d}^{2}-1}[\/latex]\r\n\r\n21.\u00a0[latex]\\frac{t+5}{t+3}[\/latex]\r\n\r\n23.\u00a0[latex]\\frac{6x - 5}{6x+5}[\/latex]\r\n\r\n25.\u00a0[latex]\\frac{p+6}{4p+3}[\/latex]\r\n\r\n27.\u00a0[latex]\\frac{2d+9}{d+11}[\/latex]\r\n\r\n29.\u00a0[latex]\\frac{12b+5}{3b - 1}[\/latex]\r\n\r\n31.\u00a0[latex]\\frac{4y - 1}{y+4}[\/latex]\r\n\r\n33.\u00a0[latex]\\frac{10x+4y}{xy}[\/latex]\r\n\r\n35.\u00a0[latex]\\frac{9a - 7}{{a}^{2}-2a - 3}[\/latex]\r\n\r\n37.\u00a0[latex]\\frac{2{y}^{2}-y+9}{{y}^{2}-y - 2}[\/latex]\r\n\r\n39.\u00a0[latex]\\frac{5{z}^{2}+z+5}{{z}^{2}-z - 2}[\/latex]\r\n\r\n41.\u00a0[latex]\\frac{x+2xy+y}{x+xy+y+1}[\/latex]\r\n\r\n43.\u00a0[latex]\\frac{2b+7a}{a{b}^{2}}[\/latex]\r\n\r\n45.\u00a0[latex]\\frac{18+ab}{4b}[\/latex]\r\n\r\n47.\u00a0[latex]a-b[\/latex]\r\n\r\n49.\u00a0[latex]\\frac{3{c}^{2}+3c - 2}{2{c}^{2}+5c+2}[\/latex]\r\n\r\n51.\u00a0[latex]\\frac{15x+7}{x - 1}[\/latex]\r\n\r\n53.\u00a0[latex]\\frac{x+9}{x - 9}[\/latex]\r\n\r\n55.\u00a0[latex]\\frac{1}{y+2}[\/latex]\r\n\r\n57.\u00a0[latex]4[\/latex]","rendered":"<h2>Solutions to Try Its<\/h2>\n<p>1.\u00a0[latex]\\frac{1}{x+6}[\/latex]<\/p>\n<p>2.\u00a0[latex]\\frac{\\left(x+5\\right)\\left(x+6\\right)}{\\left(x+2\\right)\\left(x+4\\right)}[\/latex]<\/p>\n<p>3.\u00a0[latex]1[\/latex]<\/p>\n<p>4.\u00a0[latex]\\frac{2\\left(x - 7\\right)}{\\left(x+5\\right)\\left(x - 3\\right)}[\/latex]<\/p>\n<p>5.\u00a0[latex]\\frac{{x}^{2}-{y}^{2}}{x{y}^{2}}[\/latex]<\/p>\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\n<p>1.\u00a0You can factor the numerator and denominator to see if any of the terms can cancel one another out.<\/p>\n<p>3.\u00a0True. Multiplication and division do not require finding the LCD because the denominators can be combined through those operations, whereas addition and subtraction require like terms.<\/p>\n<p>5.\u00a0[latex]\\frac{y+5}{y+6}[\/latex]<\/p>\n<p>7.\u00a0[latex]3b+3[\/latex]<\/p>\n<p>9.\u00a0[latex]\\frac{x+4}{2x+2}[\/latex]<\/p>\n<p>11.\u00a0[latex]\\frac{a+3}{a - 3}[\/latex]<\/p>\n<p>13.\u00a0[latex]\\frac{3n - 8}{7n - 3}[\/latex]<\/p>\n<p>15.\u00a0[latex]\\frac{c - 6}{c+6}[\/latex]<\/p>\n<p>17.\u00a0[latex]1[\/latex]<\/p>\n<p>19.\u00a0[latex]\\frac{{d}^{2}-25}{25{d}^{2}-1}[\/latex]<\/p>\n<p>21.\u00a0[latex]\\frac{t+5}{t+3}[\/latex]<\/p>\n<p>23.\u00a0[latex]\\frac{6x - 5}{6x+5}[\/latex]<\/p>\n<p>25.\u00a0[latex]\\frac{p+6}{4p+3}[\/latex]<\/p>\n<p>27.\u00a0[latex]\\frac{2d+9}{d+11}[\/latex]<\/p>\n<p>29.\u00a0[latex]\\frac{12b+5}{3b - 1}[\/latex]<\/p>\n<p>31.\u00a0[latex]\\frac{4y - 1}{y+4}[\/latex]<\/p>\n<p>33.\u00a0[latex]\\frac{10x+4y}{xy}[\/latex]<\/p>\n<p>35.\u00a0[latex]\\frac{9a - 7}{{a}^{2}-2a - 3}[\/latex]<\/p>\n<p>37.\u00a0[latex]\\frac{2{y}^{2}-y+9}{{y}^{2}-y - 2}[\/latex]<\/p>\n<p>39.\u00a0[latex]\\frac{5{z}^{2}+z+5}{{z}^{2}-z - 2}[\/latex]<\/p>\n<p>41.\u00a0[latex]\\frac{x+2xy+y}{x+xy+y+1}[\/latex]<\/p>\n<p>43.\u00a0[latex]\\frac{2b+7a}{a{b}^{2}}[\/latex]<\/p>\n<p>45.\u00a0[latex]\\frac{18+ab}{4b}[\/latex]<\/p>\n<p>47.\u00a0[latex]a-b[\/latex]<\/p>\n<p>49.\u00a0[latex]\\frac{3{c}^{2}+3c - 2}{2{c}^{2}+5c+2}[\/latex]<\/p>\n<p>51.\u00a0[latex]\\frac{15x+7}{x - 1}[\/latex]<\/p>\n<p>53.\u00a0[latex]\\frac{x+9}{x - 9}[\/latex]<\/p>\n<p>55.\u00a0[latex]\\frac{1}{y+2}[\/latex]<\/p>\n<p>57.\u00a0[latex]4[\/latex]<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-335\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>College Algebra. <strong>Authored by<\/strong>: OpenStax College Algebra. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\">http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":8,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"College Algebra\",\"author\":\"OpenStax College Algebra\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-335","chapter","type-chapter","status-publish","hentry"],"part":206,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/335","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":5,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/335\/revisions"}],"predecessor-version":[{"id":609,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/335\/revisions\/609"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/206"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/335\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/media?parent=335"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=335"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/contributor?post=335"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/wp-json\/wp\/v2\/license?post=335"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}