{"id":279,"date":"2015-09-18T20:30:56","date_gmt":"2015-09-18T20:30:56","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=279"},"modified":"2015-11-03T19:20:47","modified_gmt":"2015-11-03T19:20:47","slug":"solutions-3","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/chapter\/solutions-3\/","title":{"raw":"Solutions","rendered":"Solutions"},"content":{"raw":"<h2>Solutions to Try Its<\/h2>\r\n1.\u00a0a. [latex]15[\/latex]\r\nb. [latex]3[\/latex]\r\nc. [latex]4[\/latex]\r\nd. [latex]17[\/latex]\r\n\r\n2.\u00a0[latex]5|x||y|\\sqrt{2yz}[\/latex]. Notice the absolute value signs around <em>x<\/em> and <em>y<\/em>? That\u2019s because their value must be positive!\r\n\r\n3.\u00a0[latex]10|x|[\/latex]\r\n\r\n4.\u00a0[latex]\\frac{x\\sqrt{2}}{3{y}^{2}}[\/latex]. We do not need the absolute value signs for [latex]{y}^{2}[\/latex] because that term will always be nonnegative.\r\n\r\n5.\u00a0[latex]{b}^{4}\\sqrt{3ab}[\/latex]\r\n\r\n6.\u00a0[latex]13\\sqrt{5}[\/latex]\r\n\r\n7.\u00a0[latex]0[\/latex]\r\n\r\n8.\u00a0[latex]6\\sqrt{6}[\/latex]\r\n\r\n9.\u00a0[latex]14 - 7\\sqrt{3}[\/latex]\r\n\r\n10.\u00a0a. [latex]-6[\/latex]\r\nb. [latex]6[\/latex]\r\nc. [latex]88\\sqrt[3]{9}[\/latex]\r\n\r\n11.\u00a0[latex]{\\left(\\sqrt{9}\\right)}^{5}={3}^{5}=243[\/latex]\r\n\r\n12.\u00a0[latex]x{\\left(5y\\right)}^{\\frac{9}{2}}[\/latex]\r\n\r\n13.\u00a0[latex]28{x}^{\\frac{23}{15}}[\/latex]\r\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\r\n1.\u00a0When there is no index, it is assumed to be 2 or the square root. The expression would only be equal to the radicand if the index were 1.\r\n\r\n3.\u00a0The principal square root is the nonnegative root of the number.\r\n\r\n5.\u00a016\r\n\r\n7.\u00a010\r\n\r\n9.\u00a014\r\n\r\n11.\u00a0[latex]7\\sqrt{2}[\/latex]\r\n\r\n13.\u00a0[latex]\\frac{9\\sqrt{5}}{5}[\/latex]\r\n\r\n15.\u00a025\r\n\r\n17.\u00a0[latex]\\sqrt{2}[\/latex]\r\n\r\n19.\u00a0[latex]2\\sqrt{6}[\/latex]\r\n\r\n21.\u00a0[latex]5\\sqrt{6}[\/latex]\r\n\r\n23.\u00a0[latex]6\\sqrt{35}[\/latex]\r\n\r\n25.\u00a0[latex]\\frac{2}{15}[\/latex]\r\n\r\n27.\u00a0[latex]\\frac{6\\sqrt{10}}{19}[\/latex]\r\n\r\n29.\u00a0[latex]-\\frac{1+\\sqrt{17}}{2}[\/latex]\r\n\r\n31.\u00a0[latex]7\\sqrt[3]{2}[\/latex]\r\n\r\n33.\u00a0[latex]15\\sqrt{5}[\/latex]\r\n\r\n35.\u00a0[latex]20{x}^{2}[\/latex]\r\n\r\n37.\u00a0[latex]7\\sqrt{p}[\/latex]\r\n\r\n39.\u00a0[latex]18{m}^{2}\\sqrt{m}[\/latex]\r\n\r\n41.\u00a0[latex]2b\\sqrt{a}[\/latex]\r\n\r\n43.\u00a0[latex]\\frac{15x}{7}[\/latex]\r\n\r\n45.\u00a0[latex]5{y}^{4}\\sqrt{2}[\/latex]\r\n\r\n47.\u00a0[latex]\\frac{4\\sqrt{7d}}{7d}[\/latex]\r\n\r\n49.\u00a0[latex]\\frac{2\\sqrt{2}+2\\sqrt{6x}}{1 - 3x}[\/latex]\r\n\r\n51.\u00a0[latex]-w\\sqrt{2w}[\/latex]\r\n\r\n53.\u00a0[latex]\\frac{3\\sqrt{x}-\\sqrt{3x}}{2}[\/latex]\r\n\r\n55.\u00a0[latex]5{n}^{5}\\sqrt{5}[\/latex]\r\n\r\n57.\u00a0[latex]\\frac{9\\sqrt{m}}{19m}[\/latex]\r\n\r\n59.\u00a0[latex]\\frac{2}{3d}[\/latex]\r\n\r\n61.\u00a0[latex]\\frac{3\\sqrt[4]{2{x}^{2}}}{2}[\/latex]\r\n\r\n63.\u00a0[latex]6z\\sqrt[3]{2}[\/latex]\r\n\r\n65.\u00a0500 feet\r\n\r\n67.\u00a0[latex]\\frac{-5\\sqrt{2}-6}{7}[\/latex]\r\n\r\n69.\u00a0[latex]\\frac{\\sqrt{mnc}}{{a}^{9}cmn}[\/latex]\r\n\r\n71.\u00a0[latex]\\frac{2\\sqrt{2}x+\\sqrt{2}}{4}[\/latex]\r\n\r\n73.\u00a0[latex]\\frac{\\sqrt{3}}{3}[\/latex]","rendered":"<h2>Solutions to Try Its<\/h2>\n<p>1.\u00a0a. [latex]15[\/latex]<br \/>\nb. [latex]3[\/latex]<br \/>\nc. [latex]4[\/latex]<br \/>\nd. [latex]17[\/latex]<\/p>\n<p>2.\u00a0[latex]5|x||y|\\sqrt{2yz}[\/latex]. Notice the absolute value signs around <em>x<\/em> and <em>y<\/em>? That\u2019s because their value must be positive!<\/p>\n<p>3.\u00a0[latex]10|x|[\/latex]<\/p>\n<p>4.\u00a0[latex]\\frac{x\\sqrt{2}}{3{y}^{2}}[\/latex]. We do not need the absolute value signs for [latex]{y}^{2}[\/latex] because that term will always be nonnegative.<\/p>\n<p>5.\u00a0[latex]{b}^{4}\\sqrt{3ab}[\/latex]<\/p>\n<p>6.\u00a0[latex]13\\sqrt{5}[\/latex]<\/p>\n<p>7.\u00a0[latex]0[\/latex]<\/p>\n<p>8.\u00a0[latex]6\\sqrt{6}[\/latex]<\/p>\n<p>9.\u00a0[latex]14 - 7\\sqrt{3}[\/latex]<\/p>\n<p>10.\u00a0a. [latex]-6[\/latex]<br \/>\nb. [latex]6[\/latex]<br \/>\nc. [latex]88\\sqrt[3]{9}[\/latex]<\/p>\n<p>11.\u00a0[latex]{\\left(\\sqrt{9}\\right)}^{5}={3}^{5}=243[\/latex]<\/p>\n<p>12.\u00a0[latex]x{\\left(5y\\right)}^{\\frac{9}{2}}[\/latex]<\/p>\n<p>13.\u00a0[latex]28{x}^{\\frac{23}{15}}[\/latex]<\/p>\n<h2>Solutions to Odd-Numbered Exercises<\/h2>\n<p>1.\u00a0When there is no index, it is assumed to be 2 or the square root. The expression would only be equal to the radicand if the index were 1.<\/p>\n<p>3.\u00a0The principal square root is the nonnegative root of the number.<\/p>\n<p>5.\u00a016<\/p>\n<p>7.\u00a010<\/p>\n<p>9.\u00a014<\/p>\n<p>11.\u00a0[latex]7\\sqrt{2}[\/latex]<\/p>\n<p>13.\u00a0[latex]\\frac{9\\sqrt{5}}{5}[\/latex]<\/p>\n<p>15.\u00a025<\/p>\n<p>17.\u00a0[latex]\\sqrt{2}[\/latex]<\/p>\n<p>19.\u00a0[latex]2\\sqrt{6}[\/latex]<\/p>\n<p>21.\u00a0[latex]5\\sqrt{6}[\/latex]<\/p>\n<p>23.\u00a0[latex]6\\sqrt{35}[\/latex]<\/p>\n<p>25.\u00a0[latex]\\frac{2}{15}[\/latex]<\/p>\n<p>27.\u00a0[latex]\\frac{6\\sqrt{10}}{19}[\/latex]<\/p>\n<p>29.\u00a0[latex]-\\frac{1+\\sqrt{17}}{2}[\/latex]<\/p>\n<p>31.\u00a0[latex]7\\sqrt[3]{2}[\/latex]<\/p>\n<p>33.\u00a0[latex]15\\sqrt{5}[\/latex]<\/p>\n<p>35.\u00a0[latex]20{x}^{2}[\/latex]<\/p>\n<p>37.\u00a0[latex]7\\sqrt{p}[\/latex]<\/p>\n<p>39.\u00a0[latex]18{m}^{2}\\sqrt{m}[\/latex]<\/p>\n<p>41.\u00a0[latex]2b\\sqrt{a}[\/latex]<\/p>\n<p>43.\u00a0[latex]\\frac{15x}{7}[\/latex]<\/p>\n<p>45.\u00a0[latex]5{y}^{4}\\sqrt{2}[\/latex]<\/p>\n<p>47.\u00a0[latex]\\frac{4\\sqrt{7d}}{7d}[\/latex]<\/p>\n<p>49.\u00a0[latex]\\frac{2\\sqrt{2}+2\\sqrt{6x}}{1 - 3x}[\/latex]<\/p>\n<p>51.\u00a0[latex]-w\\sqrt{2w}[\/latex]<\/p>\n<p>53.\u00a0[latex]\\frac{3\\sqrt{x}-\\sqrt{3x}}{2}[\/latex]<\/p>\n<p>55.\u00a0[latex]5{n}^{5}\\sqrt{5}[\/latex]<\/p>\n<p>57.\u00a0[latex]\\frac{9\\sqrt{m}}{19m}[\/latex]<\/p>\n<p>59.\u00a0[latex]\\frac{2}{3d}[\/latex]<\/p>\n<p>61.\u00a0[latex]\\frac{3\\sqrt[4]{2{x}^{2}}}{2}[\/latex]<\/p>\n<p>63.\u00a0[latex]6z\\sqrt[3]{2}[\/latex]<\/p>\n<p>65.\u00a0500 feet<\/p>\n<p>67.\u00a0[latex]\\frac{-5\\sqrt{2}-6}{7}[\/latex]<\/p>\n<p>69.\u00a0[latex]\\frac{\\sqrt{mnc}}{{a}^{9}cmn}[\/latex]<\/p>\n<p>71.\u00a0[latex]\\frac{2\\sqrt{2}x+\\sqrt{2}}{4}[\/latex]<\/p>\n<p>73.\u00a0[latex]\\frac{\\sqrt{3}}{3}[\/latex]<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-279\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>College Algebra. <strong>Authored by<\/strong>: OpenStax College Algebra. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\">http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":10,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"College Algebra\",\"author\":\"OpenStax College Algebra\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-279","chapter","type-chapter","status-publish","hentry"],"part":203,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/279","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":5,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/279\/revisions"}],"predecessor-version":[{"id":546,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/279\/revisions\/546"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/203"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/279\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/media?parent=279"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=279"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/contributor?post=279"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/license?post=279"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}