{"id":1333,"date":"2021-02-19T19:15:57","date_gmt":"2021-02-19T19:15:57","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/?post_type=chapter&#038;p=1333"},"modified":"2021-02-25T20:42:30","modified_gmt":"2021-02-25T20:42:30","slug":"exercises-8","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/chapter\/exercises-8\/","title":{"raw":"Exercises","rendered":"Exercises"},"content":{"raw":"<strong><span style=\"text-decoration: underline\">Part I<\/span><\/strong>\r\n<ol>\r\n \t<li id=\"fs-idm228245568\">Explain why the symbol for an atom of the element oxygen and the formula for a molecule of oxygen differ.<\/li>\r\n \t<li>Explain why the symbol for the element sulfur and the formula for a molecule of sulfur differ.<\/li>\r\n \t<li>Write the molecular and empirical formulas of the following compounds:\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211040\/CNX_Chem_02_04_Question3a_img1.jpg\" alt=\"Figure A shows a carbon atom that forms two, separate double bonds with two oxygen atoms.\" \/><\/li>\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211041\/CNX_Chem_02_04_Question3b_img1.jpg\" alt=\"Figure B shows a hydrogen atom which forms a single bond with a carbon atom. The carbon atom forms a triple bond with another carbon atom. The second carbon atom forms a single bond with a hydrogen atom.\" \/><\/li>\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211042\/CNX_Chem_02_04_Question3c_img1.jpg\" alt=\"Figure C shows a carbon atom forming a double bond with another carbon atom. Each carbon atom forms a single bond with two hydrogen atoms.\" \/><\/li>\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211043\/CNX_Chem_02_04_Question3d_img1.jpg\" alt=\"Figure D shows a sulfur atom forming single bonds with four oxygen atoms. Two of the oxygen atoms form a single bond with a hydrogen atom.\" \/><\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Write the molecular and empirical formulas of the following compounds:\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211044\/CNX_Chem_02_04_Question4a_img1.jpg\" alt=\"Figure A shows a structural diagram of four carbon atoms bonded together into a chain. The two carbon atoms on the left form a double bond with each other. All of the remaining carbon atoms form single bonds with each other. The leftmost carbon also forms single bonds with two hydrogen. The second carbon in the chain forms a single bond with a hydrogen atom. The third carbon in the chain forms a single bond with two hydrogen atoms each. The rightmost carbon forms a single bond with three hydrogen atoms each.\" \/><\/li>\r\n \t<li><img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211045\/CNX_Chem_02_04_Question4b_img1.jpg\" alt=\"Figure B shows a structural diagram of a molecule that has a chain of four carbon atoms. The leftmost carbon atom forms a single bond with three hydrogen atoms each and single bond with the second carbon atom. The second carbon atom forms a triple bond with the third carbon atom. The third carbon atom forms a single bond to the fourth carbon atom. The fourth carbon atom forms a single bond to three hydrogen atoms each.\" width=\"325\" height=\"142\" \/><\/li>\r\n \t<li><img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211046\/CNX_Chem_02_04_Question4c_img1.jpg\" alt=\"Figure C shows a structural diagram of two silicon atoms are bonded together with a single bond. Each of the silicon atoms form single bonds to two chlorine atoms each and one hydrogen atom.\" width=\"325\" height=\"142\" \/><\/li>\r\n \t<li><img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211048\/CNX_Chem_02_04_Question4d_img1.jpg\" alt=\"Figure D shows a structural diagram of a phosphorus atom that forms a single bond to four oxygen atoms each. Three of the oxygen atoms each have a single bond to a hydrogen atom.\" width=\"325\" height=\"142\" \/><\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Determine the empirical formulas for the following compounds:\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>caffeine, C<sub>8<\/sub>H<sub>10<\/sub>N<sub>4<\/sub>O<sub>2 \u00a0<\/sub><\/li>\r\n \t<li>fructose, C<sub>12<\/sub>H<sub>22<\/sub>O<sub>11 \u00a0<\/sub><\/li>\r\n \t<li>hydrogen peroxide, H<sub>2<\/sub>O<sub>2 \u00a0<\/sub><\/li>\r\n \t<li>glucose, C<sub>6<\/sub>H<sub>12<\/sub>O<sub>6 \u00a0<\/sub><\/li>\r\n \t<li>ascorbic acid (vitamin C), C<sub>6<\/sub>H<sub>8<\/sub>O<sub>6<\/sub><\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Determine the empirical formulas for the following compounds:\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>acetic acid, C<sub>2<\/sub>H<sub>4<\/sub>O<sub>2 \u00a0<\/sub><\/li>\r\n \t<li>citric acid, C<sub>6<\/sub>H<sub>8<\/sub>O<sub>7 \u00a0\u00a0<\/sub><\/li>\r\n \t<li>hydrazine, N<sub>2<\/sub>H<sub>4 \u00a0\u00a0<\/sub><\/li>\r\n \t<li>nicotine, C<sub>10<\/sub>H<sub>14<\/sub>N<sub>2 \u00a0\u00a0<\/sub><\/li>\r\n \t<li>butane, C<sub>4<\/sub>H<sub>10<\/sub><\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Write the empirical formulas for the following compounds:\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211049\/CNX_Chem_02_04_Question7a_img1.jpg\" alt=\"Figure A shows a structural diagram of two carbon atoms that form a single bond with each other. The left carbon atom forms single bonds with hydrogen atoms each. The right carbon forms a double bond to an oxygen atom. The right carbon also forms a single bonded to another oxygen atom. This oxygen atom also forms a single bond to a hydrogen atom.\" \/><\/li>\r\n \t<li><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211050\/CNX_Chem_02_04_Question7b_img1.jpg\" alt=\"Figure B shows a structural diagram containing a leftmost carbon that forms single bonds to three hydrogen atoms each. This leftmost carbon also forms a single bond to a second carbon atom. The second carbon atom forms a double bond with an oxygen atom. The second carbon also forms a single bond to a second oxygen atom. This oxygen atom forms a single bond to a third carbon atom. This third carbon atom forms single bonds with two hydrogen atoms each as well as a single bond with another carbon atom. The rightmost carbon atom forms a single bond with three hydrogen atoms each.\" \/><\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"317029\"]Show Selected Answers[\/reveal-answer]\r\n[hidden-answer a=\"317029\"]\r\n\r\n1.\u00a0The symbol for the element oxygen, O, represents both the element and one atom of oxygen. A molecule of oxygen, O<sub>2<\/sub>, contains two oxygen atoms; the subscript 2 in the formula must be used to distinguish the diatomic molecule from two single oxygen atoms.\r\n\r\n3.\u00a0(a) molecular CO<sub>2<\/sub>, empirical CO<sub>2<\/sub>; (b) molecular C<sub>2<\/sub>H<sub>2<\/sub>, empirical CH; (c) molecular C<sub>2<\/sub>H<sub>4<\/sub>, empirical CH<sub>2<\/sub>; (d) molecular H<sub>2<\/sub>SO<sub>4<\/sub>, empirical H<sub>2<\/sub>SO<sub>4<\/sub>\r\n\r\n5.\u00a0(a) C<sub>4<\/sub>H<sub>5<\/sub>N<sub>2<\/sub>O; (b) C<sub>12<\/sub>H<sub>22<\/sub>O<sub>11<\/sub>; (c) HO; (d) CH<sub>2<\/sub>O; (e) C<sub>3<\/sub>H<sub>4<\/sub>O<sub>3<\/sub>\r\n\r\n7. (a) CH<sub>2<\/sub>O; (b) C<sub>2<\/sub>H<sub>4<\/sub>O\r\n\r\n[\/hidden-answer]\r\n\r\n<span style=\"text-decoration: underline\"><strong>Part II<\/strong><\/span>\r\n<ol>\r\n \t<li>Open the <a href=\"https:\/\/phet.colorado.edu\/en\/simulation\/build-a-molecule\" target=\"_blank\" rel=\"noopener\">Build a Molecule simulation<\/a> and select the \u201cPlayground\u201d tab. Select an appropriate atoms \u201cKit\u201d to build a molecule with two carbon and six hydrogen atoms. Drag atoms into the space above the \u201cKit\u201d to make a molecule. A name will appear when you have made an actual molecule that exists (even if it is not the one you want). You can use the scissors tool to separate atoms if you would like to change the connections.\r\n<ol>\r\n \t<li>Draw the structural formula of this molecule and state its name.<\/li>\r\n \t<li>Can you arrange these atoms in any way to make a different compound?<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Use the <a href=\"https:\/\/phet.colorado.edu\/en\/simulation\/build-a-molecule\" target=\"_blank\" rel=\"noopener\">Build a Molecule simulation<\/a> to repeat question 1, but build a molecule with two carbons, six hydrogens, and one oxygen.\r\n<ol>\r\n \t<li>Draw the structural formula of this molecule and state its name.<\/li>\r\n \t<li>Can you arrange these atoms to make a different molecule? If so, draw its structural formula and state its name.<\/li>\r\n \t<li>How are the molecules drawn in (a) and (b) the same? How do they differ? What are they called (the type of relationship between these molecules, not their names).<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Use the <a href=\"https:\/\/phet.colorado.edu\/en\/simulation\/build-a-molecule\" target=\"_blank\" rel=\"noopener\">Build a Molecule simulation<\/a> to repeat question 1, but build a molecule with three carbons, seven hydrogens, and one chlorine.\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>Draw the structural formula of this molecule and state its name.<\/li>\r\n \t<li>Can you arrange these atoms to make a different molecule? If so, draw its structural formula and state its name.<\/li>\r\n \t<li>How are the molecules drawn in (a) and (b) the same? How do they differ? What are they called (the type of relationship between these molecules, not their names)?<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"690363\"]Show Answers to Question 2[\/reveal-answer]\r\n[hidden-answer a=\"690363\"]\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>ethanol\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211052\/CNX_Chem_02_04_Question9a_img1.jpg\" alt=\"A Lewis Structure is shown. An oxygen atom is bonded to a hydrogen atom and a carbon atom. The carbon atom is bonded to two hydrogen atoms and another carbon atom. That carbon atom is bonded to three more hydrogen atoms. There are a total of two carbon atoms, six hydrogen atoms, and one oxygen atoms.\" \/><\/li>\r\n \t<li>methoxymethane, more commonly known as dimethyl ether\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211053\/CNX_Chem_02_04_Question9b_img1.jpg\" alt=\"A Lewis Structure is shown. An oxygen atom is bonded to two carbon atoms. Each carbon atom is bonded to three different hydrogen atoms. There are a total of two carbon atoms, six hydrogen atoms, and one oxygen atom.\" \/><\/li>\r\n \t<li>These molecules have the same chemical composition (types and number of atoms) but different chemical structures. They are structural isomers.<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n\r\n<span style=\"text-decoration: underline\"><strong>Part III<\/strong><\/span>\r\n<ol>\r\n \t<li><span style=\"font-size: 1rem;text-align: initial\">What property of carbon makes it essential for organic life?<\/span><\/li>\r\n \t<li>Compare and contrast saturated and unsaturated triglycerides:<\/li>\r\n<\/ol>\r\n<div id=\"fs-idm137628192\" class=\"solution\">\r\n<div id=\"fs-idm106256016\" class=\"solution\">\r\n\r\n[reveal-answer q=\"317029\"]Show Selected Answers[\/reveal-answer]\r\n[hidden-answer a=\"317029\"]\r\n\r\n1.\u00a0Carbon is unique and found in all living things because it can form up to four covalent bonds between atoms or molecules. These can be nonpolar or polar covalent bonds, and they allow for the formation of long chains of carbon molecules that combine to form proteins and DNA.\r\n\r\n2.\u00a0Saturated triglycerides contain no double bonds between carbon atoms; they are usually solid at room temperature. Unsaturated triglycerides contain at least one double bond between carbon atoms and are usually liquid at room temperature.\r\n\r\n[\/hidden-answer]\r\n\r\nPart IV\r\n<ol>\r\n \t<li>Why are biological macromolecules considered organic?<\/li>\r\n \t<li>What role do electrons play in dehydration synthesis and hydrolysis?<\/li>\r\n \t<li>Name the reaction in which macromolecules are produced:<\/li>\r\n \t<li>Name the reaction in which macromolecules are broken down:<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"317029\"]Show Selected Answers[\/reveal-answer]\r\n[hidden-answer a=\"317029\"]\r\n\r\n1. Biological macromolecules are organic because they contain carbon and hydrogen.\r\n\r\n2. In a dehydration synthesis reaction, the hydrogen of one monomer combines with the hydroxyl group of another monomer, releasing a molecule of water. This creates an opening in the outer shells of atoms in the monomers, which can share electrons and form covalent bonds.\r\n\r\n3. Dehydration synthesis\r\n\r\n4. Hydrolysis\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>","rendered":"<p><strong><span style=\"text-decoration: underline\">Part I<\/span><\/strong><\/p>\n<ol>\n<li id=\"fs-idm228245568\">Explain why the symbol for an atom of the element oxygen and the formula for a molecule of oxygen differ.<\/li>\n<li>Explain why the symbol for the element sulfur and the formula for a molecule of sulfur differ.<\/li>\n<li>Write the molecular and empirical formulas of the following compounds:\n<ol style=\"list-style-type: lower-alpha\">\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211040\/CNX_Chem_02_04_Question3a_img1.jpg\" alt=\"Figure A shows a carbon atom that forms two, separate double bonds with two oxygen atoms.\" \/><\/li>\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211041\/CNX_Chem_02_04_Question3b_img1.jpg\" alt=\"Figure B shows a hydrogen atom which forms a single bond with a carbon atom. The carbon atom forms a triple bond with another carbon atom. The second carbon atom forms a single bond with a hydrogen atom.\" \/><\/li>\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211042\/CNX_Chem_02_04_Question3c_img1.jpg\" alt=\"Figure C shows a carbon atom forming a double bond with another carbon atom. Each carbon atom forms a single bond with two hydrogen atoms.\" \/><\/li>\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211043\/CNX_Chem_02_04_Question3d_img1.jpg\" alt=\"Figure D shows a sulfur atom forming single bonds with four oxygen atoms. Two of the oxygen atoms form a single bond with a hydrogen atom.\" \/><\/li>\n<\/ol>\n<\/li>\n<li>Write the molecular and empirical formulas of the following compounds:\n<ol style=\"list-style-type: lower-alpha\">\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211044\/CNX_Chem_02_04_Question4a_img1.jpg\" alt=\"Figure A shows a structural diagram of four carbon atoms bonded together into a chain. The two carbon atoms on the left form a double bond with each other. All of the remaining carbon atoms form single bonds with each other. The leftmost carbon also forms single bonds with two hydrogen. The second carbon in the chain forms a single bond with a hydrogen atom. The third carbon in the chain forms a single bond with two hydrogen atoms each. The rightmost carbon forms a single bond with three hydrogen atoms each.\" \/><\/li>\n<li><img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211045\/CNX_Chem_02_04_Question4b_img1.jpg\" alt=\"Figure B shows a structural diagram of a molecule that has a chain of four carbon atoms. The leftmost carbon atom forms a single bond with three hydrogen atoms each and single bond with the second carbon atom. The second carbon atom forms a triple bond with the third carbon atom. The third carbon atom forms a single bond to the fourth carbon atom. The fourth carbon atom forms a single bond to three hydrogen atoms each.\" width=\"325\" height=\"142\" \/><\/li>\n<li><img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211046\/CNX_Chem_02_04_Question4c_img1.jpg\" alt=\"Figure C shows a structural diagram of two silicon atoms are bonded together with a single bond. Each of the silicon atoms form single bonds to two chlorine atoms each and one hydrogen atom.\" width=\"325\" height=\"142\" \/><\/li>\n<li><img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211048\/CNX_Chem_02_04_Question4d_img1.jpg\" alt=\"Figure D shows a structural diagram of a phosphorus atom that forms a single bond to four oxygen atoms each. Three of the oxygen atoms each have a single bond to a hydrogen atom.\" width=\"325\" height=\"142\" \/><\/li>\n<\/ol>\n<\/li>\n<li>Determine the empirical formulas for the following compounds:\n<ol style=\"list-style-type: lower-alpha\">\n<li>caffeine, C<sub>8<\/sub>H<sub>10<\/sub>N<sub>4<\/sub>O<sub>2 \u00a0<\/sub><\/li>\n<li>fructose, C<sub>12<\/sub>H<sub>22<\/sub>O<sub>11 \u00a0<\/sub><\/li>\n<li>hydrogen peroxide, H<sub>2<\/sub>O<sub>2 \u00a0<\/sub><\/li>\n<li>glucose, C<sub>6<\/sub>H<sub>12<\/sub>O<sub>6 \u00a0<\/sub><\/li>\n<li>ascorbic acid (vitamin C), C<sub>6<\/sub>H<sub>8<\/sub>O<sub>6<\/sub><\/li>\n<\/ol>\n<\/li>\n<li>Determine the empirical formulas for the following compounds:\n<ol style=\"list-style-type: lower-alpha\">\n<li>acetic acid, C<sub>2<\/sub>H<sub>4<\/sub>O<sub>2 \u00a0<\/sub><\/li>\n<li>citric acid, C<sub>6<\/sub>H<sub>8<\/sub>O<sub>7 \u00a0\u00a0<\/sub><\/li>\n<li>hydrazine, N<sub>2<\/sub>H<sub>4 \u00a0\u00a0<\/sub><\/li>\n<li>nicotine, C<sub>10<\/sub>H<sub>14<\/sub>N<sub>2 \u00a0\u00a0<\/sub><\/li>\n<li>butane, C<sub>4<\/sub>H<sub>10<\/sub><\/li>\n<\/ol>\n<\/li>\n<li>Write the empirical formulas for the following compounds:\n<ol style=\"list-style-type: lower-alpha\">\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211049\/CNX_Chem_02_04_Question7a_img1.jpg\" alt=\"Figure A shows a structural diagram of two carbon atoms that form a single bond with each other. The left carbon atom forms single bonds with hydrogen atoms each. The right carbon forms a double bond to an oxygen atom. The right carbon also forms a single bonded to another oxygen atom. This oxygen atom also forms a single bond to a hydrogen atom.\" \/><\/li>\n<li><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211050\/CNX_Chem_02_04_Question7b_img1.jpg\" alt=\"Figure B shows a structural diagram containing a leftmost carbon that forms single bonds to three hydrogen atoms each. This leftmost carbon also forms a single bond to a second carbon atom. The second carbon atom forms a double bond with an oxygen atom. The second carbon also forms a single bond to a second oxygen atom. This oxygen atom forms a single bond to a third carbon atom. This third carbon atom forms single bonds with two hydrogen atoms each as well as a single bond with another carbon atom. The rightmost carbon atom forms a single bond with three hydrogen atoms each.\" \/><\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q317029\">Show Selected Answers<\/span><\/p>\n<div id=\"q317029\" class=\"hidden-answer\" style=\"display: none\">\n<p>1.\u00a0The symbol for the element oxygen, O, represents both the element and one atom of oxygen. A molecule of oxygen, O<sub>2<\/sub>, contains two oxygen atoms; the subscript 2 in the formula must be used to distinguish the diatomic molecule from two single oxygen atoms.<\/p>\n<p>3.\u00a0(a) molecular CO<sub>2<\/sub>, empirical CO<sub>2<\/sub>; (b) molecular C<sub>2<\/sub>H<sub>2<\/sub>, empirical CH; (c) molecular C<sub>2<\/sub>H<sub>4<\/sub>, empirical CH<sub>2<\/sub>; (d) molecular H<sub>2<\/sub>SO<sub>4<\/sub>, empirical H<sub>2<\/sub>SO<sub>4<\/sub><\/p>\n<p>5.\u00a0(a) C<sub>4<\/sub>H<sub>5<\/sub>N<sub>2<\/sub>O; (b) C<sub>12<\/sub>H<sub>22<\/sub>O<sub>11<\/sub>; (c) HO; (d) CH<sub>2<\/sub>O; (e) C<sub>3<\/sub>H<sub>4<\/sub>O<sub>3<\/sub><\/p>\n<p>7. (a) CH<sub>2<\/sub>O; (b) C<sub>2<\/sub>H<sub>4<\/sub>O<\/p>\n<\/div>\n<\/div>\n<p><span style=\"text-decoration: underline\"><strong>Part II<\/strong><\/span><\/p>\n<ol>\n<li>Open the <a href=\"https:\/\/phet.colorado.edu\/en\/simulation\/build-a-molecule\" target=\"_blank\" rel=\"noopener\">Build a Molecule simulation<\/a> and select the \u201cPlayground\u201d tab. Select an appropriate atoms \u201cKit\u201d to build a molecule with two carbon and six hydrogen atoms. Drag atoms into the space above the \u201cKit\u201d to make a molecule. A name will appear when you have made an actual molecule that exists (even if it is not the one you want). You can use the scissors tool to separate atoms if you would like to change the connections.\n<ol>\n<li>Draw the structural formula of this molecule and state its name.<\/li>\n<li>Can you arrange these atoms in any way to make a different compound?<\/li>\n<\/ol>\n<\/li>\n<li>Use the <a href=\"https:\/\/phet.colorado.edu\/en\/simulation\/build-a-molecule\" target=\"_blank\" rel=\"noopener\">Build a Molecule simulation<\/a> to repeat question 1, but build a molecule with two carbons, six hydrogens, and one oxygen.\n<ol>\n<li>Draw the structural formula of this molecule and state its name.<\/li>\n<li>Can you arrange these atoms to make a different molecule? If so, draw its structural formula and state its name.<\/li>\n<li>How are the molecules drawn in (a) and (b) the same? How do they differ? What are they called (the type of relationship between these molecules, not their names).<\/li>\n<\/ol>\n<\/li>\n<li>Use the <a href=\"https:\/\/phet.colorado.edu\/en\/simulation\/build-a-molecule\" target=\"_blank\" rel=\"noopener\">Build a Molecule simulation<\/a> to repeat question 1, but build a molecule with three carbons, seven hydrogens, and one chlorine.\n<ol style=\"list-style-type: lower-alpha\">\n<li>Draw the structural formula of this molecule and state its name.<\/li>\n<li>Can you arrange these atoms to make a different molecule? If so, draw its structural formula and state its name.<\/li>\n<li>How are the molecules drawn in (a) and (b) the same? How do they differ? What are they called (the type of relationship between these molecules, not their names)?<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q690363\">Show Answers to Question 2<\/span><\/p>\n<div id=\"q690363\" class=\"hidden-answer\" style=\"display: none\">\n<ol style=\"list-style-type: lower-alpha\">\n<li>ethanol<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211052\/CNX_Chem_02_04_Question9a_img1.jpg\" alt=\"A Lewis Structure is shown. An oxygen atom is bonded to a hydrogen atom and a carbon atom. The carbon atom is bonded to two hydrogen atoms and another carbon atom. That carbon atom is bonded to three more hydrogen atoms. There are a total of two carbon atoms, six hydrogen atoms, and one oxygen atoms.\" \/><\/li>\n<li>methoxymethane, more commonly known as dimethyl ether<br \/>\n<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211053\/CNX_Chem_02_04_Question9b_img1.jpg\" alt=\"A Lewis Structure is shown. An oxygen atom is bonded to two carbon atoms. Each carbon atom is bonded to three different hydrogen atoms. There are a total of two carbon atoms, six hydrogen atoms, and one oxygen atom.\" \/><\/li>\n<li>These molecules have the same chemical composition (types and number of atoms) but different chemical structures. They are structural isomers.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p><span style=\"text-decoration: underline\"><strong>Part III<\/strong><\/span><\/p>\n<ol>\n<li><span style=\"font-size: 1rem;text-align: initial\">What property of carbon makes it essential for organic life?<\/span><\/li>\n<li>Compare and contrast saturated and unsaturated triglycerides:<\/li>\n<\/ol>\n<div id=\"fs-idm137628192\" class=\"solution\">\n<div id=\"fs-idm106256016\" class=\"solution\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q317029\">Show Selected Answers<\/span><\/p>\n<div id=\"q317029\" class=\"hidden-answer\" style=\"display: none\">\n<p>1.\u00a0Carbon is unique and found in all living things because it can form up to four covalent bonds between atoms or molecules. These can be nonpolar or polar covalent bonds, and they allow for the formation of long chains of carbon molecules that combine to form proteins and DNA.<\/p>\n<p>2.\u00a0Saturated triglycerides contain no double bonds between carbon atoms; they are usually solid at room temperature. Unsaturated triglycerides contain at least one double bond between carbon atoms and are usually liquid at room temperature.<\/p>\n<\/div>\n<\/div>\n<p>Part IV<\/p>\n<ol>\n<li>Why are biological macromolecules considered organic?<\/li>\n<li>What role do electrons play in dehydration synthesis and hydrolysis?<\/li>\n<li>Name the reaction in which macromolecules are produced:<\/li>\n<li>Name the reaction in which macromolecules are broken down:<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q317029\">Show Selected Answers<\/span><\/p>\n<div id=\"q317029\" class=\"hidden-answer\" style=\"display: none\">\n<p>1. Biological macromolecules are organic because they contain carbon and hydrogen.<\/p>\n<p>2. In a dehydration synthesis reaction, the hydrogen of one monomer combines with the hydroxyl group of another monomer, releasing a molecule of water. This creates an opening in the outer shells of atoms in the monomers, which can share electrons and form covalent bonds.<\/p>\n<p>3. Dehydration synthesis<\/p>\n<p>4. Hydrolysis<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"author":359083,"menu_order":5,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1333","chapter","type-chapter","status-publish","hentry"],"part":311,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/pressbooks\/v2\/chapters\/1333","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/wp\/v2\/users\/359083"}],"version-history":[{"count":7,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/pressbooks\/v2\/chapters\/1333\/revisions"}],"predecessor-version":[{"id":1402,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/pressbooks\/v2\/chapters\/1333\/revisions\/1402"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/pressbooks\/v2\/parts\/311"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/pressbooks\/v2\/chapters\/1333\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/wp\/v2\/media?parent=1333"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/pressbooks\/v2\/chapter-type?post=1333"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/wp\/v2\/contributor?post=1333"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-introbio2\/wp-json\/wp\/v2\/license?post=1333"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}