{"id":15513,"date":"2019-09-04T19:38:27","date_gmt":"2019-09-04T19:38:27","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=15513"},"modified":"2025-02-05T05:18:11","modified_gmt":"2025-02-05T05:18:11","slug":"problem-set-7-inverse-functions","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/precalculus\/chapter\/problem-set-7-inverse-functions\/","title":{"raw":"Problem Set 7: Inverse Functions","rendered":"Problem Set 7: Inverse Functions"},"content":{"raw":"1. Describe why the horizontal line test is an effective way to determine whether a function is one-to-one?\r\n\r\n2. Why do we restrict the domain of the function [latex]f\\left(x\\right)={x}^{2}[\/latex] to find the function\u2019s inverse?\r\n\r\n3. Can a function be its own inverse? Explain.\r\n\r\n4. Are one-to-one functions either always increasing or always decreasing? Why or why not?\r\n\r\n5. How do you find the inverse of a function algebraically?\r\n\r\n6. Show that the function [latex]f\\left(x\\right)=a-x[\/latex] is its own inverse for all real numbers [latex]a[\/latex].\r\n\r\nFor the following exercises, find [latex]{f}^{-1}\\left(x\\right)[\/latex] for each function.\r\n\r\n7. [latex]f\\left(x\\right)=x+3[\/latex]\r\n\r\n8.\u00a0[latex]f\\left(x\\right)=x+5[\/latex]\r\n\r\n9. [latex]f\\left(x\\right)=2-x[\/latex]\r\n\r\n10.\u00a0[latex]f\\left(x\\right)=3-x[\/latex]\r\n\r\n11.\u00a0[latex]f\\left(x\\right)=\\frac{x}{x+2}[\/latex]\r\n\r\n12.\u00a0[latex]f\\left(x\\right)=\\frac{2x+3}{5x+4}[\/latex]\r\n\r\nFor the following exercises, find a domain on which each function [latex]f[\/latex] is one-to-one and non-decreasing. Write the domain in interval notation. Then find the inverse of [latex]f[\/latex] restricted to that domain.\r\n\r\n13. [latex]f\\left(x\\right)={\\left(x+7\\right)}^{2}[\/latex]\r\n\r\n14.\u00a0[latex]f\\left(x\\right)={\\left(x - 6\\right)}^{2}[\/latex]\r\n\r\n15. [latex]f\\left(x\\right)={x}^{2}-5[\/latex]\r\n\r\n16.\u00a0Given [latex]f\\left(x\\right)=\\frac{x}{2}+x[\/latex] and [latex]g\\left(x\\right)=\\frac{2x}{1-x}[\/latex]\r\n\r\na. Find [latex]f\\left(g\\left(x\\right)\\right)[\/latex] and [latex]g\\left(f\\left(x\\right)\\right)[\/latex]\r\n\r\nb. What does the answer tell us about the relationship between [latex]f\\left(x\\right)[\/latex] and [latex]g\\left(x\\right)?[\/latex]\r\n\r\nFor the following exercises, use function composition to verify that [latex]f\\left(x\\right)[\/latex] and [latex]g\\left(x\\right)[\/latex] are inverse functions.\r\n\r\n17. [latex]f\\left(x\\right)=\\sqrt[3]{x - 1}[\/latex] and [latex]g\\left(x\\right)={x}^{3}+1[\/latex]\r\n\r\n18.\u00a0[latex]f\\left(x\\right)=-3x+5[\/latex] and [latex]g\\left(x\\right)=\\frac{x - 5}{-3}[\/latex]\r\n\r\nFor the following exercises, use a graphing utility to determine whether each function is one-to-one.\r\n\r\n19. [latex]f\\left(x\\right)=\\sqrt{x}[\/latex]\r\n\r\n20.\u00a0[latex]f\\left(x\\right)=\\sqrt[3]{3x+1}[\/latex]\r\n\r\n21. [latex]f\\left(x\\right)=-5x+1[\/latex]\r\n\r\n22.\u00a0[latex]f\\left(x\\right)={x}^{3}-27[\/latex]\r\n\r\nFor the following exercises, determine whether the graph represents a one-to-one function.\r\n\r\n23.\r\n<img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010629\/CNX_Precalc_Figure_01_07_2012.jpg\" alt=\"Graph of an upright parabola with vertex at (10, -10), passing through (0,0) and (25,0)\" width=\"487\" height=\"253\" \/>\r\n\r\n24.\r\n<img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010629\/CNX_Precalc_Figure_01_07_2022.jpg\" alt=\"Graph of a step-function, with y = -5 for {x|-10&lt;=x,0} and y = 0 for {x|0&lt;=x&lt;10}\" width=\"487\" height=\"376\" \/>\r\n\r\nFor the following exercises, use the graph of [latex]f[\/latex] shown below.\r\n<img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010629\/CNX_Precalc_Figure_01_07_2032.jpg\" alt=\"Graph of the line y = (-3\/2)x + 3\" width=\"487\" height=\"368\" \/>\r\n25. Find [latex]f\\left(0\\right)[\/latex].\r\n\r\n26. Solve [latex]f\\left(x\\right)=0[\/latex].\r\n\r\n27. Find [latex]{f}^{-1}\\left(0\\right)[\/latex].\r\n\r\n28.\u00a0Solve [latex]{f}^{-1}\\left(x\\right)=0[\/latex].\r\n\r\nFor the following exercises, use the graph of the one-to-one function shown below.\r\n<img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010629\/CNX_Precalc_Figure_01_07_2042.jpg\" alt=\"Graph of a square root function for {x|x&gt;=2}\" width=\"487\" height=\"254\" \/>\r\n29. Sketch the graph of [latex]{f}^{-1}[\/latex].\r\n\r\n30. Find [latex]f\\left(6\\right)\\text{ and }{f}^{-1}\\left(2\\right)[\/latex].\r\n\r\n31. If the complete graph of [latex]f[\/latex] is shown, find the domain of [latex]f[\/latex].\r\n\r\n32. If the complete graph of [latex]f[\/latex] is shown, find the range of [latex]f[\/latex].\r\n\r\nFor the following exercises, evaluate or solve, assuming that the function [latex]f[\/latex] is one-to-one.\r\n\r\n33. If [latex]f\\left(6\\right)=7[\/latex], find [latex]{f}^{-1}\\left(7\\right)[\/latex].\r\n\r\n34.\u00a0If [latex]f\\left(3\\right)=2[\/latex], find [latex]{f}^{-1}\\left(2\\right)[\/latex].\r\n\r\n35. If [latex]{f}^{-1}\\left(-4\\right)=-8[\/latex], find [latex]f\\left(-8\\right)[\/latex].\r\n\r\n36.\u00a0If [latex]{f}^{-1}\\left(-2\\right)=-1[\/latex], find [latex]f\\left(-1\\right)[\/latex].\r\n\r\nFor the following exercises, use the values listed in the table below\u00a0to evaluate or solve.\r\n<table id=\"Table_01_07_06\" summary=\"Two column and ten rows. The first column is labeled, \">\r\n<tbody>\r\n<tr>\r\n<td style=\"text-align: center;\"><strong> [latex]x[\/latex] <\/strong><\/td>\r\n<td style=\"text-align: center;\"><strong> [latex]f\\left(x\\right)[\/latex] <\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">0<\/td>\r\n<td style=\"text-align: center;\">8<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">1<\/td>\r\n<td style=\"text-align: center;\">0<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">2<\/td>\r\n<td style=\"text-align: center;\">7<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">3<\/td>\r\n<td style=\"text-align: center;\">4<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">4<\/td>\r\n<td style=\"text-align: center;\">2<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">5<\/td>\r\n<td style=\"text-align: center;\">6<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">6<\/td>\r\n<td style=\"text-align: center;\">5<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">7<\/td>\r\n<td style=\"text-align: center;\">3<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">8<\/td>\r\n<td style=\"text-align: center;\">9<\/td>\r\n<\/tr>\r\n<tr>\r\n<td style=\"text-align: center;\">9<\/td>\r\n<td style=\"text-align: center;\">1<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n37. Find [latex]f\\left(1\\right)[\/latex].\r\n\r\n38.\u00a0Solve [latex]f\\left(x\\right)=3[\/latex].\r\n\r\n39. Find [latex]{f}^{-1}\\left(0\\right)[\/latex].\r\n\r\n40.\u00a0Solve [latex]{f}^{-1}\\left(x\\right)=7[\/latex].\r\n\r\n41. Use the tabular representation of [latex]f[\/latex] to create a table for [latex]{f}^{-1}\\left(x\\right)[\/latex].\r\n<table>\r\n<tbody>\r\n<tr>\r\n<td><strong> [latex]x[\/latex] <\/strong><\/td>\r\n<td>3<\/td>\r\n<td>6<\/td>\r\n<td>9<\/td>\r\n<td>13<\/td>\r\n<td>14<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><strong> [latex]f\\left(x\\right)[\/latex] <\/strong><\/td>\r\n<td>1<\/td>\r\n<td>4<\/td>\r\n<td>7<\/td>\r\n<td>12<\/td>\r\n<td>16<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nFor the following exercises, find the inverse function. Then, graph the function and its inverse.\r\n\r\n42. [latex]f\\left(x\\right)=\\frac{3}{x - 2}[\/latex]\r\n\r\n43. [latex]f\\left(x\\right)={x}^{3}-1[\/latex]\r\n\r\n44. Find the inverse function of [latex]f\\left(x\\right)=\\frac{1}{x - 1}[\/latex]. Use a graphing utility to find its domain and range. Write the domain and range in interval notation.\r\n\r\n45.\u00a0To convert from [latex]x[\/latex] degrees Celsius to [latex]y[\/latex] degrees Fahrenheit, we use the formula [latex]f\\left(x\\right)=\\frac{9}{5}x+32[\/latex]. Find the inverse function, if it exists, and explain its meaning.\r\n\r\n46.\u00a0The circumference [latex]C[\/latex] of a circle is a function of its radius given by [latex]C\\left(r\\right)=2\\pi r[\/latex]. Express the radius of a circle as a function of its circumference. Call this function [latex]r\\left(C\\right)[\/latex]. Find [latex]r\\left(36\\pi \\right)[\/latex] and interpret its meaning.\r\n\r\n47. A car travels at a constant speed of 50 miles per hour. The distance the car travels in miles is a function of time, [latex]t[\/latex], in hours given by [latex]d\\left(t\\right)=50t[\/latex]. Find the inverse function by expressing the time of travel in terms of the distance traveled. Call this function [latex]t\\left(d\\right)[\/latex]. Find [latex]t\\left(180\\right)[\/latex] and interpret its meaning.","rendered":"<p>1. Describe why the horizontal line test is an effective way to determine whether a function is one-to-one?<\/p>\n<p>2. Why do we restrict the domain of the function [latex]f\\left(x\\right)={x}^{2}[\/latex] to find the function\u2019s inverse?<\/p>\n<p>3. Can a function be its own inverse? Explain.<\/p>\n<p>4. Are one-to-one functions either always increasing or always decreasing? Why or why not?<\/p>\n<p>5. How do you find the inverse of a function algebraically?<\/p>\n<p>6. Show that the function [latex]f\\left(x\\right)=a-x[\/latex] is its own inverse for all real numbers [latex]a[\/latex].<\/p>\n<p>For the following exercises, find [latex]{f}^{-1}\\left(x\\right)[\/latex] for each function.<\/p>\n<p>7. [latex]f\\left(x\\right)=x+3[\/latex]<\/p>\n<p>8.\u00a0[latex]f\\left(x\\right)=x+5[\/latex]<\/p>\n<p>9. [latex]f\\left(x\\right)=2-x[\/latex]<\/p>\n<p>10.\u00a0[latex]f\\left(x\\right)=3-x[\/latex]<\/p>\n<p>11.\u00a0[latex]f\\left(x\\right)=\\frac{x}{x+2}[\/latex]<\/p>\n<p>12.\u00a0[latex]f\\left(x\\right)=\\frac{2x+3}{5x+4}[\/latex]<\/p>\n<p>For the following exercises, find a domain on which each function [latex]f[\/latex] is one-to-one and non-decreasing. Write the domain in interval notation. Then find the inverse of [latex]f[\/latex] restricted to that domain.<\/p>\n<p>13. [latex]f\\left(x\\right)={\\left(x+7\\right)}^{2}[\/latex]<\/p>\n<p>14.\u00a0[latex]f\\left(x\\right)={\\left(x - 6\\right)}^{2}[\/latex]<\/p>\n<p>15. [latex]f\\left(x\\right)={x}^{2}-5[\/latex]<\/p>\n<p>16.\u00a0Given [latex]f\\left(x\\right)=\\frac{x}{2}+x[\/latex] and [latex]g\\left(x\\right)=\\frac{2x}{1-x}[\/latex]<\/p>\n<p>a. Find [latex]f\\left(g\\left(x\\right)\\right)[\/latex] and [latex]g\\left(f\\left(x\\right)\\right)[\/latex]<\/p>\n<p>b. What does the answer tell us about the relationship between [latex]f\\left(x\\right)[\/latex] and [latex]g\\left(x\\right)?[\/latex]<\/p>\n<p>For the following exercises, use function composition to verify that [latex]f\\left(x\\right)[\/latex] and [latex]g\\left(x\\right)[\/latex] are inverse functions.<\/p>\n<p>17. [latex]f\\left(x\\right)=\\sqrt[3]{x - 1}[\/latex] and [latex]g\\left(x\\right)={x}^{3}+1[\/latex]<\/p>\n<p>18.\u00a0[latex]f\\left(x\\right)=-3x+5[\/latex] and [latex]g\\left(x\\right)=\\frac{x - 5}{-3}[\/latex]<\/p>\n<p>For the following exercises, use a graphing utility to determine whether each function is one-to-one.<\/p>\n<p>19. [latex]f\\left(x\\right)=\\sqrt{x}[\/latex]<\/p>\n<p>20.\u00a0[latex]f\\left(x\\right)=\\sqrt[3]{3x+1}[\/latex]<\/p>\n<p>21. [latex]f\\left(x\\right)=-5x+1[\/latex]<\/p>\n<p>22.\u00a0[latex]f\\left(x\\right)={x}^{3}-27[\/latex]<\/p>\n<p>For the following exercises, determine whether the graph represents a one-to-one function.<\/p>\n<p>23.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010629\/CNX_Precalc_Figure_01_07_2012.jpg\" alt=\"Graph of an upright parabola with vertex at (10, -10), passing through (0,0) and (25,0)\" width=\"487\" height=\"253\" \/><\/p>\n<p>24.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010629\/CNX_Precalc_Figure_01_07_2022.jpg\" alt=\"Graph of a step-function, with y = -5 for {x|-10&lt;=x,0} and y = 0 for {x|0&lt;=x&lt;10}\" width=\"487\" height=\"376\" \/><\/p>\n<p>For the following exercises, use the graph of [latex]f[\/latex] shown below.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010629\/CNX_Precalc_Figure_01_07_2032.jpg\" alt=\"Graph of the line y = (-3\/2)x + 3\" width=\"487\" height=\"368\" \/><br \/>\n25. Find [latex]f\\left(0\\right)[\/latex].<\/p>\n<p>26. Solve [latex]f\\left(x\\right)=0[\/latex].<\/p>\n<p>27. Find [latex]{f}^{-1}\\left(0\\right)[\/latex].<\/p>\n<p>28.\u00a0Solve [latex]{f}^{-1}\\left(x\\right)=0[\/latex].<\/p>\n<p>For the following exercises, use the graph of the one-to-one function shown below.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/1227\/2015\/04\/03010629\/CNX_Precalc_Figure_01_07_2042.jpg\" alt=\"Graph of a square root function for {x|x&gt;=2}\" width=\"487\" height=\"254\" \/><br \/>\n29. Sketch the graph of [latex]{f}^{-1}[\/latex].<\/p>\n<p>30. Find [latex]f\\left(6\\right)\\text{ and }{f}^{-1}\\left(2\\right)[\/latex].<\/p>\n<p>31. If the complete graph of [latex]f[\/latex] is shown, find the domain of [latex]f[\/latex].<\/p>\n<p>32. If the complete graph of [latex]f[\/latex] is shown, find the range of [latex]f[\/latex].<\/p>\n<p>For the following exercises, evaluate or solve, assuming that the function [latex]f[\/latex] is one-to-one.<\/p>\n<p>33. If [latex]f\\left(6\\right)=7[\/latex], find [latex]{f}^{-1}\\left(7\\right)[\/latex].<\/p>\n<p>34.\u00a0If [latex]f\\left(3\\right)=2[\/latex], find [latex]{f}^{-1}\\left(2\\right)[\/latex].<\/p>\n<p>35. If [latex]{f}^{-1}\\left(-4\\right)=-8[\/latex], find [latex]f\\left(-8\\right)[\/latex].<\/p>\n<p>36.\u00a0If [latex]{f}^{-1}\\left(-2\\right)=-1[\/latex], find [latex]f\\left(-1\\right)[\/latex].<\/p>\n<p>For the following exercises, use the values listed in the table below\u00a0to evaluate or solve.<\/p>\n<table id=\"Table_01_07_06\" summary=\"Two column and ten rows. The first column is labeled,\">\n<tbody>\n<tr>\n<td style=\"text-align: center;\"><strong> [latex]x[\/latex] <\/strong><\/td>\n<td style=\"text-align: center;\"><strong> [latex]f\\left(x\\right)[\/latex] <\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">0<\/td>\n<td style=\"text-align: center;\">8<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">1<\/td>\n<td style=\"text-align: center;\">0<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">2<\/td>\n<td style=\"text-align: center;\">7<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">3<\/td>\n<td style=\"text-align: center;\">4<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">4<\/td>\n<td style=\"text-align: center;\">2<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">5<\/td>\n<td style=\"text-align: center;\">6<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">6<\/td>\n<td style=\"text-align: center;\">5<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">7<\/td>\n<td style=\"text-align: center;\">3<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">8<\/td>\n<td style=\"text-align: center;\">9<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\">9<\/td>\n<td style=\"text-align: center;\">1<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>37. Find [latex]f\\left(1\\right)[\/latex].<\/p>\n<p>38.\u00a0Solve [latex]f\\left(x\\right)=3[\/latex].<\/p>\n<p>39. Find [latex]{f}^{-1}\\left(0\\right)[\/latex].<\/p>\n<p>40.\u00a0Solve [latex]{f}^{-1}\\left(x\\right)=7[\/latex].<\/p>\n<p>41. Use the tabular representation of [latex]f[\/latex] to create a table for [latex]{f}^{-1}\\left(x\\right)[\/latex].<\/p>\n<table>\n<tbody>\n<tr>\n<td><strong> [latex]x[\/latex] <\/strong><\/td>\n<td>3<\/td>\n<td>6<\/td>\n<td>9<\/td>\n<td>13<\/td>\n<td>14<\/td>\n<\/tr>\n<tr>\n<td><strong> [latex]f\\left(x\\right)[\/latex] <\/strong><\/td>\n<td>1<\/td>\n<td>4<\/td>\n<td>7<\/td>\n<td>12<\/td>\n<td>16<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>For the following exercises, find the inverse function. Then, graph the function and its inverse.<\/p>\n<p>42. [latex]f\\left(x\\right)=\\frac{3}{x - 2}[\/latex]<\/p>\n<p>43. [latex]f\\left(x\\right)={x}^{3}-1[\/latex]<\/p>\n<p>44. Find the inverse function of [latex]f\\left(x\\right)=\\frac{1}{x - 1}[\/latex]. Use a graphing utility to find its domain and range. Write the domain and range in interval notation.<\/p>\n<p>45.\u00a0To convert from [latex]x[\/latex] degrees Celsius to [latex]y[\/latex] degrees Fahrenheit, we use the formula [latex]f\\left(x\\right)=\\frac{9}{5}x+32[\/latex]. Find the inverse function, if it exists, and explain its meaning.<\/p>\n<p>46.\u00a0The circumference [latex]C[\/latex] of a circle is a function of its radius given by [latex]C\\left(r\\right)=2\\pi r[\/latex]. Express the radius of a circle as a function of its circumference. Call this function [latex]r\\left(C\\right)[\/latex]. Find [latex]r\\left(36\\pi \\right)[\/latex] and interpret its meaning.<\/p>\n<p>47. A car travels at a constant speed of 50 miles per hour. The distance the car travels in miles is a function of time, [latex]t[\/latex], in hours given by [latex]d\\left(t\\right)=50t[\/latex]. Find the inverse function by expressing the time of travel in terms of the distance traveled. Call this function [latex]t\\left(d\\right)[\/latex]. Find [latex]t\\left(180\\right)[\/latex] and interpret its meaning.<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-15513\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":169554,"menu_order":20,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-15513","chapter","type-chapter","status-publish","hentry"],"part":10705,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15513","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/169554"}],"version-history":[{"count":1,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15513\/revisions"}],"predecessor-version":[{"id":15514,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15513\/revisions\/15514"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/10705"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15513\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=15513"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=15513"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=15513"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=15513"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}