{"id":15475,"date":"2019-09-04T18:59:12","date_gmt":"2019-09-04T18:59:12","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=15475"},"modified":"2025-02-05T05:18:07","modified_gmt":"2025-02-05T05:18:07","slug":"problem-set-2-domain-and-range","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/precalculus\/chapter\/problem-set-2-domain-and-range\/","title":{"raw":"Problem Set 2: Domain and Range","rendered":"Problem Set 2: Domain and Range"},"content":{"raw":"<div id=\"fs-id1165135245908\" class=\"problem\">\r\n\r\n1. Why does the domain differ for different functions?\r\n\r\n2. How do we determine the domain of a function defined by an equation?\r\n\r\n3. Explain why the domain of [latex]f\\left(x\\right)=\\sqrt[3]{x}[\/latex] is different from the domain of [latex]f\\left(x\\right)=\\sqrt[]{x}[\/latex].\r\n\r\n4. When describing sets of numbers using interval notation, when do you use a parenthesis and when do you use a bracket?\r\n\r\n5. How do you graph a piecewise function?\r\n<p id=\"fs-id1165137408926\">For the following exercises, find the domain of each function using interval notation.<\/p>\r\n6. [latex]f\\left(x\\right)=-2x\\left(x - 1\\right)\\left(x - 2\\right)[\/latex]\r\n\r\n7. [latex]f\\left(x\\right)=5 - 2{x}^{2}[\/latex]\r\n\r\n8. [latex]f\\left(x\\right)=3\\sqrt{x - 2}[\/latex]\r\n\r\n9. [latex]f\\left(x\\right)=3-\\sqrt{6 - 2x}[\/latex]\r\n\r\n10. [latex]f\\left(x\\right)=\\sqrt{4 - 3x}[\/latex]\r\n\r\n11. [latex]f\\left(x\\right)=\\sqrt{{x}^{2}+4}[\/latex]\r\n\r\n12. [latex]f\\left(x\\right)=\\sqrt[3]{1 - 2x}[\/latex]\r\n\r\n13. [latex]f\\left(x\\right)=\\sqrt[3]{x - 1}[\/latex]\r\n\r\n14. [latex]f\\left(x\\right)=\\frac{9}{x - 6}[\/latex]\r\n\r\n15. [latex]f\\left(x\\right)=\\frac{3x+1}{4x+2} [\/latex]\r\n\r\n16. [latex]f\\left(x\\right)=\\frac{\\sqrt{x+4}}{x - 4} [\/latex]\r\n\r\n17. [latex]f\\left(x\\right)=\\frac{x - 3}{{x}^{2}+9x - 22} [\/latex]\r\n\r\n18. [latex]f\\left(x\\right)=\\frac{1}{{x}^{2}-x - 6} [\/latex]\r\n\r\n19. [latex]f\\left(x\\right)=\\frac{2{x}^{3}-250}{{x}^{2}-2x - 15} [\/latex]\r\n\r\n20. [latex]\\frac{5}{\\sqrt{x - 3}} [\/latex]\r\n\r\n21. [latex]\\frac{2x+1}{\\sqrt{5-x}} [\/latex]\r\n\r\n22. [latex]f\\left(x\\right)=\\frac{\\sqrt{x - 4}}{\\sqrt{x - 6}} [\/latex]\r\n\r\n23. [latex]f\\left(x\\right)=\\frac{\\sqrt{x - 6}}{\\sqrt{x - 4}} [\/latex]\r\n\r\n24. [latex]f\\left(x\\right)=\\frac{x}{x} [\/latex]\r\n\r\n25. [latex]f\\left(x\\right)=\\frac{{x}^{2}-9x}{{x}^{2}-81} [\/latex]\r\n\r\n26. Find the domain of the function [latex]f\\left(x\\right)=\\sqrt{2{x}^{3}-50x} [\/latex] by:\r\n<div style=\"margin: 0 0 0 40px; border: none; padding: 0px;\">a. using algebra.\r\nb. graphing the function in the radicand and determining intervals on the <em>x<\/em>-axis for which the radicand is nonnegative.<\/div>\r\nFor the following exercises, write the domain and range of each function using interval notation.\r\n\r\n27.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005038\/CNX_Precalc_Figure_01_02_202.jpg\" alt=\"Graph of a function from (2, 8].\" width=\"487\" height=\"222\" \/>\r\n\r\nDomain: ________ Range: ________\r\n\r\n28.\r\n\r\n&nbsp;\r\n\r\n&nbsp;\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005038\/CNX_Precalc_Figure_01_02_203.jpg\" alt=\"Graph of a function from [4, 8).\" width=\"487\" height=\"222\" \/>\r\n\r\n29.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005038\/CNX_Precalc_Figure_01_02_204.jpg\" alt=\"Graph of a function from [-4, 4].\" width=\"487\" height=\"220\" \/>\r\n\r\n<\/div>\r\n30.\r\n\r\n&nbsp;\r\n<div id=\"fs-id1165135245908\" class=\"problem\">\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005039\/CNX_Precalc_Figure_01_02_205.jpg\" alt=\"Graph of a function from [2, 6].\" width=\"487\" height=\"282\" \/>\r\n\r\n31.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005039\/CNX_Precalc_Figure_01_02_206.jpg\" alt=\"Graph of a function from [-5, 3).\" width=\"487\" height=\"189\" \/>\r\n\r\n32.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005039\/CNX_Precalc_Figure_01_02_207.jpg\" alt=\"Graph of a function from [-3, 2).\" width=\"487\" height=\"377\" \/>\r\n\r\n33.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005039\/CNX_Precalc_Figure_01_02_208.jpg\" alt=\"Graph of a function from (-infinity, 2].\" width=\"487\" height=\"220\" \/>\r\n\r\n34.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005040\/CNX_Precalc_Figure_01_02_209.jpg\" alt=\"Graph of a function from [-4, infinity).\" width=\"487\" height=\"316\" \/>\r\n\r\n35.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005040\/CNX_Precalc_Figure_01_02_210.jpg\" alt=\"Graph of a function from [-6, -1\/6]U[1\/6, 6]\/.\" width=\"975\" height=\"442\" \/>\r\n\r\n36.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005040\/CNX_Precalc_Figure_01_02_211.jpg\" alt=\"Graph of a function from (-2.5, infinity).\" width=\"487\" height=\"535\" \/>\r\n\r\n37.\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005040\/CNX_Precalc_Figure_01_02_212.jpg\" alt=\"Graph of a function from [-3, infinity).\" width=\"975\" height=\"379\" \/>\r\n\r\nFor the following exercises, sketch a graph of the piecewise function. Write the domain in interval notation.\r\n\r\n38. [latex]f(x)=\\begin{cases}{x}+{1}&amp;\\text{ if }&amp;{ x }&lt;{ -2 } \\\\{-2x - 3}&amp;\\text{ if }&amp;{ x }\\ge { -2 }\\\\ \\end{cases} [\/latex]\r\n\r\n39. [latex]f\\left(x\\right)=\\begin{cases}{2x - 1}&amp;\\text{ if }&amp;{ x }&lt;{ 1 }\\\\ {1+x }&amp;\\text{ if }&amp;{ x }\\ge{ 1 } \\end{cases}[\/latex]\r\n\r\n40. [latex]f\\left(x\\right)=\\begin{cases}{x+1}&amp;\\text{ if }&amp;{ x }&lt;{ 0 }\\\\ {x - 1 }&amp;\\text{ if }&amp;{ x }&gt;{ 0 }\\end{cases}[\/latex]\r\n\r\n41. [latex]f\\left(x\\right)=\\begin{cases}{3} &amp;\\text{ if }&amp;{ x } &lt;{ 0 }\\\\ \\sqrt{x}&amp;\\text{ if }&amp;{ x }\\ge { 0 }\\end{cases}[\/latex]\r\n\r\n42. [latex]f\\left(x\\right)=\\begin{cases}{x}^{2}&amp;\\text{ if }&amp;{ x } &lt;{ 0 }\\\\ {1-x}&amp;\\text{ if }&amp;{ x } &gt;{ 0 }\\end{cases}[\/latex]\r\n\r\n43. [latex]f\\left(x\\right)=\\begin{cases}{x}^{2}&amp;\\text{ if }&amp;{ x }&lt;{ 0 }\\\\ {x+2 }&amp;\\text{ if }&amp;{ x }\\ge { 0 }\\end{cases}[\/latex]\r\n\r\n44. [latex]f\\left(x\\right)=\\begin{cases}x+1&amp; \\text{if}&amp; x&lt;1\\\\ {x}^{3}&amp; \\text{if}&amp; x\\ge 1\\end{cases}[\/latex]\r\n\r\n45. [latex]f\\left(x\\right)=\\begin{cases}|x|&amp;\\text{ if }&amp;{ x }&lt;{ 2 }\\\\ { 1 }&amp;\\text{ if }&amp;{ x }\\ge{ 2 }\\end{cases}[\/latex]\r\nFor the following exercises, given each function [latex]f[\/latex], evaluate [latex]f\\left(-3\\right),f\\left(-2\\right),f\\left(-1\\right)[\/latex], and [latex]f\\left(0\\right)[\/latex].\r\n\r\n46. [latex]f\\left(x\\right)=\\begin{cases}{ x+1 }&amp;\\text{ if }&amp;{ x }&lt;{ -2 }\\\\ { -2x - 3 }&amp;\\text{ if }&amp;{ x }\\ge{ -2 }\\end{cases}[\/latex]\r\n\r\n47. [latex]f\\left(x\\right)=\\begin{cases}{ 1 }&amp;\\text{ if }&amp;{ x }\\le{ -3 }\\\\{ 0 }&amp;\\text{ if }&amp;{ x }&gt;{ -3 }\\end{cases}[\/latex]\r\n\r\n48. [latex]f\\left(x\\right)=\\begin{cases}{-2}{x}^{2}+{ 3 }&amp;\\text{ if }&amp;{ x }\\le { -1 }\\\\ { 5x } - { 7 } &amp;\\text{ if }&amp;{ x } &gt; { -1 }\\end{cases}[\/latex]\r\nFor the following exercises, given each function [latex]f[\/latex], evaluate [latex]f\\left(-1\\right),f\\left(0\\right),f\\left(2\\right)[\/latex], and [latex]f\\left(4\\right)[\/latex].\r\n\r\n49. [latex]f\\left(x\\right)=\\begin{cases}{ 7x+3 }&amp;\\text{ if }&amp;{ x }&lt;{ 0 }\\\\{ 7x+6 }&amp;\\text{ if }&amp;{ x }\\ge{ 0 }\\end{cases}[\/latex]\r\n\r\n50. [latex]f\\left(x\\right)=\\begin{cases}{x}^{2}{ -2 }&amp;\\text{ if }&amp;{ x }&lt;{ 2 }\\\\{ 4+|x - 5|}&amp;\\text{ if }&amp;{ x }\\ge{ 2 }\\end{cases}[\/latex]\r\n\r\n51. [latex]f\\left(x\\right)=\\begin{cases}5x&amp; \\text{if}&amp; x&lt;0\\\\ 3&amp; \\text{if}&amp; 0\\le x\\le 3\\\\ {x}^{2}&amp; \\text{if}&amp; x&gt;3\\end{cases}[\/latex]\r\nFor the following exercises, write the domain for the piecewise function in interval notation.\r\n\r\n52. [latex]f\\left(x\\right)=\\begin{cases}{x+1}&amp;\\text{ if }&amp;{ x }&lt;{ -2 }\\\\{ -2x - 3}&amp;\\text{ if }&amp;{ x }\\ge{ -2 }\\end{cases}[\/latex]\r\n\r\n53. [latex]f\\left(x\\right)=\\begin{cases}{x}^{2}{ -2 }&amp;\\text{ if}&amp;{ x }&lt;{ 1 }\\\\{-x}^{2}+{2}&amp;\\text{ if }&amp;{ x }&gt;{ 1 }\\end{cases}[\/latex]\r\n\r\n54. [latex]f\\left(x\\right)=\\begin{cases}{ 2x - 3 }&amp;\\text{ if }&amp;{ x }&lt;{ 0 }\\\\{ -3}{x}^{2}&amp;\\text{ if }&amp;{ x }\\ge{ 2 }\\end{cases}[\/latex]\r\n\r\n55. Graph [latex]y=\\frac{1}{{x}^{2}}[\/latex] on the viewing window [latex]\\left[-0.5,-0.1\\right][\/latex] and [latex]\\left[0.1,0.5\\right][\/latex]. Determine the corresponding range for the viewing window. Show the graphs.\r\n\r\n56. Graph [latex]y=\\frac{1}{x}[\/latex] on the viewing window [latex]\\left[-0.5,-0.1\\right][\/latex] and [latex]\\left[0.1,\\text{ }0.5\\right][\/latex]. Determine the corresponding range for the viewing window. Show the graphs.\r\n\r\n57. Suppose the range of a function [latex]f[\/latex] is [latex]\\left[-5,\\text{ }8\\right][\/latex]. What is the range of [latex]|f\\left(x\\right)|?[\/latex]\r\n\r\n58. Create a function in which the range is all nonnegative real numbers.\r\n\r\n59 .Create a function in which the domain is [latex]x&gt;2[\/latex].\r\n\r\n60. The cost in dollars of making [latex]x[\/latex] items is given by the function [latex]C\\left(x\\right)=10x+500[\/latex].\r\n<div style=\"margin: 0 0 0 40px; border: none; padding: 0px;\">A. The fixed cost is determined when zero items are produced. Find the fixed cost for this item.\r\nB. What is the cost of making 25 items?\r\nC. Suppose the maximum cost allowed is $1500. What are the domain and range of the cost function, [latex]C\\left(x\\right)?[\/latex]<\/div>\r\n61. The height [latex]h[\/latex] of a projectile is a function of the time [latex]t[\/latex] it is in the air. The height in feet for [latex]t[\/latex] seconds is given by the function [latex]h\\left(t\\right)=-16{t}^{2}+96t[\/latex]. What is the domain of the function? What does the domain mean in the context of the problem?\r\n\r\n<\/div>","rendered":"<div id=\"fs-id1165135245908\" class=\"problem\">\n<p>1. Why does the domain differ for different functions?<\/p>\n<p>2. How do we determine the domain of a function defined by an equation?<\/p>\n<p>3. Explain why the domain of [latex]f\\left(x\\right)=\\sqrt[3]{x}[\/latex] is different from the domain of [latex]f\\left(x\\right)=\\sqrt[]{x}[\/latex].<\/p>\n<p>4. When describing sets of numbers using interval notation, when do you use a parenthesis and when do you use a bracket?<\/p>\n<p>5. How do you graph a piecewise function?<\/p>\n<p id=\"fs-id1165137408926\">For the following exercises, find the domain of each function using interval notation.<\/p>\n<p>6. [latex]f\\left(x\\right)=-2x\\left(x - 1\\right)\\left(x - 2\\right)[\/latex]<\/p>\n<p>7. [latex]f\\left(x\\right)=5 - 2{x}^{2}[\/latex]<\/p>\n<p>8. [latex]f\\left(x\\right)=3\\sqrt{x - 2}[\/latex]<\/p>\n<p>9. [latex]f\\left(x\\right)=3-\\sqrt{6 - 2x}[\/latex]<\/p>\n<p>10. [latex]f\\left(x\\right)=\\sqrt{4 - 3x}[\/latex]<\/p>\n<p>11. [latex]f\\left(x\\right)=\\sqrt{{x}^{2}+4}[\/latex]<\/p>\n<p>12. [latex]f\\left(x\\right)=\\sqrt[3]{1 - 2x}[\/latex]<\/p>\n<p>13. [latex]f\\left(x\\right)=\\sqrt[3]{x - 1}[\/latex]<\/p>\n<p>14. [latex]f\\left(x\\right)=\\frac{9}{x - 6}[\/latex]<\/p>\n<p>15. [latex]f\\left(x\\right)=\\frac{3x+1}{4x+2}[\/latex]<\/p>\n<p>16. [latex]f\\left(x\\right)=\\frac{\\sqrt{x+4}}{x - 4}[\/latex]<\/p>\n<p>17. [latex]f\\left(x\\right)=\\frac{x - 3}{{x}^{2}+9x - 22}[\/latex]<\/p>\n<p>18. [latex]f\\left(x\\right)=\\frac{1}{{x}^{2}-x - 6}[\/latex]<\/p>\n<p>19. [latex]f\\left(x\\right)=\\frac{2{x}^{3}-250}{{x}^{2}-2x - 15}[\/latex]<\/p>\n<p>20. [latex]\\frac{5}{\\sqrt{x - 3}}[\/latex]<\/p>\n<p>21. [latex]\\frac{2x+1}{\\sqrt{5-x}}[\/latex]<\/p>\n<p>22. [latex]f\\left(x\\right)=\\frac{\\sqrt{x - 4}}{\\sqrt{x - 6}}[\/latex]<\/p>\n<p>23. [latex]f\\left(x\\right)=\\frac{\\sqrt{x - 6}}{\\sqrt{x - 4}}[\/latex]<\/p>\n<p>24. [latex]f\\left(x\\right)=\\frac{x}{x}[\/latex]<\/p>\n<p>25. [latex]f\\left(x\\right)=\\frac{{x}^{2}-9x}{{x}^{2}-81}[\/latex]<\/p>\n<p>26. Find the domain of the function [latex]f\\left(x\\right)=\\sqrt{2{x}^{3}-50x}[\/latex] by:<\/p>\n<div style=\"margin: 0 0 0 40px; border: none; padding: 0px;\">a. using algebra.<br \/>\nb. graphing the function in the radicand and determining intervals on the <em>x<\/em>-axis for which the radicand is nonnegative.<\/div>\n<p>For the following exercises, write the domain and range of each function using interval notation.<\/p>\n<p>27.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005038\/CNX_Precalc_Figure_01_02_202.jpg\" alt=\"Graph of a function from (2, 8].\" width=\"487\" height=\"222\" \/><\/p>\n<p>Domain: ________ Range: ________<\/p>\n<p>28.<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005038\/CNX_Precalc_Figure_01_02_203.jpg\" alt=\"Graph of a function from [4, 8).\" width=\"487\" height=\"222\" \/><\/p>\n<p>29.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005038\/CNX_Precalc_Figure_01_02_204.jpg\" alt=\"Graph of a function from [-4, 4].\" width=\"487\" height=\"220\" \/><\/p>\n<\/div>\n<p>30.<\/p>\n<p>&nbsp;<\/p>\n<div id=\"fs-id1165135245908\" class=\"problem\">\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005039\/CNX_Precalc_Figure_01_02_205.jpg\" alt=\"Graph of a function from [2, 6].\" width=\"487\" height=\"282\" \/><\/p>\n<p>31.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005039\/CNX_Precalc_Figure_01_02_206.jpg\" alt=\"Graph of a function from [-5, 3).\" width=\"487\" height=\"189\" \/><\/p>\n<p>32.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005039\/CNX_Precalc_Figure_01_02_207.jpg\" alt=\"Graph of a function from [-3, 2).\" width=\"487\" height=\"377\" \/><\/p>\n<p>33.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005039\/CNX_Precalc_Figure_01_02_208.jpg\" alt=\"Graph of a function from (-infinity, 2].\" width=\"487\" height=\"220\" \/><\/p>\n<p>34.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005040\/CNX_Precalc_Figure_01_02_209.jpg\" alt=\"Graph of a function from [-4, infinity).\" width=\"487\" height=\"316\" \/><\/p>\n<p>35.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005040\/CNX_Precalc_Figure_01_02_210.jpg\" alt=\"Graph of a function from [-6, -1\/6]U[1\/6, 6]\/.\" width=\"975\" height=\"442\" \/><\/p>\n<p>36.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005040\/CNX_Precalc_Figure_01_02_211.jpg\" alt=\"Graph of a function from (-2.5, infinity).\" width=\"487\" height=\"535\" \/><\/p>\n<p>37.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03005040\/CNX_Precalc_Figure_01_02_212.jpg\" alt=\"Graph of a function from [-3, infinity).\" width=\"975\" height=\"379\" \/><\/p>\n<p>For the following exercises, sketch a graph of the piecewise function. Write the domain in interval notation.<\/p>\n<p>38. [latex]f(x)=\\begin{cases}{x}+{1}&\\text{ if }&{ x }<{ -2 } \\\\{-2x - 3}&\\text{ if }&{ x }\\ge { -2 }\\\\ \\end{cases}[\/latex]\n\n39. [latex]f\\left(x\\right)=\\begin{cases}{2x - 1}&\\text{ if }&{ x }<{ 1 }\\\\ {1+x }&\\text{ if }&{ x }\\ge{ 1 } \\end{cases}[\/latex]\n\n40. [latex]f\\left(x\\right)=\\begin{cases}{x+1}&\\text{ if }&{ x }<{ 0 }\\\\ {x - 1 }&\\text{ if }&{ x }>{ 0 }\\end{cases}[\/latex]<\/p>\n<p>41. [latex]f\\left(x\\right)=\\begin{cases}{3} &\\text{ if }&{ x } <{ 0 }\\\\ \\sqrt{x}&\\text{ if }&{ x }\\ge { 0 }\\end{cases}[\/latex]\n\n42. [latex]f\\left(x\\right)=\\begin{cases}{x}^{2}&\\text{ if }&{ x } <{ 0 }\\\\ {1-x}&\\text{ if }&{ x } >{ 0 }\\end{cases}[\/latex]<\/p>\n<p>43. [latex]f\\left(x\\right)=\\begin{cases}{x}^{2}&\\text{ if }&{ x }<{ 0 }\\\\ {x+2 }&\\text{ if }&{ x }\\ge { 0 }\\end{cases}[\/latex]\n\n44. [latex]f\\left(x\\right)=\\begin{cases}x+1& \\text{if}& x<1\\\\ {x}^{3}& \\text{if}& x\\ge 1\\end{cases}[\/latex]\n\n45. [latex]f\\left(x\\right)=\\begin{cases}|x|&\\text{ if }&{ x }<{ 2 }\\\\ { 1 }&\\text{ if }&{ x }\\ge{ 2 }\\end{cases}[\/latex]\nFor the following exercises, given each function [latex]f[\/latex], evaluate [latex]f\\left(-3\\right),f\\left(-2\\right),f\\left(-1\\right)[\/latex], and [latex]f\\left(0\\right)[\/latex].\n\n46. [latex]f\\left(x\\right)=\\begin{cases}{ x+1 }&\\text{ if }&{ x }<{ -2 }\\\\ { -2x - 3 }&\\text{ if }&{ x }\\ge{ -2 }\\end{cases}[\/latex]\n\n47. [latex]f\\left(x\\right)=\\begin{cases}{ 1 }&\\text{ if }&{ x }\\le{ -3 }\\\\{ 0 }&\\text{ if }&{ x }>{ -3 }\\end{cases}[\/latex]<\/p>\n<p>48. [latex]f\\left(x\\right)=\\begin{cases}{-2}{x}^{2}+{ 3 }&\\text{ if }&{ x }\\le { -1 }\\\\ { 5x } - { 7 } &\\text{ if }&{ x } > { -1 }\\end{cases}[\/latex]<br \/>\nFor the following exercises, given each function [latex]f[\/latex], evaluate [latex]f\\left(-1\\right),f\\left(0\\right),f\\left(2\\right)[\/latex], and [latex]f\\left(4\\right)[\/latex].<\/p>\n<p>49. [latex]f\\left(x\\right)=\\begin{cases}{ 7x+3 }&\\text{ if }&{ x }<{ 0 }\\\\{ 7x+6 }&\\text{ if }&{ x }\\ge{ 0 }\\end{cases}[\/latex]\n\n50. [latex]f\\left(x\\right)=\\begin{cases}{x}^{2}{ -2 }&\\text{ if }&{ x }<{ 2 }\\\\{ 4+|x - 5|}&\\text{ if }&{ x }\\ge{ 2 }\\end{cases}[\/latex]\n\n51. [latex]f\\left(x\\right)=\\begin{cases}5x& \\text{if}& x<0\\\\ 3& \\text{if}& 0\\le x\\le 3\\\\ {x}^{2}& \\text{if}& x>3\\end{cases}[\/latex]<br \/>\nFor the following exercises, write the domain for the piecewise function in interval notation.<\/p>\n<p>52. [latex]f\\left(x\\right)=\\begin{cases}{x+1}&\\text{ if }&{ x }<{ -2 }\\\\{ -2x - 3}&\\text{ if }&{ x }\\ge{ -2 }\\end{cases}[\/latex]\n\n53. [latex]f\\left(x\\right)=\\begin{cases}{x}^{2}{ -2 }&\\text{ if}&{ x }<{ 1 }\\\\{-x}^{2}+{2}&\\text{ if }&{ x }>{ 1 }\\end{cases}[\/latex]<\/p>\n<p>54. [latex]f\\left(x\\right)=\\begin{cases}{ 2x - 3 }&\\text{ if }&{ x }<{ 0 }\\\\{ -3}{x}^{2}&\\text{ if }&{ x }\\ge{ 2 }\\end{cases}[\/latex]\n\n55. Graph [latex]y=\\frac{1}{{x}^{2}}[\/latex] on the viewing window [latex]\\left[-0.5,-0.1\\right][\/latex] and [latex]\\left[0.1,0.5\\right][\/latex]. Determine the corresponding range for the viewing window. Show the graphs.\n\n56. Graph [latex]y=\\frac{1}{x}[\/latex] on the viewing window [latex]\\left[-0.5,-0.1\\right][\/latex] and [latex]\\left[0.1,\\text{ }0.5\\right][\/latex]. Determine the corresponding range for the viewing window. Show the graphs.\n\n57. Suppose the range of a function [latex]f[\/latex] is [latex]\\left[-5,\\text{ }8\\right][\/latex]. What is the range of [latex]|f\\left(x\\right)|?[\/latex]\n\n58. Create a function in which the range is all nonnegative real numbers.\n\n59 .Create a function in which the domain is [latex]x>2[\/latex].<\/p>\n<p>60. The cost in dollars of making [latex]x[\/latex] items is given by the function [latex]C\\left(x\\right)=10x+500[\/latex].<\/p>\n<div style=\"margin: 0 0 0 40px; border: none; padding: 0px;\">A. The fixed cost is determined when zero items are produced. Find the fixed cost for this item.<br \/>\nB. What is the cost of making 25 items?<br \/>\nC. Suppose the maximum cost allowed is $1500. What are the domain and range of the cost function, [latex]C\\left(x\\right)?[\/latex]<\/div>\n<p>61. The height [latex]h[\/latex] of a projectile is a function of the time [latex]t[\/latex] it is in the air. The height in feet for [latex]t[\/latex] seconds is given by the function [latex]h\\left(t\\right)=-16{t}^{2}+96t[\/latex]. What is the domain of the function? What does the domain mean in the context of the problem?<\/p>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-15475\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":169554,"menu_order":10,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download For Free at : http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-15475","chapter","type-chapter","status-publish","hentry"],"part":10705,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15475","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/169554"}],"version-history":[{"count":2,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15475\/revisions"}],"predecessor-version":[{"id":15484,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15475\/revisions\/15484"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/10705"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15475\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=15475"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=15475"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=15475"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=15475"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}