{"id":1114,"date":"2015-11-12T18:35:32","date_gmt":"2015-11-12T18:35:32","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=1114"},"modified":"2017-03-31T22:08:17","modified_gmt":"2017-03-31T22:08:17","slug":"solve-a-system-of-linear-equations","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/chapter\/solve-a-system-of-linear-equations\/","title":{"raw":"Solve a system of linear equations","rendered":"Solve a system of linear equations"},"content":{"raw":"<p id=\"fs-id1165137627910\">A system of linear equations includes two or more linear equations. The graphs of two lines will intersect at a single point if they are not parallel. Two parallel lines can also intersect if they are coincident, which means they are the same line and they intersect at every point. For two lines that are not parallel, the single point of intersection will satisfy both equations and therefore represent the solution to the system.<\/p>\r\n<p id=\"fs-id1165137812669\">To find this point when the equations are given as functions, we can solve for an input value so that [latex]f\\left(x\\right)=g\\left(x\\right)[\/latex]. In other words, we can set the formulas for the lines equal to one another, and solve for the input that satisfies the equation.<\/p>\r\n\r\n<div id=\"Example_02_02_12\" class=\"example\" data-type=\"example\">\r\n<div id=\"fs-id1165137896187\" class=\"exercise\" data-type=\"exercise\">\r\n<div id=\"fs-id1165137896189\" class=\"problem textbox shaded\" data-type=\"problem\">\r\n<h3 data-type=\"title\">Example 12: Finding a Point of Intersection Algebraically<\/h3>\r\n<p id=\"fs-id1165135693776\">Find the point of intersection of the lines [latex]h\\left(t\\right)=3t - 4[\/latex] and [latex]j\\left(t\\right)=5-t[\/latex].<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165137838169\" class=\"solution textbox shaded\" data-type=\"solution\">\r\n<h3>Solution<\/h3>\r\n<p id=\"fs-id1165137838172\">Set [latex]h\\left(t\\right)=j\\left(t\\right)[\/latex].<\/p>\r\n\r\n<div id=\"fs-id1165137762108\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}3t - 4=5-t\\hfill \\\\ \\text{ }4t=9\\hfill \\\\ \\text{ }t=\\frac{9}{4}\\hfill \\end{cases}[\/latex]<\/div>\r\n<p id=\"fs-id1165137644219\">This tells us the lines intersect when the input is [latex]\\frac{9}{4}[\/latex].<\/p>\r\n<p id=\"fs-id1165137812337\">We can then find the output value of the intersection point by evaluating either function at this input.<\/p>\r\n\r\n<div id=\"fs-id1165134042758\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}j\\left(\\frac{9}{4}\\right)=5-\\frac{9}{4}\\hfill \\\\ \\text{ }=\\frac{11}{4}\\hfill \\end{cases}[\/latex]<\/div>\r\n<p id=\"fs-id1165137745176\">These lines intersect at the point [latex]\\left(\\frac{9}{4},\\frac{11}{4}\\right)[\/latex].<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135191329\" class=\"commentary\" data-type=\"commentary\">\r\n<h3 data-type=\"title\">Analysis of the Solution<\/h3>\r\nLooking at Figure 24, this result seems reasonable.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"487\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201118\/CNX_Precalc_Figure_02_02_0242.jpg\" alt=\"Graph of two functions h(t) = 3t - 4 and j(t) = t +5 and their intersection at (9\/4, 11\/4).\" width=\"487\" height=\"441\" data-media-type=\"image\/jpg\"\/><b>Figure 24<\/b>[\/caption]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137603219\" class=\"note precalculus qa textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"Q&amp;A\">\r\n<h3>Q &amp; A<\/h3>\r\n<p id=\"fs-id1165137447025\"><strong>If we were asked to find the point of intersection of two distinct parallel lines, should something in the solution process alert us to the fact that there are no solutions?<\/strong><\/p>\r\n<p id=\"fs-id1165137447030\"><em data-effect=\"italics\">Yes. After setting the two equations equal to one another, the result would be the contradiction \"0 = non-zero real number\".<\/em><\/p>\r\n\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 8<\/h3>\r\n<p id=\"fs-id1165137832295\">Using the graph in the Analysis of the Solution for Example 12,\u00a0identify the following for the function [latex]j\\left(t\\right)[\/latex]:<\/p>\r\n<p style=\"padding-left: 60px;\">a. y-intercept<\/p>\r\n<p style=\"padding-left: 60px;\">b. x-intercept(s)<\/p>\r\n<p style=\"padding-left: 60px;\">c. slope<\/p>\r\n<p style=\"padding-left: 60px;\">d. Is [latex]j\\left(t\\right)[\/latex] parallel or perpendicular to [latex]h\\left(t\\right)[\/latex] (or neither)?<\/p>\r\n<p style=\"padding-left: 60px;\">e. Is [latex]j\\left(t\\right)[\/latex] an increasing or decreasing function (or neither)?<\/p>\r\n<p style=\"padding-left: 60px;\">f. Write a transformation description for [latex]j\\left(t\\right)[\/latex] from the identity toolkit function [latex]f\\left(x\\right)=x[\/latex].<\/p>\r\n<a href=\"https:\/\/courses.candelalearning.com\/osprecalc\/chapter\/solutions-9\/\" target=\"_blank\">Solution<\/a>\r\n\r\n<\/div>\r\n<div id=\"Example_02_02_13\" class=\"example\" data-type=\"example\">\r\n<div id=\"fs-id1165137761773\" class=\"exercise\" data-type=\"exercise\">\r\n<div id=\"fs-id1165137761775\" class=\"problem textbox shaded\" data-type=\"problem\">\r\n<h3 data-type=\"title\">Example 13: Finding a Break-Even Point<\/h3>\r\n<p id=\"fs-id1165137761781\">A company sells sports helmets. The company incurs a one-time fixed cost for $250,000. Each helmet costs $120 to produce, and sells for $140.<\/p>\r\n\r\n<ol id=\"fs-id1165137870987\" data-number-style=\"lower-alpha\"><li>Find the cost function, <em>C<\/em>, to produce <em>x<\/em>\u00a0helmets, in dollars.<\/li>\r\n\t<li>Find the revenue function, <em>R<\/em>, from the sales of <em>x<\/em>\u00a0helmets, in dollars.<\/li>\r\n\t<li>Find the break-even point, the point of intersection of the two graphs <em>C\u00a0<\/em>and <em>R<\/em>.<\/li>\r\n<\/ol><\/div>\r\n<div id=\"fs-id1165137653644\" class=\"solution textbox shaded\" data-type=\"solution\">\r\n<h3>Solution<\/h3>\r\n<ol id=\"fs-id1165137653646\" data-number-style=\"lower-alpha\"><li>The cost function in the sum of the fixed cost, $125,000, and the variable cost, $120 per helmet.\r\n<div id=\"eip-id1885657\" class=\"equation unnumbered\" data-type=\"equation\" data-label=\"\">[latex]C\\left(x\\right)=120x+250,000[\/latex]<\/div><\/li>\r\n\t<li>The revenue function is the total revenue from the sale of [latex]x[\/latex] helmets, [latex]R\\left(x\\right)=140x[\/latex].<\/li>\r\n\t<li>The break-even point is the point of intersection of the graph of the cost and revenue functions. To find the <em data-effect=\"italics\">x<\/em>-coordinate of the coordinate pair of the point of intersection, set the two equations equal, and solve for <em>x<\/em>.\r\n<div id=\"eip-id1165133077884\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}\\text{ }C\\left(x\\right)=R\\left(x\\right)\\hfill \\\\ 250,000+120x=140x\\hfill \\\\ \\text{ }250,000=20x\\hfill \\\\ \\text{ }12,500=x\\hfill \\\\ \\text{ }x=12,500\\hfill \\end{cases}[\/latex]<\/div>\r\n<p id=\"eip-id1165134183817\">To find [latex]y[\/latex], evaluate either the revenue or the cost function at 12,500.<\/p>\r\n\r\n<div id=\"eip-id1165133220314\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}R\\left(20\\right)=140\\left(12,500\\right)\\hfill \\\\ =$1,750,000\\hfill \\end{cases}[\/latex]<\/div><\/li>\r\n<\/ol><p id=\"fs-id1165135496435\">The break-even point is (12,500, 1,750,000).<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165137935592\" class=\"commentary\" data-type=\"commentary\">\r\n<h3 data-type=\"title\">Analysis of the Solution<\/h3>\r\nThis means if the company sells 12,500 helmets, they break even; both the sales and cost incurred equaled 1.75 million dollars.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"731\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201120\/CNX_Precalc_Figure_02_02_025.jpg\" alt=\"Graph of the two functions, C(x) and R(x) where it shows that below (12500, 1750000) the company loses money and above that point the company makes a profit.\" width=\"731\" height=\"695\" data-media-type=\"image\/jpg\"\/><b>Figure 25<\/b>[\/caption]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137811889\" class=\"note precalculus media\" data-type=\"note\" data-has-label=\"true\" data-label=\"Media\"\/>","rendered":"<p id=\"fs-id1165137627910\">A system of linear equations includes two or more linear equations. The graphs of two lines will intersect at a single point if they are not parallel. Two parallel lines can also intersect if they are coincident, which means they are the same line and they intersect at every point. For two lines that are not parallel, the single point of intersection will satisfy both equations and therefore represent the solution to the system.<\/p>\n<p id=\"fs-id1165137812669\">To find this point when the equations are given as functions, we can solve for an input value so that [latex]f\\left(x\\right)=g\\left(x\\right)[\/latex]. In other words, we can set the formulas for the lines equal to one another, and solve for the input that satisfies the equation.<\/p>\n<div id=\"Example_02_02_12\" class=\"example\" data-type=\"example\">\n<div id=\"fs-id1165137896187\" class=\"exercise\" data-type=\"exercise\">\n<div id=\"fs-id1165137896189\" class=\"problem textbox shaded\" data-type=\"problem\">\n<h3 data-type=\"title\">Example 12: Finding a Point of Intersection Algebraically<\/h3>\n<p id=\"fs-id1165135693776\">Find the point of intersection of the lines [latex]h\\left(t\\right)=3t - 4[\/latex] and [latex]j\\left(t\\right)=5-t[\/latex].<\/p>\n<\/div>\n<div id=\"fs-id1165137838169\" class=\"solution textbox shaded\" data-type=\"solution\">\n<h3>Solution<\/h3>\n<p id=\"fs-id1165137838172\">Set [latex]h\\left(t\\right)=j\\left(t\\right)[\/latex].<\/p>\n<div id=\"fs-id1165137762108\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}3t - 4=5-t\\hfill \\\\ \\text{ }4t=9\\hfill \\\\ \\text{ }t=\\frac{9}{4}\\hfill \\end{cases}[\/latex]<\/div>\n<p id=\"fs-id1165137644219\">This tells us the lines intersect when the input is [latex]\\frac{9}{4}[\/latex].<\/p>\n<p id=\"fs-id1165137812337\">We can then find the output value of the intersection point by evaluating either function at this input.<\/p>\n<div id=\"fs-id1165134042758\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}j\\left(\\frac{9}{4}\\right)=5-\\frac{9}{4}\\hfill \\\\ \\text{ }=\\frac{11}{4}\\hfill \\end{cases}[\/latex]<\/div>\n<p id=\"fs-id1165137745176\">These lines intersect at the point [latex]\\left(\\frac{9}{4},\\frac{11}{4}\\right)[\/latex].<\/p>\n<\/div>\n<div id=\"fs-id1165135191329\" class=\"commentary\" data-type=\"commentary\">\n<h3 data-type=\"title\">Analysis of the Solution<\/h3>\n<p>Looking at Figure 24, this result seems reasonable.<\/p>\n<div style=\"width: 497px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201118\/CNX_Precalc_Figure_02_02_0242.jpg\" alt=\"Graph of two functions h(t) = 3t - 4 and j(t) = t +5 and their intersection at (9\/4, 11\/4).\" width=\"487\" height=\"441\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\"><b>Figure 24<\/b><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137603219\" class=\"note precalculus qa textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"Q&amp;A\">\n<h3>Q &amp; A<\/h3>\n<p id=\"fs-id1165137447025\"><strong>If we were asked to find the point of intersection of two distinct parallel lines, should something in the solution process alert us to the fact that there are no solutions?<\/strong><\/p>\n<p id=\"fs-id1165137447030\"><em data-effect=\"italics\">Yes. After setting the two equations equal to one another, the result would be the contradiction &#8220;0 = non-zero real number&#8221;.<\/em><\/p>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 8<\/h3>\n<p id=\"fs-id1165137832295\">Using the graph in the Analysis of the Solution for Example 12,\u00a0identify the following for the function [latex]j\\left(t\\right)[\/latex]:<\/p>\n<p style=\"padding-left: 60px;\">a. y-intercept<\/p>\n<p style=\"padding-left: 60px;\">b. x-intercept(s)<\/p>\n<p style=\"padding-left: 60px;\">c. slope<\/p>\n<p style=\"padding-left: 60px;\">d. Is [latex]j\\left(t\\right)[\/latex] parallel or perpendicular to [latex]h\\left(t\\right)[\/latex] (or neither)?<\/p>\n<p style=\"padding-left: 60px;\">e. Is [latex]j\\left(t\\right)[\/latex] an increasing or decreasing function (or neither)?<\/p>\n<p style=\"padding-left: 60px;\">f. Write a transformation description for [latex]j\\left(t\\right)[\/latex] from the identity toolkit function [latex]f\\left(x\\right)=x[\/latex].<\/p>\n<p><a href=\"https:\/\/courses.candelalearning.com\/osprecalc\/chapter\/solutions-9\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n<div id=\"Example_02_02_13\" class=\"example\" data-type=\"example\">\n<div id=\"fs-id1165137761773\" class=\"exercise\" data-type=\"exercise\">\n<div id=\"fs-id1165137761775\" class=\"problem textbox shaded\" data-type=\"problem\">\n<h3 data-type=\"title\">Example 13: Finding a Break-Even Point<\/h3>\n<p id=\"fs-id1165137761781\">A company sells sports helmets. The company incurs a one-time fixed cost for $250,000. Each helmet costs $120 to produce, and sells for $140.<\/p>\n<ol id=\"fs-id1165137870987\" data-number-style=\"lower-alpha\">\n<li>Find the cost function, <em>C<\/em>, to produce <em>x<\/em>\u00a0helmets, in dollars.<\/li>\n<li>Find the revenue function, <em>R<\/em>, from the sales of <em>x<\/em>\u00a0helmets, in dollars.<\/li>\n<li>Find the break-even point, the point of intersection of the two graphs <em>C\u00a0<\/em>and <em>R<\/em>.<\/li>\n<\/ol>\n<\/div>\n<div id=\"fs-id1165137653644\" class=\"solution textbox shaded\" data-type=\"solution\">\n<h3>Solution<\/h3>\n<ol id=\"fs-id1165137653646\" data-number-style=\"lower-alpha\">\n<li>The cost function in the sum of the fixed cost, $125,000, and the variable cost, $120 per helmet.\n<div id=\"eip-id1885657\" class=\"equation unnumbered\" data-type=\"equation\" data-label=\"\">[latex]C\\left(x\\right)=120x+250,000[\/latex]<\/div>\n<\/li>\n<li>The revenue function is the total revenue from the sale of [latex]x[\/latex] helmets, [latex]R\\left(x\\right)=140x[\/latex].<\/li>\n<li>The break-even point is the point of intersection of the graph of the cost and revenue functions. To find the <em data-effect=\"italics\">x<\/em>-coordinate of the coordinate pair of the point of intersection, set the two equations equal, and solve for <em>x<\/em>.\n<div id=\"eip-id1165133077884\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}\\text{ }C\\left(x\\right)=R\\left(x\\right)\\hfill \\\\ 250,000+120x=140x\\hfill \\\\ \\text{ }250,000=20x\\hfill \\\\ \\text{ }12,500=x\\hfill \\\\ \\text{ }x=12,500\\hfill \\end{cases}[\/latex]<\/div>\n<p id=\"eip-id1165134183817\">To find [latex]y[\/latex], evaluate either the revenue or the cost function at 12,500.<\/p>\n<div id=\"eip-id1165133220314\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}R\\left(20\\right)=140\\left(12,500\\right)\\hfill \\\\ =$1,750,000\\hfill \\end{cases}[\/latex]<\/div>\n<\/li>\n<\/ol>\n<p id=\"fs-id1165135496435\">The break-even point is (12,500, 1,750,000).<\/p>\n<\/div>\n<div id=\"fs-id1165137935592\" class=\"commentary\" data-type=\"commentary\">\n<h3 data-type=\"title\">Analysis of the Solution<\/h3>\n<p>This means if the company sells 12,500 helmets, they break even; both the sales and cost incurred equaled 1.75 million dollars.<\/p>\n<div style=\"width: 741px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201120\/CNX_Precalc_Figure_02_02_025.jpg\" alt=\"Graph of the two functions, C(x) and R(x) where it shows that below (12500, 1750000) the company loses money and above that point the company makes a profit.\" width=\"731\" height=\"695\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\"><b>Figure 25<\/b><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137811889\" class=\"note precalculus media\" data-type=\"note\" data-has-label=\"true\" data-label=\"Media\"><\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1114\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1114","chapter","type-chapter","status-publish","hentry"],"part":1083,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1114","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":3,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1114\/revisions"}],"predecessor-version":[{"id":2857,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1114\/revisions\/2857"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/1083"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1114\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/media?parent=1114"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=1114"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/contributor?post=1114"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/license?post=1114"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}