Corequisite Support Activity for Z-Score and the Empirical Rule: 4E – 28

What you’ll need to know

In this support activity you’ll become familiar with the following:

You will also have an opportunity to refresh the following skills:

In the next section of the course material and in the following activity, you will need to be familiar with a method for measuring how far a given data value is from the mean. You’ve seen before how to calculate deviation from the mean for a given data value. This method standardizes the distance in units of standard deviation above or below the mean. The calculations will be performed by hand, and they can be a little tricky. In this corequisite support activity, you’ll get some practice with them and learn where and how they can go wrong.

Measuring Distance from Mean

We’ll use a hypothetical typical arm span for Americans in our exploration of this method for measuring distance from the mean. Arm span is the distance from the tip of the middle finger on one hand to the tip of the middle finger on the other hand when one’s arms are stretched out and opened wide.

Suppose that, based on many measurements, a statistician believes that the distribution of arm spans of Americans has a mean of 173.40 centimeters (cm) and a standard deviation of 12.21 cm. Let’s understand that these values to pertain to the population of all American arm spans (not just a sample).

For Questions 1, 3, and 5 below, you’ll calculate arm span values that are one, two, and one-and-a-half standard deviations above and below the mean of 173.40 cm. Then, you’ll carefully follow the directions in Questions 2, 4, and 6, to make the specified calculations for each of the numbers you calculated in the previous question. Note that in each of these, you’ll have found the difference between the given value and the mean, and divided that distance by the standard deviation.  We call this standardizing the value, but  we’ll cover that more deeply in the next section. For now, let’s just get some practice making the necessary calculations by hand.

Calculate and interpret units of standard deviation as a measure of distance

question 1

What arm span value is one standard deviation above the mean? What arm span value is one standard deviation below the mean? Round to the nearest hundredth.

question 2

For each of the two answers you computed in Question 1, subtract the mean of 173.40 and then divide by the standard deviation of 12.21. In other words, calculate the following for each value computed in Question 1:

[latex]\dfrac{\text{ Value }-173.4}{12.21}[/latex]

In Question 1 you calculated a value exactly one standard deviation above and one below the mean. In Question 2, you divided the difference between the value you calculated and the mean by the standard deviation. You should have obtained positive one and negative one for the values above and below, respectively. What does positive imply? How about negative?

Let’s try another couple of sets of questions like that to observe what’s happening.

question 3

What arm span value is two standard deviations above the mean? What arm span value is two standard deviations below the mean? Round to the nearest hundredth.

question 4

For each of the two answers you computed in Question 3, subtract the mean of 173.40 and then divide by the standard deviation of 12.21. In other words, calculate the following for each value computed in Question 3:

[latex]\dfrac{\text{ Value }-173.4}{12.21}[/latex]

Hopefully you obtained positive and negative two for your answers to Question 4. Have you caught on to what’s happening in these question pairs yet?  Let’s try one more pair. In Question 5, you’ll identify values one and a half standard deviations above and below the mean. Can you predict what the answers to Question 6 should be?

question 5

What arm span value is one and a half standard deviations above the mean? What arm span value is one and a half standard deviations below the mean? Round to the nearest hundredth.

question 6

For each value computed in Question 5, calculate the following:

[latex]\dfrac{\text{ Value } -173.4}{12.21}[/latex]

In Questions 2, 4, and 6, you calculated values that were a given number of standard deviations above and below the mean. You discovered when you divided the difference between the value and the mean by the standard deviation, that the result was a positive number of standard deviations (for values above the mean) or a negative number of standard deviations (for values below the mean). That is, a resulting negative can be thought of as indicating a value that lies to the left of the mean, and the positive indicates a value that lies to the right of the mean.

Calculate the distance in units of standard deviations of an observed value from the population mean

A natural question to consider might be, given any value any distance from the mean in any direction, if we find the difference between the value and mean, then divide by the standard deviation, would we be able to discover the number of standard deviations any value is from the mean and whether it lies to the right or to the left? Answer Questions 7 and 8 to explore this idea.

question 7

Suppose a classmate has an arm span of 200 cm. How many standard deviations from the mean is this arm span and in what direction? Round your answer to the nearest hundredth.

question 8

Suppose another classmate has an arm span of 165 cm. How many standard deviations from the mean is this arm span and in what direction? Round your answer to the nearest hundredth.

Now let’s spend some time understanding how and in what way these kinds of calculations can go wrong.

Identify mistakes in calculations

Suppose the statistician making these calculations thought she was using her calculator correctly, but in three different attempts, she arrived at three different answers. The three potential answers to her computational problem are shown below in Questions 9, 10, and 11 rounded to the nearest hundredth. For each, decide if it was computed correctly or, if not, explain what went wrong. Please refer to the Order of Operations Student Resource as needed.

question 9

[latex]\dfrac{185-173.4}{12.21}\approx 170.80[/latex]

question 10

[latex]\dfrac{185-173.4}{12.21}\approx -0.95[/latex]

question 11

[latex]\dfrac{185-173.4}{12.21}\approx 0.95[/latex]

Questions 12, 13, and 14 below show three potential answers to a similar computational problem, rounded to the nearest hundredth. This time, the units of measure are included. For each, decide if it was computed correctly or, if not, explain what went wrong.

question 12

[latex]\dfrac{150\text{ cm }-173.4\text{ cm }}{12.21\text{ cm }}\approx -1.92[/latex]

question 13

[latex]\dfrac{150\text{ cm }-173.4\text{ cm }}{12.21\text{ cm }}\approx 1.92[/latex]

question 14

[latex]\dfrac{150\text{ cm }-173.4\text{ cm }}{12.21\text{ cm }}\approx -1.92\text{ cm }[/latex]

Now that you’ve had some practice making these calculations and learning how they can go wrong, it’s time to move on to the next section.