{"id":1045,"date":"2017-01-10T20:54:46","date_gmt":"2017-01-10T20:54:46","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/waymakermath4libarts\/?post_type=chapter&p=1045"},"modified":"2021-02-05T23:55:08","modified_gmt":"2021-02-05T23:55:08","slug":"putting-it-together-voting-theory","status":"web-only","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/chapter\/putting-it-together-voting-theory\/","title":{"raw":"Putting It Together: Voting Theory","rendered":"Putting It Together: Voting Theory"},"content":{"raw":"There are four candidates for senior class president, Garcia, Lee, Nguyen, and Smith. \u00a0Using a preference ballot, [latex]75[\/latex] ballots were cast, and the votes are shown below.\r\n
\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n
<\/td>\r\n[latex]20[\/latex]<\/td>\r\n[latex]3[\/latex]<\/td>\r\n[latex]8[\/latex]<\/td>\r\n[latex]16[\/latex]<\/td>\r\n[latex]28[\/latex]<\/td>\r\n<\/tr>\r\n
1st choice<\/td>\r\nGarcia<\/td>\r\nGarcia<\/td>\r\nLee<\/td>\r\nNguyen<\/td>\r\nSmith<\/td>\r\n<\/tr>\r\n
2nd choice<\/td>\r\nLee<\/td>\r\nNguyen<\/td>\r\nNguyen<\/td>\r\nGarcia<\/td>\r\nLee<\/td>\r\n<\/tr>\r\n
3rd choice<\/td>\r\nNguyen<\/td>\r\nLee<\/td>\r\nGarcia<\/td>\r\nLee<\/td>\r\nGarcia<\/td>\r\n<\/tr>\r\n
4th choice<\/td>\r\nSmith<\/td>\r\nSmith<\/td>\r\nSmith<\/td>\r\nSmith<\/td>\r\nNguyen<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n \r\n

Now that the votes are in, it should be a simple matter to find out who won the election, right? <\/em><\/p>\r\n

Well that depends on which voting system you choose.<\/em><\/p>\r\n \r\n\r\nUsing plurality method, Smith wins. \u00a0This is because Smith got [latex]28[\/latex] first place votes, while Garcia received [latex]20+3=23[\/latex], Lee [latex]8[\/latex], and Nguyen [latex]16[\/latex]. \u00a0However, Smith was the very last choice for the majority of the students! \u00a0This seems rather unfair, so let\u2019s explore another method.\r\n\r\n \r\n\r\nThe Borda count assigns points based on the ranking: 4 points for first place, 3 for second, 2 for third, and 1 for last.\r\n

\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n
<\/td>\r\nGarcia<\/td>\r\nLee<\/td>\r\nNguyen<\/td>\r\nSmith<\/td>\r\n<\/tr>\r\n
1st choice (4 pts)<\/td>\r\n[latex]23\\times4=92[\/latex]<\/td>\r\n[latex]8\\times4=32[\/latex]<\/td>\r\n[latex]16\\times4=64[\/latex]<\/td>\r\n[latex]28\\times4=112[\/latex]<\/td>\r\n<\/tr>\r\n
2nd choice (3 pts)<\/td>\r\n[latex]16\\times3=48[\/latex]<\/td>\r\n[latex]48\\times3=144[\/latex]<\/td>\r\n[latex]11\\times3=33[\/latex]<\/td>\r\n[latex]0\\times3=0[\/latex]<\/td>\r\n<\/tr>\r\n
3rd choice (2 pts)<\/td>\r\n[latex]36\\times2=72[\/latex]<\/td>\r\n[latex]19\\times2=38[\/latex]<\/td>\r\n[latex]20\\times2=40[\/latex]<\/td>\r\n[latex]0\\times2=0[\/latex]<\/td>\r\n<\/tr>\r\n
4th choice (1 pt)<\/td>\r\n[latex]0\\times1=0[\/latex]<\/td>\r\n[latex]0\\times1=0[\/latex]<\/td>\r\n[latex]28\\times1=28[\/latex]<\/td>\r\n[latex]47\\times1=47[\/latex]<\/td>\r\n<\/tr>\r\n
Total\u00a0Points<\/td>\r\n[latex]212[\/latex]<\/td>\r\n[latex]214[\/latex]<\/td>\r\n[latex]165[\/latex]<\/td>\r\n[latex]159[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n \r\n\r\nThis time Smith comes in last and Lee is the winner. \u00a0However the preference votes indicate that Lee is a lukewarm choice for most people. \u00a0Only [latex]8[\/latex] students chose Lee as their first choice. \u00a0Perhaps another voting method will reflect the students\u2019 preferences better.\r\n\r\n \r\n\r\nLet\u2019s try instant runoff voting (IRV). \u00a0This method proceeds in rounds, eliminating the candidate with the least number of first place votes at each round (with votes redistributed to voters\u2019 next choices) until a majority winner emerges. \u00a0In the first round, Lee is immediately eliminated.\r\n
\r\n\r\n\r\n\r\n\r\n\r\n\r\n
<\/td>\r\n[latex]20+3=23[\/latex]<\/td>\r\n[latex]8+16=24[\/latex]<\/td>\r\n[latex]28[\/latex]<\/td>\r\n<\/tr>\r\n
1st choice<\/td>\r\nGarcia<\/td>\r\nNguyen<\/td>\r\nSmith<\/td>\r\n<\/tr>\r\n
2nd choice<\/td>\r\nNguyen<\/td>\r\nGarcia<\/td>\r\nGarcia<\/td>\r\n<\/tr>\r\n
3rd choice<\/td>\r\nSmith<\/td>\r\nSmith<\/td>\r\nNguyen<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\nThere is still no majority winner. \u00a0Garcia is eliminated next, which gives the election to Nguyen.\r\n
\r\n\r\n\r\n\r\n\r\n\r\n
<\/td>\r\n[latex]23+24=47[\/latex]<\/td>\r\n[latex]28[\/latex]<\/td>\r\n<\/tr>\r\n
1st choice<\/td>\r\nNguyen<\/td>\r\nSmith<\/td>\r\n<\/tr>\r\n
2nd choice<\/td>\r\nSmith<\/td>\r\nNguyen<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n \r\n\r\nFinally, let\u2019s see if there is a Condorcet winner. \u00a0We examine all one-on-one contests based on the original preference schedule. \u00a0The table below summarizes the results. \u00a0Each column shows the total number of ballots in which that candidate beats the candidate listed in each row. \u00a0Remember, a majority of the [latex]75[\/latex] votes would be at least [latex]38[\/latex] (majority votes are highlighted in blue).\r\n
\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n
<\/td>\r\nGarcia<\/td>\r\nLee<\/td>\r\nNguyen<\/td>\r\nSmith<\/td>\r\n<\/tr>\r\n
Garcia<\/td>\r\n<\/td>\r\n[latex]36[\/latex]<\/td>\r\n[latex]24[\/latex]<\/td>\r\n[latex]28[\/latex]<\/td>\r\n<\/tr>\r\n
Lee<\/td>\r\n[latex]39[\/latex]<\/td>\r\n<\/td>\r\n[latex]19[\/latex]<\/td>\r\n[latex]28[\/latex]<\/td>\r\n<\/tr>\r\n
Nguyen<\/td>\r\n[latex]51[\/latex]<\/td>\r\n[latex]56[\/latex]<\/td>\r\n<\/td>\r\n[latex]28[\/latex]<\/td>\r\n<\/tr>\r\n
Smith<\/td>\r\n[latex]47[\/latex]<\/td>\r\n[latex]47[\/latex]<\/td>\r\n[latex]47[\/latex]<\/td>\r\n<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\nGarcia is the Condorcet winner with [latex]39[\/latex], [latex]51[\/latex], and [latex]47[\/latex] votes against Lee, Nguyen, and Smith, respectively.\r\n\r\n \r\n\r\nWhich voting method do you think is the most fair? \u00a0The same voting preference schedule produced four different \u201cwinners.\u201d \u00a0In a close election with many competing preferences, perhaps there is no clear winner. \u00a0However a decision must be made.\r\n\r\n \r\n\r\nThis small example serves to show why understanding voting theory helps to put the election process in perspective. \u00a0At the end of the day, one voting method must be selected and the winner decided according to those agreed-upon rules. \u00a0Try out some other voting methods and see if you can make a case for who should be the senior class president!","rendered":"

There are four candidates for senior class president, Garcia, Lee, Nguyen, and Smith. \u00a0Using a preference ballot, [latex]75[\/latex] ballots were cast, and the votes are shown below.<\/p>\n

\n\n\n\n\n\n\n\n
<\/td>\n[latex]20[\/latex]<\/td>\n[latex]3[\/latex]<\/td>\n[latex]8[\/latex]<\/td>\n[latex]16[\/latex]<\/td>\n[latex]28[\/latex]<\/td>\n<\/tr>\n
1st choice<\/td>\nGarcia<\/td>\nGarcia<\/td>\nLee<\/td>\nNguyen<\/td>\nSmith<\/td>\n<\/tr>\n
2nd choice<\/td>\nLee<\/td>\nNguyen<\/td>\nNguyen<\/td>\nGarcia<\/td>\nLee<\/td>\n<\/tr>\n
3rd choice<\/td>\nNguyen<\/td>\nLee<\/td>\nGarcia<\/td>\nLee<\/td>\nGarcia<\/td>\n<\/tr>\n
4th choice<\/td>\nSmith<\/td>\nSmith<\/td>\nSmith<\/td>\nSmith<\/td>\nNguyen<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

 <\/p>\n

Now that the votes are in, it should be a simple matter to find out who won the election, right? <\/em><\/p>\n

Well that depends on which voting system you choose.<\/em><\/p>\n

 <\/p>\n

Using plurality method, Smith wins. \u00a0This is because Smith got [latex]28[\/latex] first place votes, while Garcia received [latex]20+3=23[\/latex], Lee [latex]8[\/latex], and Nguyen [latex]16[\/latex]. \u00a0However, Smith was the very last choice for the majority of the students! \u00a0This seems rather unfair, so let\u2019s explore another method.<\/p>\n

 <\/p>\n

The Borda count assigns points based on the ranking: 4 points for first place, 3 for second, 2 for third, and 1 for last.<\/p>\n

\n\n\n\n\n\n\n\n\n
<\/td>\nGarcia<\/td>\nLee<\/td>\nNguyen<\/td>\nSmith<\/td>\n<\/tr>\n
1st choice (4 pts)<\/td>\n[latex]23\\times4=92[\/latex]<\/td>\n[latex]8\\times4=32[\/latex]<\/td>\n[latex]16\\times4=64[\/latex]<\/td>\n[latex]28\\times4=112[\/latex]<\/td>\n<\/tr>\n
2nd choice (3 pts)<\/td>\n[latex]16\\times3=48[\/latex]<\/td>\n[latex]48\\times3=144[\/latex]<\/td>\n[latex]11\\times3=33[\/latex]<\/td>\n[latex]0\\times3=0[\/latex]<\/td>\n<\/tr>\n
3rd choice (2 pts)<\/td>\n[latex]36\\times2=72[\/latex]<\/td>\n[latex]19\\times2=38[\/latex]<\/td>\n[latex]20\\times2=40[\/latex]<\/td>\n[latex]0\\times2=0[\/latex]<\/td>\n<\/tr>\n
4th choice (1 pt)<\/td>\n[latex]0\\times1=0[\/latex]<\/td>\n[latex]0\\times1=0[\/latex]<\/td>\n[latex]28\\times1=28[\/latex]<\/td>\n[latex]47\\times1=47[\/latex]<\/td>\n<\/tr>\n
Total\u00a0Points<\/td>\n[latex]212[\/latex]<\/td>\n[latex]214[\/latex]<\/td>\n[latex]165[\/latex]<\/td>\n[latex]159[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

 <\/p>\n

This time Smith comes in last and Lee is the winner. \u00a0However the preference votes indicate that Lee is a lukewarm choice for most people. \u00a0Only [latex]8[\/latex] students chose Lee as their first choice. \u00a0Perhaps another voting method will reflect the students\u2019 preferences better.<\/p>\n

 <\/p>\n

Let\u2019s try instant runoff voting (IRV). \u00a0This method proceeds in rounds, eliminating the candidate with the least number of first place votes at each round (with votes redistributed to voters\u2019 next choices) until a majority winner emerges. \u00a0In the first round, Lee is immediately eliminated.<\/p>\n

\n\n\n\n\n\n\n
<\/td>\n[latex]20+3=23[\/latex]<\/td>\n[latex]8+16=24[\/latex]<\/td>\n[latex]28[\/latex]<\/td>\n<\/tr>\n
1st choice<\/td>\nGarcia<\/td>\nNguyen<\/td>\nSmith<\/td>\n<\/tr>\n
2nd choice<\/td>\nNguyen<\/td>\nGarcia<\/td>\nGarcia<\/td>\n<\/tr>\n
3rd choice<\/td>\nSmith<\/td>\nSmith<\/td>\nNguyen<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

There is still no majority winner. \u00a0Garcia is eliminated next, which gives the election to Nguyen.<\/p>\n

\n\n\n\n\n\n
<\/td>\n[latex]23+24=47[\/latex]<\/td>\n[latex]28[\/latex]<\/td>\n<\/tr>\n
1st choice<\/td>\nNguyen<\/td>\nSmith<\/td>\n<\/tr>\n
2nd choice<\/td>\nSmith<\/td>\nNguyen<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

 <\/p>\n

Finally, let\u2019s see if there is a Condorcet winner. \u00a0We examine all one-on-one contests based on the original preference schedule. \u00a0The table below summarizes the results. \u00a0Each column shows the total number of ballots in which that candidate beats the candidate listed in each row. \u00a0Remember, a majority of the [latex]75[\/latex] votes would be at least [latex]38[\/latex] (majority votes are highlighted in blue).<\/p>\n

\n\n\n\n\n\n\n\n
<\/td>\nGarcia<\/td>\nLee<\/td>\nNguyen<\/td>\nSmith<\/td>\n<\/tr>\n
Garcia<\/td>\n<\/td>\n[latex]36[\/latex]<\/td>\n[latex]24[\/latex]<\/td>\n[latex]28[\/latex]<\/td>\n<\/tr>\n
Lee<\/td>\n[latex]39[\/latex]<\/td>\n<\/td>\n[latex]19[\/latex]<\/td>\n[latex]28[\/latex]<\/td>\n<\/tr>\n
Nguyen<\/td>\n[latex]51[\/latex]<\/td>\n[latex]56[\/latex]<\/td>\n<\/td>\n[latex]28[\/latex]<\/td>\n<\/tr>\n
Smith<\/td>\n[latex]47[\/latex]<\/td>\n[latex]47[\/latex]<\/td>\n[latex]47[\/latex]<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n

Garcia is the Condorcet winner with [latex]39[\/latex], [latex]51[\/latex], and [latex]47[\/latex] votes against Lee, Nguyen, and Smith, respectively.<\/p>\n

 <\/p>\n

Which voting method do you think is the most fair? \u00a0The same voting preference schedule produced four different \u201cwinners.\u201d \u00a0In a close election with many competing preferences, perhaps there is no clear winner. \u00a0However a decision must be made.<\/p>\n

 <\/p>\n

This small example serves to show why understanding voting theory helps to put the election process in perspective. \u00a0At the end of the day, one voting method must be selected and the winner decided according to those agreed-upon rules. \u00a0Try out some other voting methods and see if you can make a case for who should be the senior class president!<\/p>\n","protected":false},"author":21,"menu_order":23,"template":"","meta":{"_candela_citation":"","CANDELA_OUTCOMES_GUID":"","pb_show_title":"","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1045","chapter","type-chapter","status-web-only","hentry"],"part":1040,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/pressbooks\/v2\/chapters\/1045","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/wp\/v2\/users\/21"}],"version-history":[{"count":12,"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/pressbooks\/v2\/chapters\/1045\/revisions"}],"predecessor-version":[{"id":2395,"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/pressbooks\/v2\/chapters\/1045\/revisions\/2395"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/pressbooks\/v2\/parts\/1040"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/pressbooks\/v2\/chapters\/1045\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/wp\/v2\/media?parent=1045"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/pressbooks\/v2\/chapter-type?post=1045"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/wp\/v2\/contributor?post=1045"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/slcc-mathforliberalartscorequisite\/wp-json\/wp\/v2\/license?post=1045"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}