{"id":271,"date":"2015-09-18T20:26:18","date_gmt":"2015-09-18T20:26:18","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=271"},"modified":"2017-03-31T18:05:39","modified_gmt":"2017-03-31T18:05:39","slug":"understanding-nth-roots","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/chapter\/understanding-nth-roots\/","title":{"raw":"Understanding nth Roots","rendered":"Understanding nth Roots"},"content":{"raw":"Suppose we know that [latex]{a}^{3}=8[\/latex]. We want to find what number raised to the 3rd power is equal to 8. Since [latex]{2}^{3}=8[\/latex], we say that 2 is the cube root of 8.\r\n\r\nThe <em>n<\/em><sup>th<\/sup> root of [latex]a[\/latex] is a number that, when raised to the <em>n<\/em><sup>th<\/sup> power, gives [latex]a[\/latex]. For example, [latex]-3[\/latex] is the 5th root of [latex]-243[\/latex] because [latex]{\\left(-3\\right)}^{5}=-243[\/latex]. If [latex]a[\/latex] is a real number with at least one <em>n<\/em><sup>th<\/sup> root, then the <strong>principal <em>n<\/em><sup>th<\/sup> root<\/strong> of [latex]a[\/latex] is the number with the same sign as [latex]a[\/latex] that, when raised to the <em>n<\/em><sup>th<\/sup> power, equals [latex]a[\/latex].\r\n\r\nThe principal <em>n<\/em><sup>th<\/sup> root of [latex]a[\/latex] is written as [latex]\\sqrt[n]{a}[\/latex], where [latex]n[\/latex] is a positive integer greater than or equal to 2. In the radical expression, [latex]n[\/latex] is called the <strong>index<\/strong> of the radical.\r\n<div class=\"textbox\">\r\n<h3>A General Note: Principal <em>n<\/em>th Root<\/h3>\r\nIf [latex]a[\/latex] is a real number with at least one <em>n<\/em><sup>th<\/sup> root, then the <strong>principal <em>n<\/em><sup>th<\/sup> root<\/strong> of [latex]a[\/latex], written as [latex]\\sqrt[n]{a}[\/latex], is the number with the same sign as [latex]a[\/latex] that, when raised to the <em>n<\/em><sup>th<\/sup> power, equals [latex]a[\/latex]. The <strong>index<\/strong> of the radical is [latex]n[\/latex].\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 10: Simplifying <em>n<\/em>th Roots<\/h3>\r\nSimplify each of the following:\r\n<ol>\r\n \t<li>[latex]\\sqrt[5]{-32}[\/latex]<\/li>\r\n \t<li>[latex]\\sqrt[4]{4}\\cdot \\sqrt[4]{1,024}[\/latex]<\/li>\r\n \t<li>[latex]-\\sqrt[3]{\\frac{8{x}^{6}}{125}}[\/latex]<\/li>\r\n \t<li>[latex]8\\sqrt[4]{3}-\\sqrt[4]{48}[\/latex]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Solution<\/h3>\r\n<ol>\r\n \t<li>[latex]\\sqrt[5]{-32}=-2[\/latex] because [latex]{\\left(-2\\right)}^{5}=-32 \\\\ \\text{ }[\/latex]<\/li>\r\n \t<li>First, express the product as a single radical expression. [latex]\\sqrt[4]{4,096}=8[\/latex] because [latex]{8}^{4}=4,096 \\\\[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{cc}\\\\ \\frac{-\\sqrt[3]{8{x}^{6}}}{\\sqrt[3]{125}}\\hfill &amp; \\text{Write as quotient of two radical expressions}.\\hfill \\\\ \\frac{-2{x}^{2}}{5}\\hfill &amp; \\text{Simplify}.\\hfill \\\\ \\end{array}[\/latex]<\/li>\r\n \t<li>[latex]\\begin{array}{cc}\\\\ 8\\sqrt[4]{3}-2\\sqrt[4]{3}\\hfill &amp; \\text{Simplify to get equal radicands}.\\hfill \\\\ 6\\sqrt[4]{3} \\hfill &amp; \\text{Add}.\\hfill \\\\ \\end{array}[\/latex]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 10<\/h3>\r\nSimplify.\r\n<ol>\r\n \t<li>[latex]\\sqrt[3]{-216}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{3\\sqrt[4]{80}}{\\sqrt[4]{5}}[\/latex]<\/li>\r\n \t<li>[latex]6\\sqrt[3]{9,000}+7\\sqrt[3]{576}[\/latex]<\/li>\r\n<\/ol>\r\n<a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-3\/\" target=\"_blank\">Solution<\/a>\r\n\r\n<\/div>","rendered":"<p>Suppose we know that [latex]{a}^{3}=8[\/latex]. We want to find what number raised to the 3rd power is equal to 8. Since [latex]{2}^{3}=8[\/latex], we say that 2 is the cube root of 8.<\/p>\n<p>The <em>n<\/em><sup>th<\/sup> root of [latex]a[\/latex] is a number that, when raised to the <em>n<\/em><sup>th<\/sup> power, gives [latex]a[\/latex]. For example, [latex]-3[\/latex] is the 5th root of [latex]-243[\/latex] because [latex]{\\left(-3\\right)}^{5}=-243[\/latex]. If [latex]a[\/latex] is a real number with at least one <em>n<\/em><sup>th<\/sup> root, then the <strong>principal <em>n<\/em><sup>th<\/sup> root<\/strong> of [latex]a[\/latex] is the number with the same sign as [latex]a[\/latex] that, when raised to the <em>n<\/em><sup>th<\/sup> power, equals [latex]a[\/latex].<\/p>\n<p>The principal <em>n<\/em><sup>th<\/sup> root of [latex]a[\/latex] is written as [latex]\\sqrt[n]{a}[\/latex], where [latex]n[\/latex] is a positive integer greater than or equal to 2. In the radical expression, [latex]n[\/latex] is called the <strong>index<\/strong> of the radical.<\/p>\n<div class=\"textbox\">\n<h3>A General Note: Principal <em>n<\/em>th Root<\/h3>\n<p>If [latex]a[\/latex] is a real number with at least one <em>n<\/em><sup>th<\/sup> root, then the <strong>principal <em>n<\/em><sup>th<\/sup> root<\/strong> of [latex]a[\/latex], written as [latex]\\sqrt[n]{a}[\/latex], is the number with the same sign as [latex]a[\/latex] that, when raised to the <em>n<\/em><sup>th<\/sup> power, equals [latex]a[\/latex]. The <strong>index<\/strong> of the radical is [latex]n[\/latex].<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 10: Simplifying <em>n<\/em>th Roots<\/h3>\n<p>Simplify each of the following:<\/p>\n<ol>\n<li>[latex]\\sqrt[5]{-32}[\/latex]<\/li>\n<li>[latex]\\sqrt[4]{4}\\cdot \\sqrt[4]{1,024}[\/latex]<\/li>\n<li>[latex]-\\sqrt[3]{\\frac{8{x}^{6}}{125}}[\/latex]<\/li>\n<li>[latex]8\\sqrt[4]{3}-\\sqrt[4]{48}[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<ol>\n<li>[latex]\\sqrt[5]{-32}=-2[\/latex] because [latex]{\\left(-2\\right)}^{5}=-32 \\\\ \\text{ }[\/latex]<\/li>\n<li>First, express the product as a single radical expression. [latex]\\sqrt[4]{4,096}=8[\/latex] because [latex]{8}^{4}=4,096 \\\\[\/latex]<\/li>\n<li>[latex]\\begin{array}{cc}\\\\ \\frac{-\\sqrt[3]{8{x}^{6}}}{\\sqrt[3]{125}}\\hfill & \\text{Write as quotient of two radical expressions}.\\hfill \\\\ \\frac{-2{x}^{2}}{5}\\hfill & \\text{Simplify}.\\hfill \\\\ \\end{array}[\/latex]<\/li>\n<li>[latex]\\begin{array}{cc}\\\\ 8\\sqrt[4]{3}-2\\sqrt[4]{3}\\hfill & \\text{Simplify to get equal radicands}.\\hfill \\\\ 6\\sqrt[4]{3} \\hfill & \\text{Add}.\\hfill \\\\ \\end{array}[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 10<\/h3>\n<p>Simplify.<\/p>\n<ol>\n<li>[latex]\\sqrt[3]{-216}[\/latex]<\/li>\n<li>[latex]\\frac{3\\sqrt[4]{80}}{\\sqrt[4]{5}}[\/latex]<\/li>\n<li>[latex]6\\sqrt[3]{9,000}+7\\sqrt[3]{576}[\/latex]<\/li>\n<\/ol>\n<p><a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-3\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-271\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>College Algebra. <strong>Authored by<\/strong>: OpenStax College Algebra. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\">http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"College Algebra\",\"author\":\"OpenStax College Algebra\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-271","chapter","type-chapter","status-publish","hentry"],"part":203,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/271","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":7,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/271\/revisions"}],"predecessor-version":[{"id":2776,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/271\/revisions\/2776"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/203"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/271\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/media?parent=271"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=271"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/contributor?post=271"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/license?post=271"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}