{"id":1514,"date":"2015-11-12T18:35:28","date_gmt":"2015-11-12T18:35:28","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=1514"},"modified":"2017-04-03T14:55:53","modified_gmt":"2017-04-03T14:55:53","slug":"evaluate-exponential-functions-with-base-e","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/chapter\/evaluate-exponential-functions-with-base-e\/","title":{"raw":"Evaluate exponential functions with base e","rendered":"Evaluate exponential functions with base e"},"content":{"raw":"<section id=\"fs-id1165137724961\" data-depth=\"1\"><p id=\"fs-id1165135684369\">As we saw earlier, the amount earned on an account increases as the compounding frequency increases. The table below\u00a0shows that the increase from annual to semi-annual compounding is larger than the increase from monthly to daily compounding. This might lead us to ask whether this pattern will continue.<\/p>\r\n<p id=\"fs-id1165135684377\">Examine the value of $1 invested at 100% interest for 1 year, compounded at various frequencies.<\/p>\r\n\r\n<table id=\"Table_04_01_04\" summary=\"Nine rows and three columns. The first column is labeled,\"><thead><tr><th data-align=\"center\">Frequency<\/th>\r\n<th data-align=\"center\">[latex]A\\left(t\\right)={\\left(1+\\frac{1}{n}\\right)}^{n}[\/latex]<\/th>\r\n<th data-align=\"center\">Value<\/th>\r\n<\/tr><\/thead><tbody><tr><td>Annually<\/td>\r\n<td>[latex]{\\left(1+\\frac{1}{1}\\right)}^{1}[\/latex]<\/td>\r\n<td>$2<\/td>\r\n<\/tr><tr><td>Semiannually<\/td>\r\n<td>[latex]{\\left(1+\\frac{1}{2}\\right)}^{2}[\/latex]<\/td>\r\n<td>$2.25<\/td>\r\n<\/tr><tr><td>Quarterly<\/td>\r\n<td>[latex]{\\left(1+\\frac{1}{4}\\right)}^{4}[\/latex]<\/td>\r\n<td>$2.441406<\/td>\r\n<\/tr><tr><td>Monthly<\/td>\r\n<td>[latex]{\\left(1+\\frac{1}{12}\\right)}^{12}[\/latex]<\/td>\r\n<td>$2.613035<\/td>\r\n<\/tr><tr><td>Daily<\/td>\r\n<td>[latex]{\\left(1+\\frac{1}{365}\\right)}^{365}[\/latex]<\/td>\r\n<td>$2.714567<\/td>\r\n<\/tr><tr><td>Hourly<\/td>\r\n<td>[latex]{\\left(1+\\frac{1}{\\text{8766}}\\right)}^{\\text{8766}}[\/latex]<\/td>\r\n<td>$2.718127<\/td>\r\n<\/tr><tr><td>Once per minute<\/td>\r\n<td>[latex]{\\left(1+\\frac{1}{\\text{525960}}\\right)}^{\\text{525960}}[\/latex]<\/td>\r\n<td>$2.718279<\/td>\r\n<\/tr><tr><td>Once per second<\/td>\r\n<td>[latex]{\\left(1+\\frac{1}{31557600}\\right)}^{31557600}[\/latex]<\/td>\r\n<td>$2.718282<\/td>\r\n<\/tr><\/tbody><\/table><p id=\"fs-id1165137828146\">These values appear to be approaching a limit as <em>n<\/em>\u00a0increases without bound. In fact, as <em>n<\/em>\u00a0gets larger and larger, the expression [latex]{\\left(1+\\frac{1}{n}\\right)}^{n}[\/latex] approaches a number used so frequently in mathematics that it has its own name: the letter [latex]e[\/latex]. This value is an irrational number, which means that its decimal expansion goes on forever without repeating. Its approximation to six decimal places is shown below.<\/p>\r\n\r\n<div id=\"fs-id1165135511324\" class=\"note textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"A General Note\">\r\n<h3 class=\"title\" data-type=\"title\">A General Note: The Number <em data-effect=\"italics\">e<\/em><\/h3>\r\n<p id=\"fs-id1165135511335\">The letter <em data-effect=\"italics\">e<\/em> represents the irrational number<\/p>\r\n\r\n<div id=\"eip-id1165135378658\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]{\\left(1+\\frac{1}{n}\\right)}^{n},\\text{as}n\\text{increases without bound}[\/latex]<\/div>\r\n<p id=\"fs-id1165135369344\">The letter <em data-effect=\"italics\">e <\/em>is used as a base for many real-world exponential models. To work with base <em data-effect=\"italics\">e<\/em>, we use the approximation, [latex]e\\approx 2.718282[\/latex]. The constant was named by the Swiss mathematician Leonhard Euler (1707\u20131783) who first investigated and discovered many of its properties.<\/p>\r\n\r\n<\/div>\r\n<div id=\"Example_04_01_10\" class=\"example\" data-type=\"example\">\r\n<div id=\"fs-id1165135344893\" class=\"exercise\" data-type=\"exercise\">\r\n<div id=\"fs-id1165135344895\" class=\"problem textbox shaded\" data-type=\"problem\">\r\n<h3 data-type=\"title\">Example 7: Using a Calculator to Find Powers of <em data-effect=\"italics\">e<\/em><\/h3>\r\n<p id=\"fs-id1165135545973\">Calculate [latex]{e}^{3.14}[\/latex]. Round to five decimal places.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135192743\" class=\"solution textbox shaded\" data-type=\"solution\">\r\n<h3>Solution<\/h3>\r\n<p id=\"fs-id1165135192745\">On a calculator, press the button labeled [latex]\\left[{e}^{x}\\right][\/latex]. The window shows [<em>e<\/em>^(]. Type 3.14 and then close parenthesis, (]). Press [ENTER]. Rounding to 5 decimal places, [latex]{e}^{3.14}\\approx 23.10387[\/latex]. Caution: Many scientific calculators have an \"Exp\" button, which is used to enter numbers in scientific notation. It is not used to find powers of <em>e<\/em>.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 9<\/h3>\r\n<p id=\"fs-id1165135348437\">Use a calculator to find [latex]{e}^{-0.5}[\/latex]. Round to five decimal places.<\/p>\r\n<a href=\"https:\/\/courses.candelalearning.com\/osprecalc\/chapter\/solutions-25\/\" target=\"_blank\">Solution<\/a>\r\n\r\n<\/div>\r\n<\/section><section id=\"fs-id1165137827923\" data-depth=\"1\"><h2 data-type=\"title\">Investigating Continuous Growth<\/h2>\r\n<p id=\"fs-id1165137827929\">So far we have worked with rational bases for exponential functions. For most real-world phenomena, however, <em data-effect=\"italics\">e <\/em>is used as the base for exponential functions. Exponential models that use <em>e<\/em>\u00a0as the base are called <em data-effect=\"italics\">continuous growth or decay models<\/em>. We see these models in finance, computer science, and most of the sciences, such as physics, toxicology, and fluid dynamics.<\/p>\r\n\r\n<div id=\"fs-id1165137664673\" class=\"note textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"A General Note\">\r\n<h3 class=\"title\" data-type=\"title\">A General Note: The Continuous Growth\/Decay Formula<\/h3>\r\n<p id=\"fs-id1165135453868\">For all real numbers <em>t<\/em>, and all positive numbers <em>a<\/em>\u00a0and <em>r<\/em>, continuous growth or decay is represented by the formula<\/p>\r\n\r\n<div id=\"fs-id1165135536370\" class=\"equation\" style=\"text-align: center;\" data-type=\"equation\">[latex]A\\left(t\\right)=a{e}^{rt}[\/latex]<\/div>\r\n<p id=\"eip-101\">where<\/p>\r\n\r\n<ul id=\"fs-id1165135152052\"><li><em>a<\/em>\u00a0is the initial value,<\/li>\r\n\t<li><em>r<\/em>\u00a0is the continuous growth rate per unit time,<\/li>\r\n\t<li>and <em>t<\/em>\u00a0is the elapsed time.<\/li>\r\n<\/ul><p id=\"fs-id1165135560686\">If <em>r\u00a0<\/em>&gt; 0, then the formula represents continuous growth. If <em>r\u00a0<\/em>&lt; 0, then the formula represents continuous decay.<\/p>\r\n<p id=\"fs-id1165137812323\">For business applications, the continuous growth formula is called the continuous compounding formula and takes the form<\/p>\r\n\r\n<div id=\"eip-id1165134324899\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]A\\left(t\\right)=P{e}^{rt}[\/latex]<\/div>\r\n<p id=\"eip-962\">where<\/p>\r\n\r\n<ul id=\"fs-id1165137827330\"><li><em>P<\/em>\u00a0is the principal or the initial invested,<\/li>\r\n\t<li><em>r<\/em>\u00a0is the growth or interest rate per unit time,<\/li>\r\n\t<li>and <em>t<\/em>\u00a0is the period or term of the investment.<\/li>\r\n<\/ul><\/div>\r\n<div id=\"fs-id1165135411368\" class=\"note precalculus howto textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"How To\">\r\n<h3 id=\"fs-id1165135411373\">How To: Given the initial value, rate of growth or decay, and time <em>t<\/em>, solve a continuous growth or decay function.<\/h3>\r\n<ol id=\"fs-id1165135511371\" data-number-style=\"arabic\"><li>Use the information in the problem to determine <em>a<\/em>, the initial value of the function.<\/li>\r\n\t<li>Use the information in the problem to determine the growth rate <em>r<\/em>.\r\n<ol id=\"fs-id1165135188096\" data-number-style=\"lower-alpha\"><li>If the problem refers to continuous growth, then <em>r\u00a0<\/em>&gt; 0.<\/li>\r\n\t<li>If the problem refers to continuous decay, then <em>r\u00a0<\/em>&lt; 0.<\/li>\r\n<\/ol><\/li>\r\n\t<li>Use the information in the problem to determine the time <em>t<\/em>.<\/li>\r\n\t<li>Substitute the given information into the continuous growth formula and solve for <em>A<\/em>(<em>t<\/em>).<\/li>\r\n<\/ol><\/div>\r\n<div id=\"Example_04_01_11\" class=\"example\" data-type=\"example\">\r\n<div id=\"fs-id1165137835464\" class=\"exercise\" data-type=\"exercise\">\r\n<div id=\"fs-id1165137835466\" class=\"problem textbox shaded\" data-type=\"problem\">\r\n<h3 data-type=\"title\">Example 8: Calculating Continuous Growth<\/h3>\r\n<p id=\"fs-id1165137835472\">A person invested $1,000 in an account earning a nominal 10% per year compounded continuously. How much was in the account at the end of one year?<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165137694203\" class=\"solution textbox shaded\" data-type=\"solution\">\r\n<h3>Solution<\/h3>\r\n<p>Since the account is growing in value, this is a continuous compounding problem with growth rate <em>r\u00a0<\/em>= 0.10. The initial investment was $1,000, so <em>P\u00a0<\/em>= 1000. We use the continuous compounding formula to find the value after <em>t\u00a0<\/em>= 1 year:<\/p>\r\n\r\n<div id=\"eip-id1165133351794\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}A\\left(t\\right)\\hfill &amp; =P{e}^{rt}\\hfill &amp; \\text{Use the continuous compounding formula}.\\hfill \\\\ \\hfill &amp; =1000{\\left(e\\right)}^{0.1} &amp; \\text{Substitute known values for }P, r,\\text{ and }t.\\hfill \\\\ \\hfill &amp; \\approx 1105.17\\hfill &amp; \\text{Use a calculator to approximate}.\\hfill \\end{cases}[\/latex]<\/div>\r\n<p id=\"fs-id1165137895288\">The account is worth $1,105.17 after one year.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 10<\/h3>\r\n<p id=\"fs-id1165137895305\">A person invests $100,000 at a nominal 12% interest per year compounded continuously. What will be the value of the investment in 30 years?<\/p>\r\n<a href=\"https:\/\/courses.candelalearning.com\/osprecalc\/chapter\/solutions-25\/\" target=\"_blank\">Solution<\/a>\r\n\r\n<\/div>\r\n<div id=\"Example_04_01_12\" class=\"example\" data-type=\"example\">\r\n<div id=\"fs-id1165134389988\" class=\"exercise\" data-type=\"exercise\">\r\n<div id=\"fs-id1165134389990\" class=\"problem textbox shaded\" data-type=\"problem\">\r\n<h3 data-type=\"title\">Example 9: Calculating Continuous Decay<\/h3>\r\n<p id=\"fs-id1165137803700\">Radon-222 decays at a continuous rate of 17.3% per day. How much will 100 mg of Radon-222 decay to in 3 days?<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165137803706\" class=\"solution textbox shaded\" data-type=\"solution\">\r\n<h3>Solution<\/h3>\r\n<p>Since the substance is decaying, the rate, 17.3%, is negative. So, <em>r\u00a0<\/em>=\u00a0\u20130.173. The initial amount of radon-222 was 100 mg, so <em>a\u00a0<\/em>= 100. We use the continuous decay formula to find the value after <em>t\u00a0<\/em>= 3 days:<\/p>\r\n\r\n<div id=\"eip-id1165137779893\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}A\\left(t\\right)\\hfill &amp; =a{e}^{rt}\\hfill &amp; \\text{Use the continuous growth formula}.\\hfill \\\\ \\hfill &amp; =100{e}^{-0.173\\left(3\\right)} &amp; \\text{Substitute known values for }a, r,\\text{ and }t.\\hfill \\\\ \\hfill &amp; \\approx 59.5115\\hfill &amp; \\text{Use a calculator to approximate}.\\hfill \\end{cases}[\/latex]<\/div>\r\n<p id=\"fs-id1165137697132\">So 59.5115 mg of radon-222 will remain.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 11<\/h3>\r\n<p id=\"fs-id1165135348472\">Using the data in Example 9, how much radon-222 will remain after one year?<\/p>\r\n<a href=\"https:\/\/courses.candelalearning.com\/osprecalc\/chapter\/solutions-25\/\" target=\"_blank\">Solution<\/a>\r\n\r\n<\/div>\r\n<\/section>","rendered":"<section id=\"fs-id1165137724961\" data-depth=\"1\">\n<p id=\"fs-id1165135684369\">As we saw earlier, the amount earned on an account increases as the compounding frequency increases. The table below\u00a0shows that the increase from annual to semi-annual compounding is larger than the increase from monthly to daily compounding. This might lead us to ask whether this pattern will continue.<\/p>\n<p id=\"fs-id1165135684377\">Examine the value of $1 invested at 100% interest for 1 year, compounded at various frequencies.<\/p>\n<table id=\"Table_04_01_04\" summary=\"Nine rows and three columns. The first column is labeled,\">\n<thead>\n<tr>\n<th data-align=\"center\">Frequency<\/th>\n<th data-align=\"center\">[latex]A\\left(t\\right)={\\left(1+\\frac{1}{n}\\right)}^{n}[\/latex]<\/th>\n<th data-align=\"center\">Value<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>Annually<\/td>\n<td>[latex]{\\left(1+\\frac{1}{1}\\right)}^{1}[\/latex]<\/td>\n<td>$2<\/td>\n<\/tr>\n<tr>\n<td>Semiannually<\/td>\n<td>[latex]{\\left(1+\\frac{1}{2}\\right)}^{2}[\/latex]<\/td>\n<td>$2.25<\/td>\n<\/tr>\n<tr>\n<td>Quarterly<\/td>\n<td>[latex]{\\left(1+\\frac{1}{4}\\right)}^{4}[\/latex]<\/td>\n<td>$2.441406<\/td>\n<\/tr>\n<tr>\n<td>Monthly<\/td>\n<td>[latex]{\\left(1+\\frac{1}{12}\\right)}^{12}[\/latex]<\/td>\n<td>$2.613035<\/td>\n<\/tr>\n<tr>\n<td>Daily<\/td>\n<td>[latex]{\\left(1+\\frac{1}{365}\\right)}^{365}[\/latex]<\/td>\n<td>$2.714567<\/td>\n<\/tr>\n<tr>\n<td>Hourly<\/td>\n<td>[latex]{\\left(1+\\frac{1}{\\text{8766}}\\right)}^{\\text{8766}}[\/latex]<\/td>\n<td>$2.718127<\/td>\n<\/tr>\n<tr>\n<td>Once per minute<\/td>\n<td>[latex]{\\left(1+\\frac{1}{\\text{525960}}\\right)}^{\\text{525960}}[\/latex]<\/td>\n<td>$2.718279<\/td>\n<\/tr>\n<tr>\n<td>Once per second<\/td>\n<td>[latex]{\\left(1+\\frac{1}{31557600}\\right)}^{31557600}[\/latex]<\/td>\n<td>$2.718282<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p id=\"fs-id1165137828146\">These values appear to be approaching a limit as <em>n<\/em>\u00a0increases without bound. In fact, as <em>n<\/em>\u00a0gets larger and larger, the expression [latex]{\\left(1+\\frac{1}{n}\\right)}^{n}[\/latex] approaches a number used so frequently in mathematics that it has its own name: the letter [latex]e[\/latex]. This value is an irrational number, which means that its decimal expansion goes on forever without repeating. Its approximation to six decimal places is shown below.<\/p>\n<div id=\"fs-id1165135511324\" class=\"note textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"A General Note\">\n<h3 class=\"title\" data-type=\"title\">A General Note: The Number <em data-effect=\"italics\">e<\/em><\/h3>\n<p id=\"fs-id1165135511335\">The letter <em data-effect=\"italics\">e<\/em> represents the irrational number<\/p>\n<div id=\"eip-id1165135378658\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]{\\left(1+\\frac{1}{n}\\right)}^{n},\\text{as}n\\text{increases without bound}[\/latex]<\/div>\n<p id=\"fs-id1165135369344\">The letter <em data-effect=\"italics\">e <\/em>is used as a base for many real-world exponential models. To work with base <em data-effect=\"italics\">e<\/em>, we use the approximation, [latex]e\\approx 2.718282[\/latex]. The constant was named by the Swiss mathematician Leonhard Euler (1707\u20131783) who first investigated and discovered many of its properties.<\/p>\n<\/div>\n<div id=\"Example_04_01_10\" class=\"example\" data-type=\"example\">\n<div id=\"fs-id1165135344893\" class=\"exercise\" data-type=\"exercise\">\n<div id=\"fs-id1165135344895\" class=\"problem textbox shaded\" data-type=\"problem\">\n<h3 data-type=\"title\">Example 7: Using a Calculator to Find Powers of <em data-effect=\"italics\">e<\/em><\/h3>\n<p id=\"fs-id1165135545973\">Calculate [latex]{e}^{3.14}[\/latex]. Round to five decimal places.<\/p>\n<\/div>\n<div id=\"fs-id1165135192743\" class=\"solution textbox shaded\" data-type=\"solution\">\n<h3>Solution<\/h3>\n<p id=\"fs-id1165135192745\">On a calculator, press the button labeled [latex]\\left[{e}^{x}\\right][\/latex]. The window shows [<em>e<\/em>^(]. Type 3.14 and then close parenthesis, (]). Press [ENTER]. Rounding to 5 decimal places, [latex]{e}^{3.14}\\approx 23.10387[\/latex]. Caution: Many scientific calculators have an &#8220;Exp&#8221; button, which is used to enter numbers in scientific notation. It is not used to find powers of <em>e<\/em>.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 9<\/h3>\n<p id=\"fs-id1165135348437\">Use a calculator to find [latex]{e}^{-0.5}[\/latex]. Round to five decimal places.<\/p>\n<p><a href=\"https:\/\/courses.candelalearning.com\/osprecalc\/chapter\/solutions-25\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n<\/section>\n<section id=\"fs-id1165137827923\" data-depth=\"1\">\n<h2 data-type=\"title\">Investigating Continuous Growth<\/h2>\n<p id=\"fs-id1165137827929\">So far we have worked with rational bases for exponential functions. For most real-world phenomena, however, <em data-effect=\"italics\">e <\/em>is used as the base for exponential functions. Exponential models that use <em>e<\/em>\u00a0as the base are called <em data-effect=\"italics\">continuous growth or decay models<\/em>. We see these models in finance, computer science, and most of the sciences, such as physics, toxicology, and fluid dynamics.<\/p>\n<div id=\"fs-id1165137664673\" class=\"note textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"A General Note\">\n<h3 class=\"title\" data-type=\"title\">A General Note: The Continuous Growth\/Decay Formula<\/h3>\n<p id=\"fs-id1165135453868\">For all real numbers <em>t<\/em>, and all positive numbers <em>a<\/em>\u00a0and <em>r<\/em>, continuous growth or decay is represented by the formula<\/p>\n<div id=\"fs-id1165135536370\" class=\"equation\" style=\"text-align: center;\" data-type=\"equation\">[latex]A\\left(t\\right)=a{e}^{rt}[\/latex]<\/div>\n<p id=\"eip-101\">where<\/p>\n<ul id=\"fs-id1165135152052\">\n<li><em>a<\/em>\u00a0is the initial value,<\/li>\n<li><em>r<\/em>\u00a0is the continuous growth rate per unit time,<\/li>\n<li>and <em>t<\/em>\u00a0is the elapsed time.<\/li>\n<\/ul>\n<p id=\"fs-id1165135560686\">If <em>r\u00a0<\/em>&gt; 0, then the formula represents continuous growth. If <em>r\u00a0<\/em>&lt; 0, then the formula represents continuous decay.<\/p>\n<p id=\"fs-id1165137812323\">For business applications, the continuous growth formula is called the continuous compounding formula and takes the form<\/p>\n<div id=\"eip-id1165134324899\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]A\\left(t\\right)=P{e}^{rt}[\/latex]<\/div>\n<p id=\"eip-962\">where<\/p>\n<ul id=\"fs-id1165137827330\">\n<li><em>P<\/em>\u00a0is the principal or the initial invested,<\/li>\n<li><em>r<\/em>\u00a0is the growth or interest rate per unit time,<\/li>\n<li>and <em>t<\/em>\u00a0is the period or term of the investment.<\/li>\n<\/ul>\n<\/div>\n<div id=\"fs-id1165135411368\" class=\"note precalculus howto textbox\" data-type=\"note\" data-has-label=\"true\" data-label=\"How To\">\n<h3 id=\"fs-id1165135411373\">How To: Given the initial value, rate of growth or decay, and time <em>t<\/em>, solve a continuous growth or decay function.<\/h3>\n<ol id=\"fs-id1165135511371\" data-number-style=\"arabic\">\n<li>Use the information in the problem to determine <em>a<\/em>, the initial value of the function.<\/li>\n<li>Use the information in the problem to determine the growth rate <em>r<\/em>.\n<ol id=\"fs-id1165135188096\" data-number-style=\"lower-alpha\">\n<li>If the problem refers to continuous growth, then <em>r\u00a0<\/em>&gt; 0.<\/li>\n<li>If the problem refers to continuous decay, then <em>r\u00a0<\/em>&lt; 0.<\/li>\n<\/ol>\n<\/li>\n<li>Use the information in the problem to determine the time <em>t<\/em>.<\/li>\n<li>Substitute the given information into the continuous growth formula and solve for <em>A<\/em>(<em>t<\/em>).<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_04_01_11\" class=\"example\" data-type=\"example\">\n<div id=\"fs-id1165137835464\" class=\"exercise\" data-type=\"exercise\">\n<div id=\"fs-id1165137835466\" class=\"problem textbox shaded\" data-type=\"problem\">\n<h3 data-type=\"title\">Example 8: Calculating Continuous Growth<\/h3>\n<p id=\"fs-id1165137835472\">A person invested $1,000 in an account earning a nominal 10% per year compounded continuously. How much was in the account at the end of one year?<\/p>\n<\/div>\n<div id=\"fs-id1165137694203\" class=\"solution textbox shaded\" data-type=\"solution\">\n<h3>Solution<\/h3>\n<p>Since the account is growing in value, this is a continuous compounding problem with growth rate <em>r\u00a0<\/em>= 0.10. The initial investment was $1,000, so <em>P\u00a0<\/em>= 1000. We use the continuous compounding formula to find the value after <em>t\u00a0<\/em>= 1 year:<\/p>\n<div id=\"eip-id1165133351794\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}A\\left(t\\right)\\hfill & =P{e}^{rt}\\hfill & \\text{Use the continuous compounding formula}.\\hfill \\\\ \\hfill & =1000{\\left(e\\right)}^{0.1} & \\text{Substitute known values for }P, r,\\text{ and }t.\\hfill \\\\ \\hfill & \\approx 1105.17\\hfill & \\text{Use a calculator to approximate}.\\hfill \\end{cases}[\/latex]<\/div>\n<p id=\"fs-id1165137895288\">The account is worth $1,105.17 after one year.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 10<\/h3>\n<p id=\"fs-id1165137895305\">A person invests $100,000 at a nominal 12% interest per year compounded continuously. What will be the value of the investment in 30 years?<\/p>\n<p><a href=\"https:\/\/courses.candelalearning.com\/osprecalc\/chapter\/solutions-25\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n<div id=\"Example_04_01_12\" class=\"example\" data-type=\"example\">\n<div id=\"fs-id1165134389988\" class=\"exercise\" data-type=\"exercise\">\n<div id=\"fs-id1165134389990\" class=\"problem textbox shaded\" data-type=\"problem\">\n<h3 data-type=\"title\">Example 9: Calculating Continuous Decay<\/h3>\n<p id=\"fs-id1165137803700\">Radon-222 decays at a continuous rate of 17.3% per day. How much will 100 mg of Radon-222 decay to in 3 days?<\/p>\n<\/div>\n<div id=\"fs-id1165137803706\" class=\"solution textbox shaded\" data-type=\"solution\">\n<h3>Solution<\/h3>\n<p>Since the substance is decaying, the rate, 17.3%, is negative. So, <em>r\u00a0<\/em>=\u00a0\u20130.173. The initial amount of radon-222 was 100 mg, so <em>a\u00a0<\/em>= 100. We use the continuous decay formula to find the value after <em>t\u00a0<\/em>= 3 days:<\/p>\n<div id=\"eip-id1165137779893\" class=\"equation unnumbered\" style=\"text-align: center;\" data-type=\"equation\" data-label=\"\">[latex]\\begin{cases}A\\left(t\\right)\\hfill & =a{e}^{rt}\\hfill & \\text{Use the continuous growth formula}.\\hfill \\\\ \\hfill & =100{e}^{-0.173\\left(3\\right)} & \\text{Substitute known values for }a, r,\\text{ and }t.\\hfill \\\\ \\hfill & \\approx 59.5115\\hfill & \\text{Use a calculator to approximate}.\\hfill \\end{cases}[\/latex]<\/div>\n<p id=\"fs-id1165137697132\">So 59.5115 mg of radon-222 will remain.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 11<\/h3>\n<p id=\"fs-id1165135348472\">Using the data in Example 9, how much radon-222 will remain after one year?<\/p>\n<p><a href=\"https:\/\/courses.candelalearning.com\/osprecalc\/chapter\/solutions-25\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n<\/section>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1514\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1514","chapter","type-chapter","status-publish","hentry"],"part":1500,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1514","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":3,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1514\/revisions"}],"predecessor-version":[{"id":2990,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1514\/revisions\/2990"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/1500"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/1514\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/media?parent=1514"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=1514"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/contributor?post=1514"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/license?post=1514"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}