{"id":12186,"date":"2015-08-17T18:26:46","date_gmt":"2015-08-17T18:26:46","guid":{"rendered":"https:\/\/courses.candelalearning.com\/osprecalc\/?post_type=chapter&#038;p=12186"},"modified":"2019-09-09T21:31:15","modified_gmt":"2019-09-09T21:31:15","slug":"functions-practice-test","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/precalculus\/chapter\/functions-practice-test\/","title":{"raw":"Functions Practice Test","rendered":"Functions Practice Test"},"content":{"raw":"For the following exercises, determine whether each of the following relations is a function.\r\n\r\n1. <em>y\u00a0<\/em>= 2<em>x\u00a0<\/em>+ 8\r\n\r\n2. [latex]\\left\\{\\left(2,1\\right),\\left(3,2\\right),\\left(-1,1\\right),\\left(0,-2\\right)\\right\\}[\/latex]\r\n\r\nFor the following exercises, evaluate the function [latex]f\\left(x\\right)=-3{x}^{2}+2x[\/latex]\u00a0at the given input.\r\n\r\n3. [latex]f\\left(-2\\right)[\/latex]\r\n\r\n4.\u00a0[latex]f\\left(a\\right)[\/latex]\r\n\r\n5. Show that the function [latex]f\\left(x\\right)=-2{\\left(x - 1\\right)}^{2}+3[\/latex] is not one-to-one.\r\n\r\n6.\u00a0Write the domain of the function [latex]f\\left(x\\right)=\\sqrt{3-x}[\/latex] in interval notation.\r\n\r\n7. Given [latex]f\\left(x\\right)=2{x}^{2}-5x[\/latex], find [latex]f\\left(a+1\\right)-f\\left(1\\right)[\/latex].\r\n\r\n8.\u00a0Graph the function [latex]\\begin{cases}f\\left(x\\right) &amp; =x+1 &amp; \\text{ if }-2 &lt; x &lt; 3 \\\\ \\text{ }&amp; =-x &amp; \\text{ if }x\\ge 3\\end{cases}[\/latex]\r\n\r\n9. Find the average rate of change of the function [latex]f\\left(x\\right)=3 - 2{x}^{2}+x[\/latex] by finding [latex]\\frac{f\\left(b\\right)-f\\left(a\\right)}{b-a}[\/latex].\r\n\r\nFor the following exercises, use the functions [latex]f\\left(x\\right)=3 - 2{x}^{2}+x\\text{ and }g\\left(x\\right)=\\sqrt{x}[\/latex] to find the composite functions.\r\n\r\n10. [latex]\\left(g\\circ f\\right)\\left(x\\right)[\/latex]\r\n\r\n11. [latex]\\left(g\\circ f\\right)\\left(1\\right)[\/latex]\r\n\r\n12.\u00a0Express [latex]H\\left(x\\right)=\\sqrt[3]{5{x}^{2}-3x}[\/latex] as a composition of two functions, <em>f<\/em>\u00a0and <em>g<\/em>, where [latex]\\left(f\\circ g\\right)\\left(x\\right)=H\\left(x\\right)[\/latex].\r\n\r\nFor the following exercises, graph the functions by translating, stretching, and\/or compressing a toolkit function.\r\n\r\n13. [latex]f\\left(x\\right)=\\sqrt{x+6}-1[\/latex]\r\n\r\n14.\u00a0[latex]f\\left(x\\right)=\\frac{1}{x+2}-1[\/latex]\r\n\r\nFor the following exercises, determine whether the functions are even, odd, or neither.\r\n\r\n15. [latex]f\\left(x\\right)=-\\frac{5}{{x}^{2}}+9{x}^{6}[\/latex]\r\n\r\n16.\u00a0[latex]f\\left(x\\right)=-\\frac{5}{{x}^{3}}+9{x}^{5}[\/latex]\r\n\r\n17. [latex]f\\left(x\\right)=\\frac{1}{x}[\/latex]\r\n\r\n18. Graph the absolute value function [latex]f\\left(x\\right)=-2|x - 1|+3[\/latex].\r\n\r\n19. Solve [latex]|2x - 3|=17[\/latex].\r\n\r\n20.\u00a0Solve [latex]-|\\frac{1}{3}x - 3|\\ge 17[\/latex]. Express the solution in interval notation.\r\n\r\nFor the following exercises, find the inverse of the function.\r\n\r\n21. [latex]f\\left(x\\right)=3x - 5[\/latex]\r\n\r\n22. [latex]f\\left(x\\right)=\\frac{4}{x+7}[\/latex]\r\n\r\nFor the following exercises, use the graph of <em>g<\/em>\u00a0shown below.\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005127\/CNX_Precalc_Figure_01_07_245.jpg\" alt=\"Graph of a cubic function.\" data-media-type=\"image\/jpg\" \/>\r\n\r\n23.\u00a0On what intervals is the function increasing?\r\n\r\n24.\u00a0On what intervals is the function decreasing?\r\n\r\n25. Approximate the local minimum of the function. Express the answer as an ordered pair.\r\n\r\n26.\u00a0Approximate the local maximum of the function. Express the answer as an ordered pair.\r\n\r\nFor the following exercises, use the graph of the piecewise function shown below.\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005127\/CNX_Precalc_Figure_01_07_246.jpg\" alt=\"Graph of absolute function and step function.\" data-media-type=\"image\/jpg\" \/>\r\n\r\n27.\u00a0Find [latex]f\\left(2\\right)[\/latex].\r\n\r\n28.\u00a0Find [latex]f\\left(-2\\right)[\/latex].\r\n\r\n29. Write an equation for the piecewise function.\r\n\r\nFor the following exercises, use the values listed below.\r\n<table id=\"Table_01_07_07\" summary=\"..\">\r\n<tbody>\r\n<tr>\r\n<td data-align=\"left\"><em><strong>x<\/strong><\/em><\/td>\r\n<td data-align=\"left\"><em><strong>F<\/strong><\/em><strong>(<em>x<\/em>)<\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">0<\/td>\r\n<td data-align=\"left\">1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">1<\/td>\r\n<td data-align=\"left\">3<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">2<\/td>\r\n<td data-align=\"left\">5<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">3<\/td>\r\n<td data-align=\"left\">7<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">4<\/td>\r\n<td data-align=\"left\">9<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">5<\/td>\r\n<td data-align=\"left\">11<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">6<\/td>\r\n<td data-align=\"left\">13<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">7<\/td>\r\n<td data-align=\"left\">15<\/td>\r\n<\/tr>\r\n<tr>\r\n<td data-align=\"left\">8<\/td>\r\n<td data-align=\"left\">17<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n30. Find [latex]F\\left(6\\right)[\/latex].\r\n\r\n31. Solve the equation [latex]F\\left(x\\right)=5[\/latex].\r\n\r\n32.\u00a0Is the graph increasing or decreasing on its domain?\r\n\r\n33. Is the function represented by the graph one-to-one?\r\n\r\n34. Find [latex]{F}^{-1}\\left(15\\right)[\/latex].\r\n\r\n35. Given [latex]f\\left(x\\right)=-2x+11[\/latex], find [latex]{f}^{-1}\\left(x\\right)[\/latex].","rendered":"<p>For the following exercises, determine whether each of the following relations is a function.<\/p>\n<p>1. <em>y\u00a0<\/em>= 2<em>x\u00a0<\/em>+ 8<\/p>\n<p>2. [latex]\\left\\{\\left(2,1\\right),\\left(3,2\\right),\\left(-1,1\\right),\\left(0,-2\\right)\\right\\}[\/latex]<\/p>\n<p>For the following exercises, evaluate the function [latex]f\\left(x\\right)=-3{x}^{2}+2x[\/latex]\u00a0at the given input.<\/p>\n<p>3. [latex]f\\left(-2\\right)[\/latex]<\/p>\n<p>4.\u00a0[latex]f\\left(a\\right)[\/latex]<\/p>\n<p>5. Show that the function [latex]f\\left(x\\right)=-2{\\left(x - 1\\right)}^{2}+3[\/latex] is not one-to-one.<\/p>\n<p>6.\u00a0Write the domain of the function [latex]f\\left(x\\right)=\\sqrt{3-x}[\/latex] in interval notation.<\/p>\n<p>7. Given [latex]f\\left(x\\right)=2{x}^{2}-5x[\/latex], find [latex]f\\left(a+1\\right)-f\\left(1\\right)[\/latex].<\/p>\n<p>8.\u00a0Graph the function [latex]\\begin{cases}f\\left(x\\right) & =x+1 & \\text{ if }-2 < x < 3 \\\\ \\text{ }& =-x & \\text{ if }x\\ge 3\\end{cases}[\/latex]\n\n9. Find the average rate of change of the function [latex]f\\left(x\\right)=3 - 2{x}^{2}+x[\/latex] by finding [latex]\\frac{f\\left(b\\right)-f\\left(a\\right)}{b-a}[\/latex].\n\nFor the following exercises, use the functions [latex]f\\left(x\\right)=3 - 2{x}^{2}+x\\text{ and }g\\left(x\\right)=\\sqrt{x}[\/latex] to find the composite functions.\n\n10. [latex]\\left(g\\circ f\\right)\\left(x\\right)[\/latex]\n\n11. [latex]\\left(g\\circ f\\right)\\left(1\\right)[\/latex]\n\n12.\u00a0Express [latex]H\\left(x\\right)=\\sqrt[3]{5{x}^{2}-3x}[\/latex] as a composition of two functions, <em>f<\/em>\u00a0and <em>g<\/em>, where [latex]\\left(f\\circ g\\right)\\left(x\\right)=H\\left(x\\right)[\/latex].<\/p>\n<p>For the following exercises, graph the functions by translating, stretching, and\/or compressing a toolkit function.<\/p>\n<p>13. [latex]f\\left(x\\right)=\\sqrt{x+6}-1[\/latex]<\/p>\n<p>14.\u00a0[latex]f\\left(x\\right)=\\frac{1}{x+2}-1[\/latex]<\/p>\n<p>For the following exercises, determine whether the functions are even, odd, or neither.<\/p>\n<p>15. [latex]f\\left(x\\right)=-\\frac{5}{{x}^{2}}+9{x}^{6}[\/latex]<\/p>\n<p>16.\u00a0[latex]f\\left(x\\right)=-\\frac{5}{{x}^{3}}+9{x}^{5}[\/latex]<\/p>\n<p>17. [latex]f\\left(x\\right)=\\frac{1}{x}[\/latex]<\/p>\n<p>18. Graph the absolute value function [latex]f\\left(x\\right)=-2|x - 1|+3[\/latex].<\/p>\n<p>19. Solve [latex]|2x - 3|=17[\/latex].<\/p>\n<p>20.\u00a0Solve [latex]-|\\frac{1}{3}x - 3|\\ge 17[\/latex]. Express the solution in interval notation.<\/p>\n<p>For the following exercises, find the inverse of the function.<\/p>\n<p>21. [latex]f\\left(x\\right)=3x - 5[\/latex]<\/p>\n<p>22. [latex]f\\left(x\\right)=\\frac{4}{x+7}[\/latex]<\/p>\n<p>For the following exercises, use the graph of <em>g<\/em>\u00a0shown below.<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005127\/CNX_Precalc_Figure_01_07_245.jpg\" alt=\"Graph of a cubic function.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>23.\u00a0On what intervals is the function increasing?<\/p>\n<p>24.\u00a0On what intervals is the function decreasing?<\/p>\n<p>25. Approximate the local minimum of the function. Express the answer as an ordered pair.<\/p>\n<p>26.\u00a0Approximate the local maximum of the function. Express the answer as an ordered pair.<\/p>\n<p>For the following exercises, use the graph of the piecewise function shown below.<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005127\/CNX_Precalc_Figure_01_07_246.jpg\" alt=\"Graph of absolute function and step function.\" data-media-type=\"image\/jpg\" \/><\/p>\n<p>27.\u00a0Find [latex]f\\left(2\\right)[\/latex].<\/p>\n<p>28.\u00a0Find [latex]f\\left(-2\\right)[\/latex].<\/p>\n<p>29. Write an equation for the piecewise function.<\/p>\n<p>For the following exercises, use the values listed below.<\/p>\n<table id=\"Table_01_07_07\" summary=\"..\">\n<tbody>\n<tr>\n<td data-align=\"left\"><em><strong>x<\/strong><\/em><\/td>\n<td data-align=\"left\"><em><strong>F<\/strong><\/em><strong>(<em>x<\/em>)<\/strong><\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">0<\/td>\n<td data-align=\"left\">1<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">1<\/td>\n<td data-align=\"left\">3<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">2<\/td>\n<td data-align=\"left\">5<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">3<\/td>\n<td data-align=\"left\">7<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">4<\/td>\n<td data-align=\"left\">9<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">5<\/td>\n<td data-align=\"left\">11<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">6<\/td>\n<td data-align=\"left\">13<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">7<\/td>\n<td data-align=\"left\">15<\/td>\n<\/tr>\n<tr>\n<td data-align=\"left\">8<\/td>\n<td data-align=\"left\">17<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>30. Find [latex]F\\left(6\\right)[\/latex].<\/p>\n<p>31. Solve the equation [latex]F\\left(x\\right)=5[\/latex].<\/p>\n<p>32.\u00a0Is the graph increasing or decreasing on its domain?<\/p>\n<p>33. Is the function represented by the graph one-to-one?<\/p>\n<p>34. Find [latex]{F}^{-1}\\left(15\\right)[\/latex].<\/p>\n<p>35. Given [latex]f\\left(x\\right)=-2x+11[\/latex], find [latex]{f}^{-1}\\left(x\\right)[\/latex].<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-12186\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":969,"menu_order":1,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-12186","chapter","type-chapter","status-publish","hentry"],"part":12185,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/12186","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/969"}],"version-history":[{"count":6,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/12186\/revisions"}],"predecessor-version":[{"id":15797,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/12186\/revisions\/15797"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/12185"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/12186\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=12186"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=12186"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=12186"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=12186"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}