{"id":355,"date":"2015-09-18T22:45:21","date_gmt":"2015-09-18T22:45:21","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&p=355"},"modified":"2015-11-05T18:42:49","modified_gmt":"2015-11-05T18:42:49","slug":"solutions-7","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/chapter\/solutions-7\/","title":{"raw":"Solutions","rendered":"Solutions"},"content":{"raw":"

Solutions to Try Its<\/h2>\r\n1.\u00a0x<\/em>-intercept is [latex]\\left(4,0\\right)[\/latex]; y-<\/em>intercept is [latex]\\left(0,3\\right)[\/latex].\r\n\r\n\"This\r\n\r\n2.\u00a0[latex]\\left(-5,\\frac{5}{2}\\right)[\/latex]\r\n

Solutions to Odd-Numbered Exercises<\/h2>\r\n1.\u00a0Answers may vary. Yes. It is possible for a point to be on the x<\/em>-axis or on the y<\/em>-axis and therefore is considered to NOT be in one of the quadrants.\r\n\r\n3.\u00a0The y<\/em>-intercept is the point where the graph crosses the y<\/em>-axis.\r\n\r\n5.\u00a0The x-<\/em>intercept is [latex]\\left(2,0\\right)[\/latex] and the y<\/em>-intercept is [latex]\\left(0,6\\right)[\/latex].\r\n\r\n7.\u00a0The x-<\/em>intercept is [latex]\\left(2,0\\right)[\/latex] and the y<\/em>-intercept is [latex]\\left(0,-3\\right)[\/latex].\r\n\r\n9.\u00a0The x-<\/em>intercept is [latex]\\left(3,0\\right)[\/latex] and the y<\/em>-intercept is [latex]\\left(0,\\frac{9}{8}\\right)[\/latex].\r\n\r\n11.\u00a0[latex]y=4 - 2x[\/latex]\r\n\r\n13.\u00a0[latex]y=\\frac{5 - 2x}{3}[\/latex]\r\n\r\n15.\u00a0[latex]y=2x-\\frac{4}{5}[\/latex]\r\n\r\n17.\u00a0[latex]d=\\sqrt{74}[\/latex]\r\n\r\n19.\u00a0[latex]d=\\sqrt{36}=6[\/latex]\r\n\r\n21.\u00a0[latex]d\\approx 62.97[\/latex]\r\n\r\n23.\u00a0[latex]\\left(3,\\frac{-3}{2}\\right)[\/latex]\r\n\r\n25.\u00a0[latex]\\left(2,-1\\right)[\/latex]\r\n\r\n27.\u00a0[latex]\\left(0,0\\right)[\/latex]\r\n\r\n29.\u00a0[latex]y=0[\/latex]\r\n\r\n31.\u00a0not collinear\r\n\r\n\"This\r\n\r\n33.\u00a0[latex]\\left(-3,2\\right),\\left(1,3\\right),\\left(4,0\\right)[\/latex]\r\n\r\n35.\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n
[latex]x[\/latex]<\/td>\r\n[latex]y[\/latex]<\/td>\r\n<\/tr>\r\n
[latex]-3[\/latex]<\/td>\r\n1<\/td>\r\n<\/tr>\r\n
0<\/td>\r\n2<\/td>\r\n<\/tr>\r\n
3<\/td>\r\n3<\/td>\r\n<\/tr>\r\n
6<\/td>\r\n4<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n\"This\r\n\r\n37.\r\n\r\n\r\n\r\n\r\n\r\n\r\n
x<\/em><\/td>\r\ny<\/em><\/td>\r\n<\/tr>\r\n
\u20133<\/td>\r\n0<\/td>\r\n<\/tr>\r\n
0<\/td>\r\n1.5<\/td>\r\n<\/tr>\r\n
3<\/td>\r\n3<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n\"This\r\n\r\n39.\r\n\"This\r\n\r\n41.\r\n\"This\r\n\r\n43.\u00a0[latex]d=8.246[\/latex]\r\n\r\n45.\u00a0[latex]d=5[\/latex]\r\n\r\n47.\u00a0[latex]\\left(-3,4\\right)[\/latex]\r\n\r\n49.\u00a0[latex]x=0\\text{ }y=-2[\/latex]\r\n\r\n51.\u00a0[latex]x=0.75\\text{ }y=0[\/latex]\r\n\r\n53.\u00a0[latex]x=-1.667\\text{ }y=0[\/latex]\r\n\r\n55.\u00a0[latex]\\text{15}\\text{-11}.\\text{2 }=\\text{ 3}.8[\/latex] mi shorter\r\n\r\n57.\u00a0[latex]\\text{6}.0\\text{42}[\/latex]\r\n\r\n59.\u00a0Midpoint of each diagonal is the same point [latex]\\left(2,2\\right)[\/latex]. Note this is a characteristic of rectangles, but not other quadrilaterals.\r\n\r\n61.\u00a0[latex]\\text{37}[\/latex] mi\r\n\r\n63.\u00a054 ft","rendered":"

Solutions to Try Its<\/h2>\n

1.\u00a0x<\/em>-intercept is [latex]\\left(4,0\\right)[\/latex]; y-<\/em>intercept is [latex]\\left(0,3\\right)[\/latex].<\/p>\n

\"This<\/p>\n

2.\u00a0[latex]\\left(-5,\\frac{5}{2}\\right)[\/latex]<\/p>\n

Solutions to Odd-Numbered Exercises<\/h2>\n

1.\u00a0Answers may vary. Yes. It is possible for a point to be on the x<\/em>-axis or on the y<\/em>-axis and therefore is considered to NOT be in one of the quadrants.<\/p>\n

3.\u00a0The y<\/em>-intercept is the point where the graph crosses the y<\/em>-axis.<\/p>\n

5.\u00a0The x-<\/em>intercept is [latex]\\left(2,0\\right)[\/latex] and the y<\/em>-intercept is [latex]\\left(0,6\\right)[\/latex].<\/p>\n

7.\u00a0The x-<\/em>intercept is [latex]\\left(2,0\\right)[\/latex] and the y<\/em>-intercept is [latex]\\left(0,-3\\right)[\/latex].<\/p>\n

9.\u00a0The x-<\/em>intercept is [latex]\\left(3,0\\right)[\/latex] and the y<\/em>-intercept is [latex]\\left(0,\\frac{9}{8}\\right)[\/latex].<\/p>\n

11.\u00a0[latex]y=4 - 2x[\/latex]<\/p>\n

13.\u00a0[latex]y=\\frac{5 - 2x}{3}[\/latex]<\/p>\n

15.\u00a0[latex]y=2x-\\frac{4}{5}[\/latex]<\/p>\n

17.\u00a0[latex]d=\\sqrt{74}[\/latex]<\/p>\n

19.\u00a0[latex]d=\\sqrt{36}=6[\/latex]<\/p>\n

21.\u00a0[latex]d\\approx 62.97[\/latex]<\/p>\n

23.\u00a0[latex]\\left(3,\\frac{-3}{2}\\right)[\/latex]<\/p>\n

25.\u00a0[latex]\\left(2,-1\\right)[\/latex]<\/p>\n

27.\u00a0[latex]\\left(0,0\\right)[\/latex]<\/p>\n

29.\u00a0[latex]y=0[\/latex]<\/p>\n

31.\u00a0not collinear<\/p>\n

\"This<\/p>\n

33.\u00a0[latex]\\left(-3,2\\right),\\left(1,3\\right),\\left(4,0\\right)[\/latex]<\/p>\n

35.<\/p>\n\n\n\n\n\n\n\n
[latex]x[\/latex]<\/td>\n[latex]y[\/latex]<\/td>\n<\/tr>\n
[latex]-3[\/latex]<\/td>\n1<\/td>\n<\/tr>\n
0<\/td>\n2<\/td>\n<\/tr>\n
3<\/td>\n3<\/td>\n<\/tr>\n
6<\/td>\n4<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\"This<\/p>\n

37.<\/p>\n\n\n\n\n\n\n
x<\/em><\/td>\ny<\/em><\/td>\n<\/tr>\n
\u20133<\/td>\n0<\/td>\n<\/tr>\n
0<\/td>\n1.5<\/td>\n<\/tr>\n
3<\/td>\n3<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\"This<\/p>\n

39.
\n\"This<\/p>\n

41.
\n\"This<\/p>\n

43.\u00a0[latex]d=8.246[\/latex]<\/p>\n

45.\u00a0[latex]d=5[\/latex]<\/p>\n

47.\u00a0[latex]\\left(-3,4\\right)[\/latex]<\/p>\n

49.\u00a0[latex]x=0\\text{ }y=-2[\/latex]<\/p>\n

51.\u00a0[latex]x=0.75\\text{ }y=0[\/latex]<\/p>\n

53.\u00a0[latex]x=-1.667\\text{ }y=0[\/latex]<\/p>\n

55.\u00a0[latex]\\text{15}\\text{-11}.\\text{2 }=\\text{ 3}.8[\/latex] mi shorter<\/p>\n

57.\u00a0[latex]\\text{6}.0\\text{42}[\/latex]<\/p>\n

59.\u00a0Midpoint of each diagonal is the same point [latex]\\left(2,2\\right)[\/latex]. Note this is a characteristic of rectangles, but not other quadrilaterals.<\/p>\n

61.\u00a0[latex]\\text{37}[\/latex] mi<\/p>\n

63.\u00a054 ft<\/p>\n\n\t\t\t

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Candela Citations<\/h3>\n\t\t\t\t\t
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CC licensed content, Specific attribution<\/div>