{"id":1055,"date":"2015-11-12T18:35:32","date_gmt":"2015-11-12T18:35:32","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=1055"},"modified":"2015-11-12T18:35:32","modified_gmt":"2015-11-12T18:35:32","slug":"represent-a-linear-function","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/chapter\/represent-a-linear-function\/","title":{"raw":"Represent a linear function","rendered":"Represent a linear function"},"content":{"raw":"<p id=\"fs-id1165137573850\">The function describing the train\u2019s motion is a <strong>linear function<\/strong>, which is defined as a function with a constant rate of change, that is, a polynomial of degree 1. There are several ways to represent a linear function, including word form, function notation, tabular form, and graphical form. We will describe the train\u2019s motion as a function using each method.<\/p>\n\n<section id=\"fs-id1165137759903\" data-depth=\"2\"><h2 style=\"text-align: center;\" data-type=\"title\"\/>\n<h2 style=\"text-align: center;\" data-type=\"title\"\/>\n<h2 style=\"text-align: center;\" data-type=\"title\"><span style=\"text-decoration: underline;\">Representing a Linear Function in Word Form<\/span><\/h2>\n<p id=\"fs-id1165137588695\">Let\u2019s begin by describing the linear function in words. For the train problem we just considered, the following word sentence may be used to describe the function relationship.<\/p>\n\n<ul id=\"fs-id1165135526954\"><li><em data-effect=\"italics\">The train\u2019s distance from the station is a function of the time during which the train moves at a constant speed plus its original distance from the station when it began moving at constant speed.<\/em><\/li>\n<\/ul><p id=\"fs-id1165135188466\">The speed is the rate of change. Recall that a rate of change is a measure of how quickly the dependent variable changes with respect to the independent variable. The rate of change for this example is constant, which means that it is the same for each input value. As the time (input) increases by 1 second, the corresponding distance (output) increases by 83 meters. The train began moving at this constant speed at a distance of 250 meters from the station.<\/p>\n\n<\/section><section id=\"fs-id1165135639903\" data-depth=\"2\"><h2 style=\"text-align: center;\" data-type=\"title\"\/>\n<h2 style=\"text-align: center;\" data-type=\"title\"\/>\n<h2 style=\"text-align: center;\" data-type=\"title\"><span style=\"text-decoration: underline;\">Representing a Linear Function in Function Notation<\/span><\/h2>\n<p id=\"fs-id1165137833100\">Another approach to representing linear functions is by using function notation. One example of function notation is an equation written in the form known as the <strong>slope-intercept form<\/strong> of a line, where [latex]x[\/latex] is the input value, [latex]m[\/latex] is the rate of change, and [latex]b[\/latex] is the initial value of the dependent variable.<\/p>\n\n<div id=\"Equation_02_01_01\" class=\"equation\" style=\"text-align: center;\" data-type=\"equation\">[latex]\\begin{cases}\\text{Equation form}\\hfill &amp; y=mx+b\\hfill \\\\ \\text{Equation notation}\\hfill &amp; f\\left(x\\right)=mx+b\\hfill \\end{cases}[\/latex]<\/div>\n<p id=\"fs-id1165137411219\">In the example of the train, we might use the notation [latex]D\\left(t\\right)[\/latex]\u00a0in which the total distance [latex]D[\/latex]\nis a function of the time [latex]t[\/latex].\u00a0The rate, [latex]m[\/latex],\u00a0is 83 meters per second. The initial value of the dependent variable [latex]b[\/latex]\u00a0is the original distance from the station, 250 meters. We can write a generalized equation to represent the motion of the train.<\/p>\n\n<div id=\"fs-id1165137559254\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]D\\left(t\\right)=83t+250[\/latex]<\/div>\n<\/section><section id=\"fs-id1165135415800\" data-depth=\"2\"><h2 style=\"text-align: center;\" data-type=\"title\"\/>\n<h2 style=\"text-align: center;\" data-type=\"title\"\/>\n<h2 style=\"text-align: center;\" data-type=\"title\"><span style=\"text-decoration: underline;\">Representing a Linear Function in Tabular Form<\/span><\/h2>\n<p id=\"fs-id1165137438406\">A third method of representing a linear function is through the use of a table. The relationship between the distance from the station and the time is represented in the table in Figure 1. From the table, we can see that the distance changes by 83 meters for every 1 second increase in time.<\/p>\n\n\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201015\/CNX_Precalc_Figure_02_01_0152.jpg\" alt=\"Table with the first row, labeled t, containing the seconds from 0 to 3, and with the second row, labeled D(t), containing the meters 250 to 499. The first row goes up by 1 second, and the second row goes up by 83 meters.\" width=\"487\" height=\"161\" data-media-type=\"image\/jpg\"\/><b>Figure 1.<\/b> Tabular representation of the function D showing selected input and output values[\/caption]\n\n<div id=\"fs-id1165137482942\" class=\"note precalculus qa textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"Q&amp;A\">\n<h3 id=\"fs-id1165137828205\"><strong>Q &amp; A<\/strong><\/h3>\n<strong>Can the input in the previous example be any real number?<\/strong>\n<p id=\"fs-id1165135209002\"><em data-effect=\"italics\">No. The input represents time, so while nonnegative rational and irrational numbers are possible, negative real numbers are not possible for this example. The input consists of non-negative real numbers.<\/em><\/p>\n\n<\/div>\n<\/section><section id=\"fs-id1165137619188\" data-depth=\"2\"><h2 style=\"text-align: center;\" data-type=\"title\"\/>\n<h2 style=\"text-align: center;\" data-type=\"title\"\/>\n<h2 style=\"text-align: center;\" data-type=\"title\"><span style=\"text-decoration: underline;\">Representing a Linear Function in Graphical Form<\/span><\/h2>\n<p id=\"fs-id1165137827353\">Another way to represent linear functions is visually, using a graph. We can use the function relationship from above, [latex]D\\left(t\\right)=83t+250[\/latex], to draw a graph, represented in the graph in Figure 2. Notice the graph is a line. When we plot a linear function, the graph is always a line.<\/p>\n<p id=\"fs-id1165137451297\">The rate of change, which is constant, determines the slant, or <strong>slope<\/strong> of the line. The point at which the input value is zero is the vertical intercept, or <strong><em data-effect=\"italics\">y<\/em>-intercept<\/strong>, of the line. We can see from the graph that the <em data-effect=\"italics\">y<\/em>-intercept in the train example we just saw is [latex]\\left(0,250\\right)[\/latex]\u00a0and represents the distance of the train from the station when it began moving at a constant speed.<\/p>\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201017\/CNX_Precalc_Figure_02_01_0122.jpg\" alt=\"A graph of an increasing function with points at (-2, -4) and (0, 2).\" width=\"487\" height=\"289\" data-media-type=\"image\/jpg\"\/><p style=\"text-align: center;\"><strong>Figure 2.<\/strong> The graph of [latex]D\\left(t\\right)=83t+250[\/latex]. Graphs of linear functions are lines because the rate of change is constant.<\/p>\n<p id=\"fs-id1165137715509\">Notice that the graph of the train example is restricted, but this is not always the case. Consider the graph of the line [latex]f\\left(x\\right)=2{x}_{}+1[\/latex].\u00a0Ask yourself what numbers can be input to the function, that is, what is the domain of the function? The domain is comprised of all real numbers because any number may be doubled, and then have one added to the product.<\/p>\n\n<div id=\"fs-id1165137726089\" class=\"note textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"A General Note\">\n<h3 class=\"title\" data-type=\"title\">A General Note: Linear Function<\/h3>\n<p id=\"fs-id1165137454496\">A <strong>linear function<\/strong> is a function whose graph is a line. Linear functions can be written in the slope-intercept form of a line<\/p>\n\n<div id=\"Equation_02_01_02\" class=\"equation\" style=\"text-align: center;\" data-type=\"equation\">[latex]f\\left(x\\right)=mx+b[\/latex]<\/div>\n<p id=\"fs-id1165137784222\">where [latex]b[\/latex]\u00a0is the initial or starting value of the function (when input, [latex]x=0[\/latex]), and [latex]m[\/latex]\u00a0is the constant rate of change, or <strong>slope<\/strong> of the function. The <strong><em data-effect=\"italics\">y<\/em>-intercept<\/strong> is at [latex]\\left(0,b\\right)[\/latex].<\/p>\n\n<\/div>\n<div id=\"Example_02_01_01\" class=\"example\" data-type=\"example\">\n<div id=\"fs-id1165137583894\" class=\"exercise\" data-type=\"exercise\">\n<div id=\"fs-id1165135209144\" class=\"problem textbox shaded\" data-type=\"problem\">\n<h3 data-type=\"title\">Example 1: Using a Linear Function to Find the Pressure on a Diver<\/h3>\nThe pressure, [latex]P[\/latex],\u00a0in pounds per square inch (PSI) on the diver in Figure 3\u00a0depends upon her depth below the water surface, [latex]d[\/latex], in feet. This relationship may be modeled by the equation, [latex]P\\left(d\\right)=0.434d+14.696[\/latex]. Restate this function in words.\n\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201018\/CNX_Precalc_Figure_02_01_0032.jpg\" alt=\"Scuba diver.\" width=\"487\" height=\"366\" data-media-type=\"image\/jpg\"\/><b>Figure 3.<\/b> (credit: Ilse Reijs and Jan-Noud Hutten)[\/caption]\n\n<\/div>\n<div id=\"fs-id1165135181728\" class=\"solution textbox shaded\" data-type=\"solution\">\n<h3>Solution<\/h3>\n<p id=\"fs-id1165137398472\">To restate the function in words, we need to describe each part of the equation. The pressure as a function of depth equals four hundred thirty-four thousandths times depth plus fourteen and six hundred ninety-six thousandths.<\/p>\n\n<\/div>\n<div id=\"fs-id1165137738187\" class=\"commentary\" data-type=\"commentary\">\n<h3 data-type=\"title\">Analysis of the Solution<\/h3>\n<p id=\"fs-id1165137740917\">The initial value, 14.696, is the pressure in PSI on the diver at a depth of 0 feet, which is the surface of the water. The rate of change, or slope, is 0.434 PSI per foot. This tells us that the pressure on the diver increases 0.434 PSI for each foot her depth increases.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/section>","rendered":"<p id=\"fs-id1165137573850\">The function describing the train\u2019s motion is a <strong>linear function<\/strong>, which is defined as a function with a constant rate of change, that is, a polynomial of degree 1. There are several ways to represent a linear function, including word form, function notation, tabular form, and graphical form. We will describe the train\u2019s motion as a function using each method.<\/p>\n<section id=\"fs-id1165137759903\" data-depth=\"2\">\n<h2 style=\"text-align: center;\" data-type=\"title\">\n<p><span style=\"text-decoration: underline;\">Representing a Linear Function in Word Form<\/span><\/h2>\n<p id=\"fs-id1165137588695\">Let\u2019s begin by describing the linear function in words. For the train problem we just considered, the following word sentence may be used to describe the function relationship.<\/p>\n<ul id=\"fs-id1165135526954\">\n<li><em data-effect=\"italics\">The train\u2019s distance from the station is a function of the time during which the train moves at a constant speed plus its original distance from the station when it began moving at constant speed.<\/em><\/li>\n<\/ul>\n<p id=\"fs-id1165135188466\">The speed is the rate of change. Recall that a rate of change is a measure of how quickly the dependent variable changes with respect to the independent variable. The rate of change for this example is constant, which means that it is the same for each input value. As the time (input) increases by 1 second, the corresponding distance (output) increases by 83 meters. The train began moving at this constant speed at a distance of 250 meters from the station.<\/p>\n<\/section>\n<section id=\"fs-id1165135639903\" data-depth=\"2\">\n<h2 style=\"text-align: center;\" data-type=\"title\">\n<p><span style=\"text-decoration: underline;\">Representing a Linear Function in Function Notation<\/span><\/h2>\n<p id=\"fs-id1165137833100\">Another approach to representing linear functions is by using function notation. One example of function notation is an equation written in the form known as the <strong>slope-intercept form<\/strong> of a line, where [latex]x[\/latex] is the input value, [latex]m[\/latex] is the rate of change, and [latex]b[\/latex] is the initial value of the dependent variable.<\/p>\n<div id=\"Equation_02_01_01\" class=\"equation\" style=\"text-align: center;\" data-type=\"equation\">[latex]\\begin{cases}\\text{Equation form}\\hfill & y=mx+b\\hfill \\\\ \\text{Equation notation}\\hfill & f\\left(x\\right)=mx+b\\hfill \\end{cases}[\/latex]<\/div>\n<p id=\"fs-id1165137411219\">In the example of the train, we might use the notation [latex]D\\left(t\\right)[\/latex]\u00a0in which the total distance [latex]D[\/latex]<br \/>\nis a function of the time [latex]t[\/latex].\u00a0The rate, [latex]m[\/latex],\u00a0is 83 meters per second. The initial value of the dependent variable [latex]b[\/latex]\u00a0is the original distance from the station, 250 meters. We can write a generalized equation to represent the motion of the train.<\/p>\n<div id=\"fs-id1165137559254\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]D\\left(t\\right)=83t+250[\/latex]<\/div>\n<\/section>\n<section id=\"fs-id1165135415800\" data-depth=\"2\">\n<h2 style=\"text-align: center;\" data-type=\"title\">\n<p><span style=\"text-decoration: underline;\">Representing a Linear Function in Tabular Form<\/span><\/h2>\n<p id=\"fs-id1165137438406\">A third method of representing a linear function is through the use of a table. The relationship between the distance from the station and the time is represented in the table in Figure 1. From the table, we can see that the distance changes by 83 meters for every 1 second increase in time.<\/p>\n<div style=\"width: 497px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201015\/CNX_Precalc_Figure_02_01_0152.jpg\" alt=\"Table with the first row, labeled t, containing the seconds from 0 to 3, and with the second row, labeled D(t), containing the meters 250 to 499. The first row goes up by 1 second, and the second row goes up by 83 meters.\" width=\"487\" height=\"161\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\"><b>Figure 1.<\/b> Tabular representation of the function D showing selected input and output values<\/p>\n<\/div>\n<div id=\"fs-id1165137482942\" class=\"note precalculus qa textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"Q&amp;A\">\n<h3 id=\"fs-id1165137828205\"><strong>Q &amp; A<\/strong><\/h3>\n<p><strong>Can the input in the previous example be any real number?<\/strong><\/p>\n<p id=\"fs-id1165135209002\"><em data-effect=\"italics\">No. The input represents time, so while nonnegative rational and irrational numbers are possible, negative real numbers are not possible for this example. The input consists of non-negative real numbers.<\/em><\/p>\n<\/div>\n<\/section>\n<section id=\"fs-id1165137619188\" data-depth=\"2\">\n<h2 style=\"text-align: center;\" data-type=\"title\">\n<p><span style=\"text-decoration: underline;\">Representing a Linear Function in Graphical Form<\/span><\/h2>\n<p id=\"fs-id1165137827353\">Another way to represent linear functions is visually, using a graph. We can use the function relationship from above, [latex]D\\left(t\\right)=83t+250[\/latex], to draw a graph, represented in the graph in Figure 2. Notice the graph is a line. When we plot a linear function, the graph is always a line.<\/p>\n<p id=\"fs-id1165137451297\">The rate of change, which is constant, determines the slant, or <strong>slope<\/strong> of the line. The point at which the input value is zero is the vertical intercept, or <strong><em data-effect=\"italics\">y<\/em>-intercept<\/strong>, of the line. We can see from the graph that the <em data-effect=\"italics\">y<\/em>-intercept in the train example we just saw is [latex]\\left(0,250\\right)[\/latex]\u00a0and represents the distance of the train from the station when it began moving at a constant speed.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201017\/CNX_Precalc_Figure_02_01_0122.jpg\" alt=\"A graph of an increasing function with points at (-2, -4) and (0, 2).\" width=\"487\" height=\"289\" data-media-type=\"image\/jpg\" \/><\/p>\n<p style=\"text-align: center;\"><strong>Figure 2.<\/strong> The graph of [latex]D\\left(t\\right)=83t+250[\/latex]. Graphs of linear functions are lines because the rate of change is constant.<\/p>\n<p id=\"fs-id1165137715509\">Notice that the graph of the train example is restricted, but this is not always the case. Consider the graph of the line [latex]f\\left(x\\right)=2{x}_{}+1[\/latex].\u00a0Ask yourself what numbers can be input to the function, that is, what is the domain of the function? The domain is comprised of all real numbers because any number may be doubled, and then have one added to the product.<\/p>\n<div id=\"fs-id1165137726089\" class=\"note textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"A General Note\">\n<h3 class=\"title\" data-type=\"title\">A General Note: Linear Function<\/h3>\n<p id=\"fs-id1165137454496\">A <strong>linear function<\/strong> is a function whose graph is a line. Linear functions can be written in the slope-intercept form of a line<\/p>\n<div id=\"Equation_02_01_02\" class=\"equation\" style=\"text-align: center;\" data-type=\"equation\">[latex]f\\left(x\\right)=mx+b[\/latex]<\/div>\n<p id=\"fs-id1165137784222\">where [latex]b[\/latex]\u00a0is the initial or starting value of the function (when input, [latex]x=0[\/latex]), and [latex]m[\/latex]\u00a0is the constant rate of change, or <strong>slope<\/strong> of the function. The <strong><em data-effect=\"italics\">y<\/em>-intercept<\/strong> is at [latex]\\left(0,b\\right)[\/latex].<\/p>\n<\/div>\n<div id=\"Example_02_01_01\" class=\"example\" data-type=\"example\">\n<div id=\"fs-id1165137583894\" class=\"exercise\" data-type=\"exercise\">\n<div id=\"fs-id1165135209144\" class=\"problem textbox shaded\" data-type=\"problem\">\n<h3 data-type=\"title\">Example 1: Using a Linear Function to Find the Pressure on a Diver<\/h3>\n<p>The pressure, [latex]P[\/latex],\u00a0in pounds per square inch (PSI) on the diver in Figure 3\u00a0depends upon her depth below the water surface, [latex]d[\/latex], in feet. This relationship may be modeled by the equation, [latex]P\\left(d\\right)=0.434d+14.696[\/latex]. Restate this function in words.<\/p>\n<div style=\"width: 497px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201018\/CNX_Precalc_Figure_02_01_0032.jpg\" alt=\"Scuba diver.\" width=\"487\" height=\"366\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\"><b>Figure 3.<\/b> (credit: Ilse Reijs and Jan-Noud Hutten)<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135181728\" class=\"solution textbox shaded\" data-type=\"solution\">\n<h3>Solution<\/h3>\n<p id=\"fs-id1165137398472\">To restate the function in words, we need to describe each part of the equation. The pressure as a function of depth equals four hundred thirty-four thousandths times depth plus fourteen and six hundred ninety-six thousandths.<\/p>\n<\/div>\n<div id=\"fs-id1165137738187\" class=\"commentary\" data-type=\"commentary\">\n<h3 data-type=\"title\">Analysis of the Solution<\/h3>\n<p id=\"fs-id1165137740917\">The initial value, 14.696, is the pressure in PSI on the diver at a depth of 0 feet, which is the surface of the water. The rate of change, or slope, is 0.434 PSI per foot. This tells us that the pressure on the diver increases 0.434 PSI for each foot her depth increases.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1055\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":2,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1055","chapter","type-chapter","status-publish","hentry"],"part":1048,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1055","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":1,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1055\/revisions"}],"predecessor-version":[{"id":2457,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1055\/revisions\/2457"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/1048"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1055\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/media?parent=1055"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=1055"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/contributor?post=1055"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/license?post=1055"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}