{"id":1546,"date":"2015-04-22T16:30:29","date_gmt":"2015-04-22T16:30:29","guid":{"rendered":"https:\/\/courses.candelalearning.com\/oschemtemp\/?post_type=chapter&#038;p=1546"},"modified":"2015-08-27T21:44:04","modified_gmt":"2015-08-27T21:44:04","slug":"measurement-uncertainty-accuracy-and-precision-2-formulas-not-parsing","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/chapter\/measurement-uncertainty-accuracy-and-precision-2-formulas-not-parsing\/","title":{"raw":"Measurement Uncertainty, Accuracy, and Precision","rendered":"Measurement Uncertainty, Accuracy, and Precision"},"content":{"raw":"<div class=\"bcc-box bcc-highlight\">\r\n<h3>LEARNING OBJECTIVES<\/h3>\r\nBy the end of this section, you will be able to:\r\n<ul>\r\n\t<li>Define accuracy and precision<\/li>\r\n\t<li>Distinguish exact and uncertain numbers<\/li>\r\n\t<li>Correctly represent uncertainty in quantities using significant figures<\/li>\r\n\t<li>Apply proper rounding rules to computed quantities<\/li>\r\n<\/ul>\r\n<\/div>\r\n<p id=\"fs-idm288863760\">Counting is the only type of measurement that is free from uncertainty, provided the number of objects being counted does not change while the counting process is underway. The result of such a counting measurement is an example of an <span data-type=\"term\">exact number<\/span>. If we count eggs in a carton, we know <em data-effect=\"italics\">exactly<\/em> how many eggs the carton contains. The numbers of defined quantities are also exact. By definition, 1 foot is exactly 12 inches, 1 inch is exactly 2.54 centimeters, and 1 gram is exactly 0.001 kilogram. Quantities derived from measurements other than counting, however, are uncertain to varying extents due to practical limitations of the measurement process used.<\/p>\r\n\r\n<section id=\"fs-idm217277536\" data-depth=\"1\">\r\n<h2 data-type=\"title\">Significant Figures in Measurement<\/h2>\r\n<p id=\"fs-idp11446448\">The numbers of measured quantities, unlike defined or directly counted quantities, are not exact. To measure the volume of liquid in a graduated cylinder, you should make a reading at the bottom of the meniscus, the lowest point on the curved surface of the liquid.<\/p>\r\n\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"880\"]<img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210939\/CNX_Chem_01_05_Measure1.jpg\" alt=\"This diagram shows a 25 milliliter graduated cylinder filled with about 20.8 milliliters of fluid. The diagram zooms in on the meniscus, which is the curved surface of the water that is visible when the graduated cylinder is viewed from the side. You make the reading at the lowest point of the curve of the meniscus.\" width=\"880\" height=\"503\" data-media-type=\"image\/jpeg\" \/> Figure 1. To measure the volume of liquid in this graduated cylinder, you must mentally subdivide the distance between the 21 and 22 mL marks into tenths of a milliliter, and then make a reading (estimate) at the bottom of the meniscus.[\/caption]\r\n<p id=\"fs-idm176542448\">Refer to the illustration in Figure 1. The bottom of the meniscus in this case clearly lies between the 21 and 22 markings, meaning the liquid volume is <em data-effect=\"italics\">certainly<\/em> greater than 21 mL but less than 22 mL. The meniscus appears to be a bit closer to the 22-mL mark than to the 21-mL mark, and so a reasonable estimate of the liquid\u2019s volume would be 21.6 mL. In the number 21.6, then, the digits 2 and 1 are certain, but the 6 is an estimate. Some people might estimate the meniscus position to be equally distant from each of the markings and estimate the tenth-place digit as 5, while others may think it to be even closer to the 22-mL mark and estimate this digit to be 7. Note that it would be pointless to attempt to estimate a digit for the hundredths place, given that the tenths-place digit is uncertain. In general, numerical scales such as the one on this graduated cylinder will permit measurements to one-tenth of the smallest scale division. The scale in this case has 1-mL divisions, and so volumes may be measured to the nearest 0.1 mL.<\/p>\r\n<p id=\"fs-idm254904560\">This concept holds true for all measurements, even if you do not actively make an estimate. If you place a quarter on a standard electronic balance, you may obtain a reading of 6.72 g. The digits 6 and 7 are certain, and the 2 indicates that the mass of the quarter is likely between 6.71 and 6.73 grams. The quarter weighs <em data-effect=\"italics\">about<\/em> 6.72 grams, with a nominal uncertainty in the measurement of \u00b1 0.01 gram. If we weigh the quarter on a more sensitive balance, we may find that its mass is 6.723 g. This means its mass lies between 6.722 and 6.724 grams, an uncertainty of 0.001 gram. Every measurement has some <strong><span data-type=\"term\">uncertainty<\/span><\/strong>, which depends on the device used (and the user\u2019s ability). All of the digits in a measurement, including the uncertain last digit, are called <strong><span data-type=\"term\">significant figures<\/span><\/strong> or <strong><span data-type=\"term\">significant digits<\/span><\/strong>. Note that zero may be a measured value; for example, if you stand on a scale that shows weight to the nearest pound and it shows \u201c120,\u201d then the 1 (hundreds), 2 (tens) and 0 (ones) are all significant (measured) values.<\/p>\r\n<p id=\"fs-idm264880544\">Whenever you make a measurement properly, all the digits in the result are significant. But what if you were analyzing a reported value and trying to determine what is significant and what is not? Well, for starters, all nonzero digits are significant, and it is only zeros that require some thought. We will use the terms \u201cleading,\u201d \u201ctrailing,\u201d and \u201ccaptive\u201d for the zeros and will consider how to deal with them.<\/p>\r\n<span id=\"fs-idm244068192\" data-type=\"media\" data-alt=\"The left diagram uses the example of 3090. The zero in the hundreds place is labeled \u201ccaptive\u201d and the zero in the ones place is labeled trailing. The right diagram uses the example 0.008020. The three zeros in the ones, tenths, and hundredths places are labeled \u201cleading.\u201d The zero in the ten-thousandths place is labeled \u201ccaptive\u201d and the zero in the millionths place is labeled \u201ctrailing.\u201d\"> <img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210941\/CNX_Chem_01_05_SigDigits5_img1.jpg\" alt=\"The left diagram uses the example of 3090. The zero in the hundreds place is labeled \u201ccaptive\u201d and the zero in the ones place is labeled trailing. The right diagram uses the example 0.008020. The three zeros in the ones, tenths, and hundredths places are labeled \u201cleading.\u201d The zero in the ten-thousandths place is labeled \u201ccaptive\u201d and the zero in the millionths place is labeled \u201ctrailing.\u201d\" data-media-type=\"image\/jpeg\" \/><\/span>\r\n<p id=\"fs-idp31100592\">Starting with the first nonzero digit on the left, count this digit and all remaining digits to the right. This is the number of significant figures in the measurement unless the last digit is a trailing zero lying to the left of the decimal point.<\/p>\r\n<span id=\"fs-idp40720144\" data-type=\"media\" data-alt=\"The left diagram uses the example of 1267 meters. The number 1 is the first nonzero figure on the left. 1267 has 4 significant figures in total. The right diagram uses the example of 55.0 grams. The number 5 in the tens place is the first nonzero figure on the left. 55.0 has 3 significant figures. Note that the 0 is to the right of the decimal point and therefore is a significant figure.\"> <img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210943\/CNX_Chem_01_05_SigDigits1_img1.jpg\" alt=\"The left diagram uses the example of 1267 meters. The number 1 is the first nonzero figure on the left. 1267 has 4 significant figures in total. The right diagram uses the example of 55.0 grams. The number 5 in the tens place is the first nonzero figure on the left. 55.0 has 3 significant figures. Note that the 0 is to the right of the decimal point and therefore is a significant figure.\" width=\"879\" height=\"165\" data-media-type=\"image\/jpeg\" \/><\/span>\r\n<p id=\"fs-idm177076640\">Captive zeros result from measurement and are therefore always significant. Leading zeros, however, are never significant\u2014they merely tell us where the decimal point is located.<\/p>\r\n<span id=\"fs-idm113793344\" data-type=\"media\" data-alt=\"The left diagram uses the example of 70.607 milliliters. The number 7 is the first nonzero figure on the left. 70.607 has 5 significant figures in total, as all figures are measured including the 2 zeros. The right diagram uses the example of 0.00832407 M L. The number 8 is the first nonzero figure on the left. 0.00832407 has 6 significant figures.\"> <img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210944\/CNX_Chem_01_05_SigDigits2_img1.jpg\" alt=\"The left diagram uses the example of 70.607 milliliters. The number 7 is the first nonzero figure on the left. 70.607 has 5 significant figures in total, as all figures are measured including the 2 zeros. The right diagram uses the example of 0.00832407 M L. The number 8 is the first nonzero figure on the left. 0.00832407 has 6 significant figures.\" width=\"880\" height=\"134\" data-media-type=\"image\/jpeg\" \/><\/span>\r\n<p id=\"fs-idm262013360\">The leading zeros in this example are not significant. We could use exponential notation (as described in Appendix B) and express the number as 8.32407 \u00d7 10<sup>-3<\/sup>; then the number 8.32407 contains all of the significant figures, and 10<sup>-3<\/sup> locates the decimal point.<\/p>\r\n<p id=\"fs-idm210460000\">The number of significant figures is uncertain in a number that ends with a zero to the left of the decimal point location. The zeros in the measurement 1,300 grams could be significant or they could simply indicate where the decimal point is located. The ambiguity can be resolved with the use of exponential notation: 1.3 \u00d7 10<sup>3<\/sup> (two significant figures), 1.30 \u00d7 10<sup>3<\/sup> (three significant figures, if the tens place was measured), or 1.300 \u00d7 10<sup>3<\/sup> (four significant figures, if the ones place was also measured). In cases where only the decimal-formatted number is available, it is prudent to assume that all trailing zeros are not significant.<\/p>\r\n<span id=\"fs-idp29412624\" data-type=\"media\" data-alt=\"This figure uses the example of 1300 grams. The one and the 3 are significant figures as they are clearly the result of measurement. The 2 zeros could be significant if they were measured or they could be placeholders.\"> <img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210946\/CNX_Chem_01_05_SigDigits3_img1.jpg\" alt=\"This figure uses the example of 1300 grams. The one and the 3 are significant figures as they are clearly the result of measurement. The 2 zeros could be significant if they were measured or they could be placeholders.\" width=\"879\" height=\"155\" data-media-type=\"image\/jpeg\" \/><\/span>\r\n<p id=\"fs-idm173917264\">When determining significant figures, be sure to pay attention to reported values and think about the measurement and significant figures in terms of what is reasonable or likely when evaluating whether the value makes sense. For example, the official January 2014 census reported the resident population of the US as 317,297,725. Do you think the US population was correctly determined to the reported nine significant figures, that is, to the exact number of people? People are constantly being born, dying, or moving into or out of the country, and assumptions are made to account for the large number of people who are not actually counted. Because of these uncertainties, it might be more reasonable to expect that we know the population to within perhaps a million or so, in which case the population should be reported as 3.17 \u00d7 10<sup>8<\/sup> people.<\/p>\r\n\r\n<\/section><section id=\"fs-idm191691888\" data-depth=\"1\">\r\n<h2 data-type=\"title\">Significant Figures in Calculations<\/h2>\r\n<p id=\"fs-idm277117616\">A second important principle of uncertainty is that results calculated from a measurement are at least as uncertain as the measurement itself. We must take the uncertainty in our measurements into account to avoid misrepresenting the uncertainty in calculated results. One way to do this is to report the result of a calculation with the correct number of significant figures, which is determined by the following three rules for <span data-type=\"term\">rounding<\/span> numbers:<\/p>\r\n\r\n<ol id=\"fs-idm65809616\" data-number-style=\"arabic\">\r\n\t<li>When we add or subtract numbers, we should round the result to the same number of decimal places as the number with the least number of decimal places (the least precise value in terms of addition and subtraction).<\/li>\r\n\t<li>When we multiply or divide numbers, we should round the result to the same number of digits as the number with the least number of significant figures (the least precise value in terms of multiplication and division).<\/li>\r\n\t<li>If the digit to be dropped (the one immediately to the right of the digit to be retained) is less than 5, we \u201cround down\u201d and leave the retained digit unchanged; if it is more than 5, we \u201cround up\u201d and increase the retained digit by 1; if the dropped digit <em data-effect=\"italics\">is<\/em> 5, we round up or down, whichever yields an even value for the retained digit. (The last part of this rule may strike you as a bit odd, but it\u2019s based on reliable statistics and is aimed at avoiding any bias when dropping the digit \u201c5,\u201d since it is equally close to both possible values of the retained digit.)<\/li>\r\n<\/ol>\r\n<p id=\"fs-idm107335696\">The following examples illustrate the application of this rule in rounding a few different numbers to three significant figures:<\/p>\r\n\r\n<ul id=\"fs-idm192081680\" data-bullet-style=\"bullet\">\r\n\t<li>0.028675 rounds \u201cup\u201d to 0.0287 (the dropped digit, 7, is greater than 5)<\/li>\r\n\t<li>18.3384 rounds \u201cdown\u201d to 18.3 (the dropped digit, 3, is lesser than 5)<\/li>\r\n\t<li>6.8752 rounds \u201cup\u201d to 6.88 (the dropped digit is 5, and the retained digit is even)<\/li>\r\n\t<li>92.85 rounds \u201cdown\u201d to 92.8 (the dropped digit is 5, and the retained digit is even)<\/li>\r\n<\/ul>\r\n<p id=\"fs-idm178562592\">Let\u2019s work through these rules with a few examples.<\/p>\r\n\r\n<div id=\"fs-idp40552528\" data-type=\"example\">\r\n<div class=\"textbox shaded\">\r\n<h3>Example 1<\/h3>\r\n<h4 id=\"fs-idm303504976\"><span data-type=\"title\">Rounding Numbers<\/span><\/h4>\r\nRound the following to the indicated number of significant figures:\r\n<p id=\"fs-idm277227680\">(a) 31.57 (to two significant figures)<\/p>\r\n<p id=\"fs-idm113120528\">(b) 8.1649 (to three significant figures)<\/p>\r\n<p id=\"fs-idp33608880\">(c) 0.051065 (to four significant figures)<\/p>\r\n<p id=\"fs-idm208861552\">(d) 0.90275 (to four significant figures)<\/p>\r\n\r\n<h4 id=\"fs-idm125552432\"><span data-type=\"title\">Solution<\/span><\/h4>\r\n(a) 31.57 rounds \u201cup\u201d to 32 (the dropped digit is 5, and the retained digit is even)\r\n<p id=\"fs-idm180680048\">(b) 8.1649 rounds \u201cdown\u201d to 8.16 (the dropped digit, 4, is lesser than 5)<\/p>\r\n<p id=\"fs-idm167789680\">(c) 0.051065 rounds \u201cdown\u201d to 0.05106 (the dropped digit is 5, and the retained digit is even)<\/p>\r\n<p id=\"fs-idm174540832\">(d) 0.90275 rounds \u201cup\u201d to 0.9028 (the dropped digit is 5, and the retained digit is even)<\/p>\r\n\r\n<h4 id=\"fs-idm185983232\"><strong><span data-type=\"title\">Check Your Learning<\/span><\/strong><\/h4>\r\nRound the following to the indicated number of significant figures:\r\n<p id=\"fs-idm69923072\">(a) 0.424 (to two significant figures)<\/p>\r\n<p id=\"fs-idm65589936\">(b) 0.0038661 (to three significant figures)<\/p>\r\n<p id=\"fs-idm107300848\">(c) 421.25 (to four significant figures)<\/p>\r\n<p id=\"fs-idm258155488\">(d) 28,683.5 (to five significant figures)<\/p>\r\n\r\n<div id=\"fs-idm155369456\" data-type=\"note\">\r\n<div style=\"text-align: right;\" data-type=\"title\"><\/div>\r\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a0(a) 0.42; (b) 0.00387; (c) 421.2; (d) 28,684<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Example 2<\/h3>\r\n<h4 id=\"fs-idm327587104\"><strong><span data-type=\"title\">Addition and Subtraction with Significant Figures<\/span><\/strong><\/h4>\r\nRule: When we add or subtract numbers, we should round the result to the same number of decimal places as the number with the least number of decimal places (i.e., the least precise value in terms of addition and subtraction).\r\n<p id=\"fs-idm318611824\">(a) Add 1.0023 g and 4.383 g.<\/p>\r\n<p id=\"fs-idm288438480\">(b) Subtract 421.23 g from 486 g.<\/p>\r\n\r\n<h4 id=\"fs-idm277651872\"><strong><span data-type=\"title\">Solution<\/span><\/strong><\/h4>\r\n<p id=\"fs-idm21393952\">(a) [latex]\\begin{array}{l}\\\\ \\begin{array}{l}\\hfill \\\\ \\frac{\\begin{array}{c}\\phantom{\\rule{1.4em}{0ex}}1.0023 g\\\\ \\text{+ 4.383 g}\\end{array}}{\\phantom{\\rule{1.5em}{0ex}}5.3853 g}\\hfill \\end{array}\\end{array}[\/latex]<\/p>\r\n<p id=\"fs-idm107330240\">Answer is 5.385 g (round to the thousandths place; three decimal places)<\/p>\r\n<p id=\"fs-idm257863024\">(b) [latex]\\begin{array}{l}\\begin{array}{l}\\hfill \\\\ \\hfill \\end{array}\\\\ \\frac{\\begin{array}{l}\\text{}\\phantom{\\rule{0.8em}{0ex}}486 g\\hfill \\\\ -421.23 g\\hfill \\end{array}}{\\phantom{\\rule{1.3em}{0ex}}64.77 g}\\end{array}[\/latex]<\/p>\r\n<p id=\"fs-idp47889280\">Answer is 65 g (round to the ones place; no decimal places)<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210947\/CNX_Chem_01_05_SigDigits4_img1.jpg\" alt=\"Figure A shows 1.0023 being added to 4.383 to yield the answer 5.385. 1.0023 goes to the ten thousandths place, but 4.383 goes to the thousandths place, making it the less precise of the two numbers. Therefore the answer, 5.3853, should be rounded to the thousandths, to yield 5.385. Figure B shows 486 grams minus 421.23 grams, which yields the answer 64.77 grams. This answer should be round to the ones place, making the answer 65 grams.\" width=\"879\" height=\"188\" data-media-type=\"image\/jpeg\" \/><\/p>\r\n\r\n<h4 id=\"fs-idm97432976\"><strong><span data-type=\"title\">Check Your Learning<\/span><\/strong><\/h4>\r\n(a) Add 2.334 mL and 0.31 mL.\r\n<p id=\"fs-idm113279504\">(b) Subtract 55.8752 m from 56.533 m.<\/p>\r\n\r\n<div id=\"fs-idp26956096\" data-type=\"note\">\r\n<div data-type=\"title\"><\/div>\r\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a0(a) 2.64 mL; (b) 0.658 m<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idp61408240\" data-type=\"example\">\r\n<div class=\"textbox shaded\">\r\n<h3>Example 3<\/h3>\r\n<div id=\"fs-idp61408240\" data-type=\"example\">\r\n<h4>Multiplication and Division with Significant Figures<\/h4>\r\n<\/div>\r\n<div id=\"fs-idp34148976\" data-type=\"example\">\r\n<p id=\"fs-idm194335568\">Rule: When we multiply or divide numbers, we should round the result to the same number of digits as the number with the least number of significant figures (the least precise value in terms of multiplication and division).<\/p>\r\n<p id=\"fs-idm176907440\">(a) Multiply 0.6238 cm by 6.6 cm.<\/p>\r\n<p id=\"fs-idp40092848\">(b) Divide 421.23 g by 486 mL.<\/p>\r\n\r\n<h4 id=\"fs-idm318303792\"><span data-type=\"title\">Solution<\/span><\/h4>\r\n<p id=\"fs-idp11052048\">(a) [latex]\\begin{array}{l}\\begin{array}{l}\\text{0.6238 cm}\\times 6.6\\text{cm}=4.11708{\\text{cm}}^{2}\\rightarrow\\text{result is}4.1{\\text{cm}}^{2}\\left(\\text{round to two significant figures}\\right)\\hfill \\\\ \\text{four significant figures}\\times \\text{two significant figures}\\rightarrow\\text{two significant figures answer}\\hfill \\end{array}\\hfill \\end{array}[\/latex]<\/p>\r\n<p id=\"fs-idm194468576\">(b) [latex]\\begin{array}{l}\\frac{\\text{421.23 g}}{\\text{486 mL}}=\\text{0.86728 g\/mL}\\rightarrow\\text{result is 0.867 g\/mL}\\left(\\text{round to three significant figures}\\right)\\\\ \\frac{\\text{five significant figures}}{\\text{three significant figures}}\\rightarrow\\text{three significant figures answer}\\end{array}[\/latex]<\/p>\r\n\r\n<h4 id=\"fs-idp45405152\"><span data-type=\"title\">Check Your Learning<\/span><\/h4>\r\n(a) Multiply 2.334 cm and 0.320 cm.\r\n<p id=\"fs-idm155228848\">(b) Divide 55.8752 m by 56.53 s.<\/p>\r\n\r\n<div id=\"fs-idm282773952\" data-type=\"note\">\r\n<div data-type=\"title\"><\/div>\r\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a0(a) 0.747 cm<sup>2<\/sup> (b) 0.9884 m\/s<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-idp31178224\">In the midst of all these technicalities, it is important to keep in mind the reason why we use significant figures and rounding rules\u2014to correctly represent the certainty of the values we report and to ensure that a calculated result is not represented as being more certain than the least certain value used in the calculation.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3>Example 4<\/h3>\r\n<h4 id=\"fs-idm180409728\"><strong><span data-type=\"title\">Calculation with Significant Figures<\/span><\/strong><\/h4>\r\nOne common bathtub is 13.44 dm long, 5.920 dm wide, and 2.54 dm deep. Assume that the tub is rectangular and calculate its approximate volume in liters.\r\n<h4 id=\"fs-idm209075984\"><span data-type=\"title\">Solution<\/span><\/h4>\r\n<div id=\"fs-idm15365184\" data-type=\"equation\">[latex]\\begin{array}{lll}V\\hfill &amp; =\\hfill &amp; l\\times w\\times d\\hfill \\\\ &amp; =\\hfill &amp; \\text{13.44 dm}\\times \\text{5.920 dm}\\times \\text{2.54 dm}\\hfill \\\\ &amp; =\\hfill &amp; \\text{202.09459} {\\text{dm}}^{3}\\left(\\text{value from calculator}\\right)\\hfill \\\\ &amp; =\\hfill &amp; {\\text{202 dm}}^{3}\\text{, or 202 L}\\left(\\text{answer rounded to three significant figures}\\right)\\hfill \\end{array}[\/latex]<\/div>\r\n<h4 id=\"fs-idm219800928\"><span data-type=\"title\">Check Your Learning<\/span><\/h4>\r\nWhat is the density of a liquid with a mass of 31.1415 g and a volume of 30.13 cm<sup>3<\/sup>?\r\n<div id=\"fs-idm178680064\" data-type=\"note\">\r\n<div data-type=\"title\"><\/div>\r\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a01.034 g\/mL<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-idp40680240\" data-type=\"example\">\r\n<div class=\"textbox shaded\">\r\n<h3>Example 5<\/h3>\r\n<section id=\"fs-idm191691888\" data-depth=\"1\">\r\n<div id=\"fs-idm148976192\" data-type=\"example\">\r\n<h4 id=\"fs-idp29940656\"><span data-type=\"title\">Experimental Determination of Density Using Water Displacement<\/span><\/h4>\r\nA piece of rebar is weighed and then submerged in a graduated cylinder partially filled with water, with results as shown.\r\n\r\n<span id=\"fs-idm332426528\" data-type=\"media\" data-alt=\"This diagram shows the initial volume of water in a graduated cylinder as 13.5 milliliters. A 69.658 gram piece of metal rebar is added to the graduated cylinder, causing the water to reach a final volume of 22.4 milliliters\">\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210949\/CNX_Chem_01_04_CylRebar1.jpg\" alt=\"This diagram shows the initial volume of water in a graduated cylinder as 13.5 milliliters. A 69.658 gram piece of metal rebar is added to the graduated cylinder, causing the water to reach a final volume of 22.4 milliliters\" width=\"880\" height=\"670\" data-media-type=\"image\/jpeg\" \/><\/span>\r\n<p id=\"fs-idm245394240\">(a) Use these values to determine the density of this piece of rebar.<\/p>\r\n<p id=\"fs-idm209220496\">(b) Rebar is mostly iron. Does your result in (a) support this statement? How?<\/p>\r\n\r\n<h4 id=\"fs-idm325787440\"><span data-type=\"title\">Solution<\/span><\/h4>\r\nThe volume of the piece of rebar is equal to the volume of the water displaced:\r\n<div id=\"fs-idm180698816\" data-type=\"equation\">[latex]\\text{volume}=\\text{22.4 mL}-\\text{13.5 mL}=\\text{8.9 mL}={\\text{8.9 cm}}^{3}[\/latex]<\/div>\r\n<p id=\"fs-idm181276752\">(rounded to the nearest 0.1 mL, per the rule for addition and subtraction)<\/p>\r\n<p id=\"fs-idp36085040\">The density is the mass-to-volume ratio:<\/p>\r\n\r\n<div id=\"fs-idp135143440\" data-type=\"equation\">[latex]\\text{density}=\\frac{\\text{mass}}{\\text{volume}}=\\frac{\\text{69.658 g}}{{\\text{8.9 cm}}^{3}}={\\text{7.8 g\/cm}}^{3}[\/latex]<\/div>\r\n<p id=\"fs-idm277303296\">(rounded to two significant figures, per the rule for multiplication and division)<\/p>\r\n<p id=\"fs-idm243666944\">The density of iron is 7.9 g\/cm<sup>3<\/sup>, very close to that of rebar, which lends some support to the fact that rebar is mostly iron.<\/p>\r\n\r\n<h4 id=\"fs-idm259990592\"><strong><span data-type=\"title\">Check Your Learning<\/span><\/strong><\/h4>\r\nAn irregularly shaped piece of a shiny yellowish material is weighed and then submerged in a graduated cylinder, with results as shown.\r\n\r\n<span id=\"fs-idm283007920\" data-type=\"media\" data-alt=\"This diagram shows the initial volume of water in a graduated cylinder as 17.1 milliliters. A 51.842 gram gold colored rock is added to the graduated cylinder, causing the water to reach a final volume of 19.8 milliliters\">\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210950\/CNX_Chem_01_04_CylGold1.jpg\" alt=\"This diagram shows the initial volume of water in a graduated cylinder as 17.1 milliliters. A 51.842 gram gold colored rock is added to the graduated cylinder, causing the water to reach a final volume of 19.8 milliliters\" width=\"881\" height=\"672\" data-media-type=\"image\/jpeg\" \/><\/span>\r\n<p id=\"fs-idm272657872\">(a) Use these values to determine the density of this material.<\/p>\r\n<p id=\"fs-idm166920160\">(b) Do you have any reasonable guesses as to the identity of this material? Explain your reasoning.<\/p>\r\n\r\n<div id=\"fs-idm113054800\" data-type=\"note\">\r\n<div style=\"text-align: right;\" data-type=\"title\"><\/div>\r\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a0(a) 19 g\/cm<sup>3<\/sup>; (b) It is likely gold; the right appearance for gold and very close to the density given for gold in \"Measurements.\"<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/section><\/div>\r\n<\/div>\r\n<div id=\"fs-idm148976192\" data-type=\"example\">\r\n<h2 id=\"fs-idp29940656\">Accuracy and Precision<\/h2>\r\n<\/div>\r\n<\/section><section id=\"fs-idp33954960\" data-depth=\"1\">\r\n<p id=\"fs-idp4474304\">Scientists typically make repeated measurements of a quantity to ensure the quality of their findings and to know both the <strong><span data-type=\"term\">precision<\/span><\/strong> and the <strong><span data-type=\"term\">accuracy<\/span><\/strong> of their results. Measurements are said to be precise if they yield very similar results when repeated in the same manner. A measurement is considered accurate if it yields a result that is very close to the true or accepted value. Precise values agree with each other; accurate values agree with a true value. These characterizations can be extended to other contexts, such as the results of an archery competition (Figure 2).<\/p>\r\n\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"879\"]<img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210951\/CNX_Chem_01_05_Archery1.jpg\" alt=\"Figures A through C each show targets with holes where the arrows hit. The archer in figure A was both accurate and precise as all 3 arrows are clustered in the center of the target. In figure B, the archer is precise but not accurate, as all 3 arrows are clustered together but to the upper right of the center of the target. In Figure C, the archer is neither accurate nor precise as the 3 holes are not close together and are located both to the upper right and right of the target.\" width=\"879\" height=\"280\" data-media-type=\"image\/jpg\" \/> Figure 2. (a) These arrows are close to both the bull\u2019s eye and one another, so they are both accurate and precise. (b) These arrows are close to one another but not on target, so they are precise but not accurate. (c) These arrows are neither on target nor close to one another, so they are neither accurate nor precise.[\/caption]\r\n<p id=\"fs-idp174984224\">Suppose a quality control chemist at a pharmaceutical company is tasked with checking the accuracy and precision of three different machines that are meant to dispense 10 ounces (296 mL) of cough syrup into storage bottles. She proceeds to use each machine to fill five bottles and then carefully determines the actual volume dispensed, obtaining the results tabulated in Table 1.<\/p>\r\n\r\n<table id=\"fs-idp31780400\" class=\"span-all\" summary=\"The volume, in milliliters, of cough medicine delivered by dispensers 1, 2 and 3 are shown in a table. The values for dispenser 1 are 283.3, 284.1, 283.9, 284.0, and 284.1. The values for dispenser 2 are 298.3, 294.2, 296.0, 297.8, and 293.9. The values for dispenser 3 are 296.1, 295.9, 296.1, 296.0, and 296.1.\">\r\n<thead>\r\n<tr valign=\"top\">\r\n<th colspan=\"3\">Table 1. Volume (mL) of Cough Medicine Delivered by 10-oz (296 mL) Dispensers<\/th>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<th>Dispenser #1<\/th>\r\n<th>Dispenser #2<\/th>\r\n<th>Dispenser #3<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr valign=\"top\">\r\n<td>283.3<\/td>\r\n<td>298.3<\/td>\r\n<td>296.1<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td>284.1<\/td>\r\n<td>294.2<\/td>\r\n<td>295.9<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td>283.9<\/td>\r\n<td>296.0<\/td>\r\n<td>296.1<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td>284.0<\/td>\r\n<td>297.8<\/td>\r\n<td>296.0<\/td>\r\n<\/tr>\r\n<tr valign=\"top\">\r\n<td>284.1<\/td>\r\n<td>293.9<\/td>\r\n<td>296.1<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<p id=\"fs-idp4939264\">Considering these results, she will report that dispenser #1 is precise (values all close to one another, within a few tenths of a milliliter) but not accurate (none of the values are close to the target value of 296 mL, each being more than 10 mL too low). Results for dispenser #2 represent improved accuracy (each volume is less than 3 mL away from 296 mL) but worse precision (volumes vary by more than 4 mL). Finally, she can report that dispenser #3 is working well, dispensing cough syrup both accurately (all volumes within 0.1 mL of the target volume) and precisely (volumes differing from each other by no more than 0.2 mL).<\/p>\r\n\r\n<\/section><section id=\"fs-idp223627024\" class=\"summary\" data-depth=\"1\"><section id=\"fs-idm40478192\" class=\"summary\" data-depth=\"1\">\r\n<div id=\"post-355\" class=\"post-355 chapter type-chapter status-publish hentry type-1\">\r\n<div class=\"entry-content\">\r\n<div class=\"im_section\">\r\n<div class=\"im_section\">\r\n<div id=\"mclean-ch03_s01_s02_n01\" class=\"im_key_takeaways im_editable im_block\">\r\n<div class=\"bcc-box bcc-success\">\r\n<h2>Key Concepts and Summary<\/h2>\r\n<section>\r\n<div data-type=\"note\">\r\n<p id=\"fs-idp236281408\">Quantities can be exact or measured. Measured quantities have an associated uncertainty that is represented by the number of significant figures in the measurement. The uncertainty of a calculated value depends on the uncertainties in the values used in the calculation and is reflected in how the value is rounded. Measured values can be accurate (close to the true value) and\/or precise (showing little variation when measured repeatedly).<\/p>\r\n\r\n<\/div>\r\n<\/section><\/div>\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Chemistry End of Chapter Exercises<\/h3>\r\n<ol>\r\n\t<li>Express each of the following numbers in scientific notation with correct significant figures:\r\n<ol>\r\n\t<li>711.0<\/li>\r\n\t<li>0.239<\/li>\r\n\t<li>90743<\/li>\r\n\t<li>134.2<\/li>\r\n\t<li>0.05499<\/li>\r\n\t<li>10000.0<\/li>\r\n\t<li>0.000000738592<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>Express each of the following numbers in exponential notation with correct significant figures:\r\n<ol>\r\n\t<li>704<\/li>\r\n\t<li>0.03344<\/li>\r\n\t<li>547.9<\/li>\r\n\t<li>22086<\/li>\r\n\t<li>1000.00<\/li>\r\n\t<li>0.0000000651<\/li>\r\n\t<li>0.007157<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>Indicate whether each of the following can be determined exactly or must be measured with some degree of uncertainty:\r\n<ol>\r\n\t<li>the number of eggs in a basket<\/li>\r\n\t<li>the mass of a dozen eggs<\/li>\r\n\t<li>the number of gallons of gasoline necessary to fill an automobile gas tank<\/li>\r\n\t<li>the number of cm in 2 m<\/li>\r\n\t<li>the mass of a textbook<\/li>\r\n\t<li>the time required to drive from San Francisco to Kansas City at an average speed of 53 mi\/h<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>Indicate whether each of the following can be determined exactly or must be measured with some degree of uncertainty:\r\n<ol>\r\n\t<li>the number of seconds in an hour<\/li>\r\n\t<li>the number of pages in this book<\/li>\r\n\t<li>the number of grams in your weight<\/li>\r\n\t<li>the number of grams in 3 kilograms<\/li>\r\n\t<li>the volume of water you drink in one day<\/li>\r\n\t<li>the distance from San Francisco to Kansas City<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>How many significant figures are contained in each of the following measurements?\r\n<ol>\r\n\t<li>38.7 g<\/li>\r\n\t<li>2 \u00d7 10<sup>18<\/sup> m<\/li>\r\n\t<li>3,486,002 kg<\/li>\r\n\t<li>9.74150 \u00d7 10<sup>-4<\/sup> J<\/li>\r\n\t<li>0.0613 cm<sup>3 \u00a0\u00a0<\/sup><\/li>\r\n\t<li>17.0 kg<\/li>\r\n\t<li>0.01400 g\/mL<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>How many significant figures are contained in each of the following measurements?\r\n<ol>\r\n\t<li>53 cm<\/li>\r\n\t<li>2.05 \u00d7 10<sup>8<\/sup> m<\/li>\r\n\t<li>86,002 J<\/li>\r\n\t<li>9.740 \u00d7 10<sup>4<\/sup> m\/s<\/li>\r\n\t<li>10.0613 m<sup>3 \u00a0\u00a0<\/sup><\/li>\r\n\t<li>0.17 g\/mL<\/li>\r\n\t<li>0.88400 s<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>The following quantities were reported on the labels of commercial products. Determine the number of significant figures in each.\r\n<ol>\r\n\t<li>0.0055 g active ingredients<\/li>\r\n\t<li>12 tablets<\/li>\r\n\t<li>3% hydrogen peroxide<\/li>\r\n\t<li>5.5 ounces<\/li>\r\n\t<li>473 mL<\/li>\r\n\t<li>1.75% bismuth<\/li>\r\n\t<li>0.001% phosphoric acid<\/li>\r\n\t<li>99.80% inert ingredients<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>Round off each of the following numbers to two significant figures:\r\n<ol>\r\n\t<li>0.436<\/li>\r\n\t<li>9.000<\/li>\r\n\t<li>27.2<\/li>\r\n\t<li>135<\/li>\r\n\t<li>1.497 \u00d7 10<sup>-3 \u00a0\u00a0<\/sup><\/li>\r\n\t<li>0.445<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>Round off each of the following numbers to two significant figures:\r\n<ol>\r\n\t<li>517<\/li>\r\n\t<li>86.3<\/li>\r\n\t<li>6.382 \u00d7 10<sup>3 \u00a0\u00a0<\/sup><\/li>\r\n\t<li>5.0008<\/li>\r\n\t<li>22.497<\/li>\r\n\t<li>0.885<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>Perform the following calculations and report each answer with the correct number of significant figures.\r\n<ol>\r\n\t<li>628 \u00d7 342<\/li>\r\n\t<li>(5.63 \u00d7 10<sup>2<\/sup>) \u00d7 (7.4 \u00d7 10<sup>3<\/sup>)<\/li>\r\n\t<li>[latex]\\frac{28.0}{13.483}[\/latex]<\/li>\r\n\t<li>8119 \u00d7 0.000023<\/li>\r\n\t<li>14.98 + 27,340 + 84.7593<\/li>\r\n\t<li>42.7 + 0.259<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>Perform the following calculations and report each answer with the correct number of significant figures.\r\n<ol>\r\n\t<li>62.8 \u00d7 34<\/li>\r\n\t<li>0.147 + 0.0066 + 0.012<\/li>\r\n\t<li>38 \u00d7 95 \u00d7 1.792<\/li>\r\n\t<li>15 \u2013 0.15 \u2013 0.6155<\/li>\r\n\t<li>[latex]8.78\\times \\left(\\frac{0.0500}{0.478}\\right)[\/latex]<\/li>\r\n\t<li>140 + 7.68 + 0.014<\/li>\r\n\t<li>28.7 \u2013 0.0483<\/li>\r\n\t<li>[latex]\\frac{\\left(88.5-87.57\\right)}{45.13}[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>Consider the results of the archery contest shown in this figure.\r\n<ol>\r\n\t<li>Which archer is most precise?<\/li>\r\n\t<li>Which archer is most accurate?<\/li>\r\n\t<li>Who is both least precise and least accurate?\r\n<div id=\"fs-idp30946992\" data-type=\"exercise\">\r\n<div id=\"fs-idp4924640\" data-type=\"problem\">\r\n\r\n<span id=\"fs-idp94481888\" data-type=\"media\" data-alt=\"4 targets are shown each with 4 holes indicating where the arrows hit the targets. Archer W put all 4 arrows closely around the center of the target. Archer X put all 4 arrows in a tight cluster but far to the lower right of the target. Archer Y put all 4 arrows at different corners of the target. All 4 arrows are very far from the center of the target. Archer Z put 2 arrows close to the target and 2 other arrows far outside of the target.\"> <img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210953\/CNX_Chem_01_05_Archer2_img1.jpg\" alt=\"4 targets are shown each with 4 holes indicating where the arrows hit the targets. Archer W put all 4 arrows closely around the center of the target. Archer X put all 4 arrows in a tight cluster but far to the lower right of the target. Archer Y put all 4 arrows at different corners of the target. All 4 arrows are very far from the center of the target. Archer Z put 2 arrows close to the target and 2 other arrows far outside of the target.\" width=\"840\" height=\"324\" data-media-type=\"image\/jpeg\" \/><\/span>\r\n\r\n<\/div>\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/li>\r\n\t<li>Classify the following sets of measurements as accurate, precise, both, or neither.\r\n<ol>\r\n\t<li>Checking for consistency in the weight of chocolate chip cookies: 17.27g, 13.05g, 19.46g, 16.92g<\/li>\r\n\t<li>Testing the volume of a batch of 25-mL pipettes: 27.02 mL, 26.99 mL, 26.97 mL, 27.01 mL<\/li>\r\n\t<li>Determining the purity of gold: 99.9999%, 99.9998%, 99.9998%, 99.9999%<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"post-355\" class=\"post-355 chapter type-chapter status-publish hentry type-1\">\r\n<div class=\"entry-content\">\r\n<div class=\"im_section\">\r\n<div class=\"im_section\">\r\n<div id=\"mclean-ch03_s01_s02_n01\" class=\"im_key_takeaways im_editable im_block\">\r\n<div class=\"bcc-box bcc-info\">\r\n<h4>Selected Answers<\/h4>\r\n2.\u00a0(a) 7.04 \u00d7 10<sup>2<\/sup>; (b) 3.344 \u00d7 10<sup>-2<\/sup>; (c) 5.479 \u00d7 10<sup>2<\/sup>; (d) 2.2086 \u00d7 10<sup>4<\/sup>; (e) 1.00000 \u00d7 10<sup>3<\/sup>; (f) 6.51 \u00d7 10<sup>-8<\/sup>; (g) 7.157 \u00d7 10<sup>-3<\/sup>\r\n\r\n4.\u00a0(a) exact; (b) exact; (c) uncertain; (d) exact; (e) uncertain; (f) uncertain\r\n\r\n6. (a) two; (b) three; (c) five; (d) four; (e) six; (f) two; (g) five\r\n\r\n8.\u00a0(a) 0.44; (b) 9.0; (c) 27; (d) 140; (e) 1.5 \u00d7 10<sup>-3<\/sup>; (f) 0.44\r\n\r\n10.\u00a0(a) 2.15 \u00d7 10<sup>5<\/sup>; (b) 4.2 \u00d7 10<sup>6<\/sup>; (c) 2.08; (d) 0.19; (e) 27,440; (f) 43.0\r\n\r\n12.\u00a0(a) Archer X; (b) Archer W; (c) Archer Y\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/section>\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Glossary<\/h3>\r\n<strong>accuracy<\/strong>\r\nhow closely a measurement aligns with a correct value\r\n\r\n<strong>exact number<\/strong>\r\nnumber derived by counting or by definition&lt;\r\n\r\n<strong>precision<\/strong>\r\nhow closely a measurement matches the same measurement when repeated\r\n\r\n<strong>rounding<\/strong>\r\nprocedure used to ensure that calculated results properly reflect the uncertainty in the measurements used in the calculation\r\n\r\n<strong>significant figures<\/strong>\r\n(also, significant digits) all of the measured digits in a determination, including the uncertain last digit\r\n\r\n<strong>uncertainty<\/strong>\r\nestimate of amount by which measurement differs from true value\r\n\r\n<\/div>\r\n<\/section>","rendered":"<div class=\"bcc-box bcc-highlight\">\n<h3>LEARNING OBJECTIVES<\/h3>\n<p>By the end of this section, you will be able to:<\/p>\n<ul>\n<li>Define accuracy and precision<\/li>\n<li>Distinguish exact and uncertain numbers<\/li>\n<li>Correctly represent uncertainty in quantities using significant figures<\/li>\n<li>Apply proper rounding rules to computed quantities<\/li>\n<\/ul>\n<\/div>\n<p id=\"fs-idm288863760\">Counting is the only type of measurement that is free from uncertainty, provided the number of objects being counted does not change while the counting process is underway. The result of such a counting measurement is an example of an <span data-type=\"term\">exact number<\/span>. If we count eggs in a carton, we know <em data-effect=\"italics\">exactly<\/em> how many eggs the carton contains. The numbers of defined quantities are also exact. By definition, 1 foot is exactly 12 inches, 1 inch is exactly 2.54 centimeters, and 1 gram is exactly 0.001 kilogram. Quantities derived from measurements other than counting, however, are uncertain to varying extents due to practical limitations of the measurement process used.<\/p>\n<section id=\"fs-idm217277536\" data-depth=\"1\">\n<h2 data-type=\"title\">Significant Figures in Measurement<\/h2>\n<p id=\"fs-idp11446448\">The numbers of measured quantities, unlike defined or directly counted quantities, are not exact. To measure the volume of liquid in a graduated cylinder, you should make a reading at the bottom of the meniscus, the lowest point on the curved surface of the liquid.<\/p>\n<div style=\"width: 890px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210939\/CNX_Chem_01_05_Measure1.jpg\" alt=\"This diagram shows a 25 milliliter graduated cylinder filled with about 20.8 milliliters of fluid. The diagram zooms in on the meniscus, which is the curved surface of the water that is visible when the graduated cylinder is viewed from the side. You make the reading at the lowest point of the curve of the meniscus.\" width=\"880\" height=\"503\" data-media-type=\"image\/jpeg\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 1. To measure the volume of liquid in this graduated cylinder, you must mentally subdivide the distance between the 21 and 22 mL marks into tenths of a milliliter, and then make a reading (estimate) at the bottom of the meniscus.<\/p>\n<\/div>\n<p id=\"fs-idm176542448\">Refer to the illustration in Figure 1. The bottom of the meniscus in this case clearly lies between the 21 and 22 markings, meaning the liquid volume is <em data-effect=\"italics\">certainly<\/em> greater than 21 mL but less than 22 mL. The meniscus appears to be a bit closer to the 22-mL mark than to the 21-mL mark, and so a reasonable estimate of the liquid\u2019s volume would be 21.6 mL. In the number 21.6, then, the digits 2 and 1 are certain, but the 6 is an estimate. Some people might estimate the meniscus position to be equally distant from each of the markings and estimate the tenth-place digit as 5, while others may think it to be even closer to the 22-mL mark and estimate this digit to be 7. Note that it would be pointless to attempt to estimate a digit for the hundredths place, given that the tenths-place digit is uncertain. In general, numerical scales such as the one on this graduated cylinder will permit measurements to one-tenth of the smallest scale division. The scale in this case has 1-mL divisions, and so volumes may be measured to the nearest 0.1 mL.<\/p>\n<p id=\"fs-idm254904560\">This concept holds true for all measurements, even if you do not actively make an estimate. If you place a quarter on a standard electronic balance, you may obtain a reading of 6.72 g. The digits 6 and 7 are certain, and the 2 indicates that the mass of the quarter is likely between 6.71 and 6.73 grams. The quarter weighs <em data-effect=\"italics\">about<\/em> 6.72 grams, with a nominal uncertainty in the measurement of \u00b1 0.01 gram. If we weigh the quarter on a more sensitive balance, we may find that its mass is 6.723 g. This means its mass lies between 6.722 and 6.724 grams, an uncertainty of 0.001 gram. Every measurement has some <strong><span data-type=\"term\">uncertainty<\/span><\/strong>, which depends on the device used (and the user\u2019s ability). All of the digits in a measurement, including the uncertain last digit, are called <strong><span data-type=\"term\">significant figures<\/span><\/strong> or <strong><span data-type=\"term\">significant digits<\/span><\/strong>. Note that zero may be a measured value; for example, if you stand on a scale that shows weight to the nearest pound and it shows \u201c120,\u201d then the 1 (hundreds), 2 (tens) and 0 (ones) are all significant (measured) values.<\/p>\n<p id=\"fs-idm264880544\">Whenever you make a measurement properly, all the digits in the result are significant. But what if you were analyzing a reported value and trying to determine what is significant and what is not? Well, for starters, all nonzero digits are significant, and it is only zeros that require some thought. We will use the terms \u201cleading,\u201d \u201ctrailing,\u201d and \u201ccaptive\u201d for the zeros and will consider how to deal with them.<\/p>\n<p><span id=\"fs-idm244068192\" data-type=\"media\" data-alt=\"The left diagram uses the example of 3090. The zero in the hundreds place is labeled \u201ccaptive\u201d and the zero in the ones place is labeled trailing. The right diagram uses the example 0.008020. The three zeros in the ones, tenths, and hundredths places are labeled \u201cleading.\u201d The zero in the ten-thousandths place is labeled \u201ccaptive\u201d and the zero in the millionths place is labeled \u201ctrailing.\u201d\"> <img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210941\/CNX_Chem_01_05_SigDigits5_img1.jpg\" alt=\"The left diagram uses the example of 3090. The zero in the hundreds place is labeled \u201ccaptive\u201d and the zero in the ones place is labeled trailing. The right diagram uses the example 0.008020. The three zeros in the ones, tenths, and hundredths places are labeled \u201cleading.\u201d The zero in the ten-thousandths place is labeled \u201ccaptive\u201d and the zero in the millionths place is labeled \u201ctrailing.\u201d\" data-media-type=\"image\/jpeg\" \/><\/span><\/p>\n<p id=\"fs-idp31100592\">Starting with the first nonzero digit on the left, count this digit and all remaining digits to the right. This is the number of significant figures in the measurement unless the last digit is a trailing zero lying to the left of the decimal point.<\/p>\n<p><span id=\"fs-idp40720144\" data-type=\"media\" data-alt=\"The left diagram uses the example of 1267 meters. The number 1 is the first nonzero figure on the left. 1267 has 4 significant figures in total. The right diagram uses the example of 55.0 grams. The number 5 in the tens place is the first nonzero figure on the left. 55.0 has 3 significant figures. Note that the 0 is to the right of the decimal point and therefore is a significant figure.\"> <img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210943\/CNX_Chem_01_05_SigDigits1_img1.jpg\" alt=\"The left diagram uses the example of 1267 meters. The number 1 is the first nonzero figure on the left. 1267 has 4 significant figures in total. The right diagram uses the example of 55.0 grams. The number 5 in the tens place is the first nonzero figure on the left. 55.0 has 3 significant figures. Note that the 0 is to the right of the decimal point and therefore is a significant figure.\" width=\"879\" height=\"165\" data-media-type=\"image\/jpeg\" \/><\/span><\/p>\n<p id=\"fs-idm177076640\">Captive zeros result from measurement and are therefore always significant. Leading zeros, however, are never significant\u2014they merely tell us where the decimal point is located.<\/p>\n<p><span id=\"fs-idm113793344\" data-type=\"media\" data-alt=\"The left diagram uses the example of 70.607 milliliters. The number 7 is the first nonzero figure on the left. 70.607 has 5 significant figures in total, as all figures are measured including the 2 zeros. The right diagram uses the example of 0.00832407 M L. The number 8 is the first nonzero figure on the left. 0.00832407 has 6 significant figures.\"> <img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210944\/CNX_Chem_01_05_SigDigits2_img1.jpg\" alt=\"The left diagram uses the example of 70.607 milliliters. The number 7 is the first nonzero figure on the left. 70.607 has 5 significant figures in total, as all figures are measured including the 2 zeros. The right diagram uses the example of 0.00832407 M L. The number 8 is the first nonzero figure on the left. 0.00832407 has 6 significant figures.\" width=\"880\" height=\"134\" data-media-type=\"image\/jpeg\" \/><\/span><\/p>\n<p id=\"fs-idm262013360\">The leading zeros in this example are not significant. We could use exponential notation (as described in Appendix B) and express the number as 8.32407 \u00d7 10<sup>-3<\/sup>; then the number 8.32407 contains all of the significant figures, and 10<sup>-3<\/sup> locates the decimal point.<\/p>\n<p id=\"fs-idm210460000\">The number of significant figures is uncertain in a number that ends with a zero to the left of the decimal point location. The zeros in the measurement 1,300 grams could be significant or they could simply indicate where the decimal point is located. The ambiguity can be resolved with the use of exponential notation: 1.3 \u00d7 10<sup>3<\/sup> (two significant figures), 1.30 \u00d7 10<sup>3<\/sup> (three significant figures, if the tens place was measured), or 1.300 \u00d7 10<sup>3<\/sup> (four significant figures, if the ones place was also measured). In cases where only the decimal-formatted number is available, it is prudent to assume that all trailing zeros are not significant.<\/p>\n<p><span id=\"fs-idp29412624\" data-type=\"media\" data-alt=\"This figure uses the example of 1300 grams. The one and the 3 are significant figures as they are clearly the result of measurement. The 2 zeros could be significant if they were measured or they could be placeholders.\"> <img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210946\/CNX_Chem_01_05_SigDigits3_img1.jpg\" alt=\"This figure uses the example of 1300 grams. The one and the 3 are significant figures as they are clearly the result of measurement. The 2 zeros could be significant if they were measured or they could be placeholders.\" width=\"879\" height=\"155\" data-media-type=\"image\/jpeg\" \/><\/span><\/p>\n<p id=\"fs-idm173917264\">When determining significant figures, be sure to pay attention to reported values and think about the measurement and significant figures in terms of what is reasonable or likely when evaluating whether the value makes sense. For example, the official January 2014 census reported the resident population of the US as 317,297,725. Do you think the US population was correctly determined to the reported nine significant figures, that is, to the exact number of people? People are constantly being born, dying, or moving into or out of the country, and assumptions are made to account for the large number of people who are not actually counted. Because of these uncertainties, it might be more reasonable to expect that we know the population to within perhaps a million or so, in which case the population should be reported as 3.17 \u00d7 10<sup>8<\/sup> people.<\/p>\n<\/section>\n<section id=\"fs-idm191691888\" data-depth=\"1\">\n<h2 data-type=\"title\">Significant Figures in Calculations<\/h2>\n<p id=\"fs-idm277117616\">A second important principle of uncertainty is that results calculated from a measurement are at least as uncertain as the measurement itself. We must take the uncertainty in our measurements into account to avoid misrepresenting the uncertainty in calculated results. One way to do this is to report the result of a calculation with the correct number of significant figures, which is determined by the following three rules for <span data-type=\"term\">rounding<\/span> numbers:<\/p>\n<ol id=\"fs-idm65809616\" data-number-style=\"arabic\">\n<li>When we add or subtract numbers, we should round the result to the same number of decimal places as the number with the least number of decimal places (the least precise value in terms of addition and subtraction).<\/li>\n<li>When we multiply or divide numbers, we should round the result to the same number of digits as the number with the least number of significant figures (the least precise value in terms of multiplication and division).<\/li>\n<li>If the digit to be dropped (the one immediately to the right of the digit to be retained) is less than 5, we \u201cround down\u201d and leave the retained digit unchanged; if it is more than 5, we \u201cround up\u201d and increase the retained digit by 1; if the dropped digit <em data-effect=\"italics\">is<\/em> 5, we round up or down, whichever yields an even value for the retained digit. (The last part of this rule may strike you as a bit odd, but it\u2019s based on reliable statistics and is aimed at avoiding any bias when dropping the digit \u201c5,\u201d since it is equally close to both possible values of the retained digit.)<\/li>\n<\/ol>\n<p id=\"fs-idm107335696\">The following examples illustrate the application of this rule in rounding a few different numbers to three significant figures:<\/p>\n<ul id=\"fs-idm192081680\" data-bullet-style=\"bullet\">\n<li>0.028675 rounds \u201cup\u201d to 0.0287 (the dropped digit, 7, is greater than 5)<\/li>\n<li>18.3384 rounds \u201cdown\u201d to 18.3 (the dropped digit, 3, is lesser than 5)<\/li>\n<li>6.8752 rounds \u201cup\u201d to 6.88 (the dropped digit is 5, and the retained digit is even)<\/li>\n<li>92.85 rounds \u201cdown\u201d to 92.8 (the dropped digit is 5, and the retained digit is even)<\/li>\n<\/ul>\n<p id=\"fs-idm178562592\">Let\u2019s work through these rules with a few examples.<\/p>\n<div id=\"fs-idp40552528\" data-type=\"example\">\n<div class=\"textbox shaded\">\n<h3>Example 1<\/h3>\n<h4 id=\"fs-idm303504976\"><span data-type=\"title\">Rounding Numbers<\/span><\/h4>\n<p>Round the following to the indicated number of significant figures:<\/p>\n<p id=\"fs-idm277227680\">(a) 31.57 (to two significant figures)<\/p>\n<p id=\"fs-idm113120528\">(b) 8.1649 (to three significant figures)<\/p>\n<p id=\"fs-idp33608880\">(c) 0.051065 (to four significant figures)<\/p>\n<p id=\"fs-idm208861552\">(d) 0.90275 (to four significant figures)<\/p>\n<h4 id=\"fs-idm125552432\"><span data-type=\"title\">Solution<\/span><\/h4>\n<p>(a) 31.57 rounds \u201cup\u201d to 32 (the dropped digit is 5, and the retained digit is even)<\/p>\n<p id=\"fs-idm180680048\">(b) 8.1649 rounds \u201cdown\u201d to 8.16 (the dropped digit, 4, is lesser than 5)<\/p>\n<p id=\"fs-idm167789680\">(c) 0.051065 rounds \u201cdown\u201d to 0.05106 (the dropped digit is 5, and the retained digit is even)<\/p>\n<p id=\"fs-idm174540832\">(d) 0.90275 rounds \u201cup\u201d to 0.9028 (the dropped digit is 5, and the retained digit is even)<\/p>\n<h4 id=\"fs-idm185983232\"><strong><span data-type=\"title\">Check Your Learning<\/span><\/strong><\/h4>\n<p>Round the following to the indicated number of significant figures:<\/p>\n<p id=\"fs-idm69923072\">(a) 0.424 (to two significant figures)<\/p>\n<p id=\"fs-idm65589936\">(b) 0.0038661 (to three significant figures)<\/p>\n<p id=\"fs-idm107300848\">(c) 421.25 (to four significant figures)<\/p>\n<p id=\"fs-idm258155488\">(d) 28,683.5 (to five significant figures)<\/p>\n<div id=\"fs-idm155369456\" data-type=\"note\">\n<div style=\"text-align: right;\" data-type=\"title\"><\/div>\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a0(a) 0.42; (b) 0.00387; (c) 421.2; (d) 28,684<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Example 2<\/h3>\n<h4 id=\"fs-idm327587104\"><strong><span data-type=\"title\">Addition and Subtraction with Significant Figures<\/span><\/strong><\/h4>\n<p>Rule: When we add or subtract numbers, we should round the result to the same number of decimal places as the number with the least number of decimal places (i.e., the least precise value in terms of addition and subtraction).<\/p>\n<p id=\"fs-idm318611824\">(a) Add 1.0023 g and 4.383 g.<\/p>\n<p id=\"fs-idm288438480\">(b) Subtract 421.23 g from 486 g.<\/p>\n<h4 id=\"fs-idm277651872\"><strong><span data-type=\"title\">Solution<\/span><\/strong><\/h4>\n<p id=\"fs-idm21393952\">(a) [latex]\\begin{array}{l}\\\\ \\begin{array}{l}\\hfill \\\\ \\frac{\\begin{array}{c}\\phantom{\\rule{1.4em}{0ex}}1.0023 g\\\\ \\text{+ 4.383 g}\\end{array}}{\\phantom{\\rule{1.5em}{0ex}}5.3853 g}\\hfill \\end{array}\\end{array}[\/latex]<\/p>\n<p id=\"fs-idm107330240\">Answer is 5.385 g (round to the thousandths place; three decimal places)<\/p>\n<p id=\"fs-idm257863024\">(b) [latex]\\begin{array}{l}\\begin{array}{l}\\hfill \\\\ \\hfill \\end{array}\\\\ \\frac{\\begin{array}{l}\\text{}\\phantom{\\rule{0.8em}{0ex}}486 g\\hfill \\\\ -421.23 g\\hfill \\end{array}}{\\phantom{\\rule{1.3em}{0ex}}64.77 g}\\end{array}[\/latex]<\/p>\n<p id=\"fs-idp47889280\">Answer is 65 g (round to the ones place; no decimal places)<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210947\/CNX_Chem_01_05_SigDigits4_img1.jpg\" alt=\"Figure A shows 1.0023 being added to 4.383 to yield the answer 5.385. 1.0023 goes to the ten thousandths place, but 4.383 goes to the thousandths place, making it the less precise of the two numbers. Therefore the answer, 5.3853, should be rounded to the thousandths, to yield 5.385. Figure B shows 486 grams minus 421.23 grams, which yields the answer 64.77 grams. This answer should be round to the ones place, making the answer 65 grams.\" width=\"879\" height=\"188\" data-media-type=\"image\/jpeg\" \/><\/p>\n<h4 id=\"fs-idm97432976\"><strong><span data-type=\"title\">Check Your Learning<\/span><\/strong><\/h4>\n<p>(a) Add 2.334 mL and 0.31 mL.<\/p>\n<p id=\"fs-idm113279504\">(b) Subtract 55.8752 m from 56.533 m.<\/p>\n<div id=\"fs-idp26956096\" data-type=\"note\">\n<div data-type=\"title\"><\/div>\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a0(a) 2.64 mL; (b) 0.658 m<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-idp61408240\" data-type=\"example\">\n<div class=\"textbox shaded\">\n<h3>Example 3<\/h3>\n<div id=\"fs-idp61408240\" data-type=\"example\">\n<h4>Multiplication and Division with Significant Figures<\/h4>\n<\/div>\n<div id=\"fs-idp34148976\" data-type=\"example\">\n<p id=\"fs-idm194335568\">Rule: When we multiply or divide numbers, we should round the result to the same number of digits as the number with the least number of significant figures (the least precise value in terms of multiplication and division).<\/p>\n<p id=\"fs-idm176907440\">(a) Multiply 0.6238 cm by 6.6 cm.<\/p>\n<p id=\"fs-idp40092848\">(b) Divide 421.23 g by 486 mL.<\/p>\n<h4 id=\"fs-idm318303792\"><span data-type=\"title\">Solution<\/span><\/h4>\n<p id=\"fs-idp11052048\">(a) [latex]\\begin{array}{l}\\begin{array}{l}\\text{0.6238 cm}\\times 6.6\\text{cm}=4.11708{\\text{cm}}^{2}\\rightarrow\\text{result is}4.1{\\text{cm}}^{2}\\left(\\text{round to two significant figures}\\right)\\hfill \\\\ \\text{four significant figures}\\times \\text{two significant figures}\\rightarrow\\text{two significant figures answer}\\hfill \\end{array}\\hfill \\end{array}[\/latex]<\/p>\n<p id=\"fs-idm194468576\">(b) [latex]\\begin{array}{l}\\frac{\\text{421.23 g}}{\\text{486 mL}}=\\text{0.86728 g\/mL}\\rightarrow\\text{result is 0.867 g\/mL}\\left(\\text{round to three significant figures}\\right)\\\\ \\frac{\\text{five significant figures}}{\\text{three significant figures}}\\rightarrow\\text{three significant figures answer}\\end{array}[\/latex]<\/p>\n<h4 id=\"fs-idp45405152\"><span data-type=\"title\">Check Your Learning<\/span><\/h4>\n<p>(a) Multiply 2.334 cm and 0.320 cm.<\/p>\n<p id=\"fs-idm155228848\">(b) Divide 55.8752 m by 56.53 s.<\/p>\n<div id=\"fs-idm282773952\" data-type=\"note\">\n<div data-type=\"title\"><\/div>\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a0(a) 0.747 cm<sup>2<\/sup> (b) 0.9884 m\/s<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"fs-idp31178224\">In the midst of all these technicalities, it is important to keep in mind the reason why we use significant figures and rounding rules\u2014to correctly represent the certainty of the values we report and to ensure that a calculated result is not represented as being more certain than the least certain value used in the calculation.<\/p>\n<div class=\"textbox shaded\">\n<h3>Example 4<\/h3>\n<h4 id=\"fs-idm180409728\"><strong><span data-type=\"title\">Calculation with Significant Figures<\/span><\/strong><\/h4>\n<p>One common bathtub is 13.44 dm long, 5.920 dm wide, and 2.54 dm deep. Assume that the tub is rectangular and calculate its approximate volume in liters.<\/p>\n<h4 id=\"fs-idm209075984\"><span data-type=\"title\">Solution<\/span><\/h4>\n<div id=\"fs-idm15365184\" data-type=\"equation\">[latex]\\begin{array}{lll}V\\hfill & =\\hfill & l\\times w\\times d\\hfill \\\\ & =\\hfill & \\text{13.44 dm}\\times \\text{5.920 dm}\\times \\text{2.54 dm}\\hfill \\\\ & =\\hfill & \\text{202.09459} {\\text{dm}}^{3}\\left(\\text{value from calculator}\\right)\\hfill \\\\ & =\\hfill & {\\text{202 dm}}^{3}\\text{, or 202 L}\\left(\\text{answer rounded to three significant figures}\\right)\\hfill \\end{array}[\/latex]<\/div>\n<h4 id=\"fs-idm219800928\"><span data-type=\"title\">Check Your Learning<\/span><\/h4>\n<p>What is the density of a liquid with a mass of 31.1415 g and a volume of 30.13 cm<sup>3<\/sup>?<\/p>\n<div id=\"fs-idm178680064\" data-type=\"note\">\n<div data-type=\"title\"><\/div>\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a01.034 g\/mL<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-idp40680240\" data-type=\"example\">\n<div class=\"textbox shaded\">\n<h3>Example 5<\/h3>\n<section id=\"fs-idm191691888\" data-depth=\"1\">\n<div id=\"fs-idm148976192\" data-type=\"example\">\n<h4 id=\"fs-idp29940656\"><span data-type=\"title\">Experimental Determination of Density Using Water Displacement<\/span><\/h4>\n<p>A piece of rebar is weighed and then submerged in a graduated cylinder partially filled with water, with results as shown.<\/p>\n<p><span id=\"fs-idm332426528\" data-type=\"media\" data-alt=\"This diagram shows the initial volume of water in a graduated cylinder as 13.5 milliliters. A 69.658 gram piece of metal rebar is added to the graduated cylinder, causing the water to reach a final volume of 22.4 milliliters\"><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210949\/CNX_Chem_01_04_CylRebar1.jpg\" alt=\"This diagram shows the initial volume of water in a graduated cylinder as 13.5 milliliters. A 69.658 gram piece of metal rebar is added to the graduated cylinder, causing the water to reach a final volume of 22.4 milliliters\" width=\"880\" height=\"670\" data-media-type=\"image\/jpeg\" \/><\/span><\/p>\n<p id=\"fs-idm245394240\">(a) Use these values to determine the density of this piece of rebar.<\/p>\n<p id=\"fs-idm209220496\">(b) Rebar is mostly iron. Does your result in (a) support this statement? How?<\/p>\n<h4 id=\"fs-idm325787440\"><span data-type=\"title\">Solution<\/span><\/h4>\n<p>The volume of the piece of rebar is equal to the volume of the water displaced:<\/p>\n<div id=\"fs-idm180698816\" data-type=\"equation\">[latex]\\text{volume}=\\text{22.4 mL}-\\text{13.5 mL}=\\text{8.9 mL}={\\text{8.9 cm}}^{3}[\/latex]<\/div>\n<p id=\"fs-idm181276752\">(rounded to the nearest 0.1 mL, per the rule for addition and subtraction)<\/p>\n<p id=\"fs-idp36085040\">The density is the mass-to-volume ratio:<\/p>\n<div id=\"fs-idp135143440\" data-type=\"equation\">[latex]\\text{density}=\\frac{\\text{mass}}{\\text{volume}}=\\frac{\\text{69.658 g}}{{\\text{8.9 cm}}^{3}}={\\text{7.8 g\/cm}}^{3}[\/latex]<\/div>\n<p id=\"fs-idm277303296\">(rounded to two significant figures, per the rule for multiplication and division)<\/p>\n<p id=\"fs-idm243666944\">The density of iron is 7.9 g\/cm<sup>3<\/sup>, very close to that of rebar, which lends some support to the fact that rebar is mostly iron.<\/p>\n<h4 id=\"fs-idm259990592\"><strong><span data-type=\"title\">Check Your Learning<\/span><\/strong><\/h4>\n<p>An irregularly shaped piece of a shiny yellowish material is weighed and then submerged in a graduated cylinder, with results as shown.<\/p>\n<p><span id=\"fs-idm283007920\" data-type=\"media\" data-alt=\"This diagram shows the initial volume of water in a graduated cylinder as 17.1 milliliters. A 51.842 gram gold colored rock is added to the graduated cylinder, causing the water to reach a final volume of 19.8 milliliters\"><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210950\/CNX_Chem_01_04_CylGold1.jpg\" alt=\"This diagram shows the initial volume of water in a graduated cylinder as 17.1 milliliters. A 51.842 gram gold colored rock is added to the graduated cylinder, causing the water to reach a final volume of 19.8 milliliters\" width=\"881\" height=\"672\" data-media-type=\"image\/jpeg\" \/><\/span><\/p>\n<p id=\"fs-idm272657872\">(a) Use these values to determine the density of this material.<\/p>\n<p id=\"fs-idm166920160\">(b) Do you have any reasonable guesses as to the identity of this material? Explain your reasoning.<\/p>\n<div id=\"fs-idm113054800\" data-type=\"note\">\n<div style=\"text-align: right;\" data-type=\"title\"><\/div>\n<div style=\"text-align: right;\" data-type=\"title\"><strong>Answer<\/strong>:\u00a0(a) 19 g\/cm<sup>3<\/sup>; (b) It is likely gold; the right appearance for gold and very close to the density given for gold in &#8220;Measurements.&#8221;<\/div>\n<\/div>\n<\/div>\n<\/section>\n<\/div>\n<\/div>\n<div id=\"fs-idm148976192\" data-type=\"example\">\n<h2 id=\"fs-idp29940656\">Accuracy and Precision<\/h2>\n<\/div>\n<\/section>\n<section id=\"fs-idp33954960\" data-depth=\"1\">\n<p id=\"fs-idp4474304\">Scientists typically make repeated measurements of a quantity to ensure the quality of their findings and to know both the <strong><span data-type=\"term\">precision<\/span><\/strong> and the <strong><span data-type=\"term\">accuracy<\/span><\/strong> of their results. Measurements are said to be precise if they yield very similar results when repeated in the same manner. A measurement is considered accurate if it yields a result that is very close to the true or accepted value. Precise values agree with each other; accurate values agree with a true value. These characterizations can be extended to other contexts, such as the results of an archery competition (Figure 2).<\/p>\n<div style=\"width: 889px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210951\/CNX_Chem_01_05_Archery1.jpg\" alt=\"Figures A through C each show targets with holes where the arrows hit. The archer in figure A was both accurate and precise as all 3 arrows are clustered in the center of the target. In figure B, the archer is precise but not accurate, as all 3 arrows are clustered together but to the upper right of the center of the target. In Figure C, the archer is neither accurate nor precise as the 3 holes are not close together and are located both to the upper right and right of the target.\" width=\"879\" height=\"280\" data-media-type=\"image\/jpg\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 2. (a) These arrows are close to both the bull\u2019s eye and one another, so they are both accurate and precise. (b) These arrows are close to one another but not on target, so they are precise but not accurate. (c) These arrows are neither on target nor close to one another, so they are neither accurate nor precise.<\/p>\n<\/div>\n<p id=\"fs-idp174984224\">Suppose a quality control chemist at a pharmaceutical company is tasked with checking the accuracy and precision of three different machines that are meant to dispense 10 ounces (296 mL) of cough syrup into storage bottles. She proceeds to use each machine to fill five bottles and then carefully determines the actual volume dispensed, obtaining the results tabulated in Table 1.<\/p>\n<table id=\"fs-idp31780400\" class=\"span-all\" summary=\"The volume, in milliliters, of cough medicine delivered by dispensers 1, 2 and 3 are shown in a table. The values for dispenser 1 are 283.3, 284.1, 283.9, 284.0, and 284.1. The values for dispenser 2 are 298.3, 294.2, 296.0, 297.8, and 293.9. The values for dispenser 3 are 296.1, 295.9, 296.1, 296.0, and 296.1.\">\n<thead>\n<tr valign=\"top\">\n<th colspan=\"3\">Table 1. Volume (mL) of Cough Medicine Delivered by 10-oz (296 mL) Dispensers<\/th>\n<\/tr>\n<tr valign=\"top\">\n<th>Dispenser #1<\/th>\n<th>Dispenser #2<\/th>\n<th>Dispenser #3<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr valign=\"top\">\n<td>283.3<\/td>\n<td>298.3<\/td>\n<td>296.1<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td>284.1<\/td>\n<td>294.2<\/td>\n<td>295.9<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td>283.9<\/td>\n<td>296.0<\/td>\n<td>296.1<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td>284.0<\/td>\n<td>297.8<\/td>\n<td>296.0<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td>284.1<\/td>\n<td>293.9<\/td>\n<td>296.1<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p id=\"fs-idp4939264\">Considering these results, she will report that dispenser #1 is precise (values all close to one another, within a few tenths of a milliliter) but not accurate (none of the values are close to the target value of 296 mL, each being more than 10 mL too low). Results for dispenser #2 represent improved accuracy (each volume is less than 3 mL away from 296 mL) but worse precision (volumes vary by more than 4 mL). Finally, she can report that dispenser #3 is working well, dispensing cough syrup both accurately (all volumes within 0.1 mL of the target volume) and precisely (volumes differing from each other by no more than 0.2 mL).<\/p>\n<\/section>\n<section id=\"fs-idp223627024\" class=\"summary\" data-depth=\"1\">\n<section id=\"fs-idm40478192\" class=\"summary\" data-depth=\"1\">\n<div id=\"post-355\" class=\"post-355 chapter type-chapter status-publish hentry type-1\">\n<div class=\"entry-content\">\n<div class=\"im_section\">\n<div class=\"im_section\">\n<div id=\"mclean-ch03_s01_s02_n01\" class=\"im_key_takeaways im_editable im_block\">\n<div class=\"bcc-box bcc-success\">\n<h2>Key Concepts and Summary<\/h2>\n<section>\n<div data-type=\"note\">\n<p id=\"fs-idp236281408\">Quantities can be exact or measured. Measured quantities have an associated uncertainty that is represented by the number of significant figures in the measurement. The uncertainty of a calculated value depends on the uncertainties in the values used in the calculation and is reflected in how the value is rounded. Measured values can be accurate (close to the true value) and\/or precise (showing little variation when measured repeatedly).<\/p>\n<\/div>\n<\/section>\n<\/div>\n<div class=\"bcc-box bcc-info\">\n<h3>Chemistry End of Chapter Exercises<\/h3>\n<ol>\n<li>Express each of the following numbers in scientific notation with correct significant figures:\n<ol>\n<li>711.0<\/li>\n<li>0.239<\/li>\n<li>90743<\/li>\n<li>134.2<\/li>\n<li>0.05499<\/li>\n<li>10000.0<\/li>\n<li>0.000000738592<\/li>\n<\/ol>\n<\/li>\n<li>Express each of the following numbers in exponential notation with correct significant figures:\n<ol>\n<li>704<\/li>\n<li>0.03344<\/li>\n<li>547.9<\/li>\n<li>22086<\/li>\n<li>1000.00<\/li>\n<li>0.0000000651<\/li>\n<li>0.007157<\/li>\n<\/ol>\n<\/li>\n<li>Indicate whether each of the following can be determined exactly or must be measured with some degree of uncertainty:\n<ol>\n<li>the number of eggs in a basket<\/li>\n<li>the mass of a dozen eggs<\/li>\n<li>the number of gallons of gasoline necessary to fill an automobile gas tank<\/li>\n<li>the number of cm in 2 m<\/li>\n<li>the mass of a textbook<\/li>\n<li>the time required to drive from San Francisco to Kansas City at an average speed of 53 mi\/h<\/li>\n<\/ol>\n<\/li>\n<li>Indicate whether each of the following can be determined exactly or must be measured with some degree of uncertainty:\n<ol>\n<li>the number of seconds in an hour<\/li>\n<li>the number of pages in this book<\/li>\n<li>the number of grams in your weight<\/li>\n<li>the number of grams in 3 kilograms<\/li>\n<li>the volume of water you drink in one day<\/li>\n<li>the distance from San Francisco to Kansas City<\/li>\n<\/ol>\n<\/li>\n<li>How many significant figures are contained in each of the following measurements?\n<ol>\n<li>38.7 g<\/li>\n<li>2 \u00d7 10<sup>18<\/sup> m<\/li>\n<li>3,486,002 kg<\/li>\n<li>9.74150 \u00d7 10<sup>-4<\/sup> J<\/li>\n<li>0.0613 cm<sup>3 \u00a0\u00a0<\/sup><\/li>\n<li>17.0 kg<\/li>\n<li>0.01400 g\/mL<\/li>\n<\/ol>\n<\/li>\n<li>How many significant figures are contained in each of the following measurements?\n<ol>\n<li>53 cm<\/li>\n<li>2.05 \u00d7 10<sup>8<\/sup> m<\/li>\n<li>86,002 J<\/li>\n<li>9.740 \u00d7 10<sup>4<\/sup> m\/s<\/li>\n<li>10.0613 m<sup>3 \u00a0\u00a0<\/sup><\/li>\n<li>0.17 g\/mL<\/li>\n<li>0.88400 s<\/li>\n<\/ol>\n<\/li>\n<li>The following quantities were reported on the labels of commercial products. Determine the number of significant figures in each.\n<ol>\n<li>0.0055 g active ingredients<\/li>\n<li>12 tablets<\/li>\n<li>3% hydrogen peroxide<\/li>\n<li>5.5 ounces<\/li>\n<li>473 mL<\/li>\n<li>1.75% bismuth<\/li>\n<li>0.001% phosphoric acid<\/li>\n<li>99.80% inert ingredients<\/li>\n<\/ol>\n<\/li>\n<li>Round off each of the following numbers to two significant figures:\n<ol>\n<li>0.436<\/li>\n<li>9.000<\/li>\n<li>27.2<\/li>\n<li>135<\/li>\n<li>1.497 \u00d7 10<sup>-3 \u00a0\u00a0<\/sup><\/li>\n<li>0.445<\/li>\n<\/ol>\n<\/li>\n<li>Round off each of the following numbers to two significant figures:\n<ol>\n<li>517<\/li>\n<li>86.3<\/li>\n<li>6.382 \u00d7 10<sup>3 \u00a0\u00a0<\/sup><\/li>\n<li>5.0008<\/li>\n<li>22.497<\/li>\n<li>0.885<\/li>\n<\/ol>\n<\/li>\n<li>Perform the following calculations and report each answer with the correct number of significant figures.\n<ol>\n<li>628 \u00d7 342<\/li>\n<li>(5.63 \u00d7 10<sup>2<\/sup>) \u00d7 (7.4 \u00d7 10<sup>3<\/sup>)<\/li>\n<li>[latex]\\frac{28.0}{13.483}[\/latex]<\/li>\n<li>8119 \u00d7 0.000023<\/li>\n<li>14.98 + 27,340 + 84.7593<\/li>\n<li>42.7 + 0.259<\/li>\n<\/ol>\n<\/li>\n<li>Perform the following calculations and report each answer with the correct number of significant figures.\n<ol>\n<li>62.8 \u00d7 34<\/li>\n<li>0.147 + 0.0066 + 0.012<\/li>\n<li>38 \u00d7 95 \u00d7 1.792<\/li>\n<li>15 \u2013 0.15 \u2013 0.6155<\/li>\n<li>[latex]8.78\\times \\left(\\frac{0.0500}{0.478}\\right)[\/latex]<\/li>\n<li>140 + 7.68 + 0.014<\/li>\n<li>28.7 \u2013 0.0483<\/li>\n<li>[latex]\\frac{\\left(88.5-87.57\\right)}{45.13}[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>Consider the results of the archery contest shown in this figure.\n<ol>\n<li>Which archer is most precise?<\/li>\n<li>Which archer is most accurate?<\/li>\n<li>Who is both least precise and least accurate?\n<div id=\"fs-idp30946992\" data-type=\"exercise\">\n<div id=\"fs-idp4924640\" data-type=\"problem\">\n<p><span id=\"fs-idp94481888\" data-type=\"media\" data-alt=\"4 targets are shown each with 4 holes indicating where the arrows hit the targets. Archer W put all 4 arrows closely around the center of the target. Archer X put all 4 arrows in a tight cluster but far to the lower right of the target. Archer Y put all 4 arrows at different corners of the target. All 4 arrows are very far from the center of the target. Archer Z put 2 arrows close to the target and 2 other arrows far outside of the target.\"> <img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23210953\/CNX_Chem_01_05_Archer2_img1.jpg\" alt=\"4 targets are shown each with 4 holes indicating where the arrows hit the targets. Archer W put all 4 arrows closely around the center of the target. Archer X put all 4 arrows in a tight cluster but far to the lower right of the target. Archer Y put all 4 arrows at different corners of the target. All 4 arrows are very far from the center of the target. Archer Z put 2 arrows close to the target and 2 other arrows far outside of the target.\" width=\"840\" height=\"324\" data-media-type=\"image\/jpeg\" \/><\/span><\/p>\n<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/li>\n<li>Classify the following sets of measurements as accurate, precise, both, or neither.\n<ol>\n<li>Checking for consistency in the weight of chocolate chip cookies: 17.27g, 13.05g, 19.46g, 16.92g<\/li>\n<li>Testing the volume of a batch of 25-mL pipettes: 27.02 mL, 26.99 mL, 26.97 mL, 27.01 mL<\/li>\n<li>Determining the purity of gold: 99.9999%, 99.9998%, 99.9998%, 99.9999%<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"post-355\" class=\"post-355 chapter type-chapter status-publish hentry type-1\">\n<div class=\"entry-content\">\n<div class=\"im_section\">\n<div class=\"im_section\">\n<div id=\"mclean-ch03_s01_s02_n01\" class=\"im_key_takeaways im_editable im_block\">\n<div class=\"bcc-box bcc-info\">\n<h4>Selected Answers<\/h4>\n<p>2.\u00a0(a) 7.04 \u00d7 10<sup>2<\/sup>; (b) 3.344 \u00d7 10<sup>-2<\/sup>; (c) 5.479 \u00d7 10<sup>2<\/sup>; (d) 2.2086 \u00d7 10<sup>4<\/sup>; (e) 1.00000 \u00d7 10<sup>3<\/sup>; (f) 6.51 \u00d7 10<sup>-8<\/sup>; (g) 7.157 \u00d7 10<sup>-3<\/sup><\/p>\n<p>4.\u00a0(a) exact; (b) exact; (c) uncertain; (d) exact; (e) uncertain; (f) uncertain<\/p>\n<p>6. (a) two; (b) three; (c) five; (d) four; (e) six; (f) two; (g) five<\/p>\n<p>8.\u00a0(a) 0.44; (b) 9.0; (c) 27; (d) 140; (e) 1.5 \u00d7 10<sup>-3<\/sup>; (f) 0.44<\/p>\n<p>10.\u00a0(a) 2.15 \u00d7 10<sup>5<\/sup>; (b) 4.2 \u00d7 10<sup>6<\/sup>; (c) 2.08; (d) 0.19; (e) 27,440; (f) 43.0<\/p>\n<p>12.\u00a0(a) Archer X; (b) Archer W; (c) Archer Y<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/section>\n<div class=\"bcc-box bcc-success\">\n<h3>Glossary<\/h3>\n<p><strong>accuracy<\/strong><br \/>\nhow closely a measurement aligns with a correct value<\/p>\n<p><strong>exact number<\/strong><br \/>\nnumber derived by counting or by definition&lt;<\/p>\n<p><strong>precision<\/strong><br \/>\nhow closely a measurement matches the same measurement when repeated<\/p>\n<p><strong>rounding<\/strong><br \/>\nprocedure used to ensure that calculated results properly reflect the uncertainty in the measurements used in the calculation<\/p>\n<p><strong>significant figures<\/strong><br \/>\n(also, significant digits) all of the measured digits in a determination, including the uncertain last digit<\/p>\n<p><strong>uncertainty<\/strong><br \/>\nestimate of amount by which measurement differs from true value<\/p>\n<\/div>\n<\/section>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1546\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Chemistry. <strong>Provided by<\/strong>: OpenStax College. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/openstaxcollege.org\">http:\/\/openstaxcollege.org<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at https:\/\/openstaxcollege.org\/textbooks\/chemistry\/get<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":5,"menu_order":11,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Chemistry\",\"author\":\"\",\"organization\":\"OpenStax College\",\"url\":\"http:\/\/openstaxcollege.org\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at https:\/\/openstaxcollege.org\/textbooks\/chemistry\/get\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1546","chapter","type-chapter","status-publish","hentry"],"part":3042,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/pressbooks\/v2\/chapters\/1546","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/wp\/v2\/users\/5"}],"version-history":[{"count":10,"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/pressbooks\/v2\/chapters\/1546\/revisions"}],"predecessor-version":[{"id":5085,"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/pressbooks\/v2\/chapters\/1546\/revisions\/5085"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/pressbooks\/v2\/parts\/3042"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/pressbooks\/v2\/chapters\/1546\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/wp\/v2\/media?parent=1546"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/pressbooks\/v2\/chapter-type?post=1546"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/wp\/v2\/contributor?post=1546"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-buffstate-chemistryformajorsxmaster\/wp-json\/wp\/v2\/license?post=1546"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}