{"id":6692,"date":"2018-03-27T19:29:03","date_gmt":"2018-03-27T19:29:03","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/?post_type=chapter&#038;p=6692"},"modified":"2018-06-04T15:26:47","modified_gmt":"2018-06-04T15:26:47","slug":"solving-formulas-or-equations-for-a-specific-variable","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/chapter\/solving-formulas-or-equations-for-a-specific-variable\/","title":{"raw":"0.7 Solving Formulas or Equations for a Specific Variable","rendered":"0.7 Solving Formulas or Equations for a Specific Variable"},"content":{"raw":"[embed]https:\/\/youtu.be\/eDbQOeLrCNc[\/embed]\r\n<h2><b class=\"calibre3\">Solve a Formula for a Specific Variable<\/b><\/h2>\r\n<p class=\"calibre1\">We have all probably worked with some geometric formulas in our study of mathematics. Formulas are used in so many fields, it is important to recognize formulas and be able to manipulate them easily.<\/p>\r\n<p class=\"calibre1\">It is often helpful to solve a formula for a specific variable. If you need to put a formula in a spreadsheet, it is not unusual to have to solve it for a specific variable first. We isolate that variable on one side of the equals sign with a coefficient of one and all other variables and constants are on the other side of the equal sign.\u00a0 The properties of equalities from the previous page will be used to isolate specific variables from an equation or formula.<\/p>\r\n<p class=\"calibre1\">Geometric formulas often need to be solved for another variable, too. The formula [latex]V = \\frac{1}{3}\u03c0r^{2}h[\/latex]<i class=\"calibre4\">\u00a0<\/i> is used to find the volume of a right circular cone when given the radius of the base and height. In the next example, we will solve this formula for the height.<\/p>\r\n\r\n<div class=\"textbox exercises\">\r\n<h3>Example<\/h3>\r\nSolve the formula [latex]V = \\frac{1}{3}\u03c0r^{2}h[\/latex] for <em>h<\/em>.\r\n\r\n[reveal-answer q=\"319457\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"319457\"]\r\n\r\n<a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27192705\/volume2.jpg\"><img class=\"alignnone wp-image-8606 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27192705\/volume2.jpg\" alt=\"\" width=\"890\" height=\"373\" \/><\/a>\r\n\r\n&nbsp;\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<p class=\"calibre1\">In the sciences, we often need to change temperature from Fahrenheit to Celsius or vice versa. If you travel in a foreign country, you may want to change the Celsius temperature to the more familiar Fahrenheit temperature.<\/p>\r\n\r\n<div class=\"textbox exercises\">\r\n<h3>Examples<\/h3>\r\nSolve the formula [latex]C=\\frac{5}{9}(F-32)[\/latex] for F\r\n\r\n[reveal-answer q=\"649826\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"649826\"]\r\n<p class=\"calibre1\">Write the formula.<img class=\"calibre2 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/19231216\/index-141_2.png\" alt=\"image\" \/><\/p>\r\n<p class=\"calibre1\">Remove the fraction on the right.<img class=\"calibre2 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/19231217\/index-141_3.png\" alt=\"image\" \/><\/p>\r\n<p class=\"calibre1\">Simplify.<img class=\"calibre2 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/19231219\/index-141_4.png\" alt=\"image\" \/><\/p>\r\n<p class=\"calibre1\">Add 32 to both sides.<img class=\"calibre2 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/19231220\/index-141_5.png\" alt=\"image\" \/><\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nWe can now use the formula [latex]F=\\frac{9}{5}C+32[\/latex] to find the Fahrenheit temperature when you are given the Celsius temperature.\r\n\r\nThe next example uses the formula for the surface area of a right cylinder.\r\n<div class=\"textbox exercises\">\r\n<h3>Examples<\/h3>\r\nSolve the formula [latex] S = 2\u03c0r^2 + 2\u03c0rh [\/latex] for <em>h<\/em>.\r\n\r\n[reveal-answer q=\"784310\"]Show Solution[\/reveal-answer]\r\n\r\n[hidden-answer a=\"784310\"]<a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27181817\/cylinder2.jpg\"><img class=\"aligncenter wp-image-8595 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27181817\/cylinder2.jpg\" alt=\"\" width=\"735\" height=\"234\" \/><\/a>[\/hidden-answer]\r\n\r\n<\/div>\r\nSometimes we might be given an equation that is solved for [latex]y[\/latex] and needs to be solved for [latex]x[\/latex] or vice versa.\u00a0 In the following example, we are given an equation with both [latex]x[\/latex] and [latex]y[\/latex] on the same side to be solved for [latex]y[\/latex].\r\n<div class=\"textbox exercises\">\r\n<h3>Example<\/h3>\r\nSolve the formula 8[latex]x[\/latex] + 7[latex]y[\/latex] = 15 for [latex]y[\/latex]\r\n\r\n[reveal-answer q=\"576705\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"576705\"]\r\n\r\n<a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27191352\/Picture1.jpg\"><img class=\"alignnone wp-image-8602 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27191352\/Picture1.jpg\" alt=\"\" width=\"1350\" height=\"343\" \/><\/a>\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n&nbsp;","rendered":"<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"General Chemistry Lecture 0.7 Solving Formulas or Equations for a Specific Variable\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/eDbQOeLrCNc?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<h2><b class=\"calibre3\">Solve a Formula for a Specific Variable<\/b><\/h2>\n<p class=\"calibre1\">We have all probably worked with some geometric formulas in our study of mathematics. Formulas are used in so many fields, it is important to recognize formulas and be able to manipulate them easily.<\/p>\n<p class=\"calibre1\">It is often helpful to solve a formula for a specific variable. If you need to put a formula in a spreadsheet, it is not unusual to have to solve it for a specific variable first. We isolate that variable on one side of the equals sign with a coefficient of one and all other variables and constants are on the other side of the equal sign.\u00a0 The properties of equalities from the previous page will be used to isolate specific variables from an equation or formula.<\/p>\n<p class=\"calibre1\">Geometric formulas often need to be solved for another variable, too. The formula [latex]V = \\frac{1}{3}\u03c0r^{2}h[\/latex]<i class=\"calibre4\">\u00a0<\/i> is used to find the volume of a right circular cone when given the radius of the base and height. In the next example, we will solve this formula for the height.<\/p>\n<div class=\"textbox exercises\">\n<h3>Example<\/h3>\n<p>Solve the formula [latex]V = \\frac{1}{3}\u03c0r^{2}h[\/latex] for <em>h<\/em>.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q319457\">Show Solution<\/span><\/p>\n<div id=\"q319457\" class=\"hidden-answer\" style=\"display: none\">\n<p><a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27192705\/volume2.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-8606 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27192705\/volume2.jpg\" alt=\"\" width=\"890\" height=\"373\" \/><\/a><\/p>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p class=\"calibre1\">In the sciences, we often need to change temperature from Fahrenheit to Celsius or vice versa. If you travel in a foreign country, you may want to change the Celsius temperature to the more familiar Fahrenheit temperature.<\/p>\n<div class=\"textbox exercises\">\n<h3>Examples<\/h3>\n<p>Solve the formula [latex]C=\\frac{5}{9}(F-32)[\/latex] for F<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q649826\">Show Solution<\/span><\/p>\n<div id=\"q649826\" class=\"hidden-answer\" style=\"display: none\">\n<p class=\"calibre1\">Write the formula.<img decoding=\"async\" class=\"calibre2 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/19231216\/index-141_2.png\" alt=\"image\" \/><\/p>\n<p class=\"calibre1\">Remove the fraction on the right.<img decoding=\"async\" class=\"calibre2 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/19231217\/index-141_3.png\" alt=\"image\" \/><\/p>\n<p class=\"calibre1\">Simplify.<img decoding=\"async\" class=\"calibre2 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/19231219\/index-141_4.png\" alt=\"image\" \/><\/p>\n<p class=\"calibre1\">Add 32 to both sides.<img decoding=\"async\" class=\"calibre2 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/19231220\/index-141_5.png\" alt=\"image\" \/><\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>We can now use the formula [latex]F=\\frac{9}{5}C+32[\/latex] to find the Fahrenheit temperature when you are given the Celsius temperature.<\/p>\n<p>The next example uses the formula for the surface area of a right cylinder.<\/p>\n<div class=\"textbox exercises\">\n<h3>Examples<\/h3>\n<p>Solve the formula [latex]S = 2\u03c0r^2 + 2\u03c0rh[\/latex] for <em>h<\/em>.<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q784310\">Show Solution<\/span><\/p>\n<div id=\"q784310\" class=\"hidden-answer\" style=\"display: none\"><a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27181817\/cylinder2.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-8595 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27181817\/cylinder2.jpg\" alt=\"\" width=\"735\" height=\"234\" \/><\/a><\/div>\n<\/div>\n<\/div>\n<p>Sometimes we might be given an equation that is solved for [latex]y[\/latex] and needs to be solved for [latex]x[\/latex] or vice versa.\u00a0 In the following example, we are given an equation with both [latex]x[\/latex] and [latex]y[\/latex] on the same side to be solved for [latex]y[\/latex].<\/p>\n<div class=\"textbox exercises\">\n<h3>Example<\/h3>\n<p>Solve the formula 8[latex]x[\/latex] + 7[latex]y[\/latex] = 15 for [latex]y[\/latex]<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q576705\">Show Answer<\/span><\/p>\n<div id=\"q576705\" class=\"hidden-answer\" style=\"display: none\">\n<p><a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27191352\/Picture1.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-8602 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2651\/2018\/03\/27191352\/Picture1.jpg\" alt=\"\" width=\"1350\" height=\"343\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-6692\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li>OpenStax Intermediate Algebra Textbook. <strong>Authored by<\/strong>: Lynn Marecek, Santa Ana College. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/openstax.org\/details\/intermediate-algebra#details\">https:\/\/openstax.org\/details\/intermediate-algebra#details<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Intermediate Algebra by OpenStax is licensed under Creative Commons Attribution License v4.0<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":80958,"menu_order":7,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"OpenStax Intermediate Algebra Textbook\",\"author\":\"Lynn Marecek, Santa Ana College\",\"organization\":\"OpenStax\",\"url\":\"https:\/\/openstax.org\/details\/intermediate-algebra#details\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Intermediate Algebra by OpenStax is licensed under Creative Commons Attribution License v4.0\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-6692","chapter","type-chapter","status-publish","hentry"],"part":6254,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/pressbooks\/v2\/chapters\/6692","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/wp\/v2\/users\/80958"}],"version-history":[{"count":38,"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/pressbooks\/v2\/chapters\/6692\/revisions"}],"predecessor-version":[{"id":8804,"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/pressbooks\/v2\/chapters\/6692\/revisions\/8804"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/pressbooks\/v2\/parts\/6254"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/pressbooks\/v2\/chapters\/6692\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/wp\/v2\/media?parent=6692"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=6692"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/wp\/v2\/contributor?post=6692"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-albany-chemistry\/wp-json\/wp\/v2\/license?post=6692"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}