{"id":688,"date":"2015-11-06T20:51:49","date_gmt":"2015-11-06T20:51:49","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&p=688"},"modified":"2015-11-12T18:37:59","modified_gmt":"2015-11-12T18:37:59","slug":"solutions-8","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/ivytech-collegealgebra\/chapter\/solutions-8\/","title":{"raw":"Solutions","rendered":"Solutions"},"content":{"raw":"

Solutions to Try Its<\/h2>\r\n1.\u00a0[latex]\\frac{1}{4}[\/latex]\r\n\r\n2.\u00a0[latex]25[\/latex]\r\n\r\n3.\u00a0[latex]\\{-1\\}[\/latex]\r\n\r\n4.\u00a0[latex]x=0[\/latex], [latex]x=\\frac{1}{2}[\/latex], [latex]x=-\\frac{1}{2}[\/latex]\r\n\r\n5.\u00a0[latex]x=1[\/latex]; extraneous solution [latex]x=-\\frac{2}{9}[\/latex]\r\n\r\n6.\u00a0[latex]x=-2[\/latex]; extraneous solution [latex]x=-1[\/latex]\r\n\r\n7.\u00a0[latex]x=-1[\/latex], [latex]x=\\frac{3}{2}[\/latex]\r\n\r\n8.\u00a0[latex]x=-3,3,-i,i[\/latex]\r\n\r\n9.\u00a0[latex]x=2,x=12[\/latex]\r\n\r\n10.\u00a0[latex]x=-1[\/latex], [latex]x=0[\/latex] is not a solution.\r\n

Solutions to Odd-Numbered Exercises<\/h2>\r\n1.\u00a0This is not a solution to the radical equation, it is a value obtained from squaring both sides and thus changing the signs of an equation which has caused it not to be a solution in the original equation.\r\n\r\n3.\u00a0He or she is probably trying to enter negative 9, but taking the square root of [latex]-9[\/latex] is not a real number. The negative sign is in front of this, so your friend should be taking the square root of 9, cubing it, and then putting the negative sign in front, resulting in [latex]-27[\/latex].\r\n\r\n5.\u00a0A rational exponent is a fraction: the denominator of the fraction is the root or index number and the numerator is the power to which it is raised.\r\n\r\n7.\u00a0[latex]x=81[\/latex]\r\n\r\n9.\u00a0[latex]x=17[\/latex]\r\n\r\n11.\u00a0[latex]x=8, x=27[\/latex]\r\n\r\n13.\u00a0[latex]x=-2,1,-1[\/latex]\r\n\r\n15.\u00a0[latex]y=0, \\frac{3}{2}, \\frac{-3}{2}[\/latex]\r\n\r\n17.\u00a0[latex]m=1,-1[\/latex]\r\n\r\n19.\u00a0[latex]x=\\frac{2}{5}[\/latex]\r\n\r\n21. [latex]x=32[\/latex]\r\n\r\n23. [latex]t=\\frac{44}{3}[\/latex]\r\n\r\n25.\u00a0[latex]x=3[\/latex]\r\n\r\n27.\u00a0[latex]x=-2[\/latex]\r\n\r\n29.\u00a0[latex]x=4,\\frac{-4}{3}[\/latex]\r\n\r\n31.\u00a0[latex]x=\\frac{-5}{4},\\frac{7}{4}[\/latex]\r\n\r\n33.\u00a0[latex]x=3,-2[\/latex]\r\n\r\n35.\u00a0[latex]x=-5[\/latex]\r\n\r\n37.\u00a0[latex]x=1,-1,3,-3[\/latex]\r\n\r\n39.\u00a0[latex]x=2,-2[\/latex]\r\n\r\n41.\u00a0[latex]x=1,5[\/latex]\r\n\r\n43.\u00a0All real numbers\r\n\r\n45.\u00a0[latex]x=4,6,-6,-8[\/latex]\r\n\r\n47.\u00a010 in.\r\n\r\n49.\u00a090 kg","rendered":"

Solutions to Try Its<\/h2>\n

1.\u00a0[latex]\\frac{1}{4}[\/latex]<\/p>\n

2.\u00a0[latex]25[\/latex]<\/p>\n

3.\u00a0[latex]\\{-1\\}[\/latex]<\/p>\n

4.\u00a0[latex]x=0[\/latex], [latex]x=\\frac{1}{2}[\/latex], [latex]x=-\\frac{1}{2}[\/latex]<\/p>\n

5.\u00a0[latex]x=1[\/latex]; extraneous solution [latex]x=-\\frac{2}{9}[\/latex]<\/p>\n

6.\u00a0[latex]x=-2[\/latex]; extraneous solution [latex]x=-1[\/latex]<\/p>\n

7.\u00a0[latex]x=-1[\/latex], [latex]x=\\frac{3}{2}[\/latex]<\/p>\n

8.\u00a0[latex]x=-3,3,-i,i[\/latex]<\/p>\n

9.\u00a0[latex]x=2,x=12[\/latex]<\/p>\n

10.\u00a0[latex]x=-1[\/latex], [latex]x=0[\/latex] is not a solution.<\/p>\n

Solutions to Odd-Numbered Exercises<\/h2>\n

1.\u00a0This is not a solution to the radical equation, it is a value obtained from squaring both sides and thus changing the signs of an equation which has caused it not to be a solution in the original equation.<\/p>\n

3.\u00a0He or she is probably trying to enter negative 9, but taking the square root of [latex]-9[\/latex] is not a real number. The negative sign is in front of this, so your friend should be taking the square root of 9, cubing it, and then putting the negative sign in front, resulting in [latex]-27[\/latex].<\/p>\n

5.\u00a0A rational exponent is a fraction: the denominator of the fraction is the root or index number and the numerator is the power to which it is raised.<\/p>\n

7.\u00a0[latex]x=81[\/latex]<\/p>\n

9.\u00a0[latex]x=17[\/latex]<\/p>\n

11.\u00a0[latex]x=8, x=27[\/latex]<\/p>\n

13.\u00a0[latex]x=-2,1,-1[\/latex]<\/p>\n

15.\u00a0[latex]y=0, \\frac{3}{2}, \\frac{-3}{2}[\/latex]<\/p>\n

17.\u00a0[latex]m=1,-1[\/latex]<\/p>\n

19.\u00a0[latex]x=\\frac{2}{5}[\/latex]<\/p>\n

21. [latex]x=32[\/latex]<\/p>\n

23. [latex]t=\\frac{44}{3}[\/latex]<\/p>\n

25.\u00a0[latex]x=3[\/latex]<\/p>\n

27.\u00a0[latex]x=-2[\/latex]<\/p>\n

29.\u00a0[latex]x=4,\\frac{-4}{3}[\/latex]<\/p>\n

31.\u00a0[latex]x=\\frac{-5}{4},\\frac{7}{4}[\/latex]<\/p>\n

33.\u00a0[latex]x=3,-2[\/latex]<\/p>\n

35.\u00a0[latex]x=-5[\/latex]<\/p>\n

37.\u00a0[latex]x=1,-1,3,-3[\/latex]<\/p>\n

39.\u00a0[latex]x=2,-2[\/latex]<\/p>\n

41.\u00a0[latex]x=1,5[\/latex]<\/p>\n

43.\u00a0All real numbers<\/p>\n

45.\u00a0[latex]x=4,6,-6,-8[\/latex]<\/p>\n

47.\u00a010 in.<\/p>\n

49.\u00a090 kg<\/p>\n\n\t\t\t

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Candela Citations<\/h3>\n\t\t\t\t\t
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