{"id":422,"date":"2015-10-26T18:14:54","date_gmt":"2015-10-26T18:14:54","guid":{"rendered":"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/?post_type=chapter&#038;p=422"},"modified":"2015-11-12T18:37:59","modified_gmt":"2015-11-12T18:37:59","slug":"solving-an-absolute-value-equation","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/chapter\/solving-an-absolute-value-equation\/","title":{"raw":"Solving an Absolute Value Equation","rendered":"Solving an Absolute Value Equation"},"content":{"raw":"Next, we will learn how to solve an <strong>absolute value equation<\/strong>. To solve an equation such as [latex]|2x - 6|=8[\/latex], we notice that the absolute value will be equal to 8 if the quantity inside the absolute value bars is [latex]8[\/latex] or [latex]-8[\/latex]. This leads to two different equations we can solve independently.\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{lll}2x - 6=8\\hfill &amp; \\text{ or }\\hfill &amp; 2x - 6=-8\\hfill \\\\ 2x=14\\hfill &amp; \\hfill &amp; 2x=-2\\hfill \\\\ x=7\\hfill &amp; \\hfill &amp; x=-1\\hfill \\end{array}[\/latex]<\/div>\r\nKnowing how to solve problems involving absolute value functions is useful. For example, we may need to identify numbers or points on a line that are at a specified distance from a given reference point.\r\n<div class=\"textbox\">\r\n<h3>A General Note: Absolute Value Equations<\/h3>\r\nThe absolute value of <em>x <\/em>is written as [latex]|x|[\/latex]. It has the following properties:\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}\\text{If } x\\ge 0,\\text{ then }|x|=x.\\hfill \\\\ \\text{If }x&lt;0,\\text{ then }|x|=-x.\\hfill \\end{array}[\/latex]<\/div>\r\nFor real numbers [latex]A[\/latex] and [latex]B[\/latex], an equation of the form [latex]|A|=B[\/latex], with [latex]B\\ge 0[\/latex], will have solutions when [latex]A=B[\/latex] or [latex]A=-B[\/latex]. If [latex]B&lt;0[\/latex], the equation [latex]|A|=B[\/latex] has no solution.\r\n\r\nAn <strong>absolute value equation<\/strong> in the form [latex]|ax+b|=c[\/latex] has the following properties:\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}\\text{If }c&lt;0,|ax+b|=c\\text{ has no solution}.\\hfill \\\\ \\text{If }c=0,|ax+b|=c\\text{ has one solution}.\\hfill \\\\ \\text{If }c&gt;0,|ax+b|=c\\text{ has two solutions}.\\hfill \\end{array}[\/latex]<\/div>\r\n<\/div>\r\n<div class=\"textbox\">\r\n<h3>How To: Given an absolute value equation, solve it.<\/h3>\r\n<ol>\r\n\t<li>Isolate the absolute value expression on one side of the equal sign.<\/li>\r\n\t<li>If [latex]c&gt;0[\/latex], write and solve two equations: [latex]ax+b=c[\/latex] and [latex]ax+b=-c[\/latex].<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 8: Solving Absolute Value Equations<\/h3>\r\nSolve the following absolute value equations:\r\n<p style=\"padding-left: 60px;\">a. [latex]|6x+4|=8[\/latex]\r\nb. [latex]|3x+4|=-9[\/latex]\r\nc. [latex]|3x - 5|-4=6[\/latex]\r\nd. [latex]|-5x+10|=0[\/latex]<\/p>\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Solution<\/h3>\r\na. [latex]|6x+4|=8[\/latex]\r\n\r\nWrite two equations and solve each:\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{ll}6x+4\\hfill&amp;=8\\hfill&amp; 6x+4\\hfill&amp;=-8\\hfill \\\\ 6x\\hfill&amp;=4\\hfill&amp; 6x\\hfill&amp;=-12\\hfill \\\\ x\\hfill&amp;=\\frac{2}{3}\\hfill&amp; x\\hfill&amp;=-2\\hfill \\end{array}[\/latex]<\/p>\r\nThe two solutions are [latex]x=\\frac{2}{3}[\/latex], [latex]x=-2[\/latex].\r\n\r\nb. [latex]|3x+4|=-9[\/latex]\r\n\r\nThere is no solution as an absolute value cannot be negative.\r\n\r\nc. [latex]|3x - 5|-4=6[\/latex]\r\n\r\nIsolate the absolute value expression and then write two equations.\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{lll}\\hfill &amp; |3x - 5|-4=6\\hfill &amp; \\hfill \\\\ \\hfill &amp; |3x - 5|=10\\hfill &amp; \\hfill \\\\ \\hfill &amp; \\hfill &amp; \\hfill \\\\ 3x - 5=10\\hfill &amp; \\hfill &amp; 3x - 5=-10\\hfill \\\\ 3x=15\\hfill &amp; \\hfill &amp; 3x=-5\\hfill \\\\ x=5\\hfill &amp; \\hfill &amp; x=-\\frac{5}{3}\\hfill \\end{array}[\/latex]<\/div>\r\nThere are two solutions: [latex]x=5[\/latex], [latex]x=-\\frac{5}{3}[\/latex].\r\n\r\nd. [latex]|-5x+10|=0[\/latex]\r\n\r\nThe equation is set equal to zero, so we have to write only one equation.\r\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}-5x+10\\hfill&amp;=0\\hfill \\\\ -5x\\hfill&amp;=-10\\hfill \\\\ x\\hfill&amp;=2\\hfill \\end{array}[\/latex]<\/div>\r\nThere is one solution: [latex]x=2[\/latex].\r\n\r\n<\/div>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Try It 7<\/h3>\r\nSolve the absolute value equation: [latex]|1 - 4x|+8=13[\/latex].\r\n\r\n<a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-8\/\" target=\"_blank\">Solution<\/a>\r\n\r\n<\/div>","rendered":"<p>Next, we will learn how to solve an <strong>absolute value equation<\/strong>. To solve an equation such as [latex]|2x - 6|=8[\/latex], we notice that the absolute value will be equal to 8 if the quantity inside the absolute value bars is [latex]8[\/latex] or [latex]-8[\/latex]. This leads to two different equations we can solve independently.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{lll}2x - 6=8\\hfill & \\text{ or }\\hfill & 2x - 6=-8\\hfill \\\\ 2x=14\\hfill & \\hfill & 2x=-2\\hfill \\\\ x=7\\hfill & \\hfill & x=-1\\hfill \\end{array}[\/latex]<\/div>\n<p>Knowing how to solve problems involving absolute value functions is useful. For example, we may need to identify numbers or points on a line that are at a specified distance from a given reference point.<\/p>\n<div class=\"textbox\">\n<h3>A General Note: Absolute Value Equations<\/h3>\n<p>The absolute value of <em>x <\/em>is written as [latex]|x|[\/latex]. It has the following properties:<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}\\text{If } x\\ge 0,\\text{ then }|x|=x.\\hfill \\\\ \\text{If }x<0,\\text{ then }|x|=-x.\\hfill \\end{array}[\/latex]<\/div>\n<p>For real numbers [latex]A[\/latex] and [latex]B[\/latex], an equation of the form [latex]|A|=B[\/latex], with [latex]B\\ge 0[\/latex], will have solutions when [latex]A=B[\/latex] or [latex]A=-B[\/latex]. If [latex]B<0[\/latex], the equation [latex]|A|=B[\/latex] has no solution.\n\nAn <strong>absolute value equation<\/strong> in the form [latex]|ax+b|=c[\/latex] has the following properties:<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}\\text{If }c<0,|ax+b|=c\\text{ has no solution}.\\hfill \\\\ \\text{If }c=0,|ax+b|=c\\text{ has one solution}.\\hfill \\\\ \\text{If }c>0,|ax+b|=c\\text{ has two solutions}.\\hfill \\end{array}[\/latex]<\/div>\n<\/div>\n<div class=\"textbox\">\n<h3>How To: Given an absolute value equation, solve it.<\/h3>\n<ol>\n<li>Isolate the absolute value expression on one side of the equal sign.<\/li>\n<li>If [latex]c>0[\/latex], write and solve two equations: [latex]ax+b=c[\/latex] and [latex]ax+b=-c[\/latex].<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 8: Solving Absolute Value Equations<\/h3>\n<p>Solve the following absolute value equations:<\/p>\n<p style=\"padding-left: 60px;\">a. [latex]|6x+4|=8[\/latex]<br \/>\nb. [latex]|3x+4|=-9[\/latex]<br \/>\nc. [latex]|3x - 5|-4=6[\/latex]<br \/>\nd. [latex]|-5x+10|=0[\/latex]<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Solution<\/h3>\n<p>a. [latex]|6x+4|=8[\/latex]<\/p>\n<p>Write two equations and solve each:<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{ll}6x+4\\hfill&=8\\hfill& 6x+4\\hfill&=-8\\hfill \\\\ 6x\\hfill&=4\\hfill& 6x\\hfill&=-12\\hfill \\\\ x\\hfill&=\\frac{2}{3}\\hfill& x\\hfill&=-2\\hfill \\end{array}[\/latex]<\/p>\n<p>The two solutions are [latex]x=\\frac{2}{3}[\/latex], [latex]x=-2[\/latex].<\/p>\n<p>b. [latex]|3x+4|=-9[\/latex]<\/p>\n<p>There is no solution as an absolute value cannot be negative.<\/p>\n<p>c. [latex]|3x - 5|-4=6[\/latex]<\/p>\n<p>Isolate the absolute value expression and then write two equations.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{lll}\\hfill & |3x - 5|-4=6\\hfill & \\hfill \\\\ \\hfill & |3x - 5|=10\\hfill & \\hfill \\\\ \\hfill & \\hfill & \\hfill \\\\ 3x - 5=10\\hfill & \\hfill & 3x - 5=-10\\hfill \\\\ 3x=15\\hfill & \\hfill & 3x=-5\\hfill \\\\ x=5\\hfill & \\hfill & x=-\\frac{5}{3}\\hfill \\end{array}[\/latex]<\/div>\n<p>There are two solutions: [latex]x=5[\/latex], [latex]x=-\\frac{5}{3}[\/latex].<\/p>\n<p>d. [latex]|-5x+10|=0[\/latex]<\/p>\n<p>The equation is set equal to zero, so we have to write only one equation.<\/p>\n<div style=\"text-align: center;\">[latex]\\begin{array}{l}-5x+10\\hfill&=0\\hfill \\\\ -5x\\hfill&=-10\\hfill \\\\ x\\hfill&=2\\hfill \\end{array}[\/latex]<\/div>\n<p>There is one solution: [latex]x=2[\/latex].<\/p>\n<\/div>\n<div class=\"bcc-box bcc-success\">\n<h3>Try It 7<\/h3>\n<p>Solve the absolute value equation: [latex]|1 - 4x|+8=13[\/latex].<\/p>\n<p><a href=\"https:\/\/courses.candelalearning.com\/collegealgebra1xmaster\/chapter\/solutions-8\/\" target=\"_blank\">Solution<\/a><\/p>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-422\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>College Algebra. <strong>Authored by<\/strong>: OpenStax College Algebra. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\">http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":276,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc-attribution\",\"description\":\"College Algebra\",\"author\":\"OpenStax College Algebra\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/9b08c294-057f-4201-9f48-5d6ad992740d@3.278:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-422","chapter","type-chapter","status-publish","hentry"],"part":212,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/422","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/users\/276"}],"version-history":[{"count":3,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/422\/revisions"}],"predecessor-version":[{"id":697,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/422\/revisions\/697"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/parts\/212"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapters\/422\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/media?parent=422"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=422"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/contributor?post=422"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/odessa-collegealgebra\/wp-json\/wp\/v2\/license?post=422"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}