## Compound Interest

### Learning Outcomes

• Calculate compound interest given an interest scenario
• Calculate the initial balance given an interest scenario
• Solve for time in a compound interest problem

## Compounding

With simple interest, we were assuming that we pocketed the interest when we received it. In a standard bank account, any interest we earn is automatically added to our balance, and we earn interest on that interest in future years. This reinvestment of interest is called compounding.

Suppose that we deposit $1000 in a bank account offering 3% interest, compounded monthly. How will our money grow? The 3% interest is an annual percentage rate (APR) – the total interest to be paid during the year. Since interest is being paid monthly, each month, we will earn $\frac{3%}{12}$= 0.25% per month. In the first month, • P0 =$1000
• r = 0.0025 (0.25%)
• I = $1000 (0.0025) =$2.50
• A = $1000 +$2.50 = $1002.50 In the first month, we will earn$2.50 in interest, raising our account balance to $1002.50. In the second month, • P0 =$1002.50
• I = $1002.50 (0.0025) =$2.51 (rounded)
• A = $1002.50 +$2.51 = $1005.01 Notice that in the second month we earned more interest than we did in the first month. This is because we earned interest not only on the original$1000 we deposited, but we also earned interest on the $2.50 of interest we earned the first month. This is the key advantage that compounding interest gives us. Calculating out a few more months gives the following:  Month Starting balance Interest earned Ending Balance 1 1000.00 2.50 1002.50 2 1002.50 2.51 1005.01 3 1005.01 2.51 1007.52 4 1007.52 2.52 1010.04 5 1010.04 2.53 1012.57 6 1012.57 2.53 1015.10 7 1015.10 2.54 1017.64 8 1017.64 2.54 1020.18 9 1020.18 2.55 1022.73 10 1022.73 2.56 1025.29 11 1025.29 2.56 1027.85 12 1027.85 2.57 1030.42 We want to simplify the process for calculating compounding, because creating a table like the one above is time consuming. Luckily, math is good at giving you ways to take shortcuts. To find an equation to represent this, if Pm represents the amount of money after m months, then we could write the recursive equation: P0 =$1000

Pm = (1+0.0025)Pm-1

You may recognize this as the recursive form of exponential growth.

### recursive growth

Recall the underlying process of recursive growth. From a starting amount, $P_0$, each subsequent amount, $P_m$, grows in proportion to itself, $P_{m-1}$, at some rate $r$.

$P_m=P_{m-1}+r\cdot P_{m-1}$

Factoring out the $P_{m-1}$ from each term on the right-hand side

$P_m=(1+r)\cdot P_{m-1}$.

In the example below, we’ll build an explicit equation for the growth.

### Multiplying terms containing exponents

In the example below, you’ll need to use the rules for multiplying like bases containing exponents

$a^{m}a^{n}=a^{m+n}$.

That is, when multiplying like bases, we add the exponents.

Build an explicit equation for the growth of $1000 deposited in a bank account offering 3% interest, compounded monthly. View this video for a walkthrough of the concept of compound interest. While this formula works fine, it is more common to use a formula that involves the number of years, rather than the number of compounding periods. If N is the number of years, then m = N k. Making this change gives us the standard formula for compound interest. ### $m=Nk$ How did we get $m = Nk$? Recall that $m$ represents the number of compounding periods that an investment remains in the account, and $k$ represents the number of times per year that your interest is compounded. If your deposit earns interest compounded monthly, then $k = 12$. If you leave the deposit in for $1$ year, then $m = 12$. But if $k = 12$ and you leave the deposit in for $2$ years, then $m = 2*12 = 24$. Looking at that another way, $m = N\text{ years} * k$. $m = Nk$. Ex. An investment of$1000 earning interest of 4% compounded quarterly (4 times per year) is left in the account for $3$ years.

We have $4$ compounding periods per year, so $k = 4$

If we leave our money in for $1$ year, the number of compounding periods is $1*4: m=4$.

If we leave our money in for $3$ years, $m = 3*4$, or $12$.

Knowing that investments are usually left to grow over years than over a number of compounding periods, we’ll adjust the formula slightly and just write $Nk$. This will make it easier to load the formula into a spreadsheet. See the quantitative reasoning module for more on how to use spreadsheets with financial analysis.

### Compound Interest

$P_{N}=P_{0}\left(1+\frac{r}{k}\right)^{Nk}$

• PN is the balance in the account after N years.
• P0 is the starting balance of the account (also called initial deposit, or principal)
• r is the annual interest rate in decimal form
• k is the number of compounding periods in one year
• If the compounding is done annually (once a year), k = 1.
• If the compounding is done quarterly, k = 4.
• If the compounding is done monthly, k = 12.
• If the compounding is done daily, k = 365.
The most important thing to remember about using this formula is that it assumes that we put money in the account once and let it sit there earning interest.

In the next example, we show how to use the compound interest formula to find the balance on a certificate of deposit after 20 years.

### don’t forget to convert percent to a decimal

Usually, in order to perform calculations on a number expressed in percent form, you’ll need to convert it to decimal form. The rate $r$ in interest formulas must be converted from percent to decimal form before you use the formula.

### Example

A certificate of deposit (CD) is a savings instrument that many banks offer. It usually gives a higher interest rate, but you cannot access your investment for a specified length of time. Suppose you deposit $3000 in a CD paying 6% interest, compounded monthly. How much will you have in the account after 20 years? A video walkthrough of this example problem is available below. Let us compare the amount of money earned from compounding against the amount you would earn from simple interest  Years Simple Interest ($15 per month) 6% compounded monthly = 0.5% each month. 5 $3900$4046.55 10 $4800$5458.19 15 $5700$7362.28 20 $6600$9930.61 25 $7500$13394.91 30 $8400$18067.73 35 $9300$24370.65

As you can see, over a long period of time, compounding makes a large difference in the account balance. You may recognize this as the difference between linear growth and exponential growth.

### Linear growth vs exponential growth

Recall that linear growth increases at a constant rate. A graph of linear growth will describe a straight line between any two points on the graph. The graph changes by the same additive amount per unit of input.

### Rounding

It is important to be very careful about rounding when calculating things with exponents. In general, you want to keep as many decimals during calculations as you can. Be sure to keep at least 3 significant digits (numbers after any leading zeros). Rounding 0.00012345 to 0.000123 will usually give you a “close enough” answer, but keeping more digits is always better.

### Example

To see why not over-rounding is so important, suppose you were investing $1000 at 5% interest compounded monthly for 30 years.  P0 =$1000 the initial deposit r = 0.05 5% k = 12 12 months in 1 year N = 30 since we’re looking for the amount after 30 years

If we first compute r/k, we find 0.05/12 = 0.00416666666667

Here is the effect of rounding this to different values:

 r/k rounded to: Gives P­30­ to be: Error 0.004 $4208.59$259.15 0.0042 $4521.45$53.71 0.00417 $4473.09$5.35 0.004167 $4468.28$0.54 0.0041667 $4467.80$0.06 no rounding $4467.74 If you’re working in a bank, of course you wouldn’t round at all. For our purposes, the answer we got by rounding to 0.00417, three significant digits, is close enough –$5 off of $4500 isn’t too bad. Certainly keeping that fourth decimal place wouldn’t have hurt. View the following for a demonstration of this example. ### Using your calculator In many cases, you can avoid rounding completely by how you enter things in your calculator. For example, in the example above, we needed to calculate ${{P}_{30}}=1000{{\left(1+\frac{0.05}{12}\right)}^{12\times30}}$ We can quickly calculate 12×30 = 360, giving ${{P}_{30}}=1000{{\left(1+\frac{0.05}{12}\right)}^{360}}$. Now we can use the calculator.  Type this Calculator shows 0.05 ÷ 12 = . 0.00416666666667 + 1 = . 1.00416666666667 yx 360 = . 4.46774431400613 × 1000 = . 4467.74431400613 ### Using your calculator continued The previous steps were assuming you have a “one operation at a time” calculator; a more advanced calculator will often allow you to type in the entire expression to be evaluated. If you have a calculator like this, you will probably just need to enter: 1000 × ( 1 + 0.05 ÷ 12 ) yx 360 = ## Solving For Time Note: This section assumes you’ve covered solving exponential equations using logarithms, either in prior classes or in the growth models chapter. Often we are interested in how long it will take to accumulate money or how long we’d need to extend a loan to bring payments down to a reasonable level. ### Examples If you invest$2000 at 6% compounded monthly, how long will it take the account to double in value?

Get additional guidance for this example in the following: