{"id":2077,"date":"2015-11-12T18:30:42","date_gmt":"2015-11-12T18:30:42","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=2077"},"modified":"2015-11-12T18:30:42","modified_gmt":"2015-11-12T18:30:42","slug":"solutions-13","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/chapter\/solutions-13\/","title":{"raw":"Solutions","rendered":"Solutions"},"content":{"raw":"<h2>Solutions to Try Its<\/h2>\n1.\u00a038\n\n2.\u00a0[latex]\\text{26}\\text{.4}[\/latex]\n\n3.\u00a0[latex]\\text{328}[\/latex]\n\n4.\u00a0[latex]\\text{-280}[\/latex]\n\n5.\u00a0$2,025\n\n6.\u00a0[latex]\\approx 2,000.00[\/latex]\n\n7.\u00a09,840\n\n8.\u00a0$275,513.31\n\n9.\u00a0The sum is defined. It is geometric.\n\n10.\u00a0The sum of the infinite series is defined.\n\n11.\u00a0The sum of the infinite series is defined.\n\n12.\u00a03\n\n13.\u00a0The series is not geometric.\n\n14. [latex]-\\frac{3}{11}[\/latex]\n\n15.\u00a0$92,408.18\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\n1.\u00a0An [latex]n\\text{th}[\/latex] partial sum is the sum of the first [latex]n[\/latex] terms of a sequence.\n\n3.\u00a0A geometric series is the sum of the terms in a geometric sequence.\n\n5.\u00a0An annuity is a series of regular equal payments that earn a constant compounded interest.\n\n7.\u00a0[latex]\\sum _{n=0}^{4}5n[\/latex]\n\n9.\u00a0[latex]\\sum _{k=1}^{5}4[\/latex]\n\n11.\u00a0[latex]\\sum _{k=1}^{20}8k+2[\/latex]\n\n13.\u00a0[latex]{S}_{5}=\\frac{5\\left(\\frac{3}{2}+\\frac{7}{2}\\right)}{2}[\/latex]\n\n15.\u00a0[latex]{S}_{13}=\\frac{13\\left(3.2+5.6\\right)}{2}[\/latex]\n\n17.\u00a0[latex]\\sum _{k=1}^{7}8\\cdot {0.5}^{k - 1}[\/latex]\n\n19.\u00a0[latex]{S}_{5}=\\frac{9\\left(1-{\\left(\\frac{1}{3}\\right)}^{5}\\right)}{1-\\frac{1}{3}}=\\frac{121}{9}\\approx 13.44[\/latex]\n\n21.\u00a0[latex]{S}_{11}=\\frac{64\\left(1-{0.2}^{11}\\right)}{1 - 0.2}=\\frac{781,249,984}{9,765,625}\\approx 80[\/latex]\n\n23.\u00a0The series is defined. [latex]S=\\frac{2}{1 - 0.8}[\/latex]\n\n25.\u00a0The series is defined. [latex]S=\\frac{-1}{1-\\left(-\\frac{1}{2}\\right)}[\/latex]\n\n27.\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25202552\/CNX_Precalc_Figure_11_04_2022.jpg\" alt=\"Graph of Javier's deposits where the x-axis is the months of the year and the y-axis is the sum of deposits.\" data-media-type=\"image\/jpg\"\/>\n\n29.\u00a0Sample answer: The graph of [latex]{S}_{n}[\/latex] seems to be approaching 1. This makes sense because [latex]\\sum _{k=1}^{\\infty }{\\left(\\frac{1}{2}\\right)}^{k}[\/latex] is a defined infinite geometric series with [latex]S=\\frac{\\frac{1}{2}}{1-\\left(\\frac{1}{2}\\right)}=1[\/latex].\n\n31.\u00a049\n\n33.\u00a0254\n\n35.\u00a0[latex]{S}_{7}=\\frac{147}{2}[\/latex]\n\n37.\u00a0[latex]{S}_{11}=\\frac{55}{2}[\/latex]\n\n39.\u00a0[latex]{S}_{7}=5208.4[\/latex]\n\n41.\u00a0[latex]{S}_{10}=-\\frac{1023}{256}[\/latex]\n\n43.\u00a0[latex]S=-\\frac{4}{3}[\/latex]\n\n45.\u00a0[latex]S=9.2[\/latex]\n\n47.\u00a0$3,705.42\n\n49.\u00a0$695,823.97\n\n51.\u00a0[latex]{a}_{k}=30-k[\/latex]\n\n53.\u00a09 terms\n\n55.\u00a0[latex]r=\\frac{4}{5}[\/latex]\n\n57.\u00a0$400 per month\n\n59.\u00a0420 feet\n\n61.\u00a012 feet","rendered":"<h2>Solutions to Try Its<\/h2>\n<p>1.\u00a038<\/p>\n<p>2.\u00a0[latex]\\text{26}\\text{.4}[\/latex]<\/p>\n<p>3.\u00a0[latex]\\text{328}[\/latex]<\/p>\n<p>4.\u00a0[latex]\\text{-280}[\/latex]<\/p>\n<p>5.\u00a0$2,025<\/p>\n<p>6.\u00a0[latex]\\approx 2,000.00[\/latex]<\/p>\n<p>7.\u00a09,840<\/p>\n<p>8.\u00a0$275,513.31<\/p>\n<p>9.\u00a0The sum is defined. It is geometric.<\/p>\n<p>10.\u00a0The sum of the infinite series is defined.<\/p>\n<p>11.\u00a0The sum of the infinite series is defined.<\/p>\n<p>12.\u00a03<\/p>\n<p>13.\u00a0The series is not geometric.<\/p>\n<p>14. [latex]-\\frac{3}{11}[\/latex]<\/p>\n<p>15.\u00a0$92,408.18<\/p>\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\n<p>1.\u00a0An [latex]n\\text{th}[\/latex] partial sum is the sum of the first [latex]n[\/latex] terms of a sequence.<\/p>\n<p>3.\u00a0A geometric series is the sum of the terms in a geometric sequence.<\/p>\n<p>5.\u00a0An annuity is a series of regular equal payments that earn a constant compounded interest.<\/p>\n<p>7.\u00a0[latex]\\sum _{n=0}^{4}5n[\/latex]<\/p>\n<p>9.\u00a0[latex]\\sum _{k=1}^{5}4[\/latex]<\/p>\n<p>11.\u00a0[latex]\\sum _{k=1}^{20}8k+2[\/latex]<\/p>\n<p>13.\u00a0[latex]{S}_{5}=\\frac{5\\left(\\frac{3}{2}+\\frac{7}{2}\\right)}{2}[\/latex]<\/p>\n<p>15.\u00a0[latex]{S}_{13}=\\frac{13\\left(3.2+5.6\\right)}{2}[\/latex]<\/p>\n<p>17.\u00a0[latex]\\sum _{k=1}^{7}8\\cdot {0.5}^{k - 1}[\/latex]<\/p>\n<p>19.\u00a0[latex]{S}_{5}=\\frac{9\\left(1-{\\left(\\frac{1}{3}\\right)}^{5}\\right)}{1-\\frac{1}{3}}=\\frac{121}{9}\\approx 13.44[\/latex]<\/p>\n<p>21.\u00a0[latex]{S}_{11}=\\frac{64\\left(1-{0.2}^{11}\\right)}{1 - 0.2}=\\frac{781,249,984}{9,765,625}\\approx 80[\/latex]<\/p>\n<p>23.\u00a0The series is defined. [latex]S=\\frac{2}{1 - 0.8}[\/latex]<\/p>\n<p>25.\u00a0The series is defined. [latex]S=\\frac{-1}{1-\\left(-\\frac{1}{2}\\right)}[\/latex]<\/p>\n<p>27.<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25202552\/CNX_Precalc_Figure_11_04_2022.jpg\" alt=\"Graph of Javier's deposits where the x-axis is the months of the year and the y-axis is the sum of deposits.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>29.\u00a0Sample answer: The graph of [latex]{S}_{n}[\/latex] seems to be approaching 1. This makes sense because [latex]\\sum _{k=1}^{\\infty }{\\left(\\frac{1}{2}\\right)}^{k}[\/latex] is a defined infinite geometric series with [latex]S=\\frac{\\frac{1}{2}}{1-\\left(\\frac{1}{2}\\right)}=1[\/latex].<\/p>\n<p>31.\u00a049<\/p>\n<p>33.\u00a0254<\/p>\n<p>35.\u00a0[latex]{S}_{7}=\\frac{147}{2}[\/latex]<\/p>\n<p>37.\u00a0[latex]{S}_{11}=\\frac{55}{2}[\/latex]<\/p>\n<p>39.\u00a0[latex]{S}_{7}=5208.4[\/latex]<\/p>\n<p>41.\u00a0[latex]{S}_{10}=-\\frac{1023}{256}[\/latex]<\/p>\n<p>43.\u00a0[latex]S=-\\frac{4}{3}[\/latex]<\/p>\n<p>45.\u00a0[latex]S=9.2[\/latex]<\/p>\n<p>47.\u00a0$3,705.42<\/p>\n<p>49.\u00a0$695,823.97<\/p>\n<p>51.\u00a0[latex]{a}_{k}=30-k[\/latex]<\/p>\n<p>53.\u00a09 terms<\/p>\n<p>55.\u00a0[latex]r=\\frac{4}{5}[\/latex]<\/p>\n<p>57.\u00a0$400 per month<\/p>\n<p>59.\u00a0420 feet<\/p>\n<p>61.\u00a012 feet<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-2077\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: OpenStax College. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":9,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"Precalculus\",\"author\":\"OpenStax College\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-2077","chapter","type-chapter","status-publish","hentry"],"part":2065,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/2077","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":1,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/2077\/revisions"}],"predecessor-version":[{"id":2163,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/2077\/revisions\/2163"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/2065"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/2077\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/media?parent=2077"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=2077"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/contributor?post=2077"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/license?post=2077"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}