{"id":325,"date":"2015-09-18T21:23:58","date_gmt":"2015-09-18T21:23:58","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=325"},"modified":"2015-11-04T20:21:15","modified_gmt":"2015-11-04T20:21:15","slug":"multiplying-and-dividing-rational-expressions","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/chapter\/multiplying-and-dividing-rational-expressions\/","title":{"raw":"Multiplying and Dividing Rational Expressions","rendered":"Multiplying and Dividing Rational Expressions"},"content":{"raw":"<h2>Multiplying Rational Expressions<\/h2>\r\nMultiplication of rational expressions works the same way as multiplication of any other fractions. We multiply the numerators to find the numerator of the product, and then multiply the denominators to find the denominator of the product. Before multiplying, it is helpful to factor the numerators and denominators just as we did when simplifying rational expressions. We are often able to simplify the product of rational expressions.\r\n<div class=\"textbox\">\r\n<h3>How To: Given two rational expressions, multiply them.<\/h3>\r\n<ol>\r\n\t<li>Factor the numerator and denominator.<\/li>\r\n\t<li>Multiply the numerators.<\/li>\r\n\t<li>Multiply the denominators.<\/li>\r\n\t<li>Simplify.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 2: Multiplying Rational Expressions<\/h3>\r\nMultiply the rational expressions and show the product in simplest form:\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{cc}\\frac{\\left(x+5\\right)\\left(x - 1\\right)}{3\\left(x+6\\right)}\\cdot \\frac{\\left(2x - 1\\right)}{\\left(x+5\\right)}\\hfill &amp; \\text{Factor the numerator and denominator}.\\hfill \\\\ \\frac{\\left(x+5\\right)\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)\\left(x+5\\right)}\\hfill &amp; \\text{Multiply numerators and denominators}.\\hfill \\\\ \\frac{\\cancel{\\left(x+5\\right)}\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)\\cancel{\\left(x+5\\right)}}\\hfill &amp; \\text{Cancel common factors to simplify}.\\hfill \\\\ \\frac{\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)}\\hfill &amp; \\hfill \\end{array}[\/latex]<\/div>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Solution<\/h3>\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{cc}\\frac{\\left(x+5\\right)\\left(x - 1\\right)}{3\\left(x+6\\right)}\\cdot \\frac{\\left(2x - 1\\right)}{\\left(x+5\\right)}\\hfill &amp; \\text{Factor the numerator and denominator}.\\hfill \\\\ \\frac{\\left(x+5\\right)\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)\\left(x+5\\right)}\\hfill &amp; \\text{Multiply numerators and denominators}.\\hfill \\\\ \\frac{\\cancel{\\left(x+5\\right)}\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)\\cancel{\\left(x+5\\right)}}\\hfill &amp; \\text{Cancel common factors to simplify}.\\hfill \\\\ \\frac{\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)}\\hfill &amp; \\hfill \\end{array}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 2<\/h3>\r\nMultiply the rational expressions and show the product in simplest form:\r\n<div style=\"text-align: center;\">[latex]\\frac{{x}^{2}+11x+30}{{x}^{2}+5x+6}\\cdot \\frac{{x}^{2}+7x+12}{{x}^{2}+8x+16}[\/latex]<\/div>\r\n<a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-6\/\" target=\"_blank\">Solution<\/a>\r\n\r\n<\/div>\r\n<h2>Dividing Rational Expressions<\/h2>\r\nDivision of rational expressions works the same way as division of other fractions. To divide a rational expression by another rational expression, multiply the first expression by the reciprocal of the second. Using this approach, we would rewrite [latex]\\frac{1}{x}\\div \\frac{{x}^{2}}{3}[\/latex] as the product [latex]\\frac{1}{x}\\cdot \\frac{3}{{x}^{2}}[\/latex]. Once the division expression has been rewritten as a multiplication expression, we can multiply as we did before.\r\n<div style=\"text-align: center;\">[latex]\\frac{1}{x}\\cdot \\frac{3}{{x}^{2}}=\\frac{3}{{x}^{3}}[\/latex]<\/div>\r\n<div class=\"textbox\">\r\n<h3>How To: Given two rational expressions, divide them.<\/h3>\r\n<ol>\r\n\t<li>Rewrite as the first rational expression multiplied by the reciprocal of the second.<\/li>\r\n\t<li>Factor the numerators and denominators.<\/li>\r\n\t<li>Multiply the numerators.<\/li>\r\n\t<li>Multiply the denominators.<\/li>\r\n\t<li>Simplify.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 3: Dividing Rational Expressions<\/h3>\r\nDivide the rational expressions and express the quotient in simplest form:\r\n<div style=\"text-align: center;\">[latex]\\frac{2{x}^{2}+x - 6}{{x}^{2}-1}\\div \\frac{{x}^{2}-4}{{x}^{2}+2x+1}[\/latex]<\/div>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Solution<\/h3>\r\n<p style=\"text-align: center;\">[latex]\\begin{array}\\text{ }\\frac{2x^{2}+x-6}{x^{2}}\\cdot\\frac{x^{2}+2x+1}{x^{2}-4} \\hfill&amp; \\text{Rewrite as the first rational expression multiplied by the reciprocal of the second rational expression.} \\\\ \\frac{\\left(2\\times3\\right)\\cancel{\\left(x+2\\right)}}{\\cancel{\\left(x+1\\right)}\\left(x-1\\right)}\\cdot\\frac{\\cancel{\\left(x+1\\right)}\\left(x+1\\right)}{\\cancel{\\left(x+2\\right)}\\left(x-2\\right)} \\hfill&amp; \\text{Factor and cancel common factors.} \\\\ \\frac{\\left(2x+3\\right)\\left(x+1\\right)}{\\left(x-1\\right)\\left(x-2\\right)} \\hfill&amp; \\text{Multiply numerators and denominators.} \\\\ \\frac{2x^{2}+5x+3}{x^{2}-3x+2} \\hfill&amp; \\text{Simplify.}\\end{array}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 3<\/h3>\r\nDivide the rational expressions and express the quotient in simplest form:\r\n<div style=\"text-align: center;\">[latex]\\frac{9{x}^{2}-16}{3{x}^{2}+17x - 28}\\div \\frac{3{x}^{2}-2x - 8}{{x}^{2}+5x - 14}[\/latex]<\/div>\r\n<a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-6\/\" target=\"_blank\">Solution<\/a>\r\n\r\n<\/div>","rendered":"<h2>Multiplying Rational Expressions<\/h2>\n<p>Multiplication of rational expressions works the same way as multiplication of any other fractions. We multiply the numerators to find the numerator of the product, and then multiply the denominators to find the denominator of the product. Before multiplying, it is helpful to factor the numerators and denominators just as we did when simplifying rational expressions. We are often able to simplify the product of rational expressions.<\/p>\n<div class=\"textbox\">\n<h3>How To: Given two rational expressions, multiply them.<\/h3>\n<ol>\n<li>Factor the numerator and denominator.<\/li>\n<li>Multiply the numerators.<\/li>\n<li>Multiply the denominators.<\/li>\n<li>Simplify.<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 2: Multiplying Rational Expressions<\/h3>\n<p>Multiply the rational expressions and show the product in simplest form:<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{cc}\\frac{\\left(x+5\\right)\\left(x - 1\\right)}{3\\left(x+6\\right)}\\cdot \\frac{\\left(2x - 1\\right)}{\\left(x+5\\right)}\\hfill & \\text{Factor the numerator and denominator}.\\hfill \\\\ \\frac{\\left(x+5\\right)\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)\\left(x+5\\right)}\\hfill & \\text{Multiply numerators and denominators}.\\hfill \\\\ \\frac{\\cancel{\\left(x+5\\right)}\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)\\cancel{\\left(x+5\\right)}}\\hfill & \\text{Cancel common factors to simplify}.\\hfill \\\\ \\frac{\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)}\\hfill & \\hfill \\end{array}[\/latex]<\/div>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<p style=\"text-align: center;\">[latex]\\begin{array}{cc}\\frac{\\left(x+5\\right)\\left(x - 1\\right)}{3\\left(x+6\\right)}\\cdot \\frac{\\left(2x - 1\\right)}{\\left(x+5\\right)}\\hfill & \\text{Factor the numerator and denominator}.\\hfill \\\\ \\frac{\\left(x+5\\right)\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)\\left(x+5\\right)}\\hfill & \\text{Multiply numerators and denominators}.\\hfill \\\\ \\frac{\\cancel{\\left(x+5\\right)}\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)\\cancel{\\left(x+5\\right)}}\\hfill & \\text{Cancel common factors to simplify}.\\hfill \\\\ \\frac{\\left(x - 1\\right)\\left(2x - 1\\right)}{3\\left(x+6\\right)}\\hfill & \\hfill \\end{array}[\/latex]<\/p>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 2<\/h3>\n<p>Multiply the rational expressions and show the product in simplest form:<\/p>\n<div style=\"text-align: center;\">[latex]\\frac{{x}^{2}+11x+30}{{x}^{2}+5x+6}\\cdot \\frac{{x}^{2}+7x+12}{{x}^{2}+8x+16}[\/latex]<\/div>\n<p><a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-6\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n<h2>Dividing Rational Expressions<\/h2>\n<p>Division of rational expressions works the same way as division of other fractions. To divide a rational expression by another rational expression, multiply the first expression by the reciprocal of the second. Using this approach, we would rewrite [latex]\\frac{1}{x}\\div \\frac{{x}^{2}}{3}[\/latex] as the product [latex]\\frac{1}{x}\\cdot \\frac{3}{{x}^{2}}[\/latex]. Once the division expression has been rewritten as a multiplication expression, we can multiply as we did before.<\/p>\n<div style=\"text-align: center;\">[latex]\\frac{1}{x}\\cdot \\frac{3}{{x}^{2}}=\\frac{3}{{x}^{3}}[\/latex]<\/div>\n<div class=\"textbox\">\n<h3>How To: Given two rational expressions, divide them.<\/h3>\n<ol>\n<li>Rewrite as the first rational expression multiplied by the reciprocal of the second.<\/li>\n<li>Factor the numerators and denominators.<\/li>\n<li>Multiply the numerators.<\/li>\n<li>Multiply the denominators.<\/li>\n<li>Simplify.<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 3: Dividing Rational Expressions<\/h3>\n<p>Divide the rational expressions and express the quotient in simplest form:<\/p>\n<div style=\"text-align: center;\">[latex]\\frac{2{x}^{2}+x - 6}{{x}^{2}-1}\\div \\frac{{x}^{2}-4}{{x}^{2}+2x+1}[\/latex]<\/div>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<p style=\"text-align: center;\">[latex]\\begin{array}\\text{ }\\frac{2x^{2}+x-6}{x^{2}}\\cdot\\frac{x^{2}+2x+1}{x^{2}-4} \\hfill& \\text{Rewrite as the first rational expression multiplied by the reciprocal of the second rational expression.} \\\\ \\frac{\\left(2\\times3\\right)\\cancel{\\left(x+2\\right)}}{\\cancel{\\left(x+1\\right)}\\left(x-1\\right)}\\cdot\\frac{\\cancel{\\left(x+1\\right)}\\left(x+1\\right)}{\\cancel{\\left(x+2\\right)}\\left(x-2\\right)} \\hfill& \\text{Factor and cancel common factors.} \\\\ \\frac{\\left(2x+3\\right)\\left(x+1\\right)}{\\left(x-1\\right)\\left(x-2\\right)} \\hfill& \\text{Multiply numerators and denominators.} \\\\ \\frac{2x^{2}+5x+3}{x^{2}-3x+2} \\hfill& \\text{Simplify.}\\end{array}[\/latex]<\/p>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 3<\/h3>\n<p>Divide the rational expressions and express the quotient in simplest form:<\/p>\n<div style=\"text-align: center;\">[latex]\\frac{9{x}^{2}-16}{3{x}^{2}+17x - 28}\\div \\frac{3{x}^{2}-2x - 8}{{x}^{2}+5x - 14}[\/latex]<\/div>\n<p><a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-6\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-325\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>College Algebra. <strong>Authored by<\/strong>: OpenStax College Algebra. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\">http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":3,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"College Algebra\",\"author\":\"OpenStax College Algebra\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-325","chapter","type-chapter","status-publish","hentry"],"part":206,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/325","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":5,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/325\/revisions"}],"predecessor-version":[{"id":607,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/325\/revisions\/607"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/206"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/325\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/media?parent=325"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=325"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/contributor?post=325"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/license?post=325"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}