{"id":15608,"date":"2019-09-04T23:55:09","date_gmt":"2019-09-04T23:55:09","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/precalculus\/?post_type=chapter&#038;p=15608"},"modified":"2025-02-05T05:19:55","modified_gmt":"2025-02-05T05:19:55","slug":"problem-set-32-partial-fractions","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/precalculus\/chapter\/problem-set-32-partial-fractions\/","title":{"raw":"Problem Set 32: Partial Fractions","rendered":"Problem Set 32: Partial Fractions"},"content":{"raw":"1. Can any quotient of polynomials be decomposed into at least two partial fractions? If so, explain why, and if not, give an example of such a fraction\r\n\r\n2.\u00a0Can you explain why a partial fraction decomposition is unique? (Hint: Think about it as a system of equations.)\r\n\r\n3. Can you explain how to verify a partial fraction decomposition graphically?\r\n\r\n4.\u00a0You are unsure if you correctly decomposed the partial fraction correctly. Explain how you could double-check your answer.\r\n\r\n5. Once you have a system of equations generated by the partial fraction decomposition, can you explain another method to solve it? For example if you had [latex]\\frac{7x+13}{3{x}^{2}+8x+15}=\\frac{A}{x+1}+\\frac{B}{3x+5}[\/latex], we eventually simplify to [latex]7x+13=A\\left(3x+5\\right)+B\\left(x+1\\right)[\/latex]. Explain how you could intelligently choose an [latex]x[\/latex] -value that will eliminate either [latex]A[\/latex] or [latex]B[\/latex] and solve for [latex]A[\/latex] and [latex]B[\/latex].\r\n\r\nFor the following exercises, find the decomposition of the partial fraction for the nonrepeating linear factors.\r\n\r\n6. [latex]\\frac{5x+16}{{x}^{2}+10x+24}[\/latex]\r\n\r\n7. [latex]\\frac{3x - 79}{{x}^{2}-5x - 24}[\/latex]\r\n\r\n8.\u00a0[latex]\\frac{-x - 24}{{x}^{2}-2x - 24}[\/latex]\r\n\r\n9. [latex]\\frac{10x+47}{{x}^{2}+7x+10}[\/latex]\r\n\r\n10.\u00a0[latex]\\frac{x}{6{x}^{2}+25x+25}[\/latex]\r\n\r\n11. [latex]\\frac{32x - 11}{20{x}^{2}-13x+2}[\/latex]\r\n\r\n12.\u00a0[latex]\\frac{x+1}{{x}^{2}+7x+10}[\/latex]\r\n\r\n13. [latex]\\frac{5x}{{x}^{2}-9}[\/latex]\r\n\r\n14.\u00a0[latex]\\frac{10x}{{x}^{2}-25}[\/latex]\r\n\r\n15. [latex]\\frac{6x}{{x}^{2}-4}[\/latex]\r\n\r\n16.\u00a0[latex]\\frac{2x - 3}{{x}^{2}-6x+5}[\/latex]\r\n\r\n17. [latex]\\frac{4x - 1}{{x}^{2}-x - 6}[\/latex]\r\n\r\n18.\u00a0[latex]\\frac{4x+3}{{x}^{2}+8x+15}[\/latex]\r\n\r\n19. [latex]\\frac{3x - 1}{{x}^{2}-5x+6}[\/latex]\r\n\r\nFor the following exercises, find the decomposition of the partial fraction for the repeating linear factors.\r\n\r\n20. [latex]\\frac{-5x - 19}{{\\left(x+4\\right)}^{2}}[\/latex]\r\n\r\n21. [latex]\\frac{x}{{\\left(x - 2\\right)}^{2}}[\/latex]\r\n\r\n22.\u00a0[latex]\\frac{7x+14}{{\\left(x+3\\right)}^{2}}[\/latex]\r\n\r\n23. [latex]\\frac{-24x - 27}{{\\left(4x+5\\right)}^{2}}[\/latex]\r\n\r\n24.\u00a0[latex]\\frac{-24x - 27}{{\\left(6x - 7\\right)}^{2}}[\/latex]\r\n\r\n25. [latex]\\frac{5-x}{{\\left(x - 7\\right)}^{2}}[\/latex]\r\n\r\n26.\u00a0[latex]\\frac{5x+14}{2{x}^{2}+12x+18}[\/latex]\r\n\r\n27. [latex]\\frac{5{x}^{2}+20x+8}{2x{\\left(x+1\\right)}^{2}}[\/latex]\r\n\r\n28.\u00a0[latex]\\frac{4{x}^{2}+55x+25}{5x{\\left(3x+5\\right)}^{2}}[\/latex]\r\n\r\n29. [latex]\\frac{54{x}^{3}+127{x}^{2}+80x+16}{2{x}^{2}{\\left(3x+2\\right)}^{2}}[\/latex]\r\n\r\n30.\u00a0[latex]\\frac{{x}^{3}-5{x}^{2}+12x+144}{{x}^{2}\\left({x}^{2}+12x+36\\right)}[\/latex]\r\n\r\nFor the following exercises, find the decomposition of the partial fraction for the irreducible nonrepeating quadratic factor.\r\n\r\n31. [latex]\\frac{4{x}^{2}+6x+11}{\\left(x+2\\right)\\left({x}^{2}+x+3\\right)}[\/latex]\r\n\r\n32.\u00a0[latex]\\frac{4{x}^{2}+9x+23}{\\left(x - 1\\right)\\left({x}^{2}+6x+11\\right)}[\/latex]\r\n\r\n33. [latex]\\frac{-2{x}^{2}+10x+4}{\\left(x - 1\\right)\\left({x}^{2}+3x+8\\right)}[\/latex]\r\n\r\n34.\u00a0[latex]\\frac{{x}^{2}+3x+1}{\\left(x+1\\right)\\left({x}^{2}+5x - 2\\right)}[\/latex]\r\n\r\n35. [latex]\\frac{4{x}^{2}+17x - 1}{\\left(x+3\\right)\\left({x}^{2}+6x+1\\right)}[\/latex]\r\n\r\n36.\u00a0[latex]\\frac{4{x}^{2}}{\\left(x+5\\right)\\left({x}^{2}+7x - 5\\right)}[\/latex]\r\n\r\n37. [latex]\\frac{4{x}^{2}+5x+3}{{x}^{3}-1}[\/latex]\r\n\r\n38.\u00a0[latex]\\frac{-5{x}^{2}+18x - 4}{{x}^{3}+8}[\/latex]\r\n\r\n39. [latex]\\frac{3{x}^{2}-7x+33}{{x}^{3}+27}[\/latex]\r\n\r\n40.\u00a0[latex]\\frac{{x}^{2}+2x+40}{{x}^{3}-125}[\/latex]\r\n\r\n41. [latex]\\frac{4{x}^{2}+4x+12}{8{x}^{3}-27}[\/latex]\r\n\r\n42.\u00a0[latex]\\frac{-50{x}^{2}+5x - 3}{125{x}^{3}-1}[\/latex]\r\n\r\n43. [latex]\\frac{-2{x}^{3}-30{x}^{2}+36x+216}{{x}^{4}+216x}[\/latex]\r\n\r\nFor the following exercises, find the decomposition of the partial fraction for the irreducible repeating quadratic factor.\r\n\r\n44. [latex]\\frac{3{x}^{3}+2{x}^{2}+14x+15}{{\\left({x}^{2}+4\\right)}^{2}}[\/latex]\r\n\r\n45. [latex]\\frac{{x}^{3}+6{x}^{2}+5x+9}{{\\left({x}^{2}+1\\right)}^{2}}[\/latex]\r\n\r\n46.\u00a0[latex]\\frac{{x}^{3}-{x}^{2}+x - 1}{{\\left({x}^{2}-3\\right)}^{2}}[\/latex]\r\n\r\n47. [latex]\\frac{{x}^{2}+5x+5}{{\\left(x+2\\right)}^{2}}[\/latex]\r\n\r\n48.\u00a0[latex]\\frac{{x}^{3}+2{x}^{2}+4x}{{\\left({x}^{2}+2x+9\\right)}^{2}}[\/latex]\r\n\r\n49. [latex]\\frac{{x}^{2}+25}{{\\left({x}^{2}+3x+25\\right)}^{2}}[\/latex]\r\n\r\n50.\u00a0[latex]\\frac{2{x}^{3}+11x+7x+70}{{\\left(2{x}^{2}+x+14\\right)}^{2}}[\/latex]\r\n\r\n51. [latex]\\frac{5x+2}{x{\\left({x}^{2}+4\\right)}^{2}}[\/latex]\r\n\r\n52.\u00a0[latex]\\frac{{x}^{4}+{x}^{3}+8{x}^{2}+6x+36}{x{\\left({x}^{2}+6\\right)}^{2}}[\/latex]\r\n\r\n53. [latex]\\frac{2x - 9}{{\\left({x}^{2}-x\\right)}^{2}}[\/latex]\r\n\r\n54.\u00a0[latex]\\frac{5{x}^{3}-2x+1}{{\\left({x}^{2}+2x\\right)}^{2}}[\/latex]\r\n\r\nFor the following exercises, find the partial fraction expansion.\r\n\r\n55. [latex]\\frac{{x}^{2}+4}{{\\left(x+1\\right)}^{3}}[\/latex]\r\n\r\n56.\u00a0[latex]\\frac{{x}^{3}-4{x}^{2}+5x+4}{{\\left(x - 2\\right)}^{3}}[\/latex]\r\n\r\nFor the following exercises, perform the operation and then find the partial fraction decomposition.\r\n\r\n57. [latex]\\frac{7}{x+8}+\\frac{5}{x - 2}-\\frac{x - 1}{{x}^{2}-6x - 16}[\/latex]\r\n\r\n58.\u00a0[latex]\\frac{1}{x - 4}-\\frac{3}{x+6}-\\frac{2x+7}{{x}^{2}+2x - 24}[\/latex]\r\n\r\n59. [latex]\\frac{2x}{{x}^{2}-16}-\\frac{1 - 2x}{{x}^{2}+6x+8}-\\frac{x - 5}{{x}^{2}-4x}[\/latex]","rendered":"<p>1. Can any quotient of polynomials be decomposed into at least two partial fractions? If so, explain why, and if not, give an example of such a fraction<\/p>\n<p>2.\u00a0Can you explain why a partial fraction decomposition is unique? (Hint: Think about it as a system of equations.)<\/p>\n<p>3. Can you explain how to verify a partial fraction decomposition graphically?<\/p>\n<p>4.\u00a0You are unsure if you correctly decomposed the partial fraction correctly. Explain how you could double-check your answer.<\/p>\n<p>5. Once you have a system of equations generated by the partial fraction decomposition, can you explain another method to solve it? For example if you had [latex]\\frac{7x+13}{3{x}^{2}+8x+15}=\\frac{A}{x+1}+\\frac{B}{3x+5}[\/latex], we eventually simplify to [latex]7x+13=A\\left(3x+5\\right)+B\\left(x+1\\right)[\/latex]. Explain how you could intelligently choose an [latex]x[\/latex] -value that will eliminate either [latex]A[\/latex] or [latex]B[\/latex] and solve for [latex]A[\/latex] and [latex]B[\/latex].<\/p>\n<p>For the following exercises, find the decomposition of the partial fraction for the nonrepeating linear factors.<\/p>\n<p>6. [latex]\\frac{5x+16}{{x}^{2}+10x+24}[\/latex]<\/p>\n<p>7. [latex]\\frac{3x - 79}{{x}^{2}-5x - 24}[\/latex]<\/p>\n<p>8.\u00a0[latex]\\frac{-x - 24}{{x}^{2}-2x - 24}[\/latex]<\/p>\n<p>9. [latex]\\frac{10x+47}{{x}^{2}+7x+10}[\/latex]<\/p>\n<p>10.\u00a0[latex]\\frac{x}{6{x}^{2}+25x+25}[\/latex]<\/p>\n<p>11. [latex]\\frac{32x - 11}{20{x}^{2}-13x+2}[\/latex]<\/p>\n<p>12.\u00a0[latex]\\frac{x+1}{{x}^{2}+7x+10}[\/latex]<\/p>\n<p>13. [latex]\\frac{5x}{{x}^{2}-9}[\/latex]<\/p>\n<p>14.\u00a0[latex]\\frac{10x}{{x}^{2}-25}[\/latex]<\/p>\n<p>15. [latex]\\frac{6x}{{x}^{2}-4}[\/latex]<\/p>\n<p>16.\u00a0[latex]\\frac{2x - 3}{{x}^{2}-6x+5}[\/latex]<\/p>\n<p>17. [latex]\\frac{4x - 1}{{x}^{2}-x - 6}[\/latex]<\/p>\n<p>18.\u00a0[latex]\\frac{4x+3}{{x}^{2}+8x+15}[\/latex]<\/p>\n<p>19. [latex]\\frac{3x - 1}{{x}^{2}-5x+6}[\/latex]<\/p>\n<p>For the following exercises, find the decomposition of the partial fraction for the repeating linear factors.<\/p>\n<p>20. [latex]\\frac{-5x - 19}{{\\left(x+4\\right)}^{2}}[\/latex]<\/p>\n<p>21. [latex]\\frac{x}{{\\left(x - 2\\right)}^{2}}[\/latex]<\/p>\n<p>22.\u00a0[latex]\\frac{7x+14}{{\\left(x+3\\right)}^{2}}[\/latex]<\/p>\n<p>23. [latex]\\frac{-24x - 27}{{\\left(4x+5\\right)}^{2}}[\/latex]<\/p>\n<p>24.\u00a0[latex]\\frac{-24x - 27}{{\\left(6x - 7\\right)}^{2}}[\/latex]<\/p>\n<p>25. [latex]\\frac{5-x}{{\\left(x - 7\\right)}^{2}}[\/latex]<\/p>\n<p>26.\u00a0[latex]\\frac{5x+14}{2{x}^{2}+12x+18}[\/latex]<\/p>\n<p>27. [latex]\\frac{5{x}^{2}+20x+8}{2x{\\left(x+1\\right)}^{2}}[\/latex]<\/p>\n<p>28.\u00a0[latex]\\frac{4{x}^{2}+55x+25}{5x{\\left(3x+5\\right)}^{2}}[\/latex]<\/p>\n<p>29. [latex]\\frac{54{x}^{3}+127{x}^{2}+80x+16}{2{x}^{2}{\\left(3x+2\\right)}^{2}}[\/latex]<\/p>\n<p>30.\u00a0[latex]\\frac{{x}^{3}-5{x}^{2}+12x+144}{{x}^{2}\\left({x}^{2}+12x+36\\right)}[\/latex]<\/p>\n<p>For the following exercises, find the decomposition of the partial fraction for the irreducible nonrepeating quadratic factor.<\/p>\n<p>31. [latex]\\frac{4{x}^{2}+6x+11}{\\left(x+2\\right)\\left({x}^{2}+x+3\\right)}[\/latex]<\/p>\n<p>32.\u00a0[latex]\\frac{4{x}^{2}+9x+23}{\\left(x - 1\\right)\\left({x}^{2}+6x+11\\right)}[\/latex]<\/p>\n<p>33. [latex]\\frac{-2{x}^{2}+10x+4}{\\left(x - 1\\right)\\left({x}^{2}+3x+8\\right)}[\/latex]<\/p>\n<p>34.\u00a0[latex]\\frac{{x}^{2}+3x+1}{\\left(x+1\\right)\\left({x}^{2}+5x - 2\\right)}[\/latex]<\/p>\n<p>35. [latex]\\frac{4{x}^{2}+17x - 1}{\\left(x+3\\right)\\left({x}^{2}+6x+1\\right)}[\/latex]<\/p>\n<p>36.\u00a0[latex]\\frac{4{x}^{2}}{\\left(x+5\\right)\\left({x}^{2}+7x - 5\\right)}[\/latex]<\/p>\n<p>37. [latex]\\frac{4{x}^{2}+5x+3}{{x}^{3}-1}[\/latex]<\/p>\n<p>38.\u00a0[latex]\\frac{-5{x}^{2}+18x - 4}{{x}^{3}+8}[\/latex]<\/p>\n<p>39. [latex]\\frac{3{x}^{2}-7x+33}{{x}^{3}+27}[\/latex]<\/p>\n<p>40.\u00a0[latex]\\frac{{x}^{2}+2x+40}{{x}^{3}-125}[\/latex]<\/p>\n<p>41. [latex]\\frac{4{x}^{2}+4x+12}{8{x}^{3}-27}[\/latex]<\/p>\n<p>42.\u00a0[latex]\\frac{-50{x}^{2}+5x - 3}{125{x}^{3}-1}[\/latex]<\/p>\n<p>43. [latex]\\frac{-2{x}^{3}-30{x}^{2}+36x+216}{{x}^{4}+216x}[\/latex]<\/p>\n<p>For the following exercises, find the decomposition of the partial fraction for the irreducible repeating quadratic factor.<\/p>\n<p>44. [latex]\\frac{3{x}^{3}+2{x}^{2}+14x+15}{{\\left({x}^{2}+4\\right)}^{2}}[\/latex]<\/p>\n<p>45. [latex]\\frac{{x}^{3}+6{x}^{2}+5x+9}{{\\left({x}^{2}+1\\right)}^{2}}[\/latex]<\/p>\n<p>46.\u00a0[latex]\\frac{{x}^{3}-{x}^{2}+x - 1}{{\\left({x}^{2}-3\\right)}^{2}}[\/latex]<\/p>\n<p>47. [latex]\\frac{{x}^{2}+5x+5}{{\\left(x+2\\right)}^{2}}[\/latex]<\/p>\n<p>48.\u00a0[latex]\\frac{{x}^{3}+2{x}^{2}+4x}{{\\left({x}^{2}+2x+9\\right)}^{2}}[\/latex]<\/p>\n<p>49. [latex]\\frac{{x}^{2}+25}{{\\left({x}^{2}+3x+25\\right)}^{2}}[\/latex]<\/p>\n<p>50.\u00a0[latex]\\frac{2{x}^{3}+11x+7x+70}{{\\left(2{x}^{2}+x+14\\right)}^{2}}[\/latex]<\/p>\n<p>51. [latex]\\frac{5x+2}{x{\\left({x}^{2}+4\\right)}^{2}}[\/latex]<\/p>\n<p>52.\u00a0[latex]\\frac{{x}^{4}+{x}^{3}+8{x}^{2}+6x+36}{x{\\left({x}^{2}+6\\right)}^{2}}[\/latex]<\/p>\n<p>53. [latex]\\frac{2x - 9}{{\\left({x}^{2}-x\\right)}^{2}}[\/latex]<\/p>\n<p>54.\u00a0[latex]\\frac{5{x}^{3}-2x+1}{{\\left({x}^{2}+2x\\right)}^{2}}[\/latex]<\/p>\n<p>For the following exercises, find the partial fraction expansion.<\/p>\n<p>55. [latex]\\frac{{x}^{2}+4}{{\\left(x+1\\right)}^{3}}[\/latex]<\/p>\n<p>56.\u00a0[latex]\\frac{{x}^{3}-4{x}^{2}+5x+4}{{\\left(x - 2\\right)}^{3}}[\/latex]<\/p>\n<p>For the following exercises, perform the operation and then find the partial fraction decomposition.<\/p>\n<p>57. [latex]\\frac{7}{x+8}+\\frac{5}{x - 2}-\\frac{x - 1}{{x}^{2}-6x - 16}[\/latex]<\/p>\n<p>58.\u00a0[latex]\\frac{1}{x - 4}-\\frac{3}{x+6}-\\frac{2x+7}{{x}^{2}+2x - 24}[\/latex]<\/p>\n<p>59. [latex]\\frac{2x}{{x}^{2}-16}-\\frac{1 - 2x}{{x}^{2}+6x+8}-\\frac{x - 5}{{x}^{2}-4x}[\/latex]<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-15608\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":169554,"menu_order":15,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-15608","chapter","type-chapter","status-publish","hentry"],"part":14549,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15608","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/users\/169554"}],"version-history":[{"count":1,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15608\/revisions"}],"predecessor-version":[{"id":15610,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15608\/revisions\/15610"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/parts\/14549"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapters\/15608\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/media?parent=15608"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=15608"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/contributor?post=15608"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/precalculus\/wp-json\/wp\/v2\/license?post=15608"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}