Lewis Symbols

We use Lewis symbols to describe valence electron configurations of atoms and monatomic ions. A Lewis symbol consists of an elemental symbol surrounded by one dot for each of its valence electrons:

Figure 1 shows the Lewis symbols for the elements of the third period of the periodic table.

Figure 1. Lewis symbols illustrating the number of valence electrons for each element in the third period of the periodic table.

Lewis symbols can also be used to illustrate the formation of cations from atoms, as shown here for sodium and calcium:

Likewise, they can be used to show the formation of anions from atoms, as shown below for chlorine and sulfur:

Figure 2 demonstrates the use of Lewis symbols to show the transfer of electrons during the formation of ionic compounds.

Figure 2. Cations are formed when atoms lose electrons, represented by fewer Lewis dots, whereas anions are formed by atoms gaining electrons. The total number of electrons does not change.

Lewis Structures

We also use Lewis symbols to indicate the formation of covalent bonds, which are shown in Lewis structures, drawings that describe the bonding in molecules and polyatomic ions. For example, when two chlorine atoms form a chlorine molecule, they share one pair of electrons:

The Lewis structure indicates that each Cl atom has three pairs of electrons that are not used in bonding (called lone pairs) and one shared pair of electrons (written between the atoms). A dash (or line) is sometimes used to indicate a shared pair of electrons:

A single shared pair of electrons is called a single bond. Each Cl atom interacts with eight valence electrons: the six in the lone pairs and the two in the single bond.

Writing Lewis Structures with the Octet Rule

For very simple molecules and molecular ions, we can write the Lewis structures by merely pairing up the unpaired electrons on the constituent atoms. See these examples:

For more complicated molecules and molecular ions, it is helpful to follow the step-by-step procedure outlined here:

1. Determine the total number of valence (outer shell) electrons. For cations, subtract one electron for each positive charge. For anions, add one electron for each negative charge.
2. Draw a skeleton structure of the molecule or ion, arranging the atoms around a central atom. (Generally, the least electronegative element should be placed in the center.) Connect each atom to the central atom with a single bond (one electron pair).
3. Distribute the remaining electrons as lone pairs on the terminal atoms (except hydrogen), completing an octet around each atom.
4. Place all remaining electrons on the central atom.
5. Rearrange the electrons of the outer atoms to make multiple bonds with the central atom in order to obtain octets wherever possible.

Let us determine the Lewis structures of SiH₄, [latex]{\text{CHO}}_{2}{}^{-},[/latex] NO⁺, and OF₂ as examples in following this procedure:

1. Determine the total number of valence (outer shell) electrons in the molecule or ion.
   • For a molecule, we add the number of valence electrons on each atom in the molecule:
     [latex]\begin{array}{l}\\ \phantom{\rule{0.8em}{0ex}}{\text{SiH}}_{4}\\ \phantom{\rule{0.8em}{0ex}}\text{Si: 4 valence electrons/atom}\times \text{1 atom}=4\\ \underline{+\text{H: 1 valence electron/atom}\times \text{4 atoms}=4}\\ \\ \phantom{\rule{15.95em}{0ex}}=\text{8 valence electrons}\end{array}[/latex]
   • For a negative ion, such as [latex]{\text{CHO}}_{2}{}^{\text{-}},[/latex] we add the number of valence electrons on the atoms to the number of negative charges on the ion (one electron is gained for each single negative charge):
     [latex]\begin{array}{l}\\ {\text{CHO}}_{2}{}^{-}\\ \phantom{\rule{0.48em}{0ex}}\text{C: 4 valence electrons/atom}\times \text{1 atom}=4\\ \phantom{\rule{0.8em}{0ex}}\text{H: 1 valence electron/atom}\times \text{1 atom}=1\\ \phantom{\rule{0.05em}{0ex}}\text{O: 6 valence electrons/atom}\times \text{2 atoms}=12\\ \underline{+\phantom{\rule{6.5em}{0ex}}\text{1 additional electron}=1}\\ \\ \phantom{\rule{15.45em}{0ex}}=\text{18 valence electrons}\end{array}[/latex]
   • For a positive ion, such as NO⁺, we add the number of valence electrons on the atoms in the ion and then subtract the number of positive charges on the ion (one electron is lost for each single positive charge) from the total number of valence electrons:
     [latex]\begin{array}{l}\\ \\ {\text{NO}}^{+}\\ \text{N: 5 valence electrons/atom}\times \text{1 atom}=5\\ \\ \phantom{\rule{0.4em}{0ex}}\text{O: 6 valence electron/atom}\times \text{1 atom}=6\\ \phantom{\rule{0.35em}{0ex}}\underline{+\text{-1 electron (positive charge)}\phantom{\rule{1.8em}{0ex}}=-1}\\ \\ \phantom{\rule{15.02em}{0ex}}=\text{10 valence electrons}\end{array}[/latex]
   • Since OF₂ is a neutral molecule, we simply add the number of valence electrons:
     [latex]\begin{array}{l}\\ \phantom{\rule{0.8em}{0ex}}{\text{OF}}_{\text{2}}\\ \phantom{\rule{1.25em}{0ex}}\text{O: 6 valence electrons/atom}\times \text{1 atom}=6\\ \underline{+\text{F: 7 valence electrons/atom}\times \text{2 atoms}=14}\\ \phantom{\rule{16.28em}{0ex}}=\text{20 valence electrons}\end{array}[/latex]
2. Draw a skeleton structure of the molecule or ion, arranging the atoms around a central atom and connecting each atom to the central atom with a single (one electron pair) bond. (Note that we denote ions with brackets around the structure, indicating the charge outside the brackets:)
   

   When several arrangements of atoms are possible, as for [latex]{\text{CHO}}_{2}{}^{-},[/latex] we must use experimental evidence to choose the correct one. In general, the less electronegative elements are more likely to be central atoms. In [latex]{\text{CHO}}_{2}{}^{-},[/latex] the less electronegative carbon atom occupies the central position with the oxygen and hydrogen atoms surrounding it. Other examples include P in POCl₃, S in SO₂, and Cl in [latex]{\text{ClO}}_{4}{}^{-}.[/latex] An exception is that hydrogen is almost never a central atom. As the most electronegative element, fluorine also cannot be a central atom.

3. Distribute the remaining electrons as lone pairs on the terminal atoms (except hydrogen) to complete their valence shells with an octet of electrons.
   • There are no remaining electrons on SiH₄, so it is unchanged:
     
4. Place all remaining electrons on the central atom.
   • For SiH₄, [latex]{\text{CHO}}_{2}{}^{-},[/latex] and NO⁺, there are no remaining electrons; we already placed all of the electrons determined in Step 1.
   • For OF₂, we had 16 electrons remaining in Step 3, and we placed 12, leaving 4 to be placed on the central atom:
     
5. Rearrange the electrons of the outer atoms to make multiple bonds with the central atom in order to obtain octets wherever possible.
   • SiH₄: Si already has an octet, so nothing needs to be done.
   • [latex]{\text{CHO}}_{2}{}^{-}:[/latex] We have distributed the valence electrons as lone pairs on the oxygen atoms, but one oxygen atom and one carbon atom lack octets:
   • NO⁺: For this ion, we added eight valence electrons, but neither atom has an octet. We cannot add any more electrons since we have already used the total that we found in Step 1, so we must move electrons to form a multiple bond:
     

     This still does not produce an octet, so we must move another pair, forming a triple bond:
     

   • In OF₂, each atom has an octet as drawn, so nothing changes.

Fullerene Chemistry

Figure 3. Richard Smalley (1943–2005). (credit: United States Department of Energy)

Carbon soot has been known to man since prehistoric times, but it was not until fairly recently that the molecular structure of the main component of soot was discovered. In 1996, the Nobel Prize in Chemistry was awarded to Richard Smalley (Figure 3), Robert Curl, and Harold Kroto for their work in discovering a new form of carbon, the C₆₀ buckminsterfullerene molecule. An entire class of compounds, including spheres and tubes of various shapes, were discovered based on C_60. This type of molecule, called a fullerene, shows promise in a variety of applications. Because of their size and shape, fullerenes can encapsulate other molecules, so they have shown potential in various applications from hydrogen storage to targeted drug delivery systems. They also possess unique electronic and optical properties that have been put to good use in solar powered devices and chemical sensors.

Richard Smalley, a professor of physics, chemistry, and astronomy at Rice University, was one of the leading advocates for fullerene chemistry. Upon his death in 2005, the U.S. Senate honored him as the “Father of Nanotechnology.”

Exceptions to the Octet Rule

Many covalent molecules have central atoms that do not have eight electrons in their Lewis structures. These molecules fall into three categories:

• Odd-electron molecules have an odd number of valence electrons, and therefore have an unpaired electron.
• Electron-deficient molecules have a central atom that has fewer electrons than needed for a noble gas configuration.
• Hypervalent molecules have a central atom that has more electrons than needed for a noble gas configuration.

Hypervalent Molecules

Elements in the second period of the periodic table (n = 2) can accommodate only eight electrons in their valence shell orbitals because they have only four valence orbitals (one 2s and three 2p orbitals). Elements in the third and higher periods (n ≥ 3) have more than four valence orbitals and can share more than four pairs of electrons with other atoms because they have empty d orbitals in the same shell. Molecules formed from these elements are sometimes called hypervalent molecules. Figure 4 shows the Lewis structures for two hypervalent molecules, PCl₅ and SF_6.

Figure 4. In PCl5, the central atom phosphorus shares five pairs of electrons. In SF6, sulfur shares six pairs of electrons.

In some hypervalent molecules, such as IF₅ and XeF₄, some of the electrons in the outer shell of the central atom are lone pairs:

When we write the Lewis structures for these molecules, we find that we have electrons left over after filling the valence shells of the outer atoms with eight electrons. These additional electrons must be assigned to the central atom.

Example 2

Writing Lewis Structures: Octet Rule Violations

Xenon is a noble gas, but it forms a number of stable compounds. We examined XeF₄ earlier. What are the Lewis structures of XeF₂ and XeF₆?

Solution

We can draw the Lewis structure of any covalent molecule by following the six steps discussed earlier. In this case, we can condense the last few steps, since not all of them apply.

1. Calculate the number of valence electrons:XeF₂: 8 + (2 × 7) = 22XeF₆: 8 + (6 × 7) = 50
2. Draw a skeleton joining the atoms by single bonds. Xenon will be the central atom because fluorine cannot be a central atom:
   
3. Distribute the remaining electrons.XeF₂: We place three lone pairs of electrons around each F atom, accounting for 12 electrons and giving each F atom 8 electrons. Thus, six electrons (three lone pairs) remain. These lone pairs must be placed on the Xe atom. This is acceptable because Xe atoms have empty valence shell d orbitals and can accommodate more than eight electrons. The Lewis structure of XeF₂ shows two bonding pairs and three lone pairs of electrons around the Xe atom:
   
   XeF₆: We place three lone pairs of electrons around each F atom, accounting for 36 electrons. Two electrons remain, and this lone pair is placed on the Xe atom:
   

Check Your Learning

The halogens form a class of compounds called the interhalogens, in which halogen atoms covalently bond to each other. Write the Lewis structures for the interhalogens BrCl₃ and [latex]{\text{ICl}}_{4}{}^{-}.[/latex]

Answer:

 

Key Concepts and Summary

Valence electronic structures can be visualized by drawing Lewis symbols (for atoms and monatomic ions) and Lewis structures (for molecules and polyatomic ions). Lone pairs, unpaired electrons, and single, double, or triple bonds are used to indicate where the valence electrons are located around each atom in a Lewis structure. Most structures—especially those containing second row elements—obey the octet rule, in which every atom (except H) is surrounded by eight electrons. Exceptions to the octet rule occur for odd-electron molecules (free radicals), electron-deficient molecules, and hypervalent molecules.

Chemistry End of Chapter Exercises

1. Write the Lewis symbols for each of the following ions:
   1. As^3–  
   2. I^–
   3. Be²⁺  
   4. O^2– 
   5. Ga³⁺ 
   6. Li⁺  
   7. N^3–
2. Many monatomic ions are found in seawater, including the ions formed from the following list of elements. Write the Lewis symbols for the monatomic ions formed from the following elements:
   1. Cl
   2. Na
   3. Mg
   4. Ca
   5. K
   6. Br
   7. Sr
   8. F
3. Write the Lewis symbols of the ions in each of the following ionic compounds and the Lewis symbols of the atom from which they are formed:
   1. MgS
   2. Al₂O₃ 
   3. GaCl₃ 
   4. K₂O
   5. Li₃N
   6. KF
4. In the Lewis structures listed below, M and X represent various elements in the third period of the periodic table. Write the formula of each compound using the chemical symbols of each element:
   1. 
   2. 
   3. 
   4. 
5. Write the Lewis structure for the diatomic molecule P₂, an unstable form of phosphorus found in high-temperature phosphorus vapor.
6. Write Lewis structures for the following:
   1. H₂ 
   2. HBr
   3. PCl₃ 
   4. SF₂ 
   5. H₂CCH₂ 
   6. HNNH
   7. H₂CNH
   8. NO^– 
   9. N₂ 
   10. CO
   11. CN^–
7. Write Lewis structures for the following:
   1. O₂ 
   2. H₂CO
   3. AsF₃ 
   4. ClNO
   5. SiCl₄ 
   6. H₃O⁺ 
   7. [latex]{\text{NH}}_{4}{}^{+}[/latex]
   8. [latex]{\text{BF}}_{4}{}^{-}[/latex]
   9. HCCH
   10. ClCN (k) [latex]{\text{C}}_{2}{}^{\text{2+}}[/latex]
8. Write Lewis structures for the following:
   1. ClF₃ 
   2. PCl₅ 
   3. BF₃ 
   4. [latex]{\text{PF}}_{6}{}^{-}[/latex]
9. Write Lewis structures for the following:
   1. SeF₆ 
   2. XeF₄ 
   3. [latex]{\text{SeCl}}_{3}{}^{+}[/latex]
   4. Cl₂BBCl₂ (contains a B–B bond)
10. Write Lewis structures for:
    1. [latex]{\text{PO}}_{4}{}^{\text{3-}}[/latex]
    2. [latex]{\text{IC}}_{4}{}^{-}[/latex]
    3. [latex]{\text{SO}}_{3}{}^{\text{2-}}[/latex]
    4. HONO
11. Correct the following statement: “The bonds in solid PbCl₂ are ionic; the bond in a HCl molecule is covalent. Thus, all of the valence electrons in PbCl₂ are located on the Cl^– ions, and all of the valence electrons in a HCl molecule are shared between the H and Cl atoms.”
12. Write Lewis structures for the following molecules or ions:
    1. SbH₃ 
    2. XeF₂ 
    3. Se₈ (a cyclic molecule with a ring of eight Se atoms)
13. Methanol, H₃COH, is used as the fuel in some race cars. Ethanol, C₂H₅OH, is used extensively as motor fuel in Brazil. Both methanol and ethanol produce CO₂ and H₂O when they burn. Write the chemical equations for these combustion reactions using Lewis structures instead of chemical formulas.
14. Many planets in our solar system contain organic chemicals including methane (CH₄) and traces of ethylene (C₂H₄), ethane (C₂H₆), propyne (H₃CCCH), and diacetylene (HCCCCH). Write the Lewis structures for each of these molecules.
15. Carbon tetrachloride was formerly used in fire extinguishers for electrical fires. It is no longer used for this purpose because of the formation of the toxic gas phosgene, Cl₂CO. Write the Lewis structures for carbon tetrachloride and phosgene.
16. Identify the atoms that correspond to each of the following electron configurations. Then, write the Lewis symbol for the common ion formed from each atom:
    1. 1s²2s²2p⁵ 
    2. 1s²2s²2p⁶3s² 
    3. 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰ 
    4. 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁴ 
    5. 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p¹
17. The arrangement of atoms in several biologically important molecules is given below. Complete the Lewis structures of these molecules by adding multiple bonds and lone pairs. Do not add any more atoms.
    1. the amino acid serine:
       
    2. urea:
       
    3. pyruvic acid:
       
    4. uracil:
       
    5. carbonic acid:
       
18. A compound with a molar mass of about 28 g/mol contains 85.7% carbon and 14.3% hydrogen by mass. Write the Lewis structure for a molecule of the compound.
19. A compound with a molar mass of about 42 g/mol contains 85.7% carbon and 14.3% hydrogen by mass. Write the Lewis structure for a molecule of the compound.
20. Two arrangements of atoms are possible for a compound with a molar mass of about 45 g/mol that contains 52.2% C, 13.1% H, and 34.7% O by mass. Write the Lewis structures for the two molecules.
21. How are single, double, and triple bonds similar? How do they differ?

Selected Answers

1. (a) eight electrons:

(b) eight electrons:

(c) no electrons   Be²⁺

(d) eight electrons:

(e) no electrons   Ga³⁺

(f) no electrons   Li⁺

(g) eight electrons:

3. (a)

(b)

(c)

(d)

(e)

(f)

5.

 

7. (a)

In this case, the Lewis structure is inadequate to depict the fact that experimental studies have shown two unpaired electrons in each oxygen molecule.

(b)

(c)

(d)

(e)

(f)

(g)

(h)

(i)

(j)

(k)

 

9.  (a) SeF₆:

(b) XeF₄:

(c) [latex]{\text{SeCl}}_{3}{}^{+}:[/latex]

(d) Cl₂BBCl₂:

11. Two valence electrons per Pb atom are transferred to Cl atoms; the resulting Pb²⁺ ion has a 6s² valence shell configuration. Two of the valence electrons in the HCl molecule are shared, and the other six are located on the Cl atom as lone pairs of electrons.

13.  

15.

17.  (a)

(b)

(c)

(d)

(e)

 

19. A 100.0-g sample of this compound would contain 85.7 g C and 14.3 g H:

[latex]\begin{array}{l}\frac{85.7\text{g}}{12.011{\text{g mol}}^{-1}}=7.14\text{mol C}\\ \frac{14.3\text{g}}{1.00794{\text{g mol}}^{-1}}=14.19\text{mol H}\end{array}.[/latex]

This is a ratio of 2 H to 1 C, or an empirical formula of CH₂ with a formula mass of approximately 14. As [latex]\frac{42}{14}=3,[/latex] the formula is 3 × CH₂ or C₃H₆. The Lewis structure is:

 

21. Each bond includes a sharing of electrons between atoms. Two electrons are shared in a single bond; four electrons are shared in a double bond; and six electrons are shared in a triple bond.

Glossary

double bond
covalent bond in which two pairs of electrons are shared between two atoms

free radical
molecule that contains an odd number of electrons

hypervalent molecule
molecule containing at least one main group element that has more than eight electrons in its valence shell

Lewis structure
diagram showing lone pairs and bonding pairs of electrons in a molecule or an ion

Lewis symbol
symbol for an element or monatomic ion that uses a dot to represent each valence electron in the element or ion

lone pair
two (a pair of) valence electrons that are not used to form a covalent bond

octet rule
guideline that states main group atoms will form structures in which eight valence electrons interact with each nucleus, counting bonding electrons as interacting with both atoms connected by the bond

single bond
bond in which a single pair of electrons is shared between two atoms

triple bond
bond in which three pairs of electrons are shared between two atoms