{"id":6806,"date":"2020-10-09T21:16:01","date_gmt":"2020-10-09T21:16:01","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/slcc-beginalgebra\/?post_type=chapter&#038;p=6806"},"modified":"2026-02-05T08:36:29","modified_gmt":"2026-02-05T08:36:29","slug":"7-2-adding-and-subtracting-radical-expressions","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/chapter\/7-2-adding-and-subtracting-radical-expressions\/","title":{"raw":"7.2: Adding and Subtracting Radical Expressions","rendered":"7.2: Adding and Subtracting Radical Expressions"},"content":{"raw":"<div class=\"textbox learning-objectives\">\r\n<h3>section 7.2 Learning Objectives<\/h3>\r\n<strong>7.2: Adding and Subtracting Radical Expressions<\/strong>\r\n<ul>\r\n \t<li>Identify like radicals<\/li>\r\n \t<li>Simplify an expression by adding and subtracting like radicals<\/li>\r\n \t<li>Add and subtract radicals that must be simplified first<\/li>\r\n<\/ul>\r\n<\/div>\r\n&nbsp;\r\n<h2 id=\"title1\">Identify like radicals<\/h2>\r\nThere are two keys to combining radicals by addition or subtraction: look at the <strong>index<\/strong>, and look at the <strong>radicand<\/strong>. If these are the same, then addition and subtraction are possible. If not, then you cannot combine the two radicals. In the graphic below, the index of the\u00a0expression [latex]12\\sqrt[3]{xy}[\/latex] is\u00a0[latex]3[\/latex] and the radicand is [latex]xy[\/latex].\r\n\r\n<img class=\"aligncenter wp-image-3200\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/121\/2016\/07\/29230521\/Screen-Shot-2016-07-29-at-4.04.52-PM-300x141.png\" alt=\"Expression 12 cube root of x y. Two arrows point to parts of the expression. Arrow 1 to three is labeled index. Arrow 2 to x y is labeled radicand.\" width=\"511\" height=\"240\" \/>\r\n\r\nMaking sense of a string of radicals may be difficult. One helpful tip is to think of radicals as variables, and treat them the same way. When you add and subtract variables, you look for like terms, which is the same thing you will do when you add and subtract radicals.\r\n\r\nIn this first example, both radicals have the same radicand and index.\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example 1<\/h3>\r\nAdd. [latex] 3\\sqrt{11}+7\\sqrt{11}[\/latex]\r\n[reveal-answer q=\"971281\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"971281\"]\r\n\r\nThe two radicals are the same, [latex] [\/latex]. This means you can combine them as you would combine the terms [latex] 3a+7a[\/latex].\r\n<p style=\"text-align: center;\">[latex] \\text{3}\\sqrt{11}\\text{ + 7}\\sqrt{11}[\/latex]<\/p>\r\nThe answer is [latex]10\\sqrt{11}[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<h2 id=\"title1\">Simplify an expression by adding like radicals<\/h2>\r\nThis next example contains more addends, or terms that are being added together. Notice how you can combine <i>like<\/i> terms (radicals that have the same root and index), but you cannot combine <i>unlike<\/i> terms.\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example 2<\/h3>\r\nAdd. [latex] 5\\sqrt{2}+\\sqrt{3}+4\\sqrt{3}+2\\sqrt{2}[\/latex]\r\n\r\n[reveal-answer q=\"687881\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"687881\"]\r\n\r\nRearrange terms so that like radicals are next to each other. Then add.\r\n<p style=\"text-align: center;\">[latex] 5\\sqrt{2}+2\\sqrt{2}+\\sqrt{3}+4\\sqrt{3}[\/latex]<\/p>\r\nThe answer is [latex]7\\sqrt{2}+5\\sqrt{3}[\/latex]\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nNotice that the expression in the previous example is simplified even though it has two terms: [latex] 7\\sqrt{2}[\/latex] and [latex] 5\\sqrt{3}[\/latex]. It would be a mistake to try to combine them further! Some people make the mistake that [latex] 7\\sqrt{2}+5\\sqrt{3}=12\\sqrt{5}[\/latex]. This is incorrect because[latex] \\sqrt{2}[\/latex] and [latex]\\sqrt{3}[\/latex] are not like radicals so they cannot be added.\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example 3<\/h3>\r\nAdd. [latex] 3\\sqrt{5}+12\\sqrt[3]{7}+\\sqrt{5}[\/latex]\r\n\r\n[reveal-answer q=\"885242\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"885242\"]\r\n\r\nRearrange terms so that like radicals are next to each other. Then add.\r\n<p style=\"text-align: center;\">[latex] 3\\sqrt{5}+\\sqrt{5}+12\\sqrt[3]{7}[\/latex]<\/p>\r\nThe answer is [latex]4\\sqrt{5}+12\\sqrt[3]{7}[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nIn the following video, we show more examples of how to identify and add like radicals.\r\n\r\nhttps:\/\/youtu.be\/ihcZhgm3yBg\r\n<h2 id=\"title1\">Add radicals that must be simplified first<\/h2>\r\nSometimes you may need to add <i>and<\/i> simplify the radical. If the radicals are different, try simplifying first\u2014you may end up being able to combine the radicals at the end as shown in these next two examples.\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example 4<\/h3>\r\nAdd and simplify. [latex] 2\\sqrt[3]{40}+\\sqrt[3]{135}[\/latex]\r\n\r\n[reveal-answer q=\"638886\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"638886\"]\r\n\r\nSimplify each radical by identifying perfect cubes.\r\n<p style=\"text-align: center;\">[latex] \\begin{array}{r}=2\\sqrt[3]{8\\cdot 5}+\\sqrt[3]{27\\cdot 5}\\\\=2\\sqrt[3]{{{(2)}^{3}}\\cdot 5}+\\sqrt[3]{{{(3)}^{3}}\\cdot 5}\\\\=2\\sqrt[3]{{{(2)}^{3}}}\\cdot \\sqrt[3]{5}+\\sqrt[3]{{{(3)}^{3}}}\\cdot \\sqrt[3]{5}\\end{array}[\/latex]<\/p>\r\nSimplify.\r\n<p style=\"text-align: center;\">[latex] =2\\cdot 2\\cdot \\sqrt[3]{5}+3\\cdot \\sqrt[3]{5}[\/latex]<\/p>\r\n<p style=\"text-align: center;\">[latex]=4\\sqrt[3]{5}+3\\sqrt[3]{5}[\/latex]<\/p>\r\nThe answer is [latex]7\\sqrt[3]{5}[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3>Example 5<\/h3>\r\n<span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">Simplify: [latex] \\sqrt{12}+\\sqrt{27}[\/latex]<\/span><\/span>\r\n\r\n[reveal-answer q=\"690208\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"690208\"]\r\n<div style=\"font-weight: 400;\">\r\n\r\nAs written, these two radicals cannot be added because they are not like radicals.\u00a0 We\u00a0<span style=\"font-size: 1rem; text-align: initial;\">need to simplify both radicals first.\u00a0<\/span>\r\n\r\n<span class=\"TextRun BCX0 SCXW233914761\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW233914761\">Prime factor each radicand.<\/span><\/span>\r\n<p style=\"text-align: center;\"><span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">[latex] \\sqrt{12}+\\sqrt{27}=\\sqrt{2\\cdot 2\\cdot 3} + \\sqrt{3\\cdot 3\\cdot 3}[\/latex]<\/span><\/span><\/p>\r\n<span class=\"TextRun BCX0 SCXW30173351\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW30173351\">Identify pairs of identical factors and simplify.<\/span><\/span>\r\n<p style=\"text-align: center;\"><span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">[latex] =\\sqrt{2^2\\cdot 3} + \\sqrt{3^2\\cdot 3}[\/latex]<\/span><\/span><\/p>\r\n<p style=\"text-align: center;\"><span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">[latex] =2\\sqrt{3} + 3\\sqrt{3}[\/latex]<\/span><\/span><\/p>\r\n<span class=\"TextRun SCXW39848252 BCX0\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun SCXW39848252 BCX0\">In simplified form, we have like radicals and can add.<\/span><\/span>\r\n<p style=\"text-align: center;\"><span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">[latex] =5\\sqrt{3}[\/latex]<\/span><\/span><\/p>\r\n&nbsp;\r\n\r\n<\/div>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n&nbsp;\r\n\r\nThe following video shows more examples of adding radicals that require simplification.\r\n\r\nhttps:\/\/youtu.be\/S3fGUeALy7E\r\n<h2>Simplify an expression by subtracting like radicals<\/h2>\r\nSubtraction of radicals follows the same set of rules and approaches as addition\u2014the radicands and the indices must be the same for two (or more) radicals to be subtracted.\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example 6<\/h3>\r\nSubtract. [latex] 5\\sqrt{13}-3\\sqrt{13}[\/latex]\r\n\r\n[reveal-answer q=\"107411\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"107411\"]\r\n\r\nThe radicands and indices are the same, so these two radicals can be combined.\r\n<p style=\"text-align: center;\">[latex] 5\\sqrt{13}-3\\sqrt{13}[\/latex]<\/p>\r\n<p style=\"text-align: center;\">The answer is [latex]=2\\sqrt{13}[\/latex].<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Example 7<\/h3>\r\nSubtract. [latex] 4\\sqrt[3]{5}-\\sqrt[3]{3}-2\\sqrt[3]{5}[\/latex]\r\n\r\n[reveal-answer q=\"491962\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"491962\"]\r\n\r\nTwo of the radicals have the same index and radicand, so they can be combined. Rewrite the expression so that like radicals are next to each other.\r\n<p style=\"text-align: center;\">[latex]\\begin{array}{r} 4\\sqrt[3]{5}+(-\\sqrt[3]{3})+(-2\\sqrt[3]{5})\\\\=4\\sqrt[3]{5}+(-2\\sqrt[3]{5})+(-\\sqrt[3]{3})\\end{array}[\/latex]<\/p>\r\nCombine. Although the indices of [latex] 2\\sqrt[3]{5}[\/latex] and [latex] -\\sqrt[3]{3}[\/latex] are the same, the radicands are not\u2014so they cannot be combined.\r\n<p style=\"text-align: center;\">[latex] =2\\sqrt[3]{5}+(-\\sqrt[3]{3})[\/latex]<\/p>\r\nThe answer is [latex]2\\sqrt[3]{5}-\\sqrt[3]{3}[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3>Example 8<\/h3>\r\nSimplify:\u00a0[latex] 5\\sqrt{7}-8\\sqrt[4]{11}+\\sqrt{7}+3\\sqrt[4]{11}[\/latex]\r\n\r\n[reveal-answer q=\"780228\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"780228\"]\r\n\r\n<span class=\"TextRun SCXW37945795 BCX0\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun SCXW37945795 BCX0\">Notice, the radical terms are already in simplest form.<\/span><\/span><span class=\"EOP SCXW37945795 BCX0\">\u00a0<\/span>\r\n<p style=\"text-align: center;\">[latex] 5\\sqrt{7}-8\\sqrt[4]{11}+\\sqrt{7}+3\\sqrt[4]{11}[\/latex]<\/p>\r\n<span class=\"TextRun SCXW213089253 BCX0\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun SCXW213089253 BCX0\">Combine like radicals; Note that [latex]\\sqrt{7}=1\\sqrt{7}[\/latex].<\/span><\/span>\r\n<p style=\"text-align: center;\">[latex] =6\\sqrt{7}-5\\sqrt[4]{11}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n&nbsp;\r\n\r\nIn the following video, we show more examples of subtracting radical expressions when no simplifying is required.\r\n\r\nhttps:\/\/youtu.be\/77TR9HsPZ6M\r\n<h2 id=\"title1\">Subtract radicals that must be simplified first<\/h2>\r\n<div class=\"textbox exercises\">\r\n<h3>Example 9<\/h3>\r\nSimplify:\u00a0[latex] 3\\sqrt{45}-8\\sqrt{20}[\/latex]\r\n\r\n[reveal-answer q=\"667355\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"667355\"]\r\n\r\nPrime factor each radicand and identify pairs of identical factors.\r\n<p style=\"text-align: center;\">[latex] 3\\sqrt{45}-8\\sqrt{20}= 3\\sqrt{3\\cdot 3\\cdot 5}-8\\sqrt{2\\cdot 2\\cdot 5}[\/latex]<\/p>\r\n<p style=\"text-align: center;\">[latex] =3\\sqrt{3^2\\cdot 5}-8\\sqrt{2^2\\cdot 5}[\/latex]<\/p>\r\n<p style=\"text-align: center;\">[latex] =3\\cdot 3\\sqrt{5}-8\\cdot 2\\sqrt{5}[\/latex]<\/p>\r\n<span class=\"TextRun SCXW37180785 BCX0\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun SCXW37180785 BCX0\">Multiply factors outside each radical to simplify.<\/span><\/span>\r\n<p style=\"text-align: center;\">[latex] =9\\sqrt{5}-16\\sqrt{5}[\/latex]<\/p>\r\nNow that the radicals have been simplified, notice that we can now subtract like radicals.\r\n<p style=\"text-align: center;\">[latex] =-7\\sqrt{5}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n&nbsp;\r\n\r\nIn our last video, we show more examples of subtracting radicals that require simplifying.\r\n\r\nhttps:\/\/youtu.be\/6MogonN1PRQ\r\n<h2>Summary<\/h2>\r\nCombining radicals is possible when the index and the radicand of two or more radicals are the same. Radicals with the same index and radicand are known as like radicals. It is often helpful to treat radicals just as you would treat variables: like radicals can be added and subtracted in the same way that like variables can be added and subtracted. Sometimes, you will need to simplify a radical expression before it is possible to add or subtract like terms.","rendered":"<div class=\"textbox learning-objectives\">\n<h3>section 7.2 Learning Objectives<\/h3>\n<p><strong>7.2: Adding and Subtracting Radical Expressions<\/strong><\/p>\n<ul>\n<li>Identify like radicals<\/li>\n<li>Simplify an expression by adding and subtracting like radicals<\/li>\n<li>Add and subtract radicals that must be simplified first<\/li>\n<\/ul>\n<\/div>\n<p>&nbsp;<\/p>\n<h2 id=\"title1\">Identify like radicals<\/h2>\n<p>There are two keys to combining radicals by addition or subtraction: look at the <strong>index<\/strong>, and look at the <strong>radicand<\/strong>. If these are the same, then addition and subtraction are possible. If not, then you cannot combine the two radicals. In the graphic below, the index of the\u00a0expression [latex]12\\sqrt[3]{xy}[\/latex] is\u00a0[latex]3[\/latex] and the radicand is [latex]xy[\/latex].<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-3200\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/121\/2016\/07\/29230521\/Screen-Shot-2016-07-29-at-4.04.52-PM-300x141.png\" alt=\"Expression 12 cube root of x y. Two arrows point to parts of the expression. Arrow 1 to three is labeled index. Arrow 2 to x y is labeled radicand.\" width=\"511\" height=\"240\" \/><\/p>\n<p>Making sense of a string of radicals may be difficult. One helpful tip is to think of radicals as variables, and treat them the same way. When you add and subtract variables, you look for like terms, which is the same thing you will do when you add and subtract radicals.<\/p>\n<p>In this first example, both radicals have the same radicand and index.<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Example 1<\/h3>\n<p>Add. [latex]3\\sqrt{11}+7\\sqrt{11}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q971281\">Show Solution<\/span><\/p>\n<div id=\"q971281\" class=\"hidden-answer\" style=\"display: none\">\n<p>The two radicals are the same, [latex][\/latex]. This means you can combine them as you would combine the terms [latex]3a+7a[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]\\text{3}\\sqrt{11}\\text{ + 7}\\sqrt{11}[\/latex]<\/p>\n<p>The answer is [latex]10\\sqrt{11}[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<h2 id=\"title1\">Simplify an expression by adding like radicals<\/h2>\n<p>This next example contains more addends, or terms that are being added together. Notice how you can combine <i>like<\/i> terms (radicals that have the same root and index), but you cannot combine <i>unlike<\/i> terms.<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Example 2<\/h3>\n<p>Add. [latex]5\\sqrt{2}+\\sqrt{3}+4\\sqrt{3}+2\\sqrt{2}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q687881\">Show Solution<\/span><\/p>\n<div id=\"q687881\" class=\"hidden-answer\" style=\"display: none\">\n<p>Rearrange terms so that like radicals are next to each other. Then add.<\/p>\n<p style=\"text-align: center;\">[latex]5\\sqrt{2}+2\\sqrt{2}+\\sqrt{3}+4\\sqrt{3}[\/latex]<\/p>\n<p>The answer is [latex]7\\sqrt{2}+5\\sqrt{3}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>Notice that the expression in the previous example is simplified even though it has two terms: [latex]7\\sqrt{2}[\/latex] and [latex]5\\sqrt{3}[\/latex]. It would be a mistake to try to combine them further! Some people make the mistake that [latex]7\\sqrt{2}+5\\sqrt{3}=12\\sqrt{5}[\/latex]. This is incorrect because[latex]\\sqrt{2}[\/latex] and [latex]\\sqrt{3}[\/latex] are not like radicals so they cannot be added.<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Example 3<\/h3>\n<p>Add. [latex]3\\sqrt{5}+12\\sqrt[3]{7}+\\sqrt{5}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q885242\">Show Solution<\/span><\/p>\n<div id=\"q885242\" class=\"hidden-answer\" style=\"display: none\">\n<p>Rearrange terms so that like radicals are next to each other. Then add.<\/p>\n<p style=\"text-align: center;\">[latex]3\\sqrt{5}+\\sqrt{5}+12\\sqrt[3]{7}[\/latex]<\/p>\n<p>The answer is [latex]4\\sqrt{5}+12\\sqrt[3]{7}[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>In the following video, we show more examples of how to identify and add like radicals.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Adding Radicals (Basic With No Simplifying)\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/ihcZhgm3yBg?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<h2 id=\"title1\">Add radicals that must be simplified first<\/h2>\n<p>Sometimes you may need to add <i>and<\/i> simplify the radical. If the radicals are different, try simplifying first\u2014you may end up being able to combine the radicals at the end as shown in these next two examples.<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Example 4<\/h3>\n<p>Add and simplify. [latex]2\\sqrt[3]{40}+\\sqrt[3]{135}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q638886\">Show Solution<\/span><\/p>\n<div id=\"q638886\" class=\"hidden-answer\" style=\"display: none\">\n<p>Simplify each radical by identifying perfect cubes.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{r}=2\\sqrt[3]{8\\cdot 5}+\\sqrt[3]{27\\cdot 5}\\\\=2\\sqrt[3]{{{(2)}^{3}}\\cdot 5}+\\sqrt[3]{{{(3)}^{3}}\\cdot 5}\\\\=2\\sqrt[3]{{{(2)}^{3}}}\\cdot \\sqrt[3]{5}+\\sqrt[3]{{{(3)}^{3}}}\\cdot \\sqrt[3]{5}\\end{array}[\/latex]<\/p>\n<p>Simplify.<\/p>\n<p style=\"text-align: center;\">[latex]=2\\cdot 2\\cdot \\sqrt[3]{5}+3\\cdot \\sqrt[3]{5}[\/latex]<\/p>\n<p style=\"text-align: center;\">[latex]=4\\sqrt[3]{5}+3\\sqrt[3]{5}[\/latex]<\/p>\n<p>The answer is [latex]7\\sqrt[3]{5}[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<h3>Example 5<\/h3>\n<p><span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">Simplify: [latex]\\sqrt{12}+\\sqrt{27}[\/latex]<\/span><\/span><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q690208\">Show Answer<\/span><\/p>\n<div id=\"q690208\" class=\"hidden-answer\" style=\"display: none\">\n<div style=\"font-weight: 400;\">\n<p>As written, these two radicals cannot be added because they are not like radicals.\u00a0 We\u00a0<span style=\"font-size: 1rem; text-align: initial;\">need to simplify both radicals first.\u00a0<\/span><\/p>\n<p><span class=\"TextRun BCX0 SCXW233914761\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW233914761\">Prime factor each radicand.<\/span><\/span><\/p>\n<p style=\"text-align: center;\"><span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">[latex]\\sqrt{12}+\\sqrt{27}=\\sqrt{2\\cdot 2\\cdot 3} + \\sqrt{3\\cdot 3\\cdot 3}[\/latex]<\/span><\/span><\/p>\n<p><span class=\"TextRun BCX0 SCXW30173351\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW30173351\">Identify pairs of identical factors and simplify.<\/span><\/span><\/p>\n<p style=\"text-align: center;\"><span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">[latex]=\\sqrt{2^2\\cdot 3} + \\sqrt{3^2\\cdot 3}[\/latex]<\/span><\/span><\/p>\n<p style=\"text-align: center;\"><span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">[latex]=2\\sqrt{3} + 3\\sqrt{3}[\/latex]<\/span><\/span><\/p>\n<p><span class=\"TextRun SCXW39848252 BCX0\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun SCXW39848252 BCX0\">In simplified form, we have like radicals and can add.<\/span><\/span><\/p>\n<p style=\"text-align: center;\"><span class=\"TextRun BCX0 SCXW32395191\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun BCX0 SCXW32395191\">[latex]=5\\sqrt{3}[\/latex]<\/span><\/span><\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<p>The following video shows more examples of adding radicals that require simplification.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Adding Radicals That Requires Simplifying\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/S3fGUeALy7E?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<h2>Simplify an expression by subtracting like radicals<\/h2>\n<p>Subtraction of radicals follows the same set of rules and approaches as addition\u2014the radicands and the indices must be the same for two (or more) radicals to be subtracted.<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Example 6<\/h3>\n<p>Subtract. [latex]5\\sqrt{13}-3\\sqrt{13}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q107411\">Show Solution<\/span><\/p>\n<div id=\"q107411\" class=\"hidden-answer\" style=\"display: none\">\n<p>The radicands and indices are the same, so these two radicals can be combined.<\/p>\n<p style=\"text-align: center;\">[latex]5\\sqrt{13}-3\\sqrt{13}[\/latex]<\/p>\n<p style=\"text-align: center;\">The answer is [latex]=2\\sqrt{13}[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"bcc-box bcc-info\">\n<h3>Example 7<\/h3>\n<p>Subtract. [latex]4\\sqrt[3]{5}-\\sqrt[3]{3}-2\\sqrt[3]{5}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q491962\">Show Solution<\/span><\/p>\n<div id=\"q491962\" class=\"hidden-answer\" style=\"display: none\">\n<p>Two of the radicals have the same index and radicand, so they can be combined. Rewrite the expression so that like radicals are next to each other.<\/p>\n<p style=\"text-align: center;\">[latex]\\begin{array}{r} 4\\sqrt[3]{5}+(-\\sqrt[3]{3})+(-2\\sqrt[3]{5})\\\\=4\\sqrt[3]{5}+(-2\\sqrt[3]{5})+(-\\sqrt[3]{3})\\end{array}[\/latex]<\/p>\n<p>Combine. Although the indices of [latex]2\\sqrt[3]{5}[\/latex] and [latex]-\\sqrt[3]{3}[\/latex] are the same, the radicands are not\u2014so they cannot be combined.<\/p>\n<p style=\"text-align: center;\">[latex]=2\\sqrt[3]{5}+(-\\sqrt[3]{3})[\/latex]<\/p>\n<p>The answer is [latex]2\\sqrt[3]{5}-\\sqrt[3]{3}[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<h3>Example 8<\/h3>\n<p>Simplify:\u00a0[latex]5\\sqrt{7}-8\\sqrt[4]{11}+\\sqrt{7}+3\\sqrt[4]{11}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q780228\">Show Answer<\/span><\/p>\n<div id=\"q780228\" class=\"hidden-answer\" style=\"display: none\">\n<p><span class=\"TextRun SCXW37945795 BCX0\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun SCXW37945795 BCX0\">Notice, the radical terms are already in simplest form.<\/span><\/span><span class=\"EOP SCXW37945795 BCX0\">\u00a0<\/span><\/p>\n<p style=\"text-align: center;\">[latex]5\\sqrt{7}-8\\sqrt[4]{11}+\\sqrt{7}+3\\sqrt[4]{11}[\/latex]<\/p>\n<p><span class=\"TextRun SCXW213089253 BCX0\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun SCXW213089253 BCX0\">Combine like radicals; Note that [latex]\\sqrt{7}=1\\sqrt{7}[\/latex].<\/span><\/span><\/p>\n<p style=\"text-align: center;\">[latex]=6\\sqrt{7}-5\\sqrt[4]{11}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<p>In the following video, we show more examples of subtracting radical expressions when no simplifying is required.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-3\" title=\"Subtracting Radicals (Basic With No Simplifying)\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/77TR9HsPZ6M?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<h2 id=\"title1\">Subtract radicals that must be simplified first<\/h2>\n<div class=\"textbox exercises\">\n<h3>Example 9<\/h3>\n<p>Simplify:\u00a0[latex]3\\sqrt{45}-8\\sqrt{20}[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q667355\">Show Answer<\/span><\/p>\n<div id=\"q667355\" class=\"hidden-answer\" style=\"display: none\">\n<p>Prime factor each radicand and identify pairs of identical factors.<\/p>\n<p style=\"text-align: center;\">[latex]3\\sqrt{45}-8\\sqrt{20}= 3\\sqrt{3\\cdot 3\\cdot 5}-8\\sqrt{2\\cdot 2\\cdot 5}[\/latex]<\/p>\n<p style=\"text-align: center;\">[latex]=3\\sqrt{3^2\\cdot 5}-8\\sqrt{2^2\\cdot 5}[\/latex]<\/p>\n<p style=\"text-align: center;\">[latex]=3\\cdot 3\\sqrt{5}-8\\cdot 2\\sqrt{5}[\/latex]<\/p>\n<p><span class=\"TextRun SCXW37180785 BCX0\" lang=\"EN-US\" xml:lang=\"EN-US\"><span class=\"NormalTextRun SCXW37180785 BCX0\">Multiply factors outside each radical to simplify.<\/span><\/span><\/p>\n<p style=\"text-align: center;\">[latex]=9\\sqrt{5}-16\\sqrt{5}[\/latex]<\/p>\n<p>Now that the radicals have been simplified, notice that we can now subtract like radicals.<\/p>\n<p style=\"text-align: center;\">[latex]=-7\\sqrt{5}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<p>In our last video, we show more examples of subtracting radicals that require simplifying.<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-4\" title=\"Subtracting Radicals That Requires Simplifying\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/6MogonN1PRQ?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<h2>Summary<\/h2>\n<p>Combining radicals is possible when the index and the radicand of two or more radicals are the same. Radicals with the same index and radicand are known as like radicals. It is often helpful to treat radicals just as you would treat variables: like radicals can be added and subtracted in the same way that like variables can be added and subtracted. Sometimes, you will need to simplify a radical expression before it is possible to add or subtract like terms.<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-6806\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li>Adding Radicals (Basic With No Simplifying). <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com) for Lumen Learning. <strong>Provided by<\/strong>: Lumen Learning. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/ihcZhgm3yBg\">https:\/\/youtu.be\/ihcZhgm3yBg<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Adding Radicals That Requires Simplifying. <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com) for Lumen Learning. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/S3fGUeALy7E\">https:\/\/youtu.be\/S3fGUeALy7E<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Subtracting Radicals (Basic With No Simplifying). <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com) for Lumen Learning. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/77TR9HsPZ6M\">https:\/\/youtu.be\/77TR9HsPZ6M<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Subtracting Radicals That Requires Simplifying. <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com) for Lumen Learning. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/youtu.be\/6MogonN1PRQ\">https:\/\/youtu.be\/6MogonN1PRQ<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":348856,"menu_order":3,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"Adding Radicals (Basic With No Simplifying)\",\"author\":\"James Sousa (Mathispower4u.com) for Lumen Learning\",\"organization\":\"Lumen Learning\",\"url\":\"https:\/\/youtu.be\/ihcZhgm3yBg\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"original\",\"description\":\"Adding Radicals That Requires Simplifying\",\"author\":\"James Sousa (Mathispower4u.com) for Lumen Learning\",\"organization\":\"\",\"url\":\"https:\/\/youtu.be\/S3fGUeALy7E\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"original\",\"description\":\"Subtracting Radicals (Basic With No Simplifying)\",\"author\":\"James Sousa (Mathispower4u.com) for Lumen Learning\",\"organization\":\"\",\"url\":\"https:\/\/youtu.be\/77TR9HsPZ6M\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"original\",\"description\":\"Subtracting Radicals That Requires Simplifying\",\"author\":\"James Sousa (Mathispower4u.com) for Lumen Learning\",\"organization\":\"\",\"url\":\"https:\/\/youtu.be\/6MogonN1PRQ\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-6806","chapter","type-chapter","status-publish","hentry"],"part":1053,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/pressbooks\/v2\/chapters\/6806","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/wp\/v2\/users\/348856"}],"version-history":[{"count":14,"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/pressbooks\/v2\/chapters\/6806\/revisions"}],"predecessor-version":[{"id":9668,"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/pressbooks\/v2\/chapters\/6806\/revisions\/9668"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/pressbooks\/v2\/parts\/1053"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/pressbooks\/v2\/chapters\/6806\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/wp\/v2\/media?parent=6806"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/pressbooks\/v2\/chapter-type?post=6806"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/wp\/v2\/contributor?post=6806"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/slcc-elementaryalgebra\/wp-json\/wp\/v2\/license?post=6806"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}