4.3: Solving a 2×2 System of Linear Equations by Elimination

Section 4.3 Learning Objectives

4.3:  Solving a 2×2 System of Linear Equations by Addition/Elimination

  • Solve systems of linear equations using elimination
  • Recognize when systems of linear equations have no solution or an infinite number of solutions

 

Solve a system of equations using the elimination method

The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation to eliminate one of the variable terms.  In this method, you may or may not need to multiply the terms in one equation by a number first.  We will first look at examples where no multiplication is necessary to use the elimination method.  Then you will see examples using multiplication after you are familiar with the idea of the elimination method.

It is easier to show rather than tell with this method, so let’s dive right into some examples.

If you add the two equations,

[latex]x–y=−6[/latex] and [latex]x+y=8[/latex] together, watch what happens.

[latex]\displaystyle \begin{array}{l}\,\,\,\,\,x-y=\,-6\\\underline{+\,x+y=\,\,\,8}\\\,2x+0\,=\,\,\,\,2\end{array}[/latex]

You have eliminated the [latex]y[/latex]-term, and this equation can be solved using the methods for solving equations with one variable.

Let’s see how this system is solved using the elimination method.

Example 1

Use elimination to solve the system.

[latex]\begin{array}{r}x–y=−6\\x+y=\,\,\,\,8\end{array}[/latex]

Unfortunately not all systems work out this easily. How about a system like [latex]2x+y=12[/latex] and [latex]−3x+y=2[/latex]. If you add these two equations together, no variables are eliminated.

[latex]\displaystyle \begin{array}{l}\,\,\,\,2x+y=12\\\underline{-3x+y=\,\,\,2}\\-x+2y=14\end{array}[/latex]

But you want to eliminate a variable. So let’s add the opposite of one of the equations to the other equation. This means multiply every term in one of the equations by [latex]-1[/latex], so that the sign of every term is opposite.

[latex]\begin{array}{l}\,\,\,\,2x+\,\,y\,=12\rightarrow2x+y=12\rightarrow2x+y=12\\−3x+\,\,y\,=2\rightarrow−\left(−3x+y\right)=−(2)\rightarrow3x–y=−2\\\,\,\,\,5x+0y=10\end{array}[/latex]

You have eliminated the [latex]y[/latex]-variable, and the problem can now be solved.  The complete solution is shown in the example after the video.

The following video describe a similar problem where you can eliminate one variable by adding the two equations together.

CautionCaution!  When you add the opposite of one entire equation to another, make sure to change the sign of EVERY term on both sides of the equation. This is a very common mistake to make.

Example 2

Use elimination to solve the system.

[latex]\begin{array}{r}2x+y=12\\−3x+y=2\,\,\,\end{array}[/latex]

The following are two more examples showing how to solve linear systems of equations using elimination.

Example 3

Use elimination to solve the system.

[latex]\begin{array}{r}3y=2x-1 \\ 2x=5(5-y)\end{array}[/latex]

Example 4

Use elimination to solve for  [latex]x[/latex] and  [latex]y[/latex].

[latex]\begin{array}{r}4x+2y=14\\5x+2y=16\end{array}[/latex]

Go ahead and check this last example—substitute [latex](2, 3)[/latex] into both equations. You get two true statements: [latex]14=14[/latex] and [latex]16=16[/latex].

Notice that you could have used the opposite of the first equation rather than the second equation and the result would be the same.

Recognize systems that have no solution or an infinite number of solutions

Just as with the substitution method, the elimination method will sometimes eliminate both variables, and you end up with either a true statement or a false statement. Recall that a false statement means that there is no solution.

Let’s look at an example.

Example 5

Solve for  [latex]x[/latex] and  [latex]y[/latex].

[latex]\begin{array}{r}-\hspace{.02in}x\hspace{.03in}–\hspace{.03in}y=-4\\x+y=2\,\,\,\,\,\end{array}[/latex]

Graphing these lines shows that they are parallel lines and as such do not share any point in common, verifying that there is no solution.

Two parallel lines. One line is -x-y=-4. The other line is x+y=2.

If both variables are eliminated and you are left with a true statement, this indicates that there are an infinite number of ordered pairs that satisfy both of the equations. In fact, the equations are the same line.

Example 6

Solve for  [latex]x[/latex] and [latex]y[/latex].

[latex]\begin{array}{r}x+y=2\,\,\,\,\,\\-x−y=-2\end{array}[/latex]

Graphing these two equations will help to illustrate what is happening.

Two overlapping lines. One is -x-y=-2, and the other is x+y=2.

In the following video, a system of equations which has no solutions is solved using the method of elimination.

Solve a system of equations when multiplication is necessary to eliminate a variable

Many times adding the equations or adding the opposite of one of the equations will not result in eliminating a variable. Look at the system below.

[latex]\begin{array}{r}3x+4y=52\\5x+y=30\end{array}[/latex]

If you add the equations above, or add the opposite of one of the equations, you will get an equation that still has two variables. So let’s now use the multiplication property of equality first. You can multiply both sides of one of the equations by a number that will allow you to eliminate the same variable in the other equation.

We do this with multiplication.  Notice that the first equation contains the term [latex]4y[/latex], and the second equation contains the term y. If you multiply the second equation by [latex]−4[/latex], when you add both equations the  [latex]y[/latex]variable terms will add up to [latex]0[/latex].

The following example takes you through all the steps to find a solution to this system.

Example 7

Solve for [latex]x[/latex]and [latex]y[/latex].

[latex]\begin{array}{r}3x+4y=52\\5x+y=30\end{array}[/latex]

CautionCaution!  When you use multiplication to eliminate a variable, you must multiply EACH term in the equation by the number you choose.  Forgetting to multiply every term is a common mistake.

There are other ways to solve this system. Instead of multiplying one equation in order to eliminate a variable when the equations were added, you could have multiplied both equations by different numbers.

Let’s eliminate the variable  [latex]x[/latex] this time. We can achieve this by multiplying the first equation by 5 and the second equation by [latex]−3[/latex].

Example 8

Solve for [latex]x[/latex] and [latex]y[/latex].

[latex]\begin{array}{r}3x+4y=52\\5x+y=30\end{array}[/latex]

These equations were multiplied by 5 and [latex]−3[/latex] respectively, because that gave you terms that would add up to 0. Be sure to multiply all of the terms of the equation.

In the following video, you will see an example of using the elimination method for solving a system of equations.

The next example reminds us that sometimes we must deal with fractions.

Example 9

Use elimination to solve the system of equations.

[latex]\begin{array}{l}\frac{1}{2}x-\frac{3}{4}y=1\\ \frac{3}{4}x-\frac{3}{2}y=\frac{13}{8} \end{array}[/latex]

 

 

It is possible to use the elimination method with multiplication and get a result that indicates no solutions or infinitely many solutions, just as we saw in simpler systems earlier. In the following example, you will see a system that has infinitely many solutions.

Example 10

Solve the system of equations.

[latex]\begin{array}{r}x-3y=-2\\-2x+6y=4\end{array}[/latex]

In the following video, the elimination method is used to solve a system of equations. Notice that one of the equations needs to be multiplied by a negative one first.  Additionally, this system has an infinite number of solutions.

Summary

Combining equations is a powerful tool for solving a system of equations. Adding or subtracting two equations in order to eliminate a common variable is called the elimination (or addition) method. Once one variable is eliminated, it becomes much easier to solve for the other one.

Multiplication can be used to set up terms that can be eliminated in the equations before they are combined to aid in finding a solution to a system. When using the multiplication method, it is important to multiply all the terms on both sides of the equation—not just the one term you are trying to eliminate. Solving using the elimination method will yield one of three results: a single value for each variable within the system (indicating one solution), an untrue statement (indicating no solutions), or a true statement (indicating an infinite number of solutions).