{"id":431,"date":"2015-10-26T18:25:01","date_gmt":"2015-10-26T18:25:01","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&p=431"},"modified":"2015-11-12T18:37:59","modified_gmt":"2015-11-12T18:37:59","slug":"solutions-to-selected-exercises-3","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/chapter\/solutions-to-selected-exercises-3\/","title":{"raw":"Solutions to Selected Exercises","rendered":"Solutions to Selected Exercises"},"content":{"raw":"

Solutions to Try Its<\/h2>\r\n1.\u00a011 and 25\r\n\r\n2.\u00a0[latex]C=2.5x+3,650[\/latex]\r\n\r\n3.\u00a045 mi\/h\r\n\r\n4.\u00a0[latex]L=37[\/latex] cm, [latex]W=18[\/latex] cm\r\n\r\n5.\u00a0250 ft2<\/sup>\r\n

Solutions to Odd-Numbered Exercises<\/h2>\r\n1.\u00a0Answers may vary. Possible answers: We should define in words what our variable is representing. We should declare the variable. A heading.\r\n\r\n3.\u00a0[latex]2,000-x[\/latex]\r\n\r\n5.\u00a0[latex]v+10[\/latex]\r\n\r\n7.\u00a0Ann: [latex]23[\/latex]; Beth: [latex]46[\/latex]\r\n\r\n9.\u00a0[latex]20+0.05m[\/latex]\r\n\r\n11.\u00a0300 min\r\n\r\n13.\u00a0[latex]90+40P[\/latex]\r\n\r\n15.\u00a06 devices\r\n\r\n17.\u00a0[latex]50,000-x[\/latex]\r\n\r\n19.\u00a04 h\r\n\r\n21.\u00a0She traveled for 2 h at 20 mi\/h, or 40 miles.\r\n\r\n23.\u00a0$5,000 at 8% and $15,000 at 12%\r\n\r\n25.\u00a0[latex]B=100+.05x[\/latex]\r\n\r\n27.\u00a0Plan A\r\n\r\n29.\u00a0[latex]R=9[\/latex]\r\n\r\n31.\u00a0[latex]r=\\frac{4}{5}[\/latex] or 0.8\r\n\r\n33.\u00a0[latex]W=\\frac{P - 2L}{2}=\\frac{58 - 2\\left(15\\right)}{2}=14[\/latex]\r\n\r\n35.\u00a0[latex]f=\\frac{pq}{p+q}=\\frac{8\\left(13\\right)}{8+13}=\\frac{104}{21}[\/latex]\r\n\r\n37.\u00a0[latex]m=\\frac{-5}{4}[\/latex]\r\n\r\n39.\u00a0[latex]h=\\frac{2A}{{b}_{1}+{b}_{2}}[\/latex]\r\n\r\n41.\u00a0length = 360 ft; width = 160 ft\r\n\r\n43.\u00a0405 mi\r\n\r\n45.\u00a0[latex]A=88\\text{ in}{.}^{2}[\/latex]\r\n\r\n47.\u00a028.7\r\n\r\n49.\u00a0[latex]h=\\frac{V}{\\pi {r}^{2}}[\/latex]\r\n\r\n51.\u00a0[latex]r=\\sqrt{\\frac{V}{\\pi h}}[\/latex]\r\n\r\n53.\u00a0[latex]C=12\\pi [\/latex]","rendered":"

Solutions to Try Its<\/h2>\n

1.\u00a011 and 25<\/p>\n

2.\u00a0[latex]C=2.5x+3,650[\/latex]<\/p>\n

3.\u00a045 mi\/h<\/p>\n

4.\u00a0[latex]L=37[\/latex] cm, [latex]W=18[\/latex] cm<\/p>\n

5.\u00a0250 ft2<\/sup><\/p>\n

Solutions to Odd-Numbered Exercises<\/h2>\n

1.\u00a0Answers may vary. Possible answers: We should define in words what our variable is representing. We should declare the variable. A heading.<\/p>\n

3.\u00a0[latex]2,000-x[\/latex]<\/p>\n

5.\u00a0[latex]v+10[\/latex]<\/p>\n

7.\u00a0Ann: [latex]23[\/latex]; Beth: [latex]46[\/latex]<\/p>\n

9.\u00a0[latex]20+0.05m[\/latex]<\/p>\n

11.\u00a0300 min<\/p>\n

13.\u00a0[latex]90+40P[\/latex]<\/p>\n

15.\u00a06 devices<\/p>\n

17.\u00a0[latex]50,000-x[\/latex]<\/p>\n

19.\u00a04 h<\/p>\n

21.\u00a0She traveled for 2 h at 20 mi\/h, or 40 miles.<\/p>\n

23.\u00a0$5,000 at 8% and $15,000 at 12%<\/p>\n

25.\u00a0[latex]B=100+.05x[\/latex]<\/p>\n

27.\u00a0Plan A<\/p>\n

29.\u00a0[latex]R=9[\/latex]<\/p>\n

31.\u00a0[latex]r=\\frac{4}{5}[\/latex] or 0.8<\/p>\n

33.\u00a0[latex]W=\\frac{P - 2L}{2}=\\frac{58 - 2\\left(15\\right)}{2}=14[\/latex]<\/p>\n

35.\u00a0[latex]f=\\frac{pq}{p+q}=\\frac{8\\left(13\\right)}{8+13}=\\frac{104}{21}[\/latex]<\/p>\n

37.\u00a0[latex]m=\\frac{-5}{4}[\/latex]<\/p>\n

39.\u00a0[latex]h=\\frac{2A}{{b}_{1}+{b}_{2}}[\/latex]<\/p>\n

41.\u00a0length = 360 ft; width = 160 ft<\/p>\n

43.\u00a0405 mi<\/p>\n

45.\u00a0[latex]A=88\\text{ in}{.}^{2}[\/latex]<\/p>\n

47.\u00a028.7<\/p>\n

49.\u00a0[latex]h=\\frac{V}{\\pi {r}^{2}}[\/latex]<\/p>\n

51.\u00a0[latex]r=\\sqrt{\\frac{V}{\\pi h}}[\/latex]<\/p>\n

53.\u00a0[latex]C=12\\pi[\/latex]<\/p>\n\n\t\t\t

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Candela Citations<\/h3>\n\t\t\t\t\t
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