{"id":1484,"date":"2015-11-12T18:35:29","date_gmt":"2015-11-12T18:35:29","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=1484"},"modified":"2017-04-03T14:48:42","modified_gmt":"2017-04-03T14:48:42","slug":"solutions-38","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/chapter\/solutions-38\/","title":{"raw":"Solutions","rendered":"Solutions"},"content":{"raw":"<h2>Solutions to Try Its<\/h2>\r\n1.\u00a0[latex]{f}^{-1}\\left(f\\left(x\\right)\\right)={f}^{-1}\\left(\\frac{x+5}{3}\\right)=3\\left(\\frac{x+5}{3}\\right)-5=\\left(x - 5\\right)+5=x[\/latex] and [latex]f\\left({f}^{-1}\\left(x\\right)\\right)=f\\left(3x - 5\\right)=\\frac{\\left(3x - 5\\right)+5}{3}=\\frac{3x}{3}=x[\/latex]\r\n\r\n2.\u00a0[latex]{f}^{-1}\\left(x\\right)={x}^{3}-4[\/latex]\r\n\r\n3.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x - 1}[\/latex]\r\n\r\n4.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{{x}^{2}-3}{2},x\\ge 0[\/latex]\r\n\r\n5.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{2x+3}{x - 1}[\/latex]\r\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\r\n1.\u00a0It can be too difficult or impossible to solve for <em>x<\/em>\u00a0in terms of <em>y<\/em>.\r\n\r\n3.\u00a0We will need a restriction on the domain of the answer.\r\n\r\n5.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x}+4[\/latex]\r\n\r\n7.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+3}-1[\/latex]\r\n\r\n9.\u00a0[latex]{f}^{-1}\\left(x\\right)=-\\sqrt{\\frac{x - 5}{3}}[\/latex]\r\n\r\n11.\u00a0[latex]f\\left(x\\right)=\\sqrt{9-x}[\/latex]\r\n\r\n13.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt[3]{x - 5}[\/latex]\r\n\r\n15.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt[3]{4-x}[\/latex]\r\n\r\n17.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{{x}^{2}-1}{2},\\left[0,\\infty \\right)[\/latex]\r\n\r\n19.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{{\\left(x - 9\\right)}^{2}+4}{4},\\left[9,\\infty \\right)[\/latex]\r\n\r\n21.\u00a0[latex]{f}^{-1}\\left(x\\right)={\\left(\\frac{x - 9}{2}\\right)}^{3}[\/latex]\r\n\r\n23.\u00a0[latex]{f}^{-1}\\left(x\\right)={\\frac{2 - 8x}{x}}[\/latex]\r\n\r\n25.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{7x - 3}{1-x}[\/latex]\r\n\r\n27.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{5x - 4}{4x+3}[\/latex]\r\n\r\n29.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+1}-1[\/latex]\r\n\r\n31.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+6}+3[\/latex]\r\n\r\n33.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{4-x}[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201723\/CNX_Precalc_Figure_03_08_2022.jpg\" alt=\"Graph of f(x)=4- x^2 and its inverse, f^(-1)(x)= sqrt(4-x).\" data-media-type=\"image\/jpg\"\/>\r\n\r\n35.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x}+4[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201725\/CNX_Precalc_Figure_03_08_2042.jpg\" alt=\"Graph of f(x)= (x-4)^2 and its inverse, f^(-1)(x)= sqrt(x)+4.\" data-media-type=\"image\/jpg\"\/>\r\n\r\n37.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt[3]{1-x}[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201726\/CNX_Precalc_Figure_03_08_2062.jpg\" alt=\"Graph of f(x)= 1-x^3 and its inverse, f^(-1)(x)= (1-x)^(1\/3).\" data-media-type=\"image\/jpg\"\/>\r\n\r\n39.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+8}+3[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201727\/CNX_Precalc_Figure_03_08_2082.jpg\" alt=\"Graph of f(x)= x^2-6x+1 and its inverse, f^(-1)(x)= sqrt(x+8)+3.\" data-media-type=\"image\/jpg\"\/>\r\n\r\n41.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{\\frac{1}{x}}[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201728\/CNX_Precalc_Figure_03_08_2102.jpg\" alt=\"Graph of f(x)= 1\/x^2 and its inverse, f^(-1)(x)= sqrt(1\/x).\" data-media-type=\"image\/jpg\"\/>\r\n\r\n43.\u00a0[latex]\\left[-2,1\\right)\\cup \\left[3,\\infty \\right)[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201729\/CNX_Precalc_Figure_03_08_2122.jpg\" alt=\"Graph of f(x)= sqrt((x+2)(x-3)\/(x-1)).\" data-media-type=\"image\/jpg\"\/>\r\n\r\n45.\u00a0[latex]\\left[-4,2\\right)\\cup \\left[5,\\infty \\right)[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201731\/CNX_Precalc_Figure_03_08_2142.jpg\" alt=\"Graph of f(x)= sqrt((x^2-x-20)\/(x-2)).\" data-media-type=\"image\/jpg\"\/>\r\n\r\n47.\u00a0[latex]\\left(-2, 0\\right); \\left(4, 2\\right); \\left(22, 3\\right)[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201732\/CNX_Precalc_Figure_03_08_2162.jpg\" alt=\"Graph of f(x)= x^3-x-2.\" data-media-type=\"image\/jpg\"\/>\r\n\r\n49.\u00a0[latex]\\left(-4, 0\\right); \\left(0, 1\\right); \\left(10, 2\\right)[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201733\/CNX_Precalc_Figure_03_08_2182.jpg\" alt=\"Graph of f(x)= x^3+3x-4.\" data-media-type=\"image\/jpg\"\/>\r\n\r\n51.\u00a0[latex]\\left(-3, -1\\right); \\left(1, 0\\right); \\left(7, 1\\right)[\/latex]\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201735\/CNX_Precalc_Figure_03_08_2202.jpg\" alt=\"Graph of f(x)= x^4+5x+1.\" data-media-type=\"image\/jpg\"\/>\r\n\r\n53.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+\\frac{{b}^{2}}{4}}-\\frac{b}{2}[\/latex]\r\n\r\n55.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{{x}^{3}-b}{a}[\/latex]\r\n\r\n57.\u00a0[latex]t\\left(h\\right)=\\sqrt{\\frac{200-h}{4.9}}[\/latex], 5.53 seconds\r\n\r\n59.\u00a0[latex]r\\left(V\\right)=\\sqrt[3]{\\frac{3V}{4\\pi }}[\/latex], 3.63 feet\r\n\r\n61.\u00a0[latex]n\\left(C\\right)=\\frac{100C - 25}{.6-C}[\/latex], 250 mL\r\n\r\n63.\u00a0[latex]r\\left(V\\right)=\\sqrt{\\frac{V}{6\\pi }}[\/latex], 3.99 meters\r\n\r\n65.\u00a0[latex]r\\left(V\\right)=\\sqrt{\\frac{V}{4\\pi }}[\/latex], 1.99 inches","rendered":"<h2>Solutions to Try Its<\/h2>\n<p>1.\u00a0[latex]{f}^{-1}\\left(f\\left(x\\right)\\right)={f}^{-1}\\left(\\frac{x+5}{3}\\right)=3\\left(\\frac{x+5}{3}\\right)-5=\\left(x - 5\\right)+5=x[\/latex] and [latex]f\\left({f}^{-1}\\left(x\\right)\\right)=f\\left(3x - 5\\right)=\\frac{\\left(3x - 5\\right)+5}{3}=\\frac{3x}{3}=x[\/latex]<\/p>\n<p>2.\u00a0[latex]{f}^{-1}\\left(x\\right)={x}^{3}-4[\/latex]<\/p>\n<p>3.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x - 1}[\/latex]<\/p>\n<p>4.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{{x}^{2}-3}{2},x\\ge 0[\/latex]<\/p>\n<p>5.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{2x+3}{x - 1}[\/latex]<\/p>\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\n<p>1.\u00a0It can be too difficult or impossible to solve for <em>x<\/em>\u00a0in terms of <em>y<\/em>.<\/p>\n<p>3.\u00a0We will need a restriction on the domain of the answer.<\/p>\n<p>5.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x}+4[\/latex]<\/p>\n<p>7.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+3}-1[\/latex]<\/p>\n<p>9.\u00a0[latex]{f}^{-1}\\left(x\\right)=-\\sqrt{\\frac{x - 5}{3}}[\/latex]<\/p>\n<p>11.\u00a0[latex]f\\left(x\\right)=\\sqrt{9-x}[\/latex]<\/p>\n<p>13.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt[3]{x - 5}[\/latex]<\/p>\n<p>15.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt[3]{4-x}[\/latex]<\/p>\n<p>17.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{{x}^{2}-1}{2},\\left[0,\\infty \\right)[\/latex]<\/p>\n<p>19.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{{\\left(x - 9\\right)}^{2}+4}{4},\\left[9,\\infty \\right)[\/latex]<\/p>\n<p>21.\u00a0[latex]{f}^{-1}\\left(x\\right)={\\left(\\frac{x - 9}{2}\\right)}^{3}[\/latex]<\/p>\n<p>23.\u00a0[latex]{f}^{-1}\\left(x\\right)={\\frac{2 - 8x}{x}}[\/latex]<\/p>\n<p>25.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{7x - 3}{1-x}[\/latex]<\/p>\n<p>27.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{5x - 4}{4x+3}[\/latex]<\/p>\n<p>29.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+1}-1[\/latex]<\/p>\n<p>31.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+6}+3[\/latex]<\/p>\n<p>33.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{4-x}[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201723\/CNX_Precalc_Figure_03_08_2022.jpg\" alt=\"Graph of f(x)=4- x^2 and its inverse, f^(-1)(x)= sqrt(4-x).\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>35.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x}+4[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201725\/CNX_Precalc_Figure_03_08_2042.jpg\" alt=\"Graph of f(x)= (x-4)^2 and its inverse, f^(-1)(x)= sqrt(x)+4.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>37.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt[3]{1-x}[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201726\/CNX_Precalc_Figure_03_08_2062.jpg\" alt=\"Graph of f(x)= 1-x^3 and its inverse, f^(-1)(x)= (1-x)^(1\/3).\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>39.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+8}+3[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201727\/CNX_Precalc_Figure_03_08_2082.jpg\" alt=\"Graph of f(x)= x^2-6x+1 and its inverse, f^(-1)(x)= sqrt(x+8)+3.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>41.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{\\frac{1}{x}}[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201728\/CNX_Precalc_Figure_03_08_2102.jpg\" alt=\"Graph of f(x)= 1\/x^2 and its inverse, f^(-1)(x)= sqrt(1\/x).\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>43.\u00a0[latex]\\left[-2,1\\right)\\cup \\left[3,\\infty \\right)[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201729\/CNX_Precalc_Figure_03_08_2122.jpg\" alt=\"Graph of f(x)= sqrt((x+2)(x-3)\/(x-1)).\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>45.\u00a0[latex]\\left[-4,2\\right)\\cup \\left[5,\\infty \\right)[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201731\/CNX_Precalc_Figure_03_08_2142.jpg\" alt=\"Graph of f(x)= sqrt((x^2-x-20)\/(x-2)).\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>47.\u00a0[latex]\\left(-2, 0\\right); \\left(4, 2\\right); \\left(22, 3\\right)[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201732\/CNX_Precalc_Figure_03_08_2162.jpg\" alt=\"Graph of f(x)= x^3-x-2.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>49.\u00a0[latex]\\left(-4, 0\\right); \\left(0, 1\\right); \\left(10, 2\\right)[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201733\/CNX_Precalc_Figure_03_08_2182.jpg\" alt=\"Graph of f(x)= x^3+3x-4.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>51.\u00a0[latex]\\left(-3, -1\\right); \\left(1, 0\\right); \\left(7, 1\\right)[\/latex]<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25201735\/CNX_Precalc_Figure_03_08_2202.jpg\" alt=\"Graph of f(x)= x^4+5x+1.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>53.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\sqrt{x+\\frac{{b}^{2}}{4}}-\\frac{b}{2}[\/latex]<\/p>\n<p>55.\u00a0[latex]{f}^{-1}\\left(x\\right)=\\frac{{x}^{3}-b}{a}[\/latex]<\/p>\n<p>57.\u00a0[latex]t\\left(h\\right)=\\sqrt{\\frac{200-h}{4.9}}[\/latex], 5.53 seconds<\/p>\n<p>59.\u00a0[latex]r\\left(V\\right)=\\sqrt[3]{\\frac{3V}{4\\pi }}[\/latex], 3.63 feet<\/p>\n<p>61.\u00a0[latex]n\\left(C\\right)=\\frac{100C - 25}{.6-C}[\/latex], 250 mL<\/p>\n<p>63.\u00a0[latex]r\\left(V\\right)=\\sqrt{\\frac{V}{6\\pi }}[\/latex], 3.99 meters<\/p>\n<p>65.\u00a0[latex]r\\left(V\\right)=\\sqrt{\\frac{V}{4\\pi }}[\/latex], 1.99 inches<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1484\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1484","chapter","type-chapter","status-publish","hentry"],"part":1459,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1484","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":3,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1484\/revisions"}],"predecessor-version":[{"id":2974,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1484\/revisions\/2974"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/1459"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1484\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/media?parent=1484"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=1484"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/contributor?post=1484"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/license?post=1484"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}